If z equals yf x2 - y2 show that ydz divided by dx plus xdz divided by dy equals xz divided by y?

If z equals yf x2 - y2 show that ydz divided by dx plus xdz divided by dy equals xz divided by y?
by

1 Answer

Answer :

4
by

Related questions

What is the point of contact between the line y equals x plus 4 and the circle x2 plus y2 -8x plus 4y equals 30?

Description : What is the point of contact between the line y equals x plus 4 and the circle x2 plus y2 -8x plus 4y equals 30?

Last Answer : Equations: y = x+4 and x^2 +y^2 -8x +4y = 30It appears that the given line is a tangent line to the givencircle and the point of contact works out as (-1, 3)

What is the point of contact when the line y equals 2x meets the circle x2 plus y2 -8x -y plus 5 equals 0?

Description : What is the point of contact when the line y equals 2x meets the circle x2 plus y2 -8x -y plus 5 equals 0?

Last Answer : If: y = 2xThen: y^2 = 4x^2If: x^2 +y^2 -8x -y +5 = 0Then: x^2 +4x^2 -8x -2x +5 = 0Transposing terms: 5x^2 -10x +5 = 0Dividing all terms by 5: x^2 -2x +1 = 0Factorizing the above: (x-1)(x-1) = 0 meaning x = 1By substitution into original equations point of contact is madeat: (1, 2)

What are the solutions to the simultaneous equations of y equals -2x and x2 plus y2 equals 80?

Description : What are the solutions to the simultaneous equations of y equals -2x and x2 plus y2 equals 80?

Last Answer : If: y = -2x then y ^2 = 4x^2If: x^2 + y^2 = 80 then x^2 +4x^2 = 80So: 5x^2 = 80Divide all terms by 5: x^2 = 16Square root both sides: x = -4 or +4By substitution into the original equation solutions are: (-4,8) and (4, -8)

What is the length of a tangent line from the point 7 -2 to a point when it touches the circle x2 plus y2 -10 equals 49?

Description : What is the length of a tangent line from the point 7 -2 to a point when it touches the circle x2 plus y2 -10 equals 49?

Last Answer : x² + y² - 10 = 49→ x² + y² = 59= (x - 0)² + (y - 0)² = (√59)²→ circle has centre (0, 0) - the origin - and radius √59The point (7, -2) has a distance from the centre of the circleof:√((7 - 0)² + (-2 - 0)²) = √(7² + (-2)²) = √(49 + 4) = √53

What is the length of the circle radius if the circle is x2 plus y2 equals 1?

Description : What is the length of the circle radius if the circle is x2 plus y2 equals 1?

Last Answer : The center of the circle is at (0, 0) and its radius is thesquare root of 1 which is 1

What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?

Description : What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?

Last Answer : Circle equation: x^2 +y^2 -2x -6y +5 = 0Completing the squares: (x-1)^2 +(y-3)^2 = 5Centre of circle: (1, 3)Tangent line meets the x-axis at: (0, 5)Distance from (0, 5) to (1, 3) = 5 units using the distanceformula

What is the length of the tangent line from the point 9 0 to the circle x2 plus 8x plus y2 -9 equals 0?

Description : What is the length of the tangent line from the point 9 0 to the circle x2 plus 8x plus y2 -9 equals 0?

Last Answer : Equation of circle: x^2 +8x +y^2 -9 = 0Completing the square: (x+4)^2 +y^2 = 25Radius of circle: 5Center of circle: (-4, 0)Distance from (9, 0) to (-4, 0) = 13 which is ... the length of the tangent line is 12 unitsNote that the tangent line of a circle meets the radius of thecircle at right angles

What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?

Description : What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?

Last Answer : Circle equation: x^2 -4x +y^2 -6y = 4Completing the squares: (x-2)^2 +(y-3)^2 = 17Point of contact: (6, 4)Center of circle: (2, 3)Slope of radius: 1/4Slope of tangent line: -4Tangent equation: y-4 = -4(x-6) => y = -4x+28Tangent line equation in its general form: 4x+y-28 = 0

What is the length of the tangent line from the point 8 2 to a point where it meets the circle x2 plus y2 -4x -8y -5 equals 0?

Description : What is the length of the tangent line from the point 8 2 to a point where it meets the circle x2 plus y2 -4x -8y -5 equals 0?

