Description : Match the column: 1. In and ÆB = ÆC PQ PR (A) AA similarity criterion = 2. In and A = = 3. In and (B) SSS similarity criterion (C) BPT ÆB = ÆC = BC PQ PR QR 4. In , DE ÆD = ÆE BD CE (D) SAS similarity ... 7. Areas of these triangles are in the ratio (a) 9 : 35 (b) 9 : 49 (c) 49 : 9 (d) 9 : 42
Last Answer : (b) 9 : 49
Description : `PQR` is a triangular park with `PQ=PR=200m`. A.T.V. tower stands at the mid-point of `QR`. If the angles of elevation of the top of the tower at `P`,
Last Answer : `PQR` is a triangular park with `PQ=PR=200m`. A.T.V. tower stands at the mid-point of `QR`. If the angles of ... (3)` B. `50sqrt(2)` C. `100` D. `50`
Description : If AB = QR, BC = PR and CA = PQ, then -Maths 9th
Last Answer : (b) We know that, if ΔRST is congruent to ΔUVW i.e., ΔRST = ΔUVW, then sides of ΔRST fall on corresponding equal sides of ΔUVW and angles of ΔRST fall on corresponding equal angles of ΔUVW. Here, given AB = ... , or ΔCBA ≅ ΔPRQ, so option (b) is correct, or ΔBCA ≅ ΔRPQ, so option (d) is incorrect.
Description : If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th
Last Answer : Solution :-
Description : If AB = PQ, BC = QR and AC = PR, then write the congruence relation between the triangles. [Fig. 7.6] -Maths 9th
Last Answer : Solution :- △ ABC ≅ △PQR
Description : If pq plus qr pr statements must be true?
Last Answer : What is the answer ?
Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th
Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm
Description : If b = 4 units ,the coordinates of point A on the side PQ which divides PQ internally in the ratio 1: 3 are: (a) (1,0) (b) (3,3) (c) (3,0) (d) (1,1)
Last Answer : (a) (1,0)
Description : PQRS is a square. A is a point on PS ,B is a point on PQ,C is a point on QR. ABC is a triangle inside square PQRS. Angle abc = 90° . If AP=BQ=CR then prove that angle BAC =45° -Maths 9th
Last Answer : This is the sketch of the question but its hard to answer.
Description : If PQRS is trapezium such that PQ > RS and L, M are the mid-points of the diagonals PR and QS respectively then what is LM equal to? -Maths 9th
Last Answer : if pqrs is a trapezium so pq and RS are parallel is you draw a diagonal you will divide the trapezium into two parts such that two equal triangle so
Description : In the figure, PSDA is a parallelogram. Points Q and R are taken on PS such that PQ = QR= RS and PA || QB || RC. -Maths 9th
Last Answer : Given In a parallelogram PSDA, points 0 and R are on PS such that PQ = QR = RS and PA || QB || RC. To prove ar (PQE) = ar (CFD) Proof In parallelogram PABQ, and PA||QB [given] So, ... = ΔDCF [by ASA congruence rule] ∴ ar (ΔPQE) = ar (ΔCFD) [since,congruent figures have equal area] Hence proved.
Description : If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2
Last Answer : D) We have (P + Q + R)/3 = A P+Q+R = 3A (P+Q+R)^2 = 9A^2 P^2+Q^2+R^2 + 2 (PQ + QR + PR) = 9A^2 P^2+Q^2+R^2 = 9A^2 Required mean = (P^2+Q^2+R^2)/3 = 9A^2/3= 3A^2
Description : The diagram below shows the propagations of a wave. Which points are in phase? (a) PQ (b) QR (c) QS (d) TQ
Last Answer : Ans:(c)
Description : If a point O lies between two points P and R such that PO=OR then prove that PO= 1/2PR. -Maths 9th
Last Answer : THINGS WHICH ARE COINCIDE WITH EACH OTHER ARE EQUAL TO ONE ANOTHER PO+OR=PR 2PO=PR PO=OR PO=1/2PR HENCE PROVED
Description : In angle PQR angle P = 80 .If PQ =PR find angle Q and angle R -Maths 9th
Last Answer : a triangle includes 3 angles summing up as 180° so 180 =
Description : P and O are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. -Maths 9th
Last Answer : According to question PQ passes through the point of intersection O of its diagonals AC and BD.
Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2
Last Answer : (c) 77 cm 2
Description : Areas of two similar triangles are 36 cm 2 and 100 cm 2 . If the length of a side of thelarger triangle is 20 cm, then the length of the corresponding side of the smaller triangle is: (a) 12cm (b) 13cm (c) 14cm (d) 15cm
Last Answer : (a) 12cm
Description : In a rhombus if d1 = 16 cm, d2 = 12 cm, then the length of the side of the rhombus is (a) 8 cm (b) 9 cm (c) 10 cm (d) 12 cm
Last Answer : (c) 10 cm
Description : ABCD is a parallelogram with diagonal AC If a line XZ is drawn such that XZ ∥ AB, then BX/XC = ? (a) (AY/AC) (b) DZ/AZ (c) AZ/ZD (d) AC/AY Answer: (c) AZ/ZD 13. In the given figure, value of x (in cm) is (a) 5cm (b) 3.6 cm (c) 3.2 cm (d) 10 cm
Last Answer : (a) 5cm
Description : D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE || BC. Then, length of DE (in cm) is (a) 2.5 (b) 3 (c) 5 (d) 6
Last Answer : (b) 3
Description : Nomination fee for changing/altering of PLI policy is a) Rs 1/- b) Rs2/- c) Rs 5/- d) Free
Last Answer : d) Free
Description : A (5,-1) , B (-3,-2) and C (-1,8) are the vertices of ∆ ABC . The median from A meets BC at D ,then the coordinates of the point D are: (a) (-4,6) (b) (2,7/2) (c) (1,-3/2) (d) (-2,3)
Last Answer : (d) (-2,3)
Description : The endpoint A of a line segment AB is (3 , -1). If midpoint of AB is (5,7) then the coordinates of the point B are: (a) (7,13) (b) (7,15) (c) (4,3) (d) (4,4)
Last Answer : (b) (7,15)
Description : The point (-1,2) divides the line segment joining the points A(2,5) and B(x,y) in the ratio 3:4, then the value of x2 + y2 is : (a) 27 (b) 28 (c) 29 (d) 30
Last Answer : (c) 29
Description : If = = in the system of equations a 1 x + b 1 y + c 1 = 0 and a 2 x + b 2 y + c 2 = 0 Statement 1 : This is the condition for inconsistent equations Statement 2 : There exists infinitely many solutions ... statements are true ? e) S1 only f) S1 and S2 g) S1 and S3 h) S2 only Answer: (d) S2 o
Last Answer : h) S2 only
Description : What is the area of the corresponding major sector of a circle of radius 28 cm and the central angle 45 o ? (a) 4312 cm 2 (b) 2156 cm 2 (c) 1256 cm 2 (d) 3412 cm 2
Last Answer : (b) 2156 cm 2
Description : The distance of the pole B from the corner O of the park is: (a) 6√2 units (b) 3√2 units (c) 6√3 units (d) 3√3 units
Last Answer : (a) 6√2 units
Description : O is any point on the diagonal PR of a parallelogram PQRS. -Maths 9th
Last Answer : Join QS. Let diagonals PR and QS intersect each other at T. We know, that diagonals of a parallelogram bisect each other . ∴ T is the mid - point of QS. Since a median of a triangle divides it into two triangles of equal ... ar(△PTS) + ar( △STO) = ar(△PQT) = ar( △ QTO ) ⇒ ar(△PSO) = ar(△PQO)
Description : O is any point on the diagonal PR of a parallelogram PQRS (figure). -Maths 9th
Last Answer : According to question prove that ar(ΔPSO) = ar(ΔPQO).
Description : In a square of side 10 cm, its diagonal is equal to (a) 15 cm (b) 10√2 cm (c) 20 cm (d) 12 cm
Last Answer : (b) 10√2 cm
Description : A thin wire is in the shape of a circle of radius 77 cm. It is bent into a square. What is the side of the square? (a) 168 cm (b) 242 cm (c) 121 cm (d) 336 cm
Last Answer : (c) 121 cm
Description : The area of the circle that can be inscribed in a square of side 6 cm is (a) 36 π cm 2 (b) 18 π cm 2 (c) 12 π cm 2 (d) 9 π cm 2
Last Answer : (d) 9 π cm 2
Description : A goat is tied to one corner of a square plot of side 12 meter by a rope 7 meter long. Find the area it can graze? (a) 38.5 sq.m (b) 155 sq.m (c) 144 sq.m (d) 19.25 sq.m
Last Answer : (a) 38.5 sq.m
Description : The sides of a triangle are in the ratio 3 : 5 : 7 and its perimeter is 30 cm. The length of the greatest side of the triangle in cm is (1) 6 (2) 10 (3) 14 (4) 16
Last Answer : (3) 14
Description : An equilateral triangle has a side of length 4.68m. What it is perimeter ?
Last Answer : Since each side is equal, just multiply by 3.
Description : In the given figure, (not drawn to scale), P is a point on AB such that AP : PB = 4 : 3. PQ is parallel to AC and QD -Maths 9th
Last Answer : answer:
Description : Is there any way to manipulate a sine function such that the amplitude when it is positive is larger than when it is negative?
Last Answer : Herp derp. I think I have an effective solution. Not quite what I was looking for, but. Just a slight vertical shift upwards. More of the wave will then lie above the x axis. If anyone has something better, do chime in!
Description : In real life we have situations such as: Rock > Scissors, Scissors > paper and Paper > Rock. Is there a type of math to deal with this?
Last Answer : answer:In Modular Arithmetic the numbers wrap around. That might be a good place to start to define the rules mathematically. As a kid we played rock, paper, scissors, bomb,. Symbol for bomb was fist with ... Bomb destroys rock, etc. .... Mod 4 Rock, paper,scissors, lizard, Spock would be Mod 5
Description : If m and n are two odd prime numbers such that m (a) an even number (b) an odd number (c) an odd prime number (d) a prime number
Last Answer : (a) an even number
Description : Can you tender a one rupee note in such a manner that there shall be total 50 coins but none of them would be 2 paise coins?
Last Answer : Answer: 45 one paisa coins, 2 five paise coins, 2 ten paise coins, and 1 twenty-five paise coins.
Description : Deoxyribose sugar + Nitrogenous base + phosphate group (PO2 )
Last Answer : Ans. Nucleotide
Description : A young child presents with respiratory distress, worsening over 2 days. Blood gases show a pH of 7.25, a PCO2 of 7.5kPa, a PO2 of 8.5kPa, and a base excess of -4. Which of the ... required. 4) Results are consistent with late severe asthma. 5) Bicarbonate may be necessary to correct the acidosis.
Last Answer : Answers-4 In interpreting blood gas results, the following sequence may be useful: Inspect the pH: Is it low, normal or high? Inspect the CO2: Is it low, normal or high? Inspect the PO2: Is ... excess and normal pH. Bicarbonate is usually only considered if the base deficit exceeds about -8 or 00.