Description : By the 10th century AD, Buddhist art in India was being replaced by art influenced by Hinduism and _____.?
Last Answer : A. Christianity B. Judaism C. Islam D. atheism
Description : In the 3rd century BC, the rule of which ruler is inscribed in Brahmi script ?
Last Answer : Ashoka's reign is inscribed in Brahmi script in the 3rd century BC.
Description : Panini, the first Grammarian of Sanskrit language in India, lived during the A. 2nd Century BC B. 5th-6th Century BC C. 2nd Century AD D. 5th-6th Century AD
Last Answer : B. 5th-6th Century BC
Description : The heating value per unit volume of hydrogen gas is less than ______________ that of air. a) 1/12th b) 1/10th c) 2/3rd d) 1/3rd
Last Answer : Answer: d Explanation: None
Description : Hydrogen gas has less than _______________ the density of air. a) 1/12th b) 1/10th c) 2/3rd d) 1/3rd
Last Answer : Answer: b Explanation: None.
Description : The sub-multiple prefix 'pico' (p) means ____________. A. thousandth (10 to the -3rd power) B. millionth (10 to the -6th power) C. billionth (10 to the -9th power) D. trillionth (10 to the -12th power)
Last Answer : Answer: D
Description : The sub-multiple prefix 'nano' (n) means ____________. A. thousandth (10 to the -3rd power) B. millionth (10 to the -6th power) C. billionth (10 to the -9th power) D. trillionth (10 to the -12th power)
Last Answer : Answer: C
Description : The sub-multiple prefix 'micro' (Greek letter 'mu') means ____________. A. thousandth (10 to the -3rd power) B. millionth (10 to the -6th power) C. billionth (10 to the -9th power) D. trillionth (10 to the -12th power)
Last Answer : Answer: B
Description : The sub-multiple prefix 'milli' (m) means ____________. A. one thousandth (10 to the -3rd power) B. one millionth (10 to the -6th power) C. one billionth (10 to the -9th power) D. one trillionth (10 to the -12th power)
Last Answer : Answer: A
Description : The multiple prefix 'mega' (M) means ____________. A. thousand (10 to the 3rd power) B. million (10 to the 6th power) C. billion (10 to the 9th power) D. trillion (10 to the 12th power)
Description : The multiple prefix 'tera' (T) means ____________. A. thousand (10 to the 3rd power) B. million (10 to the 6th power) C. billion (10 to the 9th power) D. trillion (10 to the 12th power)
Description : The multiple prefix 'giga' (G) means ____________. A. thousand (10 to the 3rd power) B. million (10 to the 6th power) C. billion (10 to the 9th power) D. trillion (10 to the 12th power)
Description : “Chauburji” in Lahore is one of the famous monuments belonging to the Mughal period. It was reportedly built as a gateway to a beautiful garden built for Princess Zebunissa. She was an accomplished daughter of which Mughal Emperor? A. Shah Jahan B. Akbar C. Jahangir D. Aurangzeb
Last Answer : ANSWER: D
Description : 93 “Chauburji” in Lahore is one of the famous monuments belonging to the Mughal period. It was reportedly built as a gateway to a beautiful garden built for Princess Zebunissa. She was an accomplished daughter of which Mughal Emperor? A. Shah Jahan B. Akbar C. Jahangir D. Aurangzeb
Description : Lahore “Chauburji” in Lahore is one of the famous monuments belonging to the Mughal period. It was reportedly built as a gateway to a beautiful garden built for Princess Zebunissa. She was an accomplished daughter of which Mughal Emperor? A. Shah Jahan B. Akbar C. Jahangir D. Aurangzeb
Description : For What purpose the Specimen signature of AD in charge of PLI is circulated to whole circle concerned? a. To enable Payment of government Securities at any post office. b. to Limit the payment of PLI selected offices C. None of these
Last Answer : a. To enable Payment of government Securities at any post office
Description : 12th century(or 1100's) Scottish womans dress?
Last Answer : Google SCA. Society for Chronological Anachronisms. You should find a contact that will be only too happy to point you on the right direction.
Description : What happend in the 12th century that made the rent one possible?
Last Answer : Need answer
Description : The Ghaznavi Kingdom was overthrown near the end of 12th Century by the: A. Ghorids B. Mughals C. Ghaznavids D. Lodhis
Last Answer : ANSWER: A
Description : It denoted a woman in French/Creole, and that is how it figures in the title of a popular tune from the 1930s. This word may have some connection to the Dutch word for woman and is still ... in the 12th century as a bastion for single women. Name either the tune OR the Amsterdam structure.
Last Answer : Begin the Beguine OR The Begijnhof.
Description : One who possesses outstanding technical ability in a particular art or field. -Do You Know?
Last Answer : A virtuoso (from Italian virtuoso [virˈtwoːzo] or [virtuˈoːso], "virtuous", Late Latin virtuosus, Latin virtus, "virtue", "excellence" or "skill") is an individual who possesses outstanding technical ... art or field such as fine arts, music, singing, playing a musical instrument, or composition
Description : ______ risk is the potential exchange loss from outstanding obligations as a result of exchange-rate fluctuations. A. Trade B. Exchange C. Finance D. Noncompletion E. Transaction
Last Answer : E. Transaction
Description : The Gandharva School of art is also known as the (SSC CGL 1st Sit. 2013) (a) Buddhist-Roman art (b) Dravidian-Roman art (c) Greco-Roman art (d) Greco-Roman-Buddhist art
Last Answer : (d) Greco-Roman-Buddhist art
Description : One of the prominent Buddhist structures in India ______ Stupa at Sarnath was constructed by the great mauryan King Ashoka.
