What is the simplest form of 108 over 117?

What is the simplest form of 108 over 117?
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1 Answer

Answer :

It is 12/13
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What is the frequency range of an aircraft’s Very High Frequency (VHF) communications? A. 118.000 MHz to 136.975 MHz (worldwide up to 151.975 MHz) B. 108.000 MHz to 117.95 MHz C. 329.15 MHz to 335.00 MHz D. 2.0000 MHz to 29.999 MHz

Description : What is the frequency range of an aircraft’s Very High Frequency (VHF) communications? A. 118.000 MHz to 136.975 MHz (worldwide up to 151.975 MHz) B. 108.000 MHz to 117.95 MHz C. 329.15 MHz to 335.00 MHz D. 2.0000 MHz to 29.999 MHz

Last Answer : A. 118.000 MHz to 136.975 MHz (worldwide up to 151.975 MHz)

What is the frequency range of an aircraft’s radio altimeter? A. 962 MHz to 1213 MHz B. 329.15 MHz to 335.00 MHz C. 4250 MHz to 4350 MHz D. 108.00 MHz to 117.95 MHz

Description : What is the frequency range of an aircraft’s radio altimeter? A. 962 MHz to 1213 MHz B. 329.15 MHz to 335.00 MHz C. 4250 MHz to 4350 MHz D. 108.00 MHz to 117.95 MHz

Last Answer : C. 4250 MHz to 4350 MHz

What is 36 108 divided by to make it into simplest form?

Description : What is 36 108 divided by to make it into simplest form?

Last Answer : 36/108 = 18/54 = 9/27 = 3/9 = 1/3

If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is (a) 4 (b) 2 (c) 1 (d) 3

Description : If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is (a) 4 (b) 2 (c) 1 (d) 3

Last Answer : (b) 2

The gravitational field at the surface of the moon is one sixth of that at the surface of the earth. A 72 kg man weighs on the surface of the moon a.137.7 N b.250 c.72 N d.420 N e.117.7 N

Description : The gravitational field at the surface of the moon is one sixth of that at the surface of the earth. A 72 kg man weighs on the surface of the moon a.137.7 N b.250 c.72 N d.420 N e.117.7 N

Last Answer : e. 117.7 N

Evaluate each of the following using identities: (i) (399)2 (ii) (0.98)2 (iii) 991 x 1009 (iv) 117 x 83 -Maths 9th

Description : Evaluate each of the following using identities: (i) (399)2 (ii) (0.98)2 (iii) 991 x 1009 (iv) 117 x 83 -Maths 9th

Last Answer : answer:

The area of a rectangle is 117 square meters. The width is 9 meters.What is the length of the rectangle?

Description : The area of a rectangle is 117 square meters. The width is 9 meters.What is the length of the rectangle?

Last Answer : PLEASE ANSWER I NEED HELP I AM STRUGGLING

what- The Library of Congress has a collection of about 117 million items.What is the ratio of books to the total number of items?

Description : what- The Library of Congress has a collection of about 117 million items.What is the ratio of books to the total number of items?

Last Answer : 32: 117

Rs 117 was supposed to be divided among P, Q and R in the ratio 3:4:6. But, by mistake, it was divided in the ratio `(1)/(3):(1)/(4):(1)/(6)` How many

Description : Rs 117 was supposed to be divided among P, Q and R in the ratio 3:4:6. But, by mistake, it was divided in the ratio `(1)/(3):(1)/(4):(1)/(6)` How many

Last Answer : Rs 117 was supposed to be divided among P, Q and R in the ratio 3:4:6. But, by mistake, it was ... How many of P,Q and R gained due to this mistake?

What is the greatest common factor of 117 312?

Description : What is the greatest common factor of 117 312?

Last Answer : The GCF is 39.

How many gram is 117 oz?

Description : How many gram is 117 oz?

Last Answer : 3,316.894206 Grams (rounded to 6 decimal places).

How much does 12 go into 117?

