How many numbers between 16 to 189 are divisible by 9 but not by 4?

How many numbers between 16 to 189 are divisible by 9 but not by 4?
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There are 14 such numbers between 16 and 189.
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Description : Which of these numbers are divisible by 3 - a. 29 b. 16 c. 24 d. 14?

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189 2/9 +189 3/9+189 5/9+189 6/9+189 7/9 =? a) 1138 b) 1037 c) 1237 d) 1238 e) 1137

Description : 189 2/9 +189 3/9+189 5/9+189 6/9+189 7/9 =? a) 1138 b) 1037 c) 1237 d) 1238 e) 1137

Last Answer : ? = 189 2/9 + 189 3/9 +189 4/9 +189 5/9 + 189 6/9 + 189 7/9 =(189 × 6) +(2/9 + 3/9 +4/9+5/9+6/9+7/9 ) =1134 + (2+3+4+5+6+7)/9 =113 + (27/9) =1134 + 3=1137 Answer: e)

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a real estate broker sold your house for 189 000 -General Knowledge

Description : a real estate broker sold your house for 189 000 -General Knowledge

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The amount of copper in the human body is (A) 50–80 mg (B) 100–150 mg (C) 400–500 mg (D) 500–1000 mg MINERAL METABOLISM 189

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Angular velocity of second hand of clock is 0.105 rad s-1 and length of hand is 1.8 cm, then speed of tip of hand is A. 0.189 cm s-1 B. 1 cm s-1 C. 0.189 m s-1 D. 2 m s-1

Description : Angular velocity of second hand of clock is 0.105 rad s-1 and length of hand is 1.8 cm, then speed of tip of hand is A. 0.189 cm s-1 B. 1 cm s-1 C. 0.189 m s-1 D. 2 m s-1

Last Answer : 0.189 cm s-1

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Description : 104 153 189 214 ? a) 239 b) 225 c) 264 d) 235 e) None of these

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When the integers from 1 to 999 are written on a paper, the number of zeros used in writing it is: a) 192 b) 189 c) 200 d) 203 e) 216

Description : When the integers from 1 to 999 are written on a paper, the number of zeros used in writing it is: a) 192 b) 189 c) 200 d) 203 e) 216

Last Answer : From 1 to 10 : 1 zero From 11-100 : 10 zeros (100 has 2 zeros) From 101 – 900 : 8×20 = 160 zeros From 901-999 : we have 18 zeros Total = 1+10+160+18 = 189 zeros Answer: b)

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Description : 63251 × 82 = ? × 42105 a) 101 b) 123 c) 147 d) 165 e) 189

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A cricketer played 3 matches in tournament. The respective ratio between the scores of first and second matches was 3:7 and that between the scores of second and third matches between was 7 :2. the difference between first and third matches was 84 runs, what was the cricketer average score in all the matches together? A) 336 B) 146 C) 168 D) 189

Description : A cricketer played 3 matches in tournament. The respective ratio between the scores of first and second matches was 3:7 and that between the scores of second and third matches between was 7 :2. the difference ... the cricketer average score in all the matches together? A) 336 B) 146 C) 168 D) 189

Last Answer : A) The ratio between first and second matches equal to 3 :7 The ratio between second and third matches=7:2 The difference between first and third matches=3x-2x=84 runs = 84 Required average=1008/3=336 .

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Description : 20

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Description : What numbers are divisible by 4 or 6?

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Description : What is 519 divisible by in whole numbers?

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Description : What which of these numbers is divisible by 12 is it a. 6 b. 26 c. 12 d. 42?

Last Answer : c.

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Description : What numbers are 21 divisible by?

Last Answer : They are members of the infinite set of numbers of the form 21*kwhere k is an integer.

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Description : The least number that is divisible by all the numbers from 1 to 5 is: (a) 70 (b) 60 (c) 80 (d) 90

Last Answer : (b) 60

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Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Description : For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Last Answer : Given f(x) = 3x³ - kx² + 4x + 16. Since (x - k/2) is a factor of polynomial. This means x = k/2 is the zero of the given polynomial. ⇒ f(k/2) = 3(k/2)³ - k(k/2)² + 4(k/2) + 16 ⇒ 0 ... - 4k + 32) + 4(k² - 4k + 32) ⇒ 0 = (k + 4)(k² - 4k + 32) ⇒ k = -4.