Last Answer : Dhamekh
Description : Maximum warehousing period for goods belonging to 100% Export Oriented Unit is _____. A 5 years B 3 years C 1 year D no limit on time period
Last Answer : Ans :no limit on time period
Description : What is your viewpoint of the usage of CE & BCE (as alternatives to BC & AD)?
Last Answer : I had to convert back in college in the early seventies or my papers wouldn’t be accepted. Been using BCE/CE every since.
Description : Where is the AD before BC, tomorrow before yesterday, and the eight is first? -Riddles
Last Answer : In a dictionary.
Description : 4. ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30). Show that F is the mid-point of BC. -Maths 9th
Last Answer : . Solution: Given that, ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. To prove, F is the mid-point of BC. Proof, BD intersected EF at G. In ΔBAD, E is the ... point of BD and also GF || AB || DC. Thus, F is the mid point of BC (Converse of mid point theorem)
Description : ABCD is a trapezium in which AB || CD and AD = BC (see Fig. 8.23). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint : Extend AB and draw a line through C parallel to DA intersecting AB produced at E.] -Maths 9th
Last Answer : ] Solution: To Construct: Draw a line through C parallel to DA intersecting AB produced at E. (i) CE = AD (Opposite sides of a parallelogram) AD = BC (Given) , BC = CE ⇒∠CBE = ∠CEB also, ∠A+∠CBE = ... BC (Given) , ΔABC ≅ ΔBAD [SAS congruency] (iv) Diagonal AC = diagonal BD by CPCT as ΔABC ≅ ΔBA.
Description : In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram ( ... CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th
Last Answer : . Solution: (i) AB = DE and AB || DE (Given) Two opposite sides of a quadrilateral are equal and parallel to each other. Thus, quadrilateral ABED is a parallelogram (ii) Again BC = EF and BC || EF ... (Given) BC = EF (Given) AC = DF (Opposite sides of a parallelogram) , ΔABC ≅ ΔDEF [SSS congruency]
Description : ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th
Last Answer : Given: A △ABC , right - angled at C. A line through the mid - point M of hypotenuse AB parallel to BC intersects AC at D. To Prove: (i) D is the mid - point of AC (ii) MD | AC (iii) CM = MA = 1 / 2 ... congruence axiom] ⇒ AM = CM Also, M is the mid - point of AB [given] ⇒ CM = MA = 1 / 2 = AB.
Description : ABCD is a trapezium in which AB II CD and AD = BC (see flg). Show that: -Maths 9th
Last Answer : Given: ABCD is a trapezium, in which AB || DC and AD = BC. To Prove: (i) ∠A = ∠B (ii) ∠C = ∠D (iii) △ABC ≅ △BAD (iv) Diagonal AC = diagonal BD. Const.: Produce AB to E, such that a line through ... △ABC ≅ △BAD [by SAS congruence axiom] (iv) ⇒ AC = BD [c.p.c.t.] Thus, diagonal AC = diagonal BD.
Description : In the given figure, D is the mid-point of BC and L mid-is the point of AD. -Maths 9th
Last Answer : In △ABC, AD is the median ∴ ar(△ABD) = 1/2 ar(△ABC) Again, △ABD BL is the median ∴ ar(△ABL) = 1/2 ar(△ABD) = 1/2 × 1/2 ar((△ABC) = 1/4 ar((△ABC) Hence, value of x is 1/4.
Description : ABCD is a parallelogram and BC is produced to a point Q such that AD = CQ. -Maths 9th
Last Answer : In ||gm ABCD , ar(△APC) = ar(△BCP) ---i) [∵ triangles on the same base and between the same parallels have equal area] Similarly, ar( △ADQ) = ar(△ADC) ---ii) Now, ar(△ADQ) - ar(△ADP) = ar(△ADC) - ar(△ADP) ... ) From (i) and (iii) , we have ar(△BCP) = ar(△DPQ) or ar( △BPC) = ar(△DPQ)
Description : E and F are respectively the mid-points of the non-parallel sides AD and BC of a trapezium ABCD. -Maths 9th
Last Answer : According to question the mid-points of the non-parallel sides AD and BC of a trapezium ABCD.
Description : P and O are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. -Maths 9th
Last Answer : According to question PQ passes through the point of intersection O of its diagonals AC and BD.
Description : In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q. -Maths 9th
Last Answer : According to question prove that ar (ABCD) = ar (APQD).
Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th
Last Answer : According to question prove that P, Q, R and D are concyclic.
Description : ABCD is a parallelogram. A circle through A, B is so drawn that it intersects AD at P and BC at Q. -Maths 9th
Last Answer : Given ABCD is a parallelogram. A circle whose centre O passes through A, B is so drawn that it intersect AD at P and BC at Q To prove Points P, Q, C and D are con-cyclic. Construction Join PQ ... Thus, the quadrilateral QCDP is cyclic. So, the points P, Q, C and D are con-cyclic. Hence proved.