Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 
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1 Answer

Answer :

Answer – A (27 7/9 m)

Explanation – When SAME direction- MINUS

Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec.

Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.
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Related questions

Two trains are running at 120 km/hr and 60km/hr respectively in the same direction. Fast train completely passes a boy sitting in the slower train in 15 seconds. What is the length of the fast train? A) 150m B) 550 m C) 250m D) 215m

Description : Two trains are running at 120 km/hr and 60km/hr respectively in the same direction. Fast train completely passes a boy sitting in the slower train in 15 seconds. What is the length of the fast train? A) 150m B) 550 m C) 250m D) 215m 

Last Answer :  ANSWER: C  Explanation:  Speed of the 1st train = 120km/hr  Speed of the 2nd train = 60km/hr If the direction is given in the same direction then we subtract the relative speed.  Relative speed = (120 - 60) ... / 3 * 15)m  =(750/3)m  = 250m  Therefore the length of the faster train is 250m

Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these

Description : Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these

Last Answer : Answer- D (50) Explanation – Relative speed= total lengths/time (46-36) x 5/18 = [L + L ] / 36 10 x (5/18) x36 x (1/2)= L L=50 m

Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is: A.120 m B.140 m C.160 m D.180 m E.None of these

Description : Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is: A.120 m B.140 m C.160 m D.180 m E.None of these

Last Answer : Answer – D (180 m) Explanation – When OPP. direction-PLUS Relative speed = (36 + 45) km/hr = [81 x 5/18] m/sec = [45/2] m/sec. Length of train = [45/2 x 8] m = 180 m.

Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec

A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Description : A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Last Answer : Answer – B (50 km/hr) Explanation – Let speed be S Relative speed = total lengths/time [ in this case man length is neglible compare to train so neglected] (S – 5) x 5/18 = 125 /10 S- 5 = (125/10)x(18/5) S-5 = 45 S=50 km/hr

Two passenger trains are running in the same direction on parallel tracks at 210km/hr and 150km/hr respectively. The faster train passes a man 81 sec faster than the slower train. Find the length of the faster train. A) 1250m B) 1150m C) 1350m D) 1450m

Description : Two passenger trains are running in the same direction on parallel tracks at 210km/hr and 150km/hr respectively. The faster train passes a man 81 sec faster than the slower train. Find the length of the faster train. A) 1250m B) 1150m C) 1350m D) 1450m

Last Answer : ANSWER: C  Explanation:  Speed of 1st train = 210km/hr  Speed of 2nd train = 150km/hr  Here the two passenger trains are running in same direction, so  Relative speed = (210 - 150)km/hr  = 60km ... faster train = relative speed * time taken by train to pass  = 50/3 * 81  = 1350m

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Description : Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Last Answer : Answer – B (11 : 9) Explanation – In the same time, they cover 110 km and 90 km respectively.Ratio of their speeds = 110 : 90 = 11 : 9 

A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is :

Description : A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is : a) 72 metres b) 54 metres c) 55 metres d) 45 metres e) 50 meters

Last Answer : Answer: e)

Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Last Answer :  A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr

Three trains are running from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by trains will be A. 4 : 3 : 5 B. 5 : 3 : 4 C. 15 : 9 : 20 D. 15 : 20 : 12

Description : Three trains are running from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by trains will be A. 4 : 3 : 5 B. 5 : 3 : 4 C. 15 : 9 : 20 D. 15 : 20 : 12

Last Answer : Answer: D(15 : 20 : 12) Explanation: Ratio of speeds = 4 : 3 : 5 Therefore Ratio of times taken [t=d/s or t indirectly proportional to s when distance is same]= (1/4) : (1/3) : (1/5) = 15 : 20 : 12

A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds

Description : A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds

Last Answer : 15 min

A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km

A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

Description : A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

Last Answer : Answer- A(100m) Explanation: Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr Distance covered in 6 minutes =[(1/60)*6] km = (1/10)km = 100 m. Distance between the thief and policeman = (200 – 100) m = 100 m.

Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Description : Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Last Answer : Answer - B (54 kmph) Explanation - Let the length of the train be x metres. Then, the train covers x metres in 8 seconds (train is actually covering itself because length of man is very less compartable to train)and (x + ... /8]m/sec (convert to km/hr i.e x 18/5) =[120/8] x 18/5kmph = 54 kmph.

A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.

