convert 1.42 x 10^24 molecules of water into grams?

convert 1.42 x 10^24 molecules of water into grams?
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how to Convert 6.42 kilograms to grams?

Description : how to Convert 6.42 kilograms to grams?

Last Answer : Multiply by 1000.

What are the steps needed to convert 77.2 grams of methane to molecules of methane. Please wrote them out ( indluding tchart)?

Description : What are the steps needed to convert 77.2 grams of methane to molecules of methane. Please wrote them out ( indluding tchart)?

Last Answer : Step1: Find molar mass of methane, CH4. C=12; H=1; 12+1+1+1+1 = 16 g/moleStep2: Convert grams to moles. 77.2 g x 1 mole/16 g = 4.825 moles methaneStep3: Convert moles to molecules using ... 23 molecules/mole = 2.90x10^24 moleculesUnfortunately, I don't know what a tchart is, so I didn't include it.

How many grams are in 5.00x10^24 molecules of lithium hydroxide?

Description : How many grams are in 5.00x10^24 molecules of lithium hydroxide?

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Average salinity or ratio of salt as per kilogram of water of ocean is-----? A. 35 grams (Answer) B. 55 grams C. 32 grams D. 42 grams

Description : Average salinity or ratio of salt as per kilogram of water of ocean is-----? A. 35 grams (Answer) B. 55 grams C. 32 grams D. 42 grams

Last Answer : A. 35 grams (Answer)

How many grams are there in 7.4 x 1023 molecules of AgNO3?

Description : How many grams are there in 7.4 x 1023 molecules of AgNO3?

Last Answer : 7.4x10^23 x ( 1 mol AgNO3/ 6.02x10^23) x (169.88g AgNO3/ 1 mol AgNO3)=2.1x10^2g AgNO3no of molecules=7.4x10^23Mr of AgNO3=169.88we can find the no of moles, thereforein 1mol there are 6.02x10^23 molecules7 ... the substance in gram:Mr x no of Mol= Mass in grams(7.4x10^23/6.02x10^23)x169.88= 2.1x10^2

Which one of the following is largest? w) the number of molecules in 2 grams of hydrogen gas x) the number of molecules in 60 grams of lead sulfate y) the number of molecules in 20 liters of oxygen gas at standard temperature and pressure z) the population of the United States

Description : Which one of the following is largest? w) the number of molecules in 2 grams of hydrogen gas x) the number of molecules in 60 grams of lead sulfate y) the number of molecules in 20 liters of oxygen gas at standard temperature and pressure z) the population of the United States

Last Answer : ANSWER: A - THE NUMBER OF MOLECULES IN 2 GRAMS OF HYDROGEN GAS  

Convert each of the following decimals into a percentage: (i) 0.6 (ii) 0.42 (iii) 0.07 (iv) 0.005 -Maths

Description : Convert each of the following decimals into a percentage: (i) 0.6 (ii) 0.42 (iii) 0.07 (iv) 0.005 -Maths

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A mototboat can row to a place 112 km away and come back in 44 hours. The time to row 42 km with the stream is same as the time to row 24 km against the stream. Find the speed of boat in still water. A) 5.5 km/hr B) 7.5km/hr C) 10.5 km/hr D) 3.5 km/hr

Description : A mototboat can row to a place 112 km away and come back in 44 hours. The time to row 42 km with the stream is same as the time to row 24 km against the stream. Find the speed of boat in still water. A) 5.5 km/hr B) 7.5km/hr C) 10.5 km/hr D) 3.5 km/hr 

Last Answer : ANSWER: A Explanation: Downstream speed = 42/x km/hr Upstream speed = 24/x km/hr 112 / (42 / x) + 112 / (24 / x) = 44 112[x /42 + x / 24] = 44 112 / 3 [x / 14 + x / 8] = 44 11x / 56 = 44 * ... = 4 km/hr Speed of boat = 1/2 * (7 + 4) km/hr = 11 /2 speed of boat in still water = 5.5 km/hr

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Starting from point A, Ajit walks 14 metres towards west, he then turns to his right and walks 14 metres and then turns to his left and walks 10 metres. He again turns to his left and walks 14 metres and reaches to the point E. The shortest distance between A and E is (A) 38 (B) 42 (C) 52 (D) 24

Description : Starting from point A, Ajit walks 14 metres towards west, he then turns to his right and walks 14 metres and then turns to his left and walks 10 metres. He again turns to his left and walks 14 metres and reaches to the point E. The shortest distance between A and E is (A) 38 (B) 42 (C) 52 (D) 24

