If yurt or circular tent has a radius of 3 meters What is the area of the floor of the yurt Use 3.14 for and pi .?

If yurt or circular tent has a radius of 3 meters What is the area of the floor of the yurt Use 3.14 for and pi .?
by

1 Answer

Answer :

Floor area of circular tent: 3.14*3*3 = 28.26 square meters
by

Related questions

What is the area of a circle with a radius of 4mm use 3.14 for pi?

Description : What is the area of a circle with a radius of 4mm use 3.14 for pi?

Last Answer : A)12.56mm2 B)25.12mm2 C)50.24mm2 D)502.4mm2

What is the circumstances of a circle with a radius of 9.7 inches Use 3.14 for pi?

Description : What is the circumstances of a circle with a radius of 9.7 inches Use 3.14 for pi?

Last Answer : I assume you mean "circumference".The circumference of a circle with a radius of 9.7 inches is 60.95 inches.Circumference = 2 * pi * radius-or-2 * 3.14 * 9.7 = 60.95

How to live in a yurt?

Description : How to live in a yurt?

Last Answer : What is a yurt?!

How to Build a Yurt

Description : How to Build a Yurt

Last Answer : How to Build a Yurt If you travel to Central Asia, such as in Mongolia, you'll probably see round collapsible dwellings used by nomads. These felt structures are called yurts, and if you have the right ... yurt. Making it is easy as long as you have the right materials and if you follow these steps.

What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6m -Maths 9th

Description : What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6m -Maths 9th

Last Answer : Solution: Height of conical tent, h = 8m Radius of base of tent, r = 6m Slant height of tent, l2 = (r2+h2) l2 = (62+82) = (36+64) = (100) or l = 10 Again, CSA of conical tent = πrl = (3.14 6 ... .2) 3] = 188.4 L-0.2 = 62.8 L = 63 Therefore, the length of the required tarpaulin sheet will be 63 m.

A conical tent is 10 m high and the radius of its base is 24 m. Find (i) slant height of the tent. -Maths 9th

Description : A conical tent is 10 m high and the radius of its base is 24 m. Find (i) slant height of the tent. -Maths 9th

Last Answer : : Ncert solutions class 9 chapter 13-5 Let ABC be a conical tent Height of conical tent, h = 10 m Radius of conical tent, r = 24m Let the slant height of the tent be l. (i) In right triangle ... (13728/7) 70 = Rs 137280 Therefore, the cost of the canvas required to make such a tent is Rs 137280.

How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? -Maths 9th

Description : How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? -Maths 9th

Last Answer : Given, radius (r) = 7 m and height (h) = 24m ∴ Slant height (l) = √h2 + r2 = √242 + 72 = √625 = 25 m ∴ Length of canvas required

How many metres of 5 m wide cloth will be required to make a conical tent, the radius of whose base is 3.5 m and height is 12 m ? -Maths 9th

Description : How many metres of 5 m wide cloth will be required to make a conical tent, the radius of whose base is 3.5 m and height is 12 m ? -Maths 9th

Last Answer : l = √h2 + r2 = √(3.5)2 + (12)2 = √12.25 + 144 = √156.25 = 12.5 m Curved surface area = πrl = 22 / 7 × 3.5 × 12.5 = 137.5 m2 Area of cloth = 137.5 m2 Length of cloth required = C.S.A. / Width l = 137.5 / 5 = 27.5 m

How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? -Maths 9th

Description : How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? -Maths 9th

Last Answer : Given, radius (r) = 7 m and height (h) = 24m ∴ Slant height (l) = √h2 + r2 = √242 + 72 = √625 = 25 m ∴ Length of canvas required

How many metres of 5 m wide cloth will be required to make a conical tent, the radius of whose base is 3.5 m and height is 12 m ? -Maths 9th

Description : How many metres of 5 m wide cloth will be required to make a conical tent, the radius of whose base is 3.5 m and height is 12 m ? -Maths 9th

Last Answer : l = √h2 + r2 = √(3.5)2 + (12)2 = √12.25 + 144 = √156.25 = 12.5 m Curved surface area = πrl = 22 / 7 × 3.5 × 12.5 = 137.5 m2 Area of cloth = 137.5 m2 Length of cloth required = C.S.A. / Width l = 137.5 / 5 = 27.5 m

How many square metres of canvas is required for a conical tent whose height is 3.5 m and the radius of the base is 12 m? -Maths 9th

Description : How many square metres of canvas is required for a conical tent whose height is 3.5 m and the radius of the base is 12 m? -Maths 9th

Last Answer : Slantheight5l = h2+r2 ​=(3.5)2+(12)2​ total canvas required = πrl =π×12×12.5 =471 sq m​

How many square metres of canvas is required for a conical tent whose height is 3.5 m and the radius of the base is 12 m? -Maths 9th

