For an object that is speeding up at constant rate how would the acceleration vs time graph look?

For an object that is speeding up at constant rate how would the acceleration vs time graph look?
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A line angled upward
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For an object that is speeding up at constant rate how would the acceleration vs time graph look?

Description : For an object that is speeding up at constant rate how would the acceleration vs time graph look?

Last Answer : A line angled upward

What does an object that is speeding up at a constant rate in the positive direction what does the velocity vs time graph look like?

Description : What does an object that is speeding up at a constant rate in the positive direction what does the velocity vs time graph look like?

Last Answer : A line angled upward

How does the direction of the acceleration along determine if the object is speeding up or slowing down?

Description : How does the direction of the acceleration along determine if the object is speeding up or slowing down?

Last Answer : Take the component of the acceleration along the direction theobject is moving. If this component is positive (the accelerationvector, or the relevant component, points in the same direction asthe movement), then the object is speeding up.

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Description : What does the graph of acceleration vs.?

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A object moves with uniform positive acceleration. Its velocity-time graph will be (a) A straight line parallel to the time axis (b) A straight line inclined at an obtuse angle to the time axis (c) A straight line inclined at an acute angle to the time axis (d) None of these. -Science

Description : A object moves with uniform positive acceleration. Its velocity-time graph will be (a) A straight line parallel to the time axis (b) A straight line inclined at an obtuse angle to the time axis (c) A straight line inclined at an acute angle to the time axis (d) None of these. -Science

Last Answer : Answer is (c)

If the velocity-time graph of a particle is represented by y = mt + c, then the particle is moving with– (1) constant speed (2) constant velocity (3) constant acceleration (4) varying acceleration

Description : If the velocity-time graph of a particle is represented by y = mt + c, then the particle is moving with– (1) constant speed (2) constant velocity (3) constant acceleration (4) varying acceleration

Last Answer : (3) constant acceleration Explanation: In this case the given equation shows that that the velocity is linear with time and therefore the particle is moving with constant acceleration because for a ... acceleration the graph of the velocity time graph should be in linear with the time function.

If the velocity-time graph of a particle is represented by y = mt + c, then the particle is moving with (1) constant speed (2) constant velocity (3) constant acceleration (4) varying acceleration

Description : If the velocity-time graph of a particle is represented by y = mt + c, then the particle is moving with (1) constant speed (2) constant velocity (3) constant acceleration (4) varying acceleration

Last Answer : constant acceleration

An object covers distance which is directly proportional to the square of the time. Its acceleration is – (1) increasing (2) decreasing (3) zero (4) constant

Description : An object covers distance which is directly proportional to the square of the time. Its acceleration is – (1) increasing (2) decreasing (3) zero (4) constant

Last Answer : (4) constant Explanation: When an object covers distance which is directly proportional to the square of the time, its acceleration is constant. This is seen in the cases of falling objects. This connection between time and distance was first observed by Galileo.

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Description : An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 s after it was dropped. -Science

Last Answer : v=u+atv=u+at u=0u=0 v=10×5=50m/sv=10×5=50m/s

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Last Answer : (i) We can see from the graph that velocity is not changing So,acceleration is equal to zero. (ii) By Reading the graph, velocity = 20 m/s (iii) Distance covered in 15 seconds, s=u×t=20×15=300s=u×t=20×15=300 m

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Last Answer : The acceleration is given by the slope of velocity-time graph. Slope of body-A > Slope of body-B as it forms a greater angle with time axis than body B. Thus, body A moves with higher acceleration

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Last Answer : (2) Displacement - Time graph Explanation: Displacement-time graph is non linear. Linear motion (also called rectilinear motion) is motion along a straight line, and can therefore be described ... linear motion with variable velocity or non-zero acceleration. The motion of a particle (a point

The slope of a velocity-time graph represents – (1) acceleration (2) displacement (3) distance (4) speed

Description : The slope of a velocity-time graph represents – (1) acceleration (2) displacement (3) distance (4) speed

Last Answer : (1) acceleration Explanation: A plot of velocity-time is used to determine the acceleration of an object (the slope). If the acteleration is zero, then the velocity-time graph is a horizontal line (i.e ... is positive, then the line is an upward sloping line (i.e., the slope is positive).

Area under velocity-time graph tells us the A. time B. acceleration C. displacement D. velocity

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Last Answer :  displacement

Gradient of velocity-time graph tells us about object's A. velocity B. displacement C. distance D. acceleration

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: Gradient of line of velocity-time graph is tells us the A. velocity B. acceleration C. distance D. time

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The slope of a velocity-time graph represents (1) acceleration (2) displacement (3) distance (4) speed

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Is velocity the slope of the displacement vs time graph true or false?

Description : Is velocity the slope of the displacement vs time graph true or false?

Last Answer : that is true

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Last Answer : What is the answer ?

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Last Answer : It’s true or false

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Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

Description : Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

Last Answer : Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!

An object moves along a straight line with an acceleration of 2 m/s2. If its initial speed is 10 m/s, what will be its speed 2 s later? -Science

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Last Answer : u=10 m/s,t=2 s, a=2 m/s2 v=u+atv=u+at v=10+2×2=14v=10+2×2=14 m/s

what is the acceleration of a 1.4 kg object if the gravitational force pulls downward on it , but air resistance pushes upward on it with a force of 2.5 N?

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Last Answer : if g = 10(m/s)/s then force down = ma = 10*1.4=14n14n-2.5n=11.5na=f/m = 11.5/1.4 = 8.21 (m/s/)s

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Last Answer : The rate of change of velocity is zero because the value of velocity of a moving object does not change. Due to this the acceleration is also zero. That is `a = (vu) / t = (vv) / t`

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Last Answer : Acceleration of an object refers to the rate at which velocity increases with time.

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Last Answer : An object moving at the same speed ‍ there is no change in the initial velocity ( u) and the end velocity ( v) at any given time. We know that the rate at which an object changes over time is called acceleration. Acceleration , a = v-ut = u-ut = 0t = o So there is no acceleration of a moving object.

Explain the acceleration of an object moving in a circular path. ?

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Last Answer : We know that the acceleration of an object moving in a circular path is called angular acceleration. That is, the rate of change of velocity of an object moving in a circular path with time is called angular acceleration.

Explains the acceleration of an object in a circular and akabaka way. ?

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Last Answer : : We know that the rate of asymmetric growth over time is called acceleration. Acceleration is generally of two types - 1. Smooth acceleration , 2. Uneven acceleration. Again, if the velocity ... , bicycles , rickshaws go on the Akabaka road so their acceleration is uneven acceleration. Thank you!

Explain whether there is acceleration of a rotating object at a balanced speed in a circular motion ?

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