A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these

Description : A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed ... as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these

Last Answer : Answer-D (81 km/hr) Explanation4.5 km/hr =(4.5 x 5/18)m/sec =5m/4sec = 1.25 m/sec, and 5.4 km/hr =(5.4 x 5/18)m/sec =3m/2sec = 1.5 m/sec. Let the speed of the train be x m/sec. Then, (x - 1.25) ... - 12.75 => 0.1x = 2.25 => x = 22.5 Therefore Speed of the train =(22.5 x18 /5)km/hr = 81 km/hr.

A certain thing is thrown twice from a place with the gap of 45 minutes between the two shots. A girl approaching this point in a train heard the second shot 44 minutes after she heard the first shot. What is the speed of train (in kmph) if sound travels at 660 m/s? a) 62 km/hr b) 54 km/hr c) 48 km/hr d) 27 km/hr

Description : A certain thing is thrown twice from a place with the gap of 45 minutes between the two shots. A girl approaching this point in a train heard the second shot 44 minutes after she heard the first shot. What is the speed of train ... travels at 660 m/s? a) 62 km/hr b) 54 km/hr c) 48 km/hr d) 27 km/hr

Last Answer : B Actual time between the two shots being fired = 45 minutes. If a girl was stationary she would have heard the shots after 44 minutes. But since the train was moving towards the source, she heard the second shot after ... = (15 *18/5) km/hr =54 km/hr Hence the speed of the train is 54 km/hr

Two trains A and B are moving in opposite directions at 180 km/hr and 270 km/hr. their lengths are 3.30 km and 2.7 km respectively. The time taken by the slower train to cross the faster train in second is. A) 48sec B) 13 sec C) 38sec D) 24sec

Description : Two trains A and B are moving in opposite directions at 180 km/hr and 270 km/hr. their lengths are 3.30 km and 2.7 km respectively. The time taken by the slower train to cross the faster train in second is. A) 48sec B) 13 sec C) 38sec D) 24sec

Last Answer : ANSWER: A Explanation: Speed of 1st train = 180 km/hr  Speed of 2nd train = 270 km/hr  Relative speed = (180 + 270)km/hr  = 450 km/hr  = (450 * 5 / 180)m/s  = (2250 / 18)m/s  =125 m/s  Distance covered = (3.30 + 2.70)km  = 6km = 6000m  Required time = 6000 / 125  = 48sec

A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours

Description : A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours

Last Answer : A Let r = running time of the train s= stoppage time of the train D= total distance travelled by train We have: D/r= 120 and ..(1) D/(r+s) =80 ..(2) Diviving (1)&(2), D/r *(r+s)/D = ... , D=480 kms 480/r= 120 r=4 put r value in (3),we get s/4 =1/2 S = 2 hours

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Description : Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and  they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Last Answer : Answer - C (3 : 2) Explanation - Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres, and length of the second train = 17y metres. relative speed = total ... 23x + 23y = 27x + 17 y 27x-23x= 23 y-17y 4x=6y x/y=6/4=3/2= 3:2

A train 330 m long passes a man, running at 18 km/hr in the direction opposite to that of the train in 18 seconds. The speed of the train is. A) 38 km/hr B) 29km/hr C) 48km/hr D) 44km/hr

Description : A train 330 m long passes a man, running at 18 km/hr in the direction opposite to that of the train in 18 seconds. The speed of the train is. A) 38 km/hr B) 29km/hr C) 48km/hr D) 44km/hr

Last Answer : ANSWER: C Explanation:  Length of the train = 330 m  Speed = distance / time.  Speed of the train relative to man = 330 / 18 m/s  = 110 / 6 m/s  Convert m/s into km/hr  Therefore 110 / 6 m/s = (110 / ... (x +18) = 66 km/hr  X + 18 = 66  X = 48  Therefore the speed of the train is 48 km/hr.

