It is impossible for a type of O+ baby to have a type of------mother: A. AB- (Answer) B. O- C. O+ D. none

It is impossible for a type of O+ baby to have a type of------mother:

A. AB- (Answer)

B. O-

C. O+

D. none
by

1 Answer

Answer :

A. AB- (Answer)
by

Related questions

A mother of blood group O has a group O child. What could be the blood group of father of the child? (1) Only O (2) A or B or O (3) A or B (4) Only AB

Description : A mother of blood group O has a group O child. What could be the blood group of father of the child? (1) Only O (2) A or B or O (3) A or B (4) Only AB

Last Answer : (2) A or B or O

People with what blood type can give blood to anyone and are thus called universal donors? A. O- (Answer) B. O C. AB+ D. AB-

Description : People with what blood type can give blood to anyone and are thus called universal donors? A. O- (Answer) B. O C. AB+ D. AB-

Last Answer : A. O- (Answer)

What is the rarest blood type in humans? A. O- B. O+ C. AB+ D. AB- (Answer)

Description : What is the rarest blood type in humans? A. O- B. O+ C. AB+ D. AB- (Answer)

Last Answer : D. AB- (Answer)

What convincing argument was made by Anne? i) She was talkative just like any other student in the class. ii) She had the right to be talkative, as it was a classroom and not a prison. iii) She had inherited the trait from her mother, so couldn‘t stop being talkative. iv) She found it impossible to be quiet like the others as she couldn‘t change herself.

Description : What convincing argument was made by Anne? i) She was talkative just like any other student in the class. ii) She had the right to be talkative, as it was a classroom and not a prison. iii) ... being talkative. iv) She found it impossible to be quiet like the others as she couldn t change herself.

Last Answer : iii) She had inherited the trait from her mother, so couldn‘t stop being talkative.

Which blood group is universal receiver? A. Group A B. Group B C. Group AB (Answer) D. GROUP O

Description : Which blood group is universal receiver? A. Group A B. Group B C. Group AB (Answer) D. GROUP O

Last Answer : C. Group AB (Answer)

A person with which of the following blood groups can receive blood of any group? A. A B. AB (Answer) C. B D. O

Description : A person with which of the following blood groups can receive blood of any group? A. A B. AB (Answer) C. B D. O

Last Answer : B. AB (Answer)

A person of which of the following blood groups is called a universal donor? A. O (Answer) B. AB C. A D. B

Description : A person of which of the following blood groups is called a universal donor? A. O (Answer) B. AB C. A D. B

Last Answer : A. O (Answer)

Person with following blood group are considered to be universal recipient ? A. A+ B. B+ C. AB+ (Answer) D. O+ E. None of these

Description : Person with following blood group are considered to be universal recipient ? A. A+ B. B+ C. AB+ (Answer) D. O+ E. None of these

Last Answer : C. AB+ (Answer)

Is it possible to have a baby after eating MM kit ? After 1 day of eating MM kit, bleeding stopped and there was excess pain in the lower abdomen. I took painkillers and the pain did not subside , so after 3 days I got USG test and confirmed that my wife was 7 weeks pregnant . Dr. Ballen MM Kit did not work. I would like to know if my wife will face any problem now that she is going to give birth to a child , will MM Kit cause any problem for mother and baby. Please give me the correct answer I am under extra stress.

Description : Is it possible to have a baby after eating MM kit ? After 1 day of eating MM kit, bleeding stopped and there was excess pain in the lower abdomen. I took painkillers and the pain did not subside ... Kit cause any problem for mother and baby. Please give me the correct answer I am under extra stress.

Last Answer : Usually when the fetal age is maximum 9 weeks or 63 days, it can be destroyed by using MM kit. But if it is more than that, abortion can no longer be done with MM kit It may be more or less , ... will not be harmed. There will be no problem in having a baby in the future or in the present baby.

