Normal specific gravity of urine is (A) 1.000–1.010 (B) 1.012–1.024 (C) 1.025–1.034 (D) 1.035–1.045

Normal specific gravity of urine is (A) 1.000–1.010 (B) 1.012–1.024 (C) 1.025–1.034 (D) 1.035–1.045
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When fluid intake is normal, the specific gravity of urine should be a) 1.010-1.025. Urine specific gravity is a measurement of the kidney’s ability to concentrate urine.

Description : When fluid intake is normal, the specific gravity of urine should be a) 1.010-1.025. Urine specific gravity is a measurement of the kidney's ability to concentrate urine. b) 1.000. The ... intake. d) greater than 1.025. A urine specific gravity greater than 1.025 may indicate overhydration.

Last Answer : a) 1.010-1.025. Urine specific gravity is a measurement of the kidney’s ability to concentrate urine.

When the nurse notes that the post cardiac surgery patient demonstrates low urine output (< 25 ml/hr) with high specific gravity (> 1.025), the nurse suspects: a) Inadequate fluid volume Urine output of less than 25 ml/hr may indicate a decrease in cardiac output. A high specific gravity indicates increased concentration of solutes in the urine which occurs with inadequate fluid volume. b) Normal glomerular filtration Indices of normal glomerular filtration are output of 25 ml or greater per hour and specific gravity between 1.010 and 1.025. c) Overhydration Overhydration is manifested by high urine output with low specific gravity. d) Anuria The anuric patient does not produce urine.

Description : When the nurse notes that the post cardiac surgery patient demonstrates low urine output (< 25 ml/hr) with high specific gravity (> 1.025), the nurse suspects: a) Inadequate fluid volume Urine ... by high urine output with low specific gravity. d) Anuria The anuric patient does not produce urine.

Last Answer : a) Inadequate fluid volume Urine output of less than 25 ml/hr may indicate a decrease in cardiac output. A high specific gravity indicates increased concentration of solutes in the urine which occurs with inadequate fluid volume.

Fixation of specific gravity of urine to 1.010 is found in (A) Diabetes insipidus (B) Compulsive polydypsia (C) Cystinosis (D) Chronic glomerulonephritis

Description : Fixation of specific gravity of urine to 1.010 is found in (A) Diabetes insipidus (B) Compulsive polydypsia (C) Cystinosis (D) Chronic glomerulonephritis

Last Answer : D

Density of Milk is----? A. 1.024 g/cm3 B. 1.034 g/cm3 (Answer) C. 1.044 g/cm3 D. 1.054 g/cm3

Description : Density of Milk is----? A. 1.024 g/cm3 B. 1.034 g/cm3 (Answer) C. 1.044 g/cm3 D. 1.054 g/cm3

Last Answer : B. 1.034 g/cm3 (Answer)

Assume a frequency range of 401.000 MHz to 401.050 MHz, if you apply 25 kHz channeling plan, determine the center frequency of the first channel from the lower limit. A. 401.010 MHz B. 401.0125 MHz C. 401.025 MHz D. 401.00625 MHz

Description : Assume a frequency range of 401.000 MHz to 401.050 MHz, if you apply 25 kHz channeling plan, determine the center frequency of the first channel from the lower limit. A. 401.010 MHz B. 401.0125 MHz C. 401.025 MHz D. 401.00625 MHz

Last Answer : B. 401.0125 MHz

The porosity of sediments in sewer pipes, is usually taken as A. 0.010 B. 0.011 C. 0.012 D. 0.013

Description : The porosity of sediments in sewer pipes, is usually taken as A. 0.010 B. 0.011 C. 0.012 D. 0.013

Last Answer : ANS: D

The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Description : The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Last Answer : B

A 3-input neuron is trained to output a zero when the input is 110 and a one when the input is 111. After generalization, the output will be zero when and only when the input is? a) 000 or 110 or 011 or 101 b) 010 or 100 or 110 or 101 c) 000 or 010 or 110 or 100

Description : A 3-input neuron is trained to output a zero when the input is 110 and a one when the input is 111. After generalization, the output will be zero when and only when the input is? a) 000 or 110 or 011 or 101 b) 010 or 100 or 110 or 101 c) 000 or 010 or 110 or 100