Description : How much does 12 go into 117?

Last Answer : 120 = 10 x 12108 = 9 x 12117 - 108 = 99 times with 9 remaining

Is a blood sugar level of 117 high?

Description : Is a blood sugar level of 117 high?

Last Answer : Is a blood sugar level of 117 high?”

If 9 ties costst 117 pounds how much would 13 cost?

Description : If 9 ties costst 117 pounds how much would 13 cost?

Last Answer : 169 pounds

Normal range of serum sodium is (A) 30–70 mEq/L (B) 70–110 mEq/L (C) 117–135 mEq/L (D) 136–145 mEq/L

Description : Normal range of serum sodium is (A) 30–70 mEq/L (B) 70–110 mEq/L (C) 117–135 mEq/L (D) 136–145 mEq/L

Last Answer : Answer : D

Subacute combined degeneration of cord is caused due to deficiency of (A) Niacin (B) Cobalamin (C) Biotin (D) Thiamin VITAMINS 117

Description : Subacute combined degeneration of cord is caused due to deficiency of (A) Niacin (B) Cobalamin (C) Biotin (D) Thiamin VITAMINS 117

Last Answer : Answer : B

117 One of the following pairs which is correctly matched is: A. Amir Khusro, Tabaqat-e-Nasiri B. Zia-ud-Din Barani, Trikh-e-Muhammadi C. Ibn-e-Batuta, Fatwa-e-Jahandari D. Shams-e-SirajAfif, Tarikh-e-FerozShahi

Description : 117 One of the following pairs which is correctly matched is: A. Amir Khusro, Tabaqat-e-Nasiri B. Zia-ud-Din Barani, Trikh-e-Muhammadi C. Ibn-e-Batuta, Fatwa-e-Jahandari D. Shams-e-SirajAfif, Tarikh-e-FerozShahi

Last Answer : ANSWER: A

The slenderness ratio of a vertical column of square cross- section of 10 cm side and 500 cm long, is (A) 117.2 (B) 17.3 (C) 173.2 (D) 137.2

Description : The slenderness ratio of a vertical column of square cross- section of 10 cm side and 500 cm long, is (A) 117.2 (B) 17.3 (C) 173.2 (D) 137.2

Last Answer : (C) 173.2

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Description : A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Last Answer : work finished by 33 days = 33 117 8 = 30888 man hours 4/7th of the job is finished. remaining work = 1-(4/7) = 3/7 if 4/7th of the work is 30888 hours, then 3/7th of the work = [30888 ... 9 number of men = 198 since, 117 men are already working, additional men required = 198 - 117 = 81 Answer: c)

117.5 x (90 x 9.5 x 7.4) ÷ 9 =? a) 82602.5 b) 86706.5 c) 83503.5 d) 84432.3 e) 87687.2

Description : 117.5 x (90 x 9.5 x 7.4) ÷ 9 =? a) 82602.5 b) 86706.5 c) 83503.5 d) 84432.3 e) 87687.2

Last Answer : 117.5 x (90 x 9.5 x 7.4) ÷ 9 =? Sol: 117.5 x 6327 ÷ 9 = ? 117.5 x 703 = ? ? = 82602.5 Answer: a)

117.5 x (90 x 9.5 x 7.4) ÷ 9 =? a) 82602.5 b) 86706.5 c) 83503.5 d) 84432.3 e) 87687.2

Description : 117.5 x (90 x 9.5 x 7.4) ÷ 9 =? a) 82602.5 b) 86706.5 c) 83503.5 d) 84432.3 e) 87687.2

Last Answer : 117.5 x (90 x 9.5 x 7.4) ÷ 9 =? Sol: 117.5 x 6327 ÷ 9 = ? 117.5 x 703 = ? ? = 82602.5 Answer: a)

Ships’ generators produce 450-volt, three-phase, ac power; however, most equipment uses 117-volt, single-phase power What transformers and connections are used to convert 450- volt, threephase power to 117-volt, single-phase power?

