Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

1 Answer

Answer :

Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!

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