Last Answer : c) 000 or 010 or 110 or 100

In IPv4, what is the lengthof the data field given an HLEN value of 12 and total length value of 40,000? A) 39,988 B) 40,012 C) 40,048 D) 39,952

Description : In IPv4, what is the lengthof the data field given an HLEN value of 12 and total length value of 40,000? A) 39,988 B) 40,012 C) 40,048 D) 39,952

Last Answer : 39,952

An octal number 237 is equal to the binary number 1) 010 011 111 2) 010 111 011 3) 011 101 101 4) 011 000 001

Description : An octal number 237 is equal to the binary number 1) 010 011 111 2) 010 111 011 3) 011 101 101 4) 011 000 001

Last Answer : 3) 011 101 101

A 3-input neuron is trained to output a zero when the input is 110 and a one when the input is 111. After generalization, the output will be zero when and only when the input is: a) 000 or 110 or 011 or 101 b) 010 or 100 or 110 or 101 c) 000 or 010 or 110 or 100 d) 100 or 111 or 101 or 001

Description : A 3-input neuron is trained to output a zero when the input is 110 and a one when the input is 111. After generalization, the output will be zero when and only when the input is: a) 000 or 110 or 011 or 101 b) 010 or 100 or 110 or 101 c) 000 or 010 or 110 or 100 d) 100 or 111 or 101 or 001

Last Answer : c) 000 or 010 or 110 or 100

From the following information, calculate the extra cost of material by following EOQ: Annual consumption: = 45000 units Ordering cost per order: = Rs. 10 Carrying cost per unit per annum: = Rs. 10 Purchase price per unit = Rs. 50 Re-order quantity at present = 45000 units There is discount of 10% per unit in case of purchase of 45000 units in bulk. (a) No saving (b) Rs. 2,00,000 (c) Rs. 2,22,010 (d) Rs. 2,990

Description : From the following information, calculate the extra cost of material by following EOQ: Annual consumption: = 45000 units Ordering cost per order: = Rs. 10  Carrying cost per unit per annum: = Rs. 10  Purchase price per unit = Rs. ... ) No saving (b) Rs. 2,00,000 (c) Rs. 2,22,010 (d) Rs. 2,990

Last Answer : (d) Rs. 2,990

Urine examination in secondary dehydration shows (A) Ketonuria (B) Low specific gravity (C) High specific gravity (D) Albuminuria

Description : Urine examination in secondary dehydration shows (A) Ketonuria (B) Low specific gravity (C) High specific gravity (D) Albuminuria

Last Answer : Answer : B

ADH (A) Reabsorbs water from renal tubules (B) Excretes water from renal tubules (C) Excretes hypotonic urine (D) Causes low specific gravity of urine 210 MCQs IN BIOCHEMISTRY

Description : ADH (A) Reabsorbs water from renal tubules (B) Excretes water from renal tubules (C) Excretes hypotonic urine (D) Causes low specific gravity of urine 210 MCQs IN BIOCHEMISTRY

Last Answer : Answer : A

Urine specific gravity of 1.054 indicates (A) Excellent renal function (B) Inappropriate secretion of ADH (C) Extreme dehydration (D) Presence of glucose or protein

Description : Urine specific gravity of 1.054 indicates (A) Excellent renal function (B) Inappropriate secretion of ADH (C) Extreme dehydration (D) Presence of glucose or protein

Last Answer : Answer : D

A simple way to assess tubular function is to withhold food and water for 12 hours and, then, measure (A) Serum urea (B) Serum creatinine (C) Urine output in one hour (D) Specific gravity of urine

Description : A simple way to assess tubular function is to withhold food and water for 12 hours and, then, measure (A) Serum urea (B) Serum creatinine (C) Urine output in one hour (D) Specific gravity of urine

Last Answer : Answer : D

Specific gravity of urine is decreased in (A) Diabetes mellitus (B) Acute glomerulonephritis (C) Diarrhoea (D) Chronic glomerulonephritis

