What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

1 Answer

Answer :

A + b = 0, 9, 18(9,0)(8,1)(7,2)(6,3)(5,4)(4,5)(3,6)(2,7)(1,8)(0,9)(0,0)(9,9)-------------------------------------------To be divisible by 9, the sum 6 + 3 + 1 + 8 + 7 + 2 + A + B = 27+ A + B must be divisible by 9→ A + B must be a multiple of 9.→ (A, B) must be (0, 0), (0, 9), (1, 8), (2, 7), (3, 6), (4, 5),(5, 4), (6, 3), (7, 2), (8, 1), (9, 0)Note that (0, 0) must not be forgotten as 27 + 0 + 0 = 27 = 3 ×9.

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Last Answer : A + b = 0, 9, 18(9,0)(8,1)(7,2)(6,3)(5,4)(4,5)(3,6)(2,7)(1,8)(0,9)(0,0)(9,9)-------------------------------------------To be divisible by 9, the sum 6 + 3 + 1 + 8 + 7 + 2 + A + B = 27+ A ... , 5),(5, 4), (6, 3), (7, 2), (8, 1), (9, 0)Note that (0, 0) must not be forgotten as 27 + 0 + 0 = 27 = 3 9.

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