2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188
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1 Answer

Answer :

D

Let the speed of the train be x m/sec

Then distance travelled by the train in 15mins = distance travelled by sound in 15secs

X*15*60 = 320*15

900x = 4800

X=4800/900

X=5.33

Speed of the train 5.33 m/s

Convert m/s into km/hr

5.33m =(5.33*18/5)

=(95.94/5)

=19.188 km/hr
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Description : A certain thing is thrown twice from a place with the gap of 45 minutes between the two shots. A girl approaching this point in a train heard the second shot 44 minutes after she heard the first shot. What is the speed of train ... travels at 660 m/s? a) 62 km/hr b) 54 km/hr c) 48 km/hr d) 27 km/hr

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A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

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A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the certain place. What is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

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Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

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Last Answer : A Distance covered by P = 2*60 = 120 km Distance covered by Q = 3* 58 = 174 km Distance covered by R = 4*62 = 248 km Total distance = (120+174+248)km =542 km Total time taken = 2+3+4 = 9 hrs Mean speed = diatance/ time =(542 / 9)km/hr =60 2/9 km/hr

A train travels between two stations 15 km apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform retardation, the maximum speed attained by the train during the journey will by a.125 km/hr b.107 dynes c.80 km/hr d.100 km/hr e.60 km/hr

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Last Answer : d. 100 km/hr

A train travels between two stations 15 km, apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform relardation, the maximum speed attained by the train, during, the journey, will be a.60 km/hr b.80 km/hr c.125 km/hr d.100 km/hr e.107 dynes

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Last Answer : C Let Anand 's speed be X km/hr. And let the time taken by Babu be Y. Since Anand takes 9+Y hours to cross 150km at X km/hr. i.e., 150 / X = 9+Y ---eqn1 And he takes Y - 1/2 hours to cross 150km at 2X km ... )/ 2x = 19/2 150/2X =19/2 150/X = 19 X = 7.89 Hence Anand 's speed is 7.89 km/hr.

Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Description : Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Last Answer : A Speed of the rider = 40km/hr. Distance covered in 1st hour = 40 km. He increased his speed in every 1 hour by 4 km/hr. Distance covered in every 1 hours will be, 44, 48, ,... upto 12 terms.(for 12 hours). ... (2(40)+(11)4) = 6(80 + 44) = 6(124) = 744. Hence, he covers 744 km in 12 hours.

A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60

Description : A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60 

Last Answer : B Average speed =(2xy/( x+y)) km/hr Given x =60 km/hr y = 30km/hr Average speed = (2*60*30/ (60+30)) km/hr =(3600/ 90) =40 km/hr

A royal enfield bike starts with the speed of 210 km/hr with its speed increasing every 2 hrs by 30km/hr, in how many hrs will it cover 1035km? a) 2 1/2 hr b) 4 1 /2 hr c) 6 1 /2 hr d) 7 1 /2 hr

Description : A royal enfield bike starts with the speed of 210 km/hr with its speed increasing every 2 hrs by 30km/hr, in how many hrs will it cover 1035km? a) 2 1/2 hr b) 4 1 /2 hr c) 6 1 /2 hr d) 7 1 /2 hr

Last Answer : B Distance covered in 1st 2 hrs = (210*2)km =420km Distance covered in next 2 hrs = (240*2)km =480km Remaining distance = 1035 – (420+480) =1035 – 900 =135km Speed in 5th hr = 270 km/hr Time taken to cover 135 km = 135/270 = ½ hr Total time taken = (2+2+1/2) =4 ½ hrs

Tharun has to cover a distance of 84 km in 40 minutes. If he covers one-half of the distance in one-fourth of the total time, to cover the remaining distance in the remaining time, what should be his speed in km/hr? a) 42 km/hr b) 64km/hr c) 84km/hr d)76km/hr

Description : Tharun has to cover a distance of 84 km in 40 minutes. If he covers one-half of the distance in one-fourth of the total time, to cover the remaining distance in the remaining time, what should be his speed in km/hr? a) 42 km/hr b) 64km/hr c) 84km/hr d)76km/hr

Last Answer : C Tharun needs to cover 84 km in 40minutes Given that he covers one-half of the distance in one-fourth of the total time ⇒ he covers half of 84km in one-fourth of 40 minutes ⇒ He covers 42 km in ¼ * ... Distance =42km Time =30minutes =1/2 hr Required Speed = Distance / Time =42/(1/2)=84 km/hr

