What is the smallest angle and area of a triangle with sides of 6.4 cm by 5.7 cm by 8.2 cm?

What is the smallest angle and area of a triangle with sides of 6.4 cm by 5.7 cm by 8.2 cm?
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Answer :

Using trigonometry its smallest angle is 43.84 degrees and its area is 18.2 square cm--------------------------------------Using the cosine rule to find the angle:a² = b² + c² - 2bc cos A→ cos A = (b² + c² - a²)/(2bc)→ A = arccos ((6.4² + 8.2² - 5.7²)/(2 × 6.4 × 5.7)) ≈ 43.8°Area = ½ × b × c × sin A ≈ ½ × 6.4 cm × 8.2 cm × sin 43.8° ≈ 18.2 cm²
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‘If two sides and an angle of one triangle are equal to two sides and an angle of another triangle , then the two triangles must be congruent’. -Maths 9th

Description : ‘If two sides and an angle of one triangle are equal to two sides and an angle of another triangle , then the two triangles must be congruent’. -Maths 9th

Last Answer : No, because in the congruent rule, the two sides and the included angle of one triangle are equal to the two sides and the included angle of the other triangle i.e., SAS rule.