If Gowtham ride a bike at 30 km/hr, then he arrives at a certain place at 3 p.m. If he ride at 45 km/hr, he will arrive at the same place at 1 P.m. At what speed must he ride to get there at noon? a) 18 km/hr b) 24 km/hr c) 36 km/hr d) 28 km/hr

Description : If Gowtham ride a bike at 30 km/hr, then he arrives at a certain place at 3 p.m. If he ride at 45 km/hr, he will arrive at the same place at 1 P.m. At what speed must he ride to get there at noon? a) 18 km/hr b) 24 km/hr c) 36 km/hr d) 28 km/hr

Last Answer : C When speed of gowtham = 30 km/hr =d/t and, When speed of the gowtham = 45 km/hr =d/(t−2) Equating the value of d: 30t =45(t-2) 30t=45t-90 15t=90 t=6 hours Finally desired speed =d/(t-1) =30t/(t-1) =30*6/(6-1) =180/5 =36 km/hr

A train M speeding with 60km/hr crooses another train N, running in the same direction in 1 min. If the lengths of the trains M and N be 50m and 100m respectively. What is the speed of train N? A) 15 km/hr B) 61km/hr C) 51km/hr D) 50k/hr

Description : A train M speeding with 60km/hr crooses another train N, running in the same direction in 1 min. If the lengths of the trains M and N be 50m and 100m respectively. What is the speed of train N? A) 15 km/hr B) 61km/hr C) 51km/hr D) 50k/hr

Last Answer : ANSWER: C Explanation:  Let the speed of be train N be ‘x’km/hr  Speed of M relative to N = (60 – x)km/hr  = (60-x) * 5/18]m/s = (300 – 5x / 18)m/s  150 / (300 – 5x / 18) =60  2700/300-5x=60  2700=18000-300x 300x=15300  x= 153/3  x=51km/hr  Therefore the speed of the train is 51 km/hr

Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Description : Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Last Answer : B Let the speed of jagging be x km/hr Total time taken = (27/18 hrs + 4.5 hrs) =(1.5 hrs + 4.5 hrs) =6 hrs Total distance covered = (27+4.5 x) km Therefore (27 +4.5x) / 6= 27 27+4.5x = 162 4.5x = 135 X=135/4.5 =30 So jagging speed is 30 km/hr

A motor car starts with the speed of 70 km/hr with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms? A.4 hrs B.4 hrs 5 mins C.4 1/2 hrs D.2 hrs E.None of these

Description : A motor car starts with the speed of 70 km/hr with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms? A.4 hrs B.4 hrs 5 mins C.4 1/2 hrs D.2 hrs E.None of these

Last Answer : Answer - C (4 1/2 hrs) Explanation - Distance covered in first 2 hours = (70 x 2) km = 140 km Distance covered in next 2 hours = (80 x 2) km = 160 km Remaining distance = 345 - (140 + 160) = 45 km. Speed in the ... ..1 hr 45km .? ?=45/90hr=1/2hr Total time taken = 2 + 2 +1/2=4 (1/2)hrs

A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length of the platform is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters

Description : A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length ... is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters

Last Answer : Answer: c)

A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Description : A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Last Answer : A Let the distance between bus stop and destination be X. The total time taken by the bus to cover X = 4 hours Since X/2 by 40km/hr and remaining X/2 by 50km/hr Then by Time = distance/speed, we have ... = 1600 9X = 1600 X = 1600/9 = 177.7 Hence 177.7 km is the required answer.

The distance between salem and trichy is 170 km. A bus starts from salem at 6 a.m. and travels towards trichy at 20 km/hr. Another bus starts from trichy at 7 a.m. and travels towards salem at 30 km/hr. At what time will they meet? a) 7a.m b) 8a.m c) 9a.m d) 10a.m

Description : The distance between salem and trichy is 170 km. A bus starts from salem at 6 a.m. and travels towards trichy at 20 km/hr. Another bus starts from trichy at 7 a.m. and travels towards salem at 30 km/hr. At what time will they meet? a) 7a.m b) 8a.m c) 9a.m d) 10a.m

Last Answer : D Assume that they meet x hours after 6 a.m. Then, Bus 1, starting from salem, travels x hours till the bus meet. Distance travelled by bus 1 in x hours =20x km bus 2, starting from trichy , travels (x−1) hours ... +30=50x 200=50x X=4 Hence, the bus meet 4 hours after 6 a.m., i.e. at 10a.m

Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr

Two trains are running in opposite direction with the same speed. If the length of each train is 135 meters and they cross each other in 18 seconds, the speed of each train is a) 29km/hr b) 35km/hr c) 27km/hr d) 28km/hr

Description : Two trains are running in opposite direction with the same speed. If the length of each train is 135 meters and they cross each other in 18 seconds, the speed of each train is a) 29km/hr b) 35km/hr c) 27km/hr d) 28km/hr

Last Answer : c) 27km/hr

A 270 m long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? A.180 B.230 C.245 D.235 E.None of these