Description : How many square metres of canvas is required for a conical tent whose height is 3.5 m and the radius of the base is 12 m? -Maths 9th

Last Answer : Solution of this question

30 circular plates, each of radius 14 cm -Maths 9th

Description : 30 circular plates, each of radius 14 cm -Maths 9th

Last Answer : Height of the cylinder formed (h) = 30 x 3 = 90 cm Radius of the base of the cylinder formed (r) = 14 cm (i) Total surface area of the cylinder = 2 πr(r + h) = 2 x 22/7 x 14(14 + 90) = 2 x 22/7 x 14 x 104 = 9152 cm2 (ii) Volume of the cylinder formed = πr2h = 22//7 x 14 x 14 x 90 = 55440 cm3

In case of a hair pin bend of a highway, (A) Minimum radius of inner curve is 14 m (B) Minimum radius of transition is 15 m (C) Circular compound curve may be provided (D) All the above

Description : In case of a hair pin bend of a highway, (A) Minimum radius of inner curve is 14 m (B) Minimum radius of transition is 15 m (C) Circular compound curve may be provided (D) All the above

Last Answer : Answer: Option D

An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of the triangle is maximum when `theta=pi

Description : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of the triangle is maximum when `theta=pi

Last Answer : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of ... pi/4` C. `pi/6` D. None of these.

Frame the formula: The lateral surface area of a cylinder S is equal to twice the product of `pi`, radius (r) and height (h) of the cylinder.

Description : Frame the formula: The lateral surface area of a cylinder S is equal to twice the product of `pi`, radius (r) and height (h) of the cylinder.

Last Answer : Frame the formula: The lateral surface area of a cylinder S is equal to twice the product of `pi`, radius (r) ... `S=pirh` C. `2S=pirh` D. `S=2pirh`

Define a class circle having data members pi and radius. Initialize and display values of data members also calculate area of circle and display it.

Description : Define a class circle having data members pi and radius. Initialize and display values of data members also calculate area of circle and display it.

Last Answer : class abc {  float pi,radius; abc(float p, float r) { pi=p; radius=r; } void area() { float ar=pi*radius*radius; System.out.println("Area="+ar); } void display() { System.out.println("Pi="+pi ... void main(String args[]) { abc a=new abc(3.14f,5.0f); a.display(); a.area(); } }

How much greater is the area of a large pizza with a diameter of 8 inches than a medium pizza with a diameter of 7 inches use 3.14 for pi.?

Description : How much greater is the area of a large pizza with a diameter of 8 inches than a medium pizza with a diameter of 7 inches use 3.14 for pi.?

Last Answer : 6

A right circular cylinder just encloses a sphere of radius r (see fig. 13.22). Find (i) surface area of the sphere, (ii) curved surface area of the cylinder -Maths 9th

Description : A right circular cylinder just encloses a sphere of radius r (see fig. 13.22). Find (i) surface area of the sphere, (ii) curved surface area of the cylinder -Maths 9th

Last Answer : Surface area of sphere = 4πr2, where r is the radius of sphere (ii) Height of cylinder, h = r+r =2r Radius of cylinder = r CSA of cylinder formula = 2πrh = 2πr(2r) (using value of h) = 4πr2 (iii) Ratio ... sphere)/CSA of Cylinder) = 4r2/4r2 = 1/1 Ratio of the areas obtained in (i) and (ii) is 1:1.

A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. -Maths 9th

Description : A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. -Maths 9th

Last Answer : Radius of conical cap, r = 7 cm Height of conical cap, h = 24cm Slant height, l2 = (r2+h2) = (72+242) = (49+576) = (625) Or l = 25 cm CSA of 1 conical cap = πrl = (22/7)×7×24 = 550 CSA of 10 caps = (10×550) cm2 = 5500 cm2 Therefore, the area of the sheet required to make 10 such caps is 5500 cm2.

50 circular plates each of radius .... Find its total surface area -Maths 9th

Description : 50 circular plates each of radius .... Find its total surface area -Maths 9th

Last Answer : 50 circular plate diameter of plate =14cm Radius of plate = d/2=214​=7cm thickness =0.5cm → Height of the cylinder = No. of plates × thickness of plate =50×0.5 =25cm → total surface Area = curved surface + 2 × area of base =2πr.h+2×πr2 =2πr(h+r) =2π×7(25+7) =2×722​×7×32 =1408cm2

The radius of a circular plate increases by 2% on heating. If its radius is 10 cm before heating, find the approximate increase in its area.

Description : The radius of a circular plate increases by 2% on heating. If its radius is 10 cm before heating, find the approximate increase in its area.

Last Answer : The radius of a circular plate increases by 2% on heating. If its radius is 10 cm before heating, find the approximate increase in its area.