Description : Specific gravity of urine is decreased in (A) Diabetes mellitus (B) Acute glomerulonephritis (C) Diarrhoea (D) Chronic glomerulonephritis

Last Answer : B

Specific gravity of urine is raised in all of the following except (A) Diabetes mellitus (B) Diabetes insipidus (C) Dehydration (D) Acute glomerulonephritis

Description : Specific gravity of urine is raised in all of the following except (A) Diabetes mellitus (B) Diabetes insipidus (C) Dehydration (D) Acute glomerulonephritis

Last Answer : D

Specific gravity of urine increases in (A) Diabetes mellitus (B) Chronic glomerulonephritis (C) Compulsive polydypsia (D) Hypercalcemia

Description : Specific gravity of urine increases in (A) Diabetes mellitus (B) Chronic glomerulonephritis (C) Compulsive polydypsia (D) Hypercalcemia

Last Answer : A

ADH test is based on the measurement of (A) Specific gravity of urine (B) Concentration of urea in urine (C) Concentration of urea in blood (D) Volume of urine in ml/minute

Description : ADH test is based on the measurement of (A) Specific gravity of urine (B) Concentration of urea in urine (C) Concentration of urea in blood (D) Volume of urine in ml/minute

Last Answer : A

A certain fluid is flowing in a 0.5m x 0.3 channel at the rate of 3 m/s and has a specific volume of 0.012 m³/kg. Determined the mass of water flowing in kg/s.  a. 267 kg/s  b. 378 kg/s  c. 375 kg/s  d. 456.5 kg/s m = Aν/V

Description : A certain fluid is flowing in a 0.5m x 0.3 channel at the rate of 3 m/s and has a specific volume of 0.012 m³/kg. Determined the mass of water flowing in kg/s.  a. 267 kg/s  b. 378 kg/s  c. 375 kg/s  d. 456.5 kg/s m = Aν/V

Last Answer : 375 kg/s

) What is $10,034 in words?

Description : ) What is $10,034 in words?

Last Answer : Ten thousand and thirty-four dollars

The coefficient of fluctuation of speed, when the maximum and minimum speeds are 300rpm and 290 rpm (A) 0.034 (B) 0.017 (C) 0.008 (D) 0/004

Description : The coefficient of fluctuation of speed, when the maximum and minimum speeds are 300rpm and 290 rpm (A) 0.034 (B) 0.017 (C) 0.008 (D) 0/004

Last Answer : (A) 0.034

What is 0.035 in fraction form?

Description : What is 0.035 in fraction form?

Last Answer : 7 over 200.

Estimate the sum or difference of 612,797+811,035?

Description : Estimate the sum or difference of 612,797+811,035?

Last Answer : 1423832

The safe length L of a valley curve for night travel is (A) 2S - (1.50 + 0.035 S)/N if L < S (B) NS²/(1.50 + 0.035 S) if L > S (C) Neither (a) nor (b)(D) Both (a) and (b

Description : The safe length L of a valley curve for night travel is (A) 2S - (1.50 + 0.035 S)/N if L < S (B) NS²/(1.50 + 0.035 S) if L > S (C) Neither (a) nor (b) (D) Both (a) and (b

Last Answer : Answer: Option D

The volume of a bag of cement in cubic meters is about a) 0.035* b) 0.35 c) 0.53 d) .053

Description : The volume of a bag of cement in cubic meters is about a) 0.035* b) 0.35 c) 0.53 d) .053

Last Answer : a) 0.035*

Urine specific gravity?

Description : Urine specific gravity?

Last Answer : DefinitionUrine specific gravity is a laboratory test that measures the concentration of all chemical particles in the urine.See also:Urine concentration testUrine osmolalityUrinalysisAlternative NamesUrine densityHow the ... , balanced diet for several days before the test.How the test will feelTh

One international unit (I.U) of vitamin D is defined as the biological activity of (A) 0.025 µg of cholecalciferol (B) 0.025 µg of 7-dehydrocholecalciferol (C) 0.025 µg of ergosterol (D) 0.025 µg of ergocalciferol VITAMINS 113

Description : One international unit (I.U) of vitamin D is defined as the biological activity of (A) 0.025 µg of cholecalciferol (B) 0.025 µg of 7-dehydrocholecalciferol (C) 0.025 µg of ergosterol (D) 0.025 µg of ergocalciferol VITAMINS 113

Last Answer : Answer : A

What is 0.024 in percent?