Last Answer : Answer: D

What will be the volume of CO2 at NTP obtained on heating 10 grams of (90% pure) limestone [Pb. CET 2001] (A) 22.4 litre (B) 2.016 litre (C) 2.24 litre (D) 20.16 litre

Description : What will be the volume of CO2 at NTP obtained on heating 10 grams of (90% pure) limestone [Pb. CET 2001] (A) 22.4 litre (B) 2.016 litre (C) 2.24 litre (D) 20.16 litre

Last Answer : (B) 2.016 litre

If you start with 24 grams of a radioactive element with a half-life of one month, how many grams of the radioactive element will be left after 2 months? w) 1.5 grams x) 3 grams y) 6 grams z) 12 grams

Description : If you start with 24 grams of a radioactive element with a half-life of one month, how many grams of the radioactive element will be left after 2 months? w) 1.5 grams x) 3 grams y) 6 grams z) 12 grams

Last Answer : ANSWER: Y -- 6 GRAMS

Convert binary 10111111 to octal. 42) A) 2108 B) 1718 C) 2578 D) 2778

Description : Convert binary 10111111 to octal. 42) A) 2108 B) 1718 C) 2578 D) 2778

Last Answer : D) 2778

What number would you use to convert moles of CH4 to grams of CH4?

Description : What number would you use to convert moles of CH4 to grams of CH4?

Last Answer : Need answer

What is the number of molecules in 18 grams of glucose ?

Description : What is the number of molecules in 18 grams of glucose ?

Last Answer : Number of molecules in 18 g glucose is 6.02 × 10 ^ 22

What is the number of molecules in 32 grams of oxygen ?

Description : What is the number of molecules in 32 grams of oxygen ?

Last Answer : Number of molecules in 2 grams of oxygen = 6.023 x 1023 .

How many molecules of BH3 are in 14.32 grams BH3?

Description : How many molecules of BH3 are in 14.32 grams BH3?

Last Answer : Convert between BH3 weight and moles. ... To calculate molar mass of a chemical compound enter its formula and click 'Compute'. ... Molar mass calculator also displays common compound name, Hill formula, elemental composition, mass percent composition, atomic percent compositions and ...

Bottom bars under the columns are extended into the interior of the footing slab to a distance greater than (A) 42 diameters from the centre of the column (B) 42 diameters from the inner edge of the column (C) 42 diameters from the outer edge of the column (D) 24 diameters from the centre of the column

Description : Bottom bars under the columns are extended into the interior of the footing slab to a distance greater than (A) 42 diameters from the centre of the column (B) 42 diameters from the inner edge of ... ) 42 diameters from the outer edge of the column (D) 24 diameters from the centre of the column

Last Answer : Answer: Option C

The number of ATP molecules required to convert 2 molecules of lactate into glucose in mammalian liver is (A) 2 (B) 4 (C) 5 (D) 6

Description : The number of ATP molecules required to convert 2 molecules of lactate into glucose in mammalian liver is (A) 2 (B) 4 (C) 5 (D) 6

Last Answer : Answer : D

How many ATP molecules are required to convert two molecules of pyruvate into glucose?

Description : How many ATP molecules are required to convert two molecules of pyruvate into glucose?

Last Answer : Six.

Twenty grams of ice at 0˚C melts to water at 0˚C. How much does the entropy of the 20g change in this process?  a. 30.5 J/K  b. 24.6 J/K  c. 21.3 J/K  d. 15.7 J/K

Description : Twenty grams of ice at 0˚C melts to water at 0˚C. How much does the entropy of the 20g change in this process?  a. 30.5 J/K  b. 24.6 J/K  c. 21.3 J/K  d. 15.7 J/K

Last Answer : 24.6 J/K

A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Description : A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Last Answer : a.9.24,9.24

The angular acceleration of a flywheel decreases uniformly from 8 rad/sec2 to 2 rad sec2 in 6 sec at which time its angular velocity is 42 rad/sec. The initial angular velocity was a.12 rad/sec b.24 rad/sec c.30 rad/sec d.3 rad/sec e.6 rad/sec

Description : The angular acceleration of a flywheel decreases uniformly from 8 rad/sec2 to 2 rad sec2 in 6 sec at which time its angular velocity is 42 rad/sec. The initial angular velocity was a.12 rad/sec b.24 rad/sec c.30 rad/sec d.3 rad/sec e.6 rad/sec

Last Answer : a. 12 rad/sec

An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.? -Science

Description : An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.? -Science

Last Answer : Given r =42.250 km , T= 24 hour Linear velocity in circular motion is given by v=2πrT=2×3.14×42.25024=11.05km/hrv=2πrT=2×3.14×42.25024=11.05km/hr

Identify the correct trend given below : ( Atomic no : Ti=22, Cr=24 and Mo=42)

Description : Identify the correct trend given below : ( Atomic no : Ti=22, Cr=24 and Mo=42)

Last Answer : Identify the correct trend given below : ( Atomic no : Ti=22, Cr=24 and Mo=42) A. `Delta_(0)of [Cr(H_(2)O)_(6)] ... _(6)]^(+3)gt[Ti(H_(2)O)_(6)]^(2+)`

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

HCf for 24 and 42?