Kishore is travelling on his bike and has calculated to reach point P at 4 pm if he travels at 20 kmph. He will reach there at 12 noon if he travels at 30 kmph. At what speed must he travel to reach P at 2 pm? a) 18 kmph b) 12 kmph c) 24 kmph d) 16 kmph

Description : Kishore is travelling on his bike and has calculated to reach point P at 4 pm if he travels at 20 kmph. He will reach there at 12 noon if he travels at 30 kmph. At what speed must he travel to reach P at 2 pm? a) 18 kmph b) 12 kmph c) 24 kmph d) 16 kmph

Last Answer : C Let the distance be x km Travelling at 20 kmph, Kishore will reach point P at 4pm. Travelling at 30 kmph, Kishore will reach point P at 12noon. Therefore, time taken when travelling at 20km - ... his travelling time must be (12-2)=10 hours Hence, required speed =240/10=24 kmph

A bus can travel 25% faster than a van. Both start from a certain shop at the same time and reach poin P, 37.5 kms away from the shop at the same time time. On the way, however, the bus lost about 6.25 mins while shopping at the some such places. The speed of the van is. a) 72 b) 73 c) 74 d) 75

Description : A bus can travel 25% faster than a van. Both start from a certain shop at the same time and reach poin P, 37.5 kms away from the shop at the same time time. On the way, however, the bus lost about 6.25 mins while shopping at the some such places. The speed of the van is. a) 72 b) 73 c) 74 d) 75 

Last Answer : A Let speed of the car be x kmph The speed of the train = 125x/100 =5x/4 km/hr Therefore 37.5 / x – 37.5 /(5x/4) = 6.25 /60 37.5 / x – (37.5*4)/5x = 6.25 / 60 37.5 / x – 150 / 5x = 6.25 / 60 37.5 / x – 30/x = 6.25 / 60 7.5 / x = 6.25 / 60 6.25x = 7.5*60 X=72 km/hr

A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Description : A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Last Answer : A Speed of the Car = 1120 m/minute Speed of the bus=56 kms in 44 minutes =56/44 km/m =56000/44 m/mints Speed of the car : Speed of the bus, =1120:56000/44 =280:14000/44 =20:1000/44 =880:1000 =88:100 Required ratio =22:25

Robert travels from his home to anna park at a distance of 125 miles in 11/4 hrs. He returns to home in 2 hrs 15 mints. His average speed is. a) 50 b) 40 c) 30 d) 20

Description : Robert travels from his home to anna park at a distance of 125 miles in 11/4 hrs. He returns to home in 2 hrs 15 mints. His average speed is. a) 50 b) 40 c) 30 d) 20 

Last Answer : A Speed from home to annapark: (125*4/11)mph = (500/11)mph Speed from annapark to home: (125*4/9)mph = (500/9) mph Average speed = 2xy / (x+y) mph =[(2*500/11 *500/9) / (500/11+500/9)]mph =(500000/99) / ((4500+5500)/99) =(500000/99) / 10000 /99 =50mph

A train 200m in length, travels at 120 km/hr. In what time it will pass a boy who is walking at 12km an hour. a) against(opposite) it: b) in the same direction? A) 5.4,6.66 B) 7.2,5.2 C) 3.5,6 D) 12,16

Description : A train 200m in length, travels at 120 km/hr. In what time it will pass a boy who is walking at 12km an hour. a) against(opposite) it: b) in the same direction? A) 5.4,6.66 B) 7.2,5.2 C) 3.5,6 D) 12,16

Last Answer : ANSWER: A  Explanation: I) Speed of the train = 120 km/hr  Speed of the boy = 12 km/hr  Relative speed = (120 + 12) km/hr  Convert km/hr into m/s  132 km/hr = (132 * 5/ 18)m/s  = 36.66 m/s  Time = ... km/hr = (108 * 5 / 18)m/s  = 30 sec  Time = distance / speed  = 200 / 30  = 6.66 sec

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Description : Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Last Answer : Answer – A (10 min) Explanation – Due to stoppages, it covers 9 km less.Time taken to cover 9 km = (9/54 x 60) min = 10 min

In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav have covered ,by the time Dinesh meets karthick given that Dinesh speed is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Description : In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav ... is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Last Answer : B Aarav 's speed =360/6 =60 m/s Time taken by Aarav to cover 2280 m =2280/60= 38 seconds Dinesh 's speed = 2280/60=38 m/s karthick 's speed = 22m/s Time taken by Dinesh to meet karthick in ... direction: Distance covered by Aarav: =2280/(38+22) =2280/60 =38 seconds =(38*60)m =2280 m

