Description : If the non-parallel sides of a trapezium are equal, -Maths 9th
Last Answer : Given: A trapezium ABCD in which AB || CD and AD = BC To prove: ABCD is a cyclic trapezium. Construction: Draw DE perpendicular AB and CF perpendicular AB In right triangles AED and BFC, we have AD = BC ( ... = 360° (From (i) and (iii) ∠ A + ∠ C = 180° Hence, quadrilateral ABCD is cyclic.