How many grams are there in 7.4 x 1023 molecules of AgNO3?

1 Answer

Answer :

7.4x10^23 x ( 1 mol AgNO3/ 6.02x10^23) x (169.88g AgNO3/ 1 mol AgNO3)=2.1x10^2g AgNO3no of molecules=7.4x10^23Mr of AgNO3=169.88we can find the no of moles, thereforein 1mol there are 6.02x10^23 molecules7.4x10^23 molecules represent (7.4x10^23/6.02x10^23)molesin theory when we multiply molar mass (Mr) with the no of moles, we obtain the mass of the substance in gram:Mr x no of Mol= Mass in grams(7.4x10^23/6.02x10^23)x169.88= 2.1x10^2

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