Description : HCf for 24 and 42?

Last Answer : 6 is ze answer .................. YEET OFF and dont forget to thank me

Scheduled banks are required to keep cash reserve with RBI, interms of _______ A. Section 24 of the Banking Regulation Act, 1949 B. Section 20 of the Banking Regulation Act, 1949 C. Section 42(i) of the RBI Act, 1934 D. Section 42 of Negotiable Instruments Act

Description : Scheduled banks are required to keep cash reserve with RBI, interms of _______ A. Section 24 of the Banking Regulation Act, 1949 B. Section 20 of the Banking Regulation Act, 1949 C. Section 42(i) of the RBI Act, 1934 D. Section 42 of Negotiable Instruments Act

Last Answer : C. Section 42(i) of the RBI Act, 1934 Explanation: Every bank included in the Second Schedule shall maintain with the Bank an average daily balance the amount.

Right to private property which hampered the securing of socio-economic justice was abolished- a) 24 th amendment b) 42 nd amendment c) 44 th amendment d) None of them

Description : Right to private property which hampered the securing of socio-economic justice was abolished- a) 24 th amendment b) 42 nd amendment c) 44 th amendment d) None of them

Last Answer : c) 44 th amendment

The Fundamental Duties were added to the constitution – a) 24 th amendment b) 42 nd amendment c) 44 th amendment d) Constituent amendment

Description : The Fundamental Duties were added to the constitution – a) 24 th amendment b) 42 nd amendment c) 44 th amendment d) Constituent amendment

Last Answer : b) 42 nd amendment

Calculate the potential when a conductor of length 2m is having an electric field of 12.3units. a) 26.4 b) 42.6 c) 64.2 d) 24.6

Description : Calculate the potential when a conductor of length 2m is having an electric field of 12.3units. a) 26.4 b) 42.6 c) 64.2 d) 24.6

Last Answer : d) 24.6

Which one is the correct relation between energy efficiency ratio (EER) and coefficient of performance (COP)?  A. EER = 2.34 COP  B. EER = 3.24 COP  C. EER = 3.42 COP  D. EER = 4.23 COP

Description : Which one is the correct relation between energy efficiency ratio (EER) and coefficient of performance (COP)?  A. EER = 2.34 COP  B. EER = 3.24 COP  C. EER = 3.42 COP  D. EER = 4.23 COP

Last Answer : EER = 3.42 COP

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17

Description : 1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17

Last Answer : d) 8980.77

12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Description : 12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Last Answer : 12.28 × 1.5 - 15 = ? 18.42 - 15 = ? ? = 3.42 Answer: e)

How many numbers greater than 400 can be formed with digits 3,4,8,9 with no digits being repeated? a) 24 b) 18 c) 42 d) 45

Description : How many numbers greater than 400 can be formed with digits 3,4,8,9 with no digits being repeated? a) 24 b) 18 c) 42 d) 45

Last Answer : c) 42

On Ashok marg, three consecutive traffic lights change after 36, 42 and 72 seconds respectively. If the lights are switched on at 9.00 A.M sharp, at what time will they change simultaneously? a) 9 :08 :44 b) 9:08:24 c) 9:08:04 d) 9:08:34

Description : On Ashok marg, three consecutive traffic lights change after 36, 42 and 72 seconds respectively. If the lights are switched on at 9.00 A.M sharp, at what time will they change simultaneously? a) 9 :08 :44 b) 9:08:24 c) 9:08:04 d) 9:08:34

Last Answer : b) 9:08:24

Find the greatest unit of time with which 5 hours 15 minutes and 8 hours 24 minutes can both be represented as integers. (a) 70 min. (b) 63 min. (c) 48 min. (d) 42 min.

Description : Find the greatest unit of time with which 5 hours 15 minutes and 8 hours 24 minutes can both be represented as integers. (a) 70 min. (b) 63 min. (c) 48 min. (d) 42 min.

Last Answer : 63 min. 