Last Answer : Equation of circle: x^2 +y^2 -4x -8y -5 = 0Completing the squares: (x-2)^2 +(y-4)^2 = 25 which is radiussquaredCenter of circle: (2, 4)Tangent line originates from: (8, ... angle triangleUsing Pythagoras theorem: distance^2 minus radius^2 = 15Therefore length of tangent line is the square root of 15

What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?

Description : What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?

Last Answer : Equation of circle: x^2 +y^2 -4x -6y -3 = 0Completing the squares: (x-2)^2 +(y-3)^2 = 16 square unitsTherefore center of circle is at (2, 3) and its radius is 4units

What is the center and the radius of the circle x2 plus y2 equals 12x -10y -12?

Description : What is the center and the radius of the circle x2 plus y2 equals 12x -10y -12?

Last Answer : Equation of circle: x^2 +y^2 = 12x-10y-12Completing the squares: (x-6)^2 +(y+5)^2 = 49So center of circle is at (6, -5) and its radius is 7 units

Find dy/dx by implicit differentiation. 7x2 + 5xy − y2 = 8

Description : Find dy/dx by implicit differentiation. 7x2 + 5xy − y2 = 8

Last Answer : Need Answer

If `y(x)` is the solution of the differential equation `(dy)/(dx)=-2x(y-1)` with `y(0)=1`, then `lim_(xrarroo)y(x)` equals

Description : If `y(x)` is the solution of the differential equation `(dy)/(dx)=-2x(y-1)` with `y(0)=1`, then `lim_(xrarroo)y(x)` equals

Last Answer : If `y(x)` is the solution of the differential equation `(dy)/(dx)=-2x(y-1)` with `y(0)=1`, then `lim_(xrarroo)y(x)` equals

Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Description : Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Last Answer : NEED ANSWER

Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Description : Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Last Answer : According to question find the value of z

Find the value of x3 + y3 + z3 – 3xyz if x2 + y2 + z2 = 83 and x + y + z = 15 -Maths 9th

Description : Find the value of x3 + y3 + z3 – 3xyz if x2 + y2 + z2 = 83 and x + y + z = 15 -Maths 9th

Last Answer : Consider the equation x + y + z = 15 From algebraic identities, we know that (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) So, (x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + xz) From the question, x2 + y2 + z2 ... y3 + z3 - 3xyz = 15(83 - 71) => x3 + y3 + z3 - 3xyz = 15 12 Or, x3 + y3 + z3 - 3xyz = 180

Multiply x2 + 4y2 + z2 + 2xy + xz – 2yz by (-z + x-2y). -Maths 9th

Description : Multiply x2 + 4y2 + z2 + 2xy + xz – 2yz by (-z + x-2y). -Maths 9th

Last Answer : Multiply this question

Multiply x2 + 4y2 + z2 + 2xy + xz – 2yz by (-z + x-2y). -Maths 9th

Description : Multiply x2 + 4y2 + z2 + 2xy + xz – 2yz by (-z + x-2y). -Maths 9th

Last Answer : Multiply this question

What is the length of the circles radius for the circle x2 plus y2 169.?

Description : What is the length of the circles radius for the circle x2 plus y2 169.?

Last Answer : If x^2 plus y^2 = 169 then the center of the circle is at (0, 0)and its radius is the square root of 169 which is 13

The centroid of the area between the circle x2 + y2 = 16 and the line x + y = 4 will have the coordinates a.(4, 2) b.(2, 4) c.(2.34, 2.34) d.(1.16, 1.16) e.None of the above

Description : The centroid of the area between the circle x2 + y2 = 16 and the line x + y = 4 will have the coordinates a.(4, 2) b.(2, 4) c.(2.34, 2.34) d.(1.16, 1.16) e.None of the above

Last Answer : c. (2.34, 2.34)

The x coordinate of the centroid of the area enclosed by the parabolas y = x2 and x = y2 will be a.107 dynes b.0.44 c.0.43 d.0.45 e.0.46

Description : The x coordinate of the centroid of the area enclosed by the parabolas y = x2 and x = y2 will be a.107 dynes b.0.44 c.0.43 d.0.45 e.0.46

Last Answer : d. 0.45

If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1. -Maths 9th

Description : If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1. -Maths 9th

Last Answer : xsin3θ+ycos3θ=sinθcosθ (xsinθ)sin2θ+(ycosθ)cos2θ=sinθcosθ (xsinθ)sin2θ+(xsinθ)cos2θ=sinθcosθ xsinθ=sinθcosθ x=cosθ Again, ycosθ=xsinθ ycosθ=cosθsinθ y=sinθ Therefore, x2+y2=sin2θ+cos2θ=1.