Description : Ships’ generators produce 450-volt, three-phase, ac power; however, most equipment uses 117-volt, single-phase power What transformers and connections are used to convert 450- volt, threephase power to 117-volt, single-phase power?

Last Answer : A method of generating oscillations, a method of turning the oscillations on and off (keying), and an antenna to radiate the energy.

The decimal equivalent of hexadecimal FF is ________. 117) A) 25010 B) 24010 C) 25510 D) 22510

Description : The decimal equivalent of hexadecimal FF is ________. 117) A) 25010 B) 24010 C) 25510 D) 22510

Last Answer : C) 25510

In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5

Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5

Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130  = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X

What is 54 over 108 in its simplis form?

Description : What is 54 over 108 in its simplis form?

Last Answer : 54/108 in its simplest form is 1/2

What is 54 over 108 in its simplis form?

Description : What is 54 over 108 in its simplis form?

Last Answer : 54/108 in its simplest form is 1/2

What is 108 over 28 as a mixed number?

Description : What is 108 over 28 as a mixed number?

Last Answer : 108/28 = (3×28+24)/28= 3 24/28= 3 (6×4)/(7×4)= 3 ⁶/₇

What is the equivalent fraction for 108 over 180?

Description : What is the equivalent fraction for 108 over 180?

Last Answer : It is a fraction of the form (108*k)/(180*k) where k is anynon-zero integer or a common factor of 108 and 180.

What is the equivalent fraction for 108 over 180?

Description : What is the equivalent fraction for 108 over 180?

Last Answer : It is a fraction of the form (108*k)/(180*k) where k is anynon-zero integer or a common factor of 108 and 180.

Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Description : Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Last Answer : d. 20000

The concrete roof of a house is 10 m by 8 m and 10 cm thick (4"). Estimate the total heat the roof would absorb over the 12 day?  a. 1.3 x 108 J  b 2.3 x 108 J  c. 3.3 x 108 J  d. 4.3 x 108 J formula: ΔQ = ΔQ/Δtx Δt

Description : The concrete roof of a house is 10 m by 8 m and 10 cm thick (4"). Estimate the total heat the roof would absorb over the 12 day?  a. 1.3 x 108 J  b 2.3 x 108 J  c. 3.3 x 108 J  d. 4.3 x 108 J formula: ΔQ = ΔQ/Δtx Δt

Last Answer : 1.3 x 108 J

A cantilever of length 3m carries a uniformly distributed load of 15KN/m over a length of 2m from the free end.If I= 108 mm4 and E= 2×105 N/mm2,find the slope at the free end? a.0.00326 rad b.0.00578 rad c.0.00677 rad d.0.00786 rad

Description : A cantilever of length 3m carries a uniformly distributed load of 15KN/m over a length of 2m from the free end.If I= 108 mm4 and E= 2×105 N/mm2,find the slope at the free end? a.0.00326 rad b.0.00578 rad c.0.00677 rad d.0.00786 rad

Last Answer : a.0.00326 rad

What's the procedure for calculating the number of pieces of the edge of a puzzle of 108 total pieces?

Description : What's the procedure for calculating the number of pieces of the edge of a puzzle of 108 total pieces?

Last Answer : Impossible, It would almost completely depends on the size of the pieces, which you don't have. Imagine this is a rectangle. You could have two large pieces on each side, making a total of 8 ... still correct. There is not enough information in the question to be able to make an educated estimate.

Why do they say there are 100 pieces in a puzzle that actually has 108 pieces?

Description : Why do they say there are 100 pieces in a puzzle that actually has 108 pieces?

Last Answer : They had a few pieces left over at the end of the run in the factory you were the lucky one to receive them. who knows ? toss them and forget them. better to have more, than not enough.