If there is no capillarity? A. It would be impossible to use a kerosene lamp B. The blotting paper would fail to function C. There would have been no plants on earth D. All of above (Answer)

Description : If there is no capillarity? A. It would be impossible to use a kerosene lamp B. The blotting paper would fail to function C. There would have been no plants on earth D. All of above (Answer)

Last Answer : D. All of above (Answer)

“Rancidity produced in butter can be decreased by adding quinoline to the butter”. This statements shows that --------? A. Nothing is impossible B. Quinoline is an inhibitor (Answer) C. Quinoline is a catalyst D. Quinoline is an activator

Description : “Rancidity produced in butter can be decreased by adding quinoline to the butter”. This statements shows that --------? A. Nothing is impossible B. Quinoline is an inhibitor (Answer) C. Quinoline is a catalyst D. Quinoline is an activator

Last Answer : B. Quinoline is an inhibitor (Answer)

Very arcane, possibly impossible to answer movie question.

Description : Very arcane, possibly impossible to answer movie question.

Last Answer : huh…? I don’t think there is an answer.

What is the answer to 39 on the impossible quiz?

Description : What is the answer to 39 on the impossible quiz?

Last Answer : cylindrical adventures. is the answer in the impossible quiz1.

Which of the following statements is/are absolutely impossible ? (a) A woman giving birth to her own grandchild (b) A man attending his own funeral (c) The Sun not rising in the East some day (d) Cars running without petrol Choose the correct answer from the codes given below : Codes: (A) (a) and (b) (B) (c) and (d) (C) (b) (D) (a)

Description : Which of the following statements is/are absolutely impossible ? (a) A woman giving birth to her own grandchild (b) A man attending his own funeral (c) The Sun not rising in the East some day (d) Cars running without petrol Choose ... Codes: (A) (a) and (b) (B) (c) and (d) (C) (b) (D) (a)

Last Answer : Answer: A

What is the differance between blood type ab and blood type o?

Description : What is the differance between blood type ab and blood type o?

Last Answer : The difference between blood types has to do with the type of antigens on the red blood cells (RBC's) and the type of antibodies present in the blood. For example, type A blood has the A antigen on ... body (it is called the universal receiver) but can only give blood to a person with type AB blood.

A person having blood type B could safely donate blood to persons with blood types - (1) A and O (2) B and O (3) A and AB (4) B and AB

Description : A person having blood type B could safely donate blood to persons with blood types - (1) A and O (2) B and O (3) A and AB (4) B and AB

Last Answer : (4) B and AB Explanation: If someone belongs to the blood group B, he has B antigens on the surface of his red blood cells and A antibodies in' his blood plasma. So he can donate blood to persons of B and AB blood groups, but cannot receive blood from persons having B or O groups.

A man of A-blood group marries a woman of AB blood group. Which type of progeny would indicate that man is heterozygous A? (a) AB (b) A (c) O (d) B

Description : A man of A-blood group marries a woman of AB blood group. Which type of progeny would indicate that man is heterozygous A? (a) AB (b) A (c) O (d) B

Last Answer : B

A person with unknown blood group under ABO system, has suffered much blood loss in an accident and needs immediate blood transfusion. His friend who has valid certificate of his own blood type, offers for blood donation without delay. What would have been the type of blood group of the donor friend? (a) Type B (b) Type AB (c) Type O (d) Type A

Description : A person with unknown blood group under ABO system, has suffered much blood loss in an accident and needs immediate blood transfusion. His friend who has valid certificate of his own blood type, offers for blood donation ... of the donor friend? (a) Type B (b) Type AB (c) Type O (d) Type A

Last Answer : (d) Type A

A person having blood type B could safely donate blood to persons with blood types (1) A and O (2) B and O (3) A and AB (4) B and AB

Description : A person having blood type B could safely donate blood to persons with blood types (1) A and O (2) B and O (3) A and AB (4) B and AB

Last Answer : B and AB

What type of physician should Jane a new mother go to for personal care and the care of her baby?

Description : What type of physician should Jane a new mother go to for personal care and the care of her baby?