The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Description : The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Last Answer : a) Rs.22.57

Compute the maximum shearing stress developed in a phosphor bronze spring having mean diameter of 200 mm and consisting of 24 turns of 20-mm diameter wire when the spring is stretched 100 mm. and G = 42 GPa. a. 51 MPa b. 31.89 MPa c. 80 MPa d. 70 MPa

Description : Compute the maximum shearing stress developed in a phosphor bronze spring having mean diameter of 200 mm and consisting of 24 turns of 20-mm diameter wire when the spring is stretched 100 mm. and G = 42 GPa. a. 51 MPa b. 31.89 MPa c. 80 MPa d. 70 MPa

Last Answer : b. 31.89 MPa

The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18

Description : The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18

Last Answer : Answer: A

A disk drive has 100 cylinders, numbered 0 to 99. Disk requests come to the disk driver for cyclinders 12, 26, 24, 4, 42, 8 and 50 in that order. The driver is currently serving a request at cyclinder 24. A seek takes 6 msec per cyclinder moved. How much seek time is needed for shortest seek time first (SSTF) algorithm? (A) 0.984 sec (B) 0.396 sec (C) 0.738 sec (D) 0.42 sec

Description : A disk drive has 100 cylinders, numbered 0 to 99. Disk requests come to the disk driver for cyclinders 12, 26, 24, 4, 42, 8 and 50 in that order. The driver is currently serving a request at cyclinder 24. A seek takes ... (SSTF) algorithm? (A) 0.984 sec (B) 0.396 sec (C) 0.738 sec (D) 0.42 sec

Last Answer : C

A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Description : A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : B Let the total money be Rs.x Peter’s 1 day salary = Rs. x/42 Harish 1 day salary = Rs. x/56 (peter+harish)’s 1 day salary = Rs(x/42+x/56) =(4x+3x)/168 =7x/168 =x/24 Money is adequate to pay the salary of both for 24 days.

Adam and Smith are working on a project. Adam takes 18 hrs to type 108 pages on a computer, while Smith takes 15 hrs to type 120 pages. How much time will they take, working together on two different computers to type a project of 360 pages? a) 23 hrs 24 min b) 45 hrs 42 min c) 25 hrs 42 min d) 42 hrs 45 min

Description : Adam and Smith are working on a project. Adam takes 18 hrs to type 108 pages on a computer, while Smith takes 15 hrs to type 120 pages. How much time will they take, working together on two different computers to type a ... ? a) 23 hrs 24 min b) 45 hrs 42 min c) 25 hrs 42 min d) 42 hrs 45 min

Last Answer : C Number of pages typed by Adam=108 Number of pages typed by Adam in 1 hour = 108/18=6 Number of pages typed by Smith =120 Number of pages typed by Smith in 1 hour = 120/15 =8 Number of pages typed by both in ... (6 + 8) = 14 Time taken by both to type 360 pages, = (360 * 1/14) =25 hrs 42 min

A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6

Description : A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6

Last Answer : Answer: D Error = 168 – 24 = 144 Therefore, % error = 144/168 [Since, we know decrease% = decrease in value/original value × 100 %]  = 144/168 × 100  = 85.7 %

A block has a mass of 24 grams is 3 cm high, 4 cm long and 7 cm wide. What is the volume of this block?

Description : A block has a mass of 24 grams is 3 cm high, 4 cm long and 7 cm wide. What is the volume of this block?

Last Answer : Volume is calculated by LWH = 84. If you want Density, it is calculated by mass/volume => 24/84 =0.285 g/cm^3

How many grams of magnesium fluoride would you produce if you added 24 grams of magnesium to 38 grams of fluorine?

Description : How many grams of magnesium fluoride would you produce if you added 24 grams of magnesium to 38 grams of fluorine?

Last Answer : Theoretically the mass is 62,3018 g.

Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Description : Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Last Answer : B) 18.25

For each of the first 7-acetyl-CoA molecules formed by α-oxidation of palmitic acid, the yield of high energy phosphates is (A) 12 (B) 24 (C) 30 (D) 35

Description : For each of the first 7-acetyl-CoA molecules formed by α-oxidation of palmitic acid, the yield of high energy phosphates is (A) 12 (B) 24 (C) 30 (D) 35

Last Answer : Answer : D

The ratio that most closely approximates the number of net molecules of ATP formed per mole of glucose utilized under aerobic conditions to the net number formed under anaerobic conditions is (A) 4:1 (B) 13:1 (C) 18:1 (D) 24:1

Description : The ratio that most closely approximates the number of net molecules of ATP formed per mole of glucose utilized under aerobic conditions to the net number formed under anaerobic conditions is (A) 4:1 (B) 13:1 (C) 18:1 (D) 24:1

Last Answer : Answer : C