Two bike A & B start at the same time from salem to Rasipuram which are 60km apart. If the 2 bikes travel in opposite directions, they meet after 1 hr and if they travel in same direction(from salem towards Rasipuram), then A meets B after 3 hrs. what is the speed of bike A? a) 50 b) 70 c) 90 d) 30

Description : Two bike A & B start at the same time from salem to Rasipuram which are 60km apart. If the 2 bikes travel in opposite directions, they meet after 1 hr and if they travel in same direction(from salem towards Rasipuram), then A meets B after 3 hrs. what is the speed of bike A? a) 50 b) 70 c) 90 d) 30

Last Answer : B Let their speed be x km/hr and y km/hr respectively Then 60 / (x+y) = ½ X+y = 120 ------------->1 Now when they move in same direction (distance travelled by A in 3 hrs) - (Distance travelled by B in ... = 140 X=70 Put x value in 1 we get Y=120 -70=50 Y=50 Therefore A's speed = 70 km/hr

Geetha runs at a speed of 12 km per hour and she increases her speed in every hour by 1 km per hour. In how many hours will he covers 27.8km ? a) 1 1/4 hours b) 2 1/3 hours. c) 3 1/2 hours. d) 2 1/5 hours.

Description : Geetha runs at a speed of 12 km per hour and she increases her speed in every hour by 1 km per hour. In how many hours will he covers 27.8km ? a) 1 1/4 hours b) 2 1/3 hours. c) 3 1/2 hours. d) 2 1/5 hours.

Last Answer : D Geetha starts with 12 kmph. Distance covered in first 1 hour = 12 km she increases her speed in every hour by 1 km. Speed in 2nd hour = 13 km/hr Distance covered in 2nd hour = 13 km Remaining distance = 27.8 ... total time = 1 + 1 + 1/5 hours = 2 1/5 hours. Hence the answer is 2 1/5 hours.

A girl is walking at a speed of 15 km/hr along a railway track. If she is 600 m ahead of the train which is 300 m long and runs at a speed of 180 km/hr in same direction, then what is the time required to pass a girl? A) 19.63sec B) 32sec C) 8.2sec D) 28.3sec

Description : A girl is walking at a speed of 15 km/hr along a railway track. If she is 600 m ahead of the train which is 300 m long and runs at a speed of 180 km/hr in same direction, then what is the time required to pass a girl? A) 19.63sec B) 32sec C) 8.2sec D) 28.3sec

Last Answer : ANSWER:A Explanation:  Speed of a girl = 15 km/hr  speed of train = 180 km/hr By using the condition, The speed values of train and the moving object are subtracted if they are moving in same ... /45.83 = 19.63  Hence the time taken by the train to cross the girl is 19.63seconds

A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for the both the trips? A.35 kmph B.4o kmph C.48 kmph D.55 kmph E.None of these

Description : A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for the both the trips? A.35 kmph B.4o kmph C.48 kmph D.55 kmph E.None of these

Last Answer : Answer – C (48 kmph) Explanation – Speed on return trip = 150% of 40 = 60 kmph Average speed = [2 x 40 x 60] / [40 + 6]km/hr =4800/100km/hr = 48 km/hr.

P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6

Description : P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6 

Last Answer : A Let R's speed = x km/hr Then Q's speed = 4x km/hr P's speed = 12x km/hr Ratio of speeds of P<Q<R = 12x :4x:x =12:4:1 Ratio of time taken = 1/12: ¼:1 =1:3:12 If R ... mins, then Q takes 3 mins If R takes 48 mins, then Q takes =(3/12 *48)mins =(144/120mins =12mins

In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to reach the target. The time taken by P to reach the target is. a) 4 hrs 20 mins b) 4 hrs 45 mins c) 2hrs 30 mins d) 4hrs 30 mins

Description : In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to reach the target. The time taken by P to reach the target is. a) 4 hrs 20 mins b) 4 hrs 45 mins c) 2hrs 30 mins d) 4hrs 30 mins

Last Answer : D Ratio of speeds = 5:6 Ratio of time =6:5 Suppose P takes 6x hrs and Q takes 5x hrs to reach the target. Then, 6x – 5x = 45/60 X=3/4 Time taken by P = 6x hrs =(6*3/4)hrs =4.5 hrs i.e., the time taken by P to reach the target is 4hrs 30mins

A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.

Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Description :  Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Last Answer : C Total time taken = 4 hours; Time of stoppage = 1 hour, that is, actual time taken = 4 hours - 1 hours = 3 hours Speed = Distance/Time = 216/3 = 72 km/hr Average speed = Total Distance/ Total Time = 216/4 = 54 km/hr