Last Answer : Need answer

A person of which of the following blood groups is called a universal donor? (a) O (b) AB (c) A (d) B

Description : A person of which of the following blood groups is called a universal donor? (a) O (b) AB (c) A (d) B

Last Answer : Ans:(a)

A person having which of the following blood groups can receive blood of any group? (a) A (b) AB (c) B (d) O

Description : A person having which of the following blood groups can receive blood of any group? (a) A (b) AB (c) B (d) O

Last Answer : Ans:(b)

In trapezium ABCD, AB|| DC and diagonals AC and BD intersect at O. If area of triangle AOD is 30cm square , find the area of triangle BOC -Maths 9th

Description : In trapezium ABCD, AB|| DC and diagonals AC and BD intersect at O. If area of triangle AOD is 30cm square , find the area of triangle BOC -Maths 9th

Last Answer : In the given figure: Area of triangle ADC = Area of triangle BCD (Triangles on the same and parallel) Now subtract the area of triangle DOC from both of them so... (Area of triangle ADC - Area of ... => Area of triangle AOD = Area of triangle BOC Hence the area of triangle BOC is 30 cm square.

A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

Description : In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

Last Answer : Join OE. In ΔOME and ΔONE, OM =ON [equal chords are equidistant from the centre] ∠OME = ∠ONE = 90° OE =OE [common sides] ∠OME ≅ ∠ONE [by SAS congruency] ⇒ ME = NE [by CPCT] In quadrilateral OMEN, ... =ON , ME = NE and ∠OME = ∠ONE = ∠MEN = ∠MON = 90° Hence, OMEN is a square. Hence proved.

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Description : In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Last Answer : In △OBC, OB = BC ⇒ ∠BOC = ∠BCO = y ...[angles opp. to equal sides are equal] ∠OBA is the exterior angle of △BOC So, ∠ABO = 2y ...[ext. angle is equal to the sum of int. opp. angles] Similarly, ∠AOD is the exterior angle of △AOC ∴ x = 2y + y = 3y

Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. -Maths 9th

Description : Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. -Maths 9th

Last Answer : Solution of this question

In trapezium ABCD, AB|| DC and diagonals AC and BD intersect at O. If area of triangle AOD is 30cm square , find the area of triangle BOC -Maths 9th

Description : In trapezium ABCD, AB|| DC and diagonals AC and BD intersect at O. If area of triangle AOD is 30cm square , find the area of triangle BOC -Maths 9th

Last Answer : In the given figure: Area of triangle ADC = Area of triangle BCD (Triangles on the same and parallel) Now subtract the area of triangle DOC from both of them so... (Area of triangle ADC - Area of ... => Area of triangle AOD = Area of triangle BOC Hence the area of triangle BOC is 30 cm square.

A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

Description : In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

Last Answer : Join OE. In ΔOME and ΔONE, OM =ON [equal chords are equidistant from the centre] ∠OME = ∠ONE = 90° OE =OE [common sides] ∠OME ≅ ∠ONE [by SAS congruency] ⇒ ME = NE [by CPCT] In quadrilateral OMEN, ... =ON , ME = NE and ∠OME = ∠ONE = ∠MEN = ∠MON = 90° Hence, OMEN is a square. Hence proved.

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Description : In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Last Answer : In △OBC, OB = BC ⇒ ∠BOC = ∠BCO = y ...[angles opp. to equal sides are equal] ∠OBA is the exterior angle of △BOC So, ∠ABO = 2y ...[ext. angle is equal to the sum of int. opp. angles] Similarly, ∠AOD is the exterior angle of △AOC ∴ x = 2y + y = 3y

Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. -Maths 9th

Description : Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. -Maths 9th

Last Answer : Solution of this question

In Fig. 10.25, a line intersect two concentric circles with centre O at A, B, C and D, Prove that AB = CD. -Maths 9th

Description : In Fig. 10.25, a line intersect two concentric circles with centre O at A, B, C and D, Prove that AB = CD. -Maths 9th

Last Answer : Solution :- Let OP be perpendicular from O on line l. Since the perpendicular from the centre of a circle to a chord,bisects the chord.Therefore, AP = DP ...(i) BP = CP ...(ii) Subtracting (ii) from (i), we get AP - BP = DP - CP ⇒ AB = CD

If O is the centre of the circle and chord AB = OA and the area of triangle AOB -Maths 9th

Description : If O is the centre of the circle and chord AB = OA and the area of triangle AOB -Maths 9th

Last Answer : (b) 16π cm2.AB = OA ⇒ AB = OA = OB (radii of circle are equal) ⇒ ΔAOB is equilateral. ∴ If ‘r’ is the radius of the circle,then area of ΔAOB = \(rac{\sqrt3}{4}\)side2⇒ \(rac{\sqrt3}{4}\)(r)2 = 4√3 (given)⇒ r2 = 16 ⇒ r = 4∴ Area of circle = πr2 = 16π cm2.