Description : A 270 m long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? A.180 B.230 C.245 D.235 E.None of these

Last Answer : Answer – B (230) Explanation – Relative speed = total lenghths /time [120 +80] x5/18 ={ 270 + other train length (say L) } / 9 sec (x5/18 to convert km/hr to m/sec ) 200 x (5/18) x9 = 270 + L 500 = 270 +L L=230 m Note: always do cutting ,avoid solving exact

A train overtakes two girls walking along a railway track. The first girl walks at 9 km/hr. The other girl walks at 10.8 km/hr. The train needs 16.8 and 17 seconds respectively to overtake them. What is the speed of the train if both the girls are walking in the same direction as the train? A) 25 m/s B) 45 m/s C) 30m/s D) 40m/s

Description :  A train overtakes two girls walking along a railway track. The first girl walks at 9 km/hr. The other girl walks at 10.8 km/hr. The train needs 16.8 and 17 seconds respectively to overtake them. What is the speed of the ... in the same direction as the train? A) 25 m/s B) 45 m/s C) 30m/s D) 40m/s

Last Answer : ANSWER:B Explanation:  First girl speed = 9km/hr  = 9 * 5 / 18 m/s  = 5/2 m/s  = 2.5 m/s  second girl speed = 10.8 km/hr  = 10.8 * 5/18 m/s  = 54/18  = 3 m/s  Let the speed of the train ... x - 3) * 17  16.8x - 42 = 17x - 51  0.2x = 9  x = 45  Therefore the speed of the train is 45 m/s

Anand takes 9 hours more than Babu to cover 150 km. Suppose the time taken by Anand is 30 minutes less than Babu he must double his speed. Then the speed of Anand will be: a) 7.64 km/hr. b) 7.43km/hr. c) 7.89 km/hr. d) 7.25 km/hr.

Description : Anand takes 9 hours more than Babu to cover 150 km. Suppose the time taken by Anand is 30 minutes less than Babu he must double his speed. Then the speed of Anand will be: a) 7.64 km/hr. b) 7.43km/hr. c) 7.89 km/hr. d) 7.25 km/hr.

Last Answer : C Let Anand 's speed be X km/hr. And let the time taken by Babu be Y. Since Anand takes 9+Y hours to cross 150km at X km/hr. i.e., 150 / X = 9+Y ---eqn1 And he takes Y - 1/2 hours to cross 150km at 2X km ... )/ 2x = 19/2 150/2X =19/2 150/X = 19 X = 7.89 Hence Anand 's speed is 7.89 km/hr.

Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Description : Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Last Answer : A Let the distance travelled be x km x/30 – x/45 = 2 (3x – 2x) / 90 = 2 x/90 = 2 x = 180km Time taken to travel 180 km at 30 km/hr = 180 / 30 = 6 hrs So ganesh started 6 hrs before 8 pm That is 2 pm Required speed = distance / time =(180/5) =36 km/hr

A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 meters apart, then at what speed is the train travelling? A.50 kmph B.54 kmph C.60 kmph D.62 kmph E.None of these

Description : A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 meters apart, then at what speed is the train travelling? A.50 kmph B.54 kmph C.60 kmph D.62 kmph E.None of these

Last Answer : Answer – C (60 kmph) Explanation – Number of gaps between 21 telephone posts = 20 Distance traveled in 1 minute = (50 x 20) m = 1000 m = 1 km Speed = 60 km/hr

2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Description : 2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Last Answer : D Let the speed of the train be x m/sec Then distance travelled by the train in 15mins = distance travelled by sound in 15secs X*15*60 = 320*15 900x = 4800 X=4800/900 X=5.33 Speed of the train 5.33 m/s Convert m/s into km/hr 5.33m =(5.33*18/5) =(95.94/5) =19.188 km/hr

A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60

Description : A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60 

Last Answer : B Average speed =(2xy/( x+y)) km/hr Given x =60 km/hr y = 30km/hr Average speed = (2*60*30/ (60+30)) km/hr =(3600/ 90) =40 km/hr

A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr

Description : A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr

Last Answer : ANSWER : C Explanation: Relative speed = distance / time = (140 / 4.5) m/s = 31.11 m/s Convert m/s into km/hr  31.11 m/s = (31.11 * 18 / 50 km/hr  = (560 / 5) km/hr  = ... train (by sitting) = (112 - 25) km/hr = 87 km/hr  Therefore the speed of goods train is 87 km/hr.

