The single layer of carbon atoms ar- ranged in a hexagoned shape?

The single layer of carbon atoms ar-
ranged in a hexagoned shape?
by

1 Answer

Answer :

Graphene
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Related questions

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An organic compound (A) has a molecular weight 78 and an empirical formula CH. (A) is resistant to attack by oxidizing agents but undergoes substitution and addition reactions. X-ray analysis shows that the distance between adjacent carbon atoms is 1.39Å (intermediate between single and double bond lengths). The evidence suggests that compound (A) is (a) Benzene (b) Cyclohexane (c) Toluene (d) n-Hexane

Description : An organic compound (A) has a molecular weight 78 and an empirical formula CH. (A) is resistant to attack by oxidizing agents but undergoes substitution and addition reactions. X-ray analysis shows that the ... suggests that compound (A) is (a) Benzene (b) Cyclohexane (c) Toluene (d) n-Hexane

Last Answer : Benzene

An organic compound (A) has a molecular weight 78 and an empirical formula CH. (A) is resistant to attack by oxidizing agents but undergoes substitution and addition reactions. X-ray analysis shows that the distance between adjacent carbon atoms is 1.39Å (intermediate between single and double bond lengths). The evidence suggests that compound (A) is (a) Benzene (b) Cyclohexane (c) Toluene (d) n-Hexane

Description : An organic compound (A) has a molecular weight 78 and an empirical formula CH. (A) is resistant to attack by oxidizing agents but undergoes substitution and addition reactions. X-ray analysis shows that the ... suggests that compound (A) is (a) Benzene (b) Cyclohexane (c) Toluene (d) n-Hexane

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A sphere of radius r is cut from larger sphere of radius R. The distance between their centre is a. The centroid of the remaining valoume lies on the line of centres and the sistanc from the centre of the larger sphere is a.ar2 / (R2 - r2) b.107 dynes c.aR/(R2-r2) d.aR/(R - r) e.ar3 / (R3 - r3)

Description : A sphere of radius r is cut from larger sphere of radius R. The distance between their centre is a. The centroid of the remaining valoume lies on the line of centres and the sistanc from the centre of the larger sphere is a.ar2 / (R2 - r2) b.107 dynes c.aR/(R2-r2) d.aR/(R - r) e.ar3 / (R3 - r3)

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If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Description : In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Last Answer : Given, ABCD and AEFD are two parallelograms. To prove ar (APEA) = ar (AQFD) Proof In quadrilateral PQDA, AP || DQ [since, in parallelogram ABCD, AB || CD ] and PQ || AD [since, in parallelogram AEFD ... APFD) = ar (parallelogram AEFD) - ar (quadrilateral APFD) ⇒ ar (AQFD) = ar (APEA) Hence proved.

If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Description : In figure, ABCD and AEFD are two parallelograms. Prove that ar (APEA) = ar(AQFO). -Maths 9th

Last Answer : Given, ABCD and AEFD are two parallelograms. To prove ar (APEA) = ar (AQFD) Proof In quadrilateral PQDA, AP || DQ [since, in parallelogram ABCD, AB || CD ] and PQ || AD [since, in parallelogram AEFD ... APFD) = ar (parallelogram AEFD) - ar (quadrilateral APFD) ⇒ ar (AQFD) = ar (APEA) Hence proved.

In Fig. 9.30, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. Prove that ar (ABCDE) = ar(APQ). -Maths 9th

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Last Answer : hope its clearhope its clear

ABCD is a square. P, Q, R, S are the mid-points of AB, BC, CD and DA respectively. By joining AR, BS, CP, DQ, we get a quadrilateral which is a -Maths 9th

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Last Answer : According to the given statement, the figure will be a shown alongside; using mid-point theorem: In △ABC,PQ∥AC and PQ=21 AC .......(1) In △ADC,SR∥AC and SR=21 AC .... ... are perpendicular to each other) ∴PQ⊥QR(angle between two lines = angle between their parallels) Hence PQRS is a rectangle.

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Consider the following reaction : `xMnO_(4)^(-)+yC_(2)O_(4)^(2-)+zH^(+) to xMn^(2+)+2yCO_(2)+(z)/(2)H_(2)O` The value of x, y and z in the reaction ar

Description : Consider the following reaction : `xMnO_(4)^(-)+yC_(2)O_(4)^(2-)+zH^(+) to xMn^(2+)+2yCO_(2)+(z)/(2)H_(2)O` The value of x, y and z in the reaction ar

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Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two naturally occuring forms of tartaric acid ar

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Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two naturally occuring forms of tartaric acid ar

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Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two naturally occuring forms of tartaric acid ar

Description : Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two naturally occuring forms of tartaric acid ar

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Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two naturally occuring forms of tartaric acid ar

Description : Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two naturally occuring forms of tartaric acid ar

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Consider the following reaction : `xMnO_(4)^(-)+yC_(2)O_(4)^(2-)+zH^(+) to xMn^(2+)+2yCO_(2)+(z)/(2)H_(2)O` The value of x, y and z in the reaction ar

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The following figure has a network of rectangles. Two rows and three columns. (A) Totally how many rectangles are there in the figure? (B) If there ar

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In the decay process: `A overset(-alpha)(to) B overset(-alpHa)(to) C overset(-beta)(to)C` 1. A and B are isobars 2. A and D are isotopes 3. C and D ar

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Which one of the following configuration represents Ar. ?

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Who can help me with this problem Rank the following elements by electron affinity from most positive to most negative I have the elements Ar Cl O Sb and Rb?

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