A couple applied to a flywheel of mass 5 kg and of radius of gyration 20 cm produces an angular acceleration of 4 radians/sec2. The torque applied in dyne cm is a.8 x 104 b.8 x 106 c.8 x 107 d.8 x 108 e.8 x 1010

Description : A couple applied to a flywheel of mass 5 kg and of radius of gyration 20 cm produces an angular acceleration of 4 radians/sec2. The torque applied in dyne cm is a.8 x 104 b.8 x 106 c.8 x 107 d.8 x 108 e.8 x 1010

Last Answer : b. 8 x 106

One joule is equal to a.105 ergs b.108 ergs c.104 ergs d.107 ergs e.106 ergs

Description : One joule is equal to a.105 ergs b.108 ergs c.104 ergs d.107 ergs e.106 ergs

Last Answer : d. 107 ergs

The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

Description : The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

Last Answer : a. 1.27 x 108

2. Light enters from air to glass having refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3 x 108 ms-1. -Physics-10

Description : 2. Light enters from air to glass having refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3 x 108 ms-1. -Physics-10

Last Answer : Refractive index of a medium (nm) = Speed of light in vacuum/Speed of light in the medium Speed of light in vacuum (c) = 3 × 108 m/s Refractive index of glass (ng) = 1.50 Speed of light in the ... Speed of light in vacuum/ Refractive index of glass = c/ng =3 × 108/1.50 = 2x 108 ms-1.

Between 1880 and 1920 forests cover in the Indian subcontinent declined by 9.7 million hectares, from 108.6 million hectares to 98.9 million hectares. -History 9th

Description : Between 1880 and 1920 forests cover in the Indian subcontinent declined by 9.7 million hectares, from 108.6 million hectares to 98.9 million hectares. -History 9th

Last Answer : Railways: Railways were an important asset that was essential in maintaining trade through the transport of goods and the domination of the colonies through the transport of troops. Wood was needed to ... tracts, there were fewer chances of the trees growing back due to loss in soil fertility

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

Evaluate 105 x 108 without multiplying directly. -Maths 9th

Description : Evaluate 105 x 108 without multiplying directly. -Maths 9th

Last Answer : Solution :-

If a + b + c = 9 and ab + bc + ca = 23, then a3 + b3 + c3 – 3 abc = (a) 108 (b) 207 (c) 669 (d) 729 -Maths 9th

Description : If a + b + c = 9 and ab + bc + ca = 23, then a3 + b3 + c3 – 3 abc = (a) 108 (b) 207 (c) 669 (d) 729 -Maths 9th

Last Answer : a+b+c=9 and a2+b2+c2=35 Using formula, (a+b+c)2=a2+b2+c2+2(ab+bc+ca) 92=35+2(ab+bc+ca) 2(ab+bc+ca)=81−35=46 (ab+bc+ca)=23 using formula, (a3+b3+c3)−3abc=(a2+b2+c2−ab−bc−ca)(a+b+c) a3+b3+c3−3abc=(35−23)×9=9×12=108

there are 108 pigeons that need coops. each coop can hold up to seven pigeons how many coops do they need?

Description : there are 108 pigeons that need coops. each coop can hold up to seven pigeons how many coops do they need?

Last Answer : 16

how much times does 45 go into 108?

Description : how much times does 45 go into 108?

Last Answer : 1 with 90

what is 9 times what is 108?

Description : what is 9 times what is 108?

Last Answer : 12

how many times dose 5 go into 108?

Description : how many times dose 5 go into 108?

Last Answer : 21.6 times.

In an organic compound of molar mass `108 gm mol^-1 C, H and N` atoms are presents in `9 : 1 : 3.5` by mass. Molecular can be

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Silver (atomic weight `108 g mol^(-1))` has a density of `10.5 g cm^(-3)`. The number of silver atoms on a surfaces of area `10^(-12) m^(2)` can be ex

Description : Silver (atomic weight `108 g mol^(-1))` has a density of `10.5 g cm^(-3)`. The number of silver atoms on a surfaces of area `10^(-12) m^(2)` can be ex

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