Let O be any point inside a triangle ABC. Let L, M and N be the points on AB, BC and CA respectively, -Maths 9th

Description : Let O be any point inside a triangle ABC. Let L, M and N be the points on AB, BC and CA respectively, -Maths 9th

Last Answer : answer:

From a point O in the interior of a DABC if perpendiculars OD, OE and OF are drawn to the sides BC, CA and AB respectively, then which of the -Maths 9th

Description : From a point O in the interior of a DABC if perpendiculars OD, OE and OF are drawn to the sides BC, CA and AB respectively, then which of the -Maths 9th

Last Answer : (i) In Δ O C E ,D C 2 = D E 2 + E C 2 Δ O B D , D B 2 = O D 2 + B D 2 Δ O A F , O A 2 = O F 2 + A F 2 Adding we get O A 2 + O B 2 + O C 2 = O F 2 + O D 2 + O F 2 + E C 2 + B D 2 + A F 2 A F 2 + B D 2 + C E 2 = O A

In a trapezium ABCD, AB is parallel to CD and the diagonals intersect each other at O. In this case, the ratio OA/OC is equal to: -Maths 9th

Description : In a trapezium ABCD, AB is parallel to CD and the diagonals intersect each other at O. In this case, the ratio OA/OC is equal to: -Maths 9th

Last Answer : answer:

A trapezium ABCD in which AB || CD is inscribed in a circle with centre O. Suppose the diagonals AC and BD of the trapezium intersect at M -Maths 9th

Description : A trapezium ABCD in which AB || CD is inscribed in a circle with centre O. Suppose the diagonals AC and BD of the trapezium intersect at M -Maths 9th

Last Answer : answer:

ABCD is a trapezium with AB and CD as parallel sides. The diagonals intersect at O. The area of the triangle ABO is p and that of triangle CDO is q. -Maths 9th

Description : ABCD is a trapezium with AB and CD as parallel sides. The diagonals intersect at O. The area of the triangle ABO is p and that of triangle CDO is q. -Maths 9th

Last Answer : answer:

Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

Who arranges blood group a, b, o, ab ?

Description : Who arranges blood group a, b, o, ab ?

Last Answer : Carl Land Steiner made this arrangement in 1901

Blood groups of a couple are AB and O. the possible blood groups of children would be

Description : Blood groups of a couple are AB and O. the possible blood groups of children would be

Last Answer : Blood groups of a couple are AB and O. the possible blood groups of children would be A. O group only B. ... C. A or B group D. AB and O group only

Match the correct for blood group and donar compatibility :- `{:(,"Blood group",,"Donar compatibility"),(a.,A,(i),"B,O"),(b.,B,(ii),O),(c.,AB,(iii),"A

Description : Match the correct for blood group and donar compatibility :- `{:(,"Blood group",,"Donar compatibility"),(a.,A,(i),"B,O"),(b.,B,(ii),O),(c.,AB,(iii),"A

Last Answer : Match the correct for blood group and donar compatibility :- `{:(,"Blood group",,"Donar compatibility"),(a.,A,(i)," ... -(iii), b-(i), c-(iii), d-(iv)

In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the circle. If `CD=10` cm, `AB=2` cm and `bar(OA)_|_bar(CD)`

Description : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the circle. If `CD=10` cm, `AB=2` cm and `bar(OA)_|_bar(CD)`

Last Answer : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the ... |_bar(CD)` the length of OB is `"_____________"`

In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

Description : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

Last Answer : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Description : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Last Answer : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

Description : AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

Last Answer : AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

Description : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

Last Answer : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.