The point (-1,2) divides the line segment joining the points A(2,5) and B(x,y) in the ratio 3:4, then the value of x2 + y2 is : (a) 27 (b) 28 (c) 29 (d) 30

Description : The point (-1,2) divides the line segment joining the points A(2,5) and B(x,y) in the ratio 3:4, then the value of x2 + y2 is : (a) 27 (b) 28 (c) 29 (d) 30

Last Answer : (c) 29

Solve for x and y: 1/x - 1/y = 1/3, 1/x2 + 1/y2 = 5/9.

Description : Solve for x and y: 1/x - 1/y = 1/3, 1/x2 + 1/y2 = 5/9.

Last Answer : Answer: x = 3/2 or -3 and y = 3 or -3/2.

How do you solve (x-y-1)dx + (4y+x-1)dy = 0?

Description : How do you solve (x-y-1)dx + (4y+x-1)dy = 0?

Last Answer : https://www.geteasysolution.com/ entered that equation and it states that it maust be entered in another way? Link above.

In 2D-translation, a point (x, y) can move to the new position (x’, y’) by usingthe equation a.x’=x+dx and y’=y+dx b.x’=x+dx and y’=y+dy c.X’=x+dy and Y’=y+dx d.X’=x-dx and y’=y-dy

Description : In 2D-translation, a point (x, y) can move to the new position (x’, y’) by usingthe equation a.x’=x+dx and y’=y+dx b.x’=x+dx and y’=y+dy c.X’=x+dy and Y’=y+dx d.X’=x-dx and y’=y-dy

Last Answer : b.x’=x+dx and y’=y+dy

Find dy/dx by implicit differentiation. y cos x = 5x2 + 2y2

Description : Find dy/dx by implicit differentiation. y cos x = 5x2 + 2y2

Last Answer : Need Answer

If a curve is represented parametrically by the equations `x=4t^(3)+3` and `y=4+3t^(4)` and `(d^(2)x)/(dy^(2))/((dx)/(dy))^(n)` is constant then the v

Description : If a curve is represented parametrically by the equations `x=4t^(3)+3` and `y=4+3t^(4)` and `(d^(2)x)/(dy^(2))/((dx)/(dy))^(n)` is constant then the v

Last Answer : If a curve is represented parametrically by the equations `x=4t^(3)+3` and `y=4+3t^(4)` and `(d^(2) ... (dy))^(n)` is constant then the value of n, is

Center point of circle a.[x1+x2]/2; [y1+y2]/2; [z1+z2]/2 b.[x1-x2]/2; [y1-y2]/2; [z1-z2]/2 c.[x1-x2]; [y1-y2]; [z1-z2] d.[x2-x1]; [y2-y1]; [z2-z1]

Description : Center point of circle a.[x1+x2]/2; [y1+y2]/2; [z1+z2]/2 b.[x1-x2]/2; [y1-y2]/2; [z1-z2]/2 c.[x1-x2]; [y1-y2]; [z1-z2] d.[x2-x1]; [y2-y1]; [z2-z1]

Last Answer : a.[x1+x2]/2; [y1+y2]/2; [z1+z2]/2

Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Description : Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Last Answer : answer:

If the equation x2 minus ax plus 2b equals 0 has prime roots where a and b are positive integers then a minus b is equal to?

Description : If the equation x2 minus ax plus 2b equals 0 has prime roots where a and b are positive integers then a minus b is equal to?

Last Answer : I think you mean the roots are prime numbers.Let the two roots be primes p and qThen the equation factorises to (x - p)(x - q) = 0 which can beexpanded to give:x² - (p + q)x + pq = 0Which comparing ... = 2(It doesn't matter if the other prime is even (2) or not as itcancels out from a - b.)