Description : What is 0.024 in percent?

Last Answer : It is 0.024 times 100 = 2.4%

How do you write 13.024 in word form?

Description : How do you write 13.024 in word form?

Last Answer : I would write 13.024 as thirteen and twenty-four thousandths

How could yo write 0.024 in words?

Description : How could yo write 0.024 in words?

Last Answer : I would write it as twenty-four thousandths.

What is larger 4.1 or 4.045 and by how much?

Description : What is larger 4.1 or 4.045 and by how much?

Last Answer : 4.1 is larger than 4.045 by 0.055

The following air gap readings were obtained from a horizontally mounted, bilge pump, induction motor, equipped with sleeve bearings: FWD END-AFT END, Top .045 - .049, Right Side .045 - .047, Left Side .045 - .047, Bottom .045 - .041 Which of the f A. both the aft and foward bearings should be replaced. B. Shims should be removed from the aft bearing. C. The forward bearing should be lowered. D. The aft bearing should be lowered.

Description : The following air gap readings were obtained from a horizontally mounted, bilge pump, induction motor, equipped with sleeve bearings: FWD END-AFT END, Top .045 - .049, Right Side .045 - .047, Left ... the aft bearing. C. The forward bearing should be lowered. D. The aft bearing should be lowered.

Last Answer : Answer: A

When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 110 ohms the current will be _______. EL-0018 A. 1.045 amps B. 225 milliamps C. 2.045 amps D. 965.52 milliamps

Description : When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 110 ohms the current will be _______. EL-0018 A. 1.045 amps B. 225 milliamps C. 2.045 amps D. 965.52 milliamps

Last Answer : Answer: A

The following air gap readings were obtained from a horizontally mounted, bilge pump, induction motor, equipped with sleeve bearings: FWD END -AFT END, Top .045 - .049 , Right Side .045 - .047, Left Side .045 - .047 , Bottom .045 - .041 Which of the fo A. The aft bearing should be realigned or replaced. B. Shims should be removed from the aft bearing. C. The forward bearing should be lowered. D. The aft bearing should be lowered.

Description : The following air gap readings were obtained from a horizontally mounted, bilge pump, induction motor, equipped with sleeve bearings: FWD END -AFT END, Top .045 - .049 , Right Side .045 - .047, Left ... the aft bearing. C. The forward bearing should be lowered. D. The aft bearing should be lowered.

Last Answer : Answer: A

A level when set up 25 m from peg A and 50 m from peg B reads 2.847 on a staff held on A and 3.462 on a staff held on B, keeping bubble at its centre while reading. If the reduced levels of A and B are 283.665 m and 284.295 m respectively, the collimation error per 100 m is (A) 0.015 m (B) 0.030 m (C) 0.045 m (D) 0.060 m

Description : A level when set up 25 m from peg A and 50 m from peg B reads 2.847 on a staff held on A and 3.462 on a staff held on B, keeping bubble at its centre while reading. If the reduced levels of A and B are 283.665 m ... collimation error per 100 m is (A) 0.015 m (B) 0.030 m (C) 0.045 m (D) 0.060 m

Last Answer : (D) 0.060 m

The tensile force required to cause an elongation of 0.045 mm in a steel rod of 1000 mm length and 12 mm diameter, is (where E = 2 × 106 kg/cm2 ) (A) 166 kg (B) 102 kg (C) 204 kg (D) 74 kg

Description : The tensile force required to cause an elongation of 0.045 mm in a steel rod of 1000 mm length and 12 mm diameter, is (where E = 2 × 106 kg/cm2 ) (A) 166 kg (B) 102 kg (C) 204 kg (D) 74 kg

Last Answer : (B) 102 kg

Birmingham EGBB/BHX SA0850 280850 18014KT 9999 SCT 024 BKN030 BKN045 12/08 Q1011= FC0600 280600Z 280816 190015G27KT 9999 BKN025 TEMPO 0812 5000 – DZ BKN012 BECMG 1214 19022G37= FT0400 280434Z 281212 19022G37 9999BKN025 TEMPO 1902 5000 RA BKN010 BECMG 2201 25007KT Refer to the weather information for Birmingham, above. What is the total time for which the weather is forcast?