Hydraulic mean radius is A. Mean radius of sewer B. Difference in heads between two points in circular pipes C. Mean of radii in a pipe line of varying cross -sections D. Cross-sectional area/wetted perimeter

Description : Hydraulic mean radius is A. Mean radius of sewer B. Difference in heads between two points in circular pipes C. Mean of radii in a pipe line of varying cross -sections D. Cross-sectional area/wetted perimeter

Last Answer : ANS: D

If a circular grass lawn of 35 m in radius has a path 7 m wide running around it on the outside, then the area of the path is (a) 1450 m 2 (b) 1576 m 2 (c) 1694 m 2 (d) 3368 m 2

Description : If a circular grass lawn of 35 m in radius has a path 7 m wide running around it on the outside, then the area of the path is (a) 1450 m 2 (b) 1576 m 2 (c) 1694 m 2 (d) 3368 m 2

Last Answer : (c) 1694 m 2

The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of radius 3 cm is ` 36 pi cm^(3)`. What is the volume o

Description : The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of radius 3 cm is ` 36 pi cm^(3)`. What is the volume o

Last Answer : The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of ... What is the volume of a sphere of radius 15 cm?

Frame the formula for the volume (v) of a hemisphere given by two-thirds o the product of `pi` and cube of radius (r).

Description : Frame the formula for the volume (v) of a hemisphere given by two-thirds o the product of `pi` and cube of radius (r).

Last Answer : Frame the formula for the volume (v) of a hemisphere given by two-thirds o the product of `pi` and cube of radius (r).

Frame the formula for the volume (v) of a cylinder given by the product of `pi`, square of radius (r) and height (h).

Description : Frame the formula for the volume (v) of a cylinder given by the product of `pi`, square of radius (r) and height (h).

Last Answer : Frame the formula for the volume (v) of a cylinder given by the product of `pi`, square of radius (r) and height (h).

The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of radius 3 cm is ` 36 pi cm^(3)`. What is the volume o

Description : The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of radius 3 cm is ` 36 pi cm^(3)`. What is the volume o

Last Answer : The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of ... What is the volume of a sphere of radius 15 cm?

Two concentric coils each of radius equal to `2 pi cm` are placed at right angles to each other ` 3 ampere and 4 ampere` are the currents flowing in e

Description : Two concentric coils each of radius equal to `2 pi cm` are placed at right angles to each other ` 3 ampere and 4 ampere` are the currents flowing in e

Last Answer : Two concentric coils each of radius equal to `2 pi cm` are placed at right angles to each other ` 3 ampere and 4 ... ` C. `7xx10^(-5)` D. `10^(-5)`

A uniform conducting ring of mass `pi` kg and radius 1 m is kept on smooth horizontal table. A uniform but time varying magnetic field `B = (hat (i) +

Description : A uniform conducting ring of mass `pi` kg and radius 1 m is kept on smooth horizontal table. A uniform but time varying magnetic field `B = (hat (i) +

Last Answer : A uniform conducting ring of mass `pi` kg and radius 1 m is kept on smooth horizontal table. A uniform but time ... `(2)/(3pi)kJ` D. `(1)/(pi)kJ`

A uniform conducting ring of mass `pi` kg and radius 1 m is kept on smooth horizontal table. A uniform but time varying magnetic field `B = (hat (i) +

Description : A uniform conducting ring of mass `pi` kg and radius 1 m is kept on smooth horizontal table. A uniform but time varying magnetic field `B = (hat (i) +

Last Answer : A uniform conducting ring of mass `pi` kg and radius 1 m is kept on smooth horizontal table. A uniform but time ... `(5)/(pi)s` D. `(25)/(pi)s`

A thick cylinder under pi and po will have maximum stress at the 1. Outer radius 2. Inner radius 3. Mean radius 4. None

Description : A thick cylinder under pi and po will have maximum stress at the 1. Outer radius 2. Inner radius 3. Mean radius 4. None

Last Answer : 2. Inner radius

A thick cylinder under internal fluid pressure’ pi will have maximum stress at the 1. Outer radius 2. Inner radius 3. Mean radius 4. None

Description : A thick cylinder under internal fluid pressure’ pi will have maximum stress at the 1. Outer radius 2. Inner radius 3. Mean radius 4. None

Last Answer : 2. Inner radius

The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. Find the diameter of the base of the cylinder. (Assume π =22/7 ) -Maths 9th

Description : The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. Find the diameter of the base of the cylinder. (Assume π =22/7 ) -Maths 9th

Last Answer : Height of cylinder, h = 14cm Let the diameter of the cylinder be d Curved surface area of cylinder = 88 cm2 We know that, formula to find Curved surface area of cylinder is 2πrh. So 2πrh =88 cm2 (r is the ... 88 cm2 2r = 2 cm d =2 cm Therefore, the diameter of the base of the cylinder is 2 cm.