Two trains, both 50m long, moving in opposite directions cross each other in 4 seconds. If one is moving thrice as fast the other, then the speed of the faster train is. A) 45km/hr B) 19 km/hr C) 95 km/hr D) 67.5 km/hr

Description : Two trains, both 50m long, moving in opposite directions cross each other in 4 seconds. If one is moving thrice as fast the other, then the speed of the faster train is. A) 45km/hr B) 19 km/hr C) 95 km/hr D) 67.5 km/hr

Last Answer : ANSWER:D Explanation:  Let the speed of the slower train be x' m/sec  The speed of the sfaster train = 3x m/s  Relative speed = (x +3x)m/sec  = 4x m/sec  50 + 50 / 4 = 4x  100 / 4 = 4x  100 = 16x  x = 100 ... the faster train = 3 * 25 / 4  = 75 / 4 m/s = (75/4 *18 /5)km/hr  = 67.5 km/hr

The distance between two cities A and B is 330km. A train starts from A at 8 (a)m. and travels towards B at 60 km/hr. Another train starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what time do they meet? a) 10 am. b) 10 : 30 am. c) 11 am. d) 11 : 30 am. e) None of these

Description : The distance between two cities A and B is 330km. A train starts from A at 8 (a)m. and travels towards B at 60 km/hr. Another train starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what time do they meet? a) 10 am. b) 10 : 30 am. c) 11 am. d) 11 : 30 am. e) None of these

Last Answer : Distance travelled by first train in one hour = 60 x 1 = 60 km Therefore, distance between two train at 9 a.m. = 330 – 60 = 270 km Now, Relative speed of two trains = 60 + 75 = 135 km/hr Time of meeting of two trains =270/135=2 hrs. Therefore, both the trains will meet at 9 + 2 = 11 A.M. Answer: c)

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Description : Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Last Answer : A Suppose the arin is overtaken x hrs after 8.30 a.m Then distance covered by arun in x hrs = distance covered by the owner in(x-1/2) hrs 40x =55(x-1/2) 40x = 55x -55/2 55x – 40x =55/2 15x=55/2 X = 55/2*1/15 x=55/30 x= 1hr 50mins so the thief is overtaken at 10.20 a.m

Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike speed is 20 km/hr and his walking speed is 1 km/hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km

Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.

Description : Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.

Last Answer : A Mr.Aneesh travelled 60 km/hr for 1 1/2 hours (3/2 hours). Distance covered in 3/2 hours = 60 x 3/2 = 90 km. Therefore, remaining distance = 120 -90 = 30 km After 3/2 hours, the speed was ... village 2 at 3.00 pm + 3 hours 30 minutes = 6.30pm Hence the required answer is 6.30 pm.

A train crosses a platform and a scooter standing on the platform in 20 seconds, 12seconds respectively.What is the length of the platform if the speed of the train is 25 km/hr? A) 55.8 m B) 75m C) 124m D) 68.5m

Description : A train crosses a platform and a scooter standing on the platform in 20 seconds, 12seconds respectively.What is the length of the platform if the speed of the train is 25 km/hr? A) 55.8 m B) 75m C) 124m D) 68.5m 

Last Answer : Answer: A Explanation: Given that, The speed of the train = 25km/hr = 25x 5/18 m/sec = 125/18 m/sec The train crosses a scooter in 12 seconds. Then, Length of the train = 125/18*12= 83.33 Now, ... 18(X +83.3)= 2500 18X=1000.6 X=55.58 m Hence the platform is 55.58 m long.

A person runs opposite to that of chandigarh train at a speed of 10km/hr. If the relative speed between train and the boy running in opposite direction is 25km/hr. What is the length of the train, if it takes 10 seconds to cross a boy, when is at rest? A) 36.6 m B) 40.6 m C) 43.6m D) 41.6m

Description :  A person runs opposite to that of chandigarh train at a speed of 10km/hr. If the relative speed between train and the boy running in opposite direction is 25km/hr. What is the length of the train, if it takes 10 seconds to cross a boy, when is at rest? A) 36.6 m B) 40.6 m C) 43.6m D) 41.6m

Last Answer : ANSWER : D  Explanation: Speed of person = 10km/hr  As the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed.  Relative speed = speed of train + speed of ... s  Distance = speed * time = 25 / 6 * 10 = 250/6 m/s = 41.6 m

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%