If a = (xy)/(x+y), b = (xz)/(x+z), and c = (yz)/(y+z), where a, b and c are non-zero, then what is x equal to ? -Maths 9th

Description : If a = (xy)/(x+y), b = (xz)/(x+z), and c = (yz)/(y+z), where a, b and c are non-zero, then what is x equal to ? -Maths 9th

Last Answer : answer:

If a function is described by F = (3x + z, y 2 − sin x 2 z, xz + ye x5 ), then the divergence theorem value in the region 0<x<1, 0<y<3 and 0<z<2 will be a) 13 b) 26 c) 39 d) 51

Description : If a function is described by F = (3x + z, y 2 − sin x 2 z, xz + ye x5 ), then the divergence theorem value in the region 0

Last Answer : c) 39

For the implementation of a paging scheme, suppose the average process size be x bytes, the page size be y bytes, and each page entry requires z bytes. The optimum page size that minimizes the total overhead due to the page table and the internal fragmentation loss is given by (A) x/2 (B) xz/2 (C) √2xz (D) (√xz)/2

Description : For the implementation of a paging scheme, suppose the average process size be x bytes, the page size be y bytes, and each page entry requires z bytes. The optimum page size that minimizes the total overhead due to the page ... fragmentation loss is given by (A) x/2 (B) xz/2 (C) √2xz (D) (√xz)/2

Last Answer : (C) √2xz 

If x2 - 1 is a factor of ax4 + bx3 + cx2 + dx + e , show that a + c + e = b + d = 0. -Maths 9th

Description : If x2 - 1 is a factor of ax4 + bx3 + cx2 + dx + e , show that a + c + e = b + d = 0. -Maths 9th

Last Answer : Since x2 - 1 = (x - 1) is a factor of p(x) = ax4 + bx3 + cx2 + dx + e ∴ p(x) is divisible by (x+1) and (x-1) separately ⇒ p(1) = 0 and p(-1) = 0 p(1) = a(1)4 + b(1)3 + c(1)2 + d(1) + e = 0 ... (b+d) = 0 ⇒ b + d = 0 ---- (iii) comparing equations (ii) and (iii) , we get a + c + e = b + d = 0

If x2 - 1 is a factor of ax4 + bx3 + cx2 + dx + e , show that a + c + e = b + d = 0. -Maths 9th

Description : If x2 - 1 is a factor of ax4 + bx3 + cx2 + dx + e , show that a + c + e = b + d = 0. -Maths 9th

Last Answer : Since x2 - 1 = (x - 1) is a factor of p(x) = ax4 + bx3 + cx2 + dx + e ∴ p(x) is divisible by (x+1) and (x-1) separately ⇒ p(1) = 0 and p(-1) = 0 p(1) = a(1)4 + b(1)3 + c(1)2 + d(1) + e = 0 ... (b+d) = 0 ⇒ b + d = 0 ---- (iii) comparing equations (ii) and (iii) , we get a + c + e = b + d = 0

To generate a rotation , we must specify a.Rotation angle θ b.Distances dx and dy c.Rotation distance d.All of the mentioned

Description : To generate a rotation , we must specify a.Rotation angle θ b.Distances dx and dy c.Rotation distance d.All of the mentioned

Last Answer : a.Rotation angle θ

A straight line segment is translated by applying the transformation equation a.P’=P+T b.Dx and Dy c.P’=P+P d.Only c

Description : A straight line segment is translated by applying the transformation equation a.P’=P+T b.Dx and Dy c.P’=P+P d.Only c

Last Answer : a.P’=P+T

The translation distances (dx, dy) is called as a.Translation vector b.Shift vector c.Both a and b d.Neither a nor b

Description : The translation distances (dx, dy) is called as a.Translation vector b.Shift vector c.Both a and b d.Neither a nor b

Last Answer : c.Both a and b

The two-dimensional rotation equation in the matrix form is a.P’=T+P b.P’=S*P c.P’=R*P d.P’=dx+dy

Description : The two-dimensional rotation equation in the matrix form is a.P’=T+P b.P’=S*P c.P’=R*P d.P’=dx+dy

Last Answer : c.P’=R*P

The matrix representation for scaling in homogeneous coordinates is a.P’=S*P b.P’=R*P c.P’=dx+dy d.P’=S*S

Description : The matrix representation for scaling in homogeneous coordinates is a.P’=S*P b.P’=R*P c.P’=dx+dy d.P’=S*S

Last Answer : a.P’=S*P

The volume of a parallelepiped in Cartesian is a) dV = dx dy dz b) dV = dx dy c) dV = dy dz d) dV = dx dz