Why would i use square meters to measure a floor tile?

Description : Why would i use square meters to measure a floor tile?

Last Answer : Need answer

What kind of Pi(e) did you have for 3.14 Day?

Description : What kind of Pi(e) did you have for 3.14 Day?

Last Answer : Going to pick up some blueberry pie after work. And maybe some pizza too! I went out this morning trying to find a piece of pie anywhere near our office, no luck at all!

3.14.16 - Had any pi today?

Description : 3.14.16 - Had any pi today?

Last Answer : Planning to have apple pi. Not sure if I should make it Dutch Apple pi.

After striking the floor, a rubber ball rebounds (7/8)th of height from which it has fallen. Find the total distance that it travels before coming to rest, if it is gently dropped from a height of 420 meters. a) 2940 b) 6300 c) 1080 d) 3360

Description : After striking the floor, a rubber ball rebounds (7/8)th of height from which it has fallen. Find the total distance that it travels before coming to rest, if it is gently dropped from a height of 420 meters. a) 2940 b) 6300 c) 1080 d) 3360

Last Answer : b) 6300

A 10 kilogram ball falls from a height of 5 meters and rebounds from the floor to a height of 3 meters. The energy lost by the ball is: w) 20 joules x) 98 joules y) 196 joules z) 294 joules

Description : A 10 kilogram ball falls from a height of 5 meters and rebounds from the floor to a height of 3 meters. The energy lost by the ball is: w) 20 joules x) 98 joules y) 196 joules z) 294 joules 

Last Answer : ANSWER: Y -- 196 JOULES

A certain machine exerts a force of 200 newtons on a box whose mass is 30 kilograms. The machine moves the box a distance of 20 meters along a horizontal floor. What amount of work does the machine do on the box?

Description : A certain machine exerts a force of 200 newtons on a box whose mass is 30 kilograms. The machine moves the box a distance of 20 meters along a horizontal floor. What amount of work does the machine do on the box?

Last Answer : ANSWER: 4000 JOULES

Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find (i) radius of the base -Maths 9th

Description : Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find (i) radius of the base -Maths 9th

Last Answer : Slant height of cone, l = 14 cm Let the radius of the cone be r. (i) We know, CSA of cone = πrl Given: Curved surface area of a cone is 308 cm2 (308 ) = (22/7) r 14 308 = 44 r r = 308 ... Total surface area of cone = 308+(22/7) 72 = 308+154 Therefore, the total surface area of the cone is 462 cm2.

Calculate the surface area of a hemispherical dome of a temple with radius 14 m to be whitewashed from outside. -Maths 9th

Description : Calculate the surface area of a hemispherical dome of a temple with radius 14 m to be whitewashed from outside. -Maths 9th

Last Answer : Here, radius of hemispherical dome (r) = 14 m Surface area of dome = 2πr2 = 2 × 22 / 7 × 14 × 14 = 1232 m2 Hence , total surface area to be whitewashed from outside is 1232 m2

Calculate the surface area of a hemispherical dome of a temple with radius 14 m to be whitewashed from outside. -Maths 9th

Description : Calculate the surface area of a hemispherical dome of a temple with radius 14 m to be whitewashed from outside. -Maths 9th

Last Answer : Here, radius of hemispherical dome (r) = 14 m Surface area of dome = 2πr2 = 2 × 22 / 7 × 14 × 14 = 1232 m2 Hence , total surface area to be whitewashed from outside is 1232 m2

In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2

Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2

Last Answer : (c) 77 cm 2

Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

Description : Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

Last Answer : According to question, l×b = ¶r2 l ×22 = 22/7 ×14 × 14 l = 22/7 ×14 × 14/22 cms = 28 cms. Answer: b)

How many meters is the radius of proton ?

Last Answer : Proton radius 1 * 10 ^ -15 m.

How many sq ft in 500 meters radius?

Description : How many sq ft in 500 meters radius?

Last Answer : Feel Free to Answer

What is the circumference of a circle with a radius of 67.5 meters?

Description : What is the circumference of a circle with a radius of 67.5 meters?

Last Answer : The circumference of a circle it Pi times the diameter. Thediameter is 2 times the radius. So the diameter is 135 and Pi is3.1416. So the circumference is 424.115 metres.

A toy train moves in a circle of 8 meters radius with a speed of 4 meters per second. What is the magnitude of the acceleration of the train?

Description : A toy train moves in a circle of 8 meters radius with a speed of 4 meters per second. What is the magnitude of the acceleration of the train?

Last Answer : ANSWER: 2 METERS PER SECOND SQUARED

Found a rusted, circular floor grate from the 1800's. What should I do with it?

Description : Found a rusted, circular floor grate from the 1800's. What should I do with it?

Last Answer : Turn it into a wall hanging.