Description : Birmingham EGBB/BHX SA0850 280850 18014KT 9999 SCT 024 BKN030 BKN045 12/08 Q1011= FC0600 280600Z 280816 190015G27KT 9999 BKN025 TEMPO 0812 5000 - DZ BKN012 BECMG 1214 19022G37= FT0400 280434Z 281212 ... information for Birmingham, above. What is the total time for which the weather is forcast?

Last Answer : 28 hours

Optimum penetration of a .024 or .031 inch self-threading pin in dentin is . . . a. 0.5 mm b. 1.0 mm c. 2.0 mm d. 2.5 mm e. 3.0 mm

Description : Optimum penetration of a .024 or .031 inch self-threading pin in dentin is . . . a. 0.5 mm b. 1.0 mm c. 2.0 mm d. 2.5 mm e. 3.0 mm

Last Answer : c. 2.0 mm

Which of the listed ranges represents specific gravity corrected for temperature for the electrolyte of a fully charged portable lead-acid battery? A. 1.100 to 1.150 B. 1.180 to 1.200 C. 1.280 to 1.300 D. 1.750 to 2.000

Description : Which of the listed ranges represents specific gravity corrected for temperature for the electrolyte of a fully charged portable lead-acid battery? A. 1.100 to 1.150 B. 1.180 to 1.200 C. 1.280 to 1.300 D. 1.750 to 2.000

Last Answer : Answer: C

How do you write 4.012 in fraction form?

Description : How do you write 4.012 in fraction form?

Last Answer : 4.012 is a fraction. The fact that it is expressed as a decimaldoes not mean it is not a fraction. As a ratio, it can be writtenas 4012/1000. You may simplify that ratio if you so wish.

In word form what is 0.012?

Description : In word form what is 0.012?

Last Answer : How

0.012 in word form?

Description : 0.012 in word form?

Last Answer : Hdv

What is 0.012 in word form?

Description : What is 0.012 in word form?

Last Answer : zero twelves

The binary equivalent of the decimal number 10 is __________ a) 0010 b) 10 c) 1010 d) 010

Description : The binary equivalent of the decimal number 10 is __________ a) 0010 b) 10 c) 1010 d) 010

Last Answer : Answer: c Explanation: To get the binary equivalent of any number, we need to divide the number by 2 and obtain the remainders as : We then write the remainders in the reverse order as 1010

If the discharge of a sewer running half is 628 1.p.s., i = 0.001, and n = 0.010, the diameter of the sewer, is A. 1.39 m B. 1.49 m C. 1.59 m D. 1.69 m

Description : If the discharge of a sewer running half is 628 1.p.s., i = 0.001, and n = 0.010, the diameter of the sewer, is A. 1.39 m B. 1.49 m C. 1.59 m D. 1.69 m

Last Answer : ANS: D

The formula which accepts the value of rugosity coefficient n = 0.012 to be used in Manning’s formula, is given by A. Bazin B. Crimp and Bruges C. William-Hazen D. Kutter

Description : The formula which accepts the value of rugosity coefficient n = 0.012 to be used in Manning’s formula, is given by A. Bazin B. Crimp and Bruges C. William-Hazen D. Kutter

Last Answer : ANS: B

When a voltage of 132 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be ________. EL-0018 A. 0.012 amps B. 77.5 milliamps C. 10,362 amps D. 0.792 amps

Description : When a voltage of 132 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be ________. EL-0018 A. 0.012 amps B. 77.5 milliamps C. 10,362 amps D. 0.792 amps

Last Answer : Answer: A

When a voltage of 124 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be________. EL-0018 A. 0.012 amps B. 82.50 amps C. 10.354 amps D. 0.8439 amps

Description : When a voltage of 124 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be________. EL-0018 A. 0.012 amps B. 82.50 amps C. 10.354 amps D. 0.8439 amps

Last Answer : Answer: A