Description : The volume of a parallelepiped in Cartesian is a) dV = dx dy dz b) dV = dx dy c) dV = dy dz d) dV = dx dz

Last Answer : a) dV = dx dy dz

Which of the following is a differential equation for deflection? a.dy / dx = (M/EI) b. dy / dx = (MI/E) c.d2y / dx2 = (M/EI) d.d2y / dx2 = (ME/I)

Description : Which of the following is a differential equation for deflection? a.dy / dx = (M/EI) b. dy / dx = (MI/E) c.d2y / dx2 = (M/EI) d.d2y / dx2 = (ME/I)

Last Answer : c.d2y / dx2 = (M/EI)

Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Description : Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Last Answer : Remainder = 145 Again, we should evaluate p(5) Let p(y) = y3 + y2 - 2y + 5 ∴ p(5) = 53 + 52 - 2 x 5 + 5 = 125 + 25 - 10 + 5 = 145 Thus , we find that p(5) is the remainder when p(y) is divided by y - 5 .

Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Description : Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Last Answer : Remainder = 145 Again, we should evaluate p(5) Let p(y) = y3 + y2 - 2y + 5 ∴ p(5) = 53 + 52 - 2 x 5 + 5 = 125 + 25 - 10 + 5 = 145 Thus , we find that p(5) is the remainder when p(y) is divided by y - 5 .

Find the value of 4x2 + y2 + 25z2 + 4xy – 10yz – 20zx when x = 4, y = 3 and z = 2. -Maths 9th

Description : Find the value of 4x2 + y2 + 25z2 + 4xy – 10yz – 20zx when x = 4, y = 3 and z = 2. -Maths 9th

Last Answer : 4x²+y²+25z²+4xy-10yz-20zx when x=4, y=3 &z=2 so =>4(4)²+(3)²+ 25(2)²+4(4)(3)-10(3)(2)-20(2)(4) =>64+9+100+48-60-160 =>221-220 =>1

The polygons are scaled by applying the following transformation. a.X’=x * Sx + Xf(1-Sx) & Y’=y * Sy + Yf(1-Sy) b.X’=x * Sx + Xf(1+Sx) & Y’=y * Sy + Yf(1+Sy c.X’=x * Sx + Xf(1-Sx) & Y’=y * Sy – Yf(1-Sy) d.X’=x * Sx * Xf(1-Sx) & Y’=y * Sy * Yf(1-Sy)

Description : The polygons are scaled by applying the following transformation. a.X’=x * Sx + Xf(1-Sx) & Y’=y * Sy + Yf(1-Sy) b.X’=x * Sx + Xf(1+Sx) & Y’=y * Sy + Yf(1+Sy c.X’=x * Sx + Xf(1-Sx) & Y’=y * Sy – Yf(1-Sy) d.X’=x * Sx * Xf(1-Sx) & Y’=y * Sy * Yf(1-Sy)

Last Answer : a.X’=x * Sx + Xf(1-Sx) & Y’=y * Sy + Yf(1-Sy)

In the expression of dynamic load capacity P=XVF r + YF a , Y stands for? (a) Race rotation factor (b) Radial load factor (c) Thrust load factor (d) Service factor

Description : In the expression of dynamic load capacity P=XVF r + YF a , Y stands for? (a) Race rotation factor (b) Radial load factor (c) Thrust load factor (d) Service factor

Last Answer : (c) Thrust load factor

The relationship between kinetic energy and the potential energy of a swinging pendulum bob is one of the following. Is it: w) kinetic energy is greater than potential energy x) kinetic energy is less than potential energy y) kinetic energy is equal to potential energy z) kinetic energy plus potential energy equals a constant

Description : The relationship between kinetic energy and the potential energy of a swinging pendulum bob is one of the following. Is it: w) kinetic energy is greater than potential energy x) kinetic ... kinetic energy is equal to potential energy z) kinetic energy plus potential energy equals a constant  

Last Answer : ANSWER: Z -- KINETIC ENERGY PLUS POTENTIAL ENERGY EQUALS A CONSTANT 

What is the result of isolating x2 in the equation below x2 plus (y - 5)2 30?

Description : What is the result of isolating x2 in the equation below x2 plus (y - 5)2 30?

Last Answer : Need answer