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Description : What number is divisible by 9 123 234 or 345?

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Description : Is 646 divisible by 9?

Last Answer : 6 + 4 + 6 = 161 + 6 = 7→ No; 646 is not divisible by 9 (there is a remainder of 7).-----------------------------------------Only if the sum of the ... ifthis single digit is 9 is the original number divisible by 9,otherwise this single digit is the remainder when the originalnumber is divided by 9.

Is 4932 divisible by 9?

Description : Is 4932 divisible by 9?

Last Answer : Yes

Is 90 divisible by 2 3 4 5 6 9 10?

Description : Is 90 divisible by 2 3 4 5 6 9 10?

Last Answer : Yes, all except 4

What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Description : What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Last Answer : A + b = 0, 9, 18(9,0)(8,1)(7,2)(6,3)(5,4)(4,5)(3,6)(2,7)(1,8)(0,9)(0,0)(9,9)-------------------------------------------To be divisible by 9, the sum 6 + 3 + 1 + 8 + 7 + 2 + A + B = 27+ A ... , 5),(5, 4), (6, 3), (7, 2), (8, 1), (9, 0)Note that (0, 0) must not be forgotten as 27 + 0 + 0 = 27 = 3 9.

What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Description : What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Last Answer : A can be 0 or 9.

Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Description : Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Last Answer : If the sum of digits add up to 9 then the number is divisible by 9 as for example the digits of 450 add up to 9 and so 450/9 = 50-------------------------------------- ... sum is 9, then the original number is divisible by 9, otherwise it is the remainder when the original number is divided by 9.

Is 90 divisible by 5 and 9?

Description : Is 90 divisible by 5 and 9?

Last Answer : Yes. 90 is divisible by 9, 10 times. 90 is divisible by 5, 18times.

Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Description : Why the divisibility test for 9 is valid and a way to determine whether a three-digit counting number ABC is divisible by 9?

Last Answer : If the sum of digits add up to 9 then the number is divisible by 9 as for example the digits of 450 add up to 9 and so 450/9 = 50-------------------------------------- ... sum is 9, then the original number is divisible by 9, otherwise it is the remainder when the original number is divided by 9.

What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Description : What are all of the different ways to choose the ones digit A in 271854A so that the number will be divisible by 9?

Last Answer : A can be 0 or 9.

What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Description : What are all of the different ways to choose the tens digit A and the ones digit B in the number 631872AB so that the number will be divisible by 9?

Last Answer : A + b = 0, 9, 18(9,0)(8,1)(7,2)(6,3)(5,4)(4,5)(3,6)(2,7)(1,8)(0,9)(0,0)(9,9)-------------------------------------------To be divisible by 9, the sum 6 + 3 + 1 + 8 + 7 + 2 + A + B = 27+ A ... , 5),(5, 4), (6, 3), (7, 2), (8, 1), (9, 0)Note that (0, 0) must not be forgotten as 27 + 0 + 0 = 27 = 3 9.

Is 90 divisible by 5 and 9?

Description : Is 90 divisible by 5 and 9?

Last Answer : Yes. 90 is divisible by 9, 10 times. 90 is divisible by 5, 18times.

Is 104 divisible by 9?

Description : Is 104 divisible by 9?

Last Answer : No.To check if a number is divisible by 9 add the digits togetherand if the sum is divisible by 9 then so is the original number.The check can be used on the sum so keep summing until a singledigit remains. If ... = 55 is not 9, so 104 is not divisible by 9; it has a remainder of5 when divided by 9

Is N divisible by 9? (N is a two digit number) I. R(N/3) = 2 II. R(n/7)=1 (a) statement (I) alone is sufficient (b) statement (II) alone is sufficient (c) Both statements (I) and (II) together are not sufficient (d) Both statements (I) and (II) together are necessary

Description : Is N divisible by 9? (N is a two digit number) I. R(N/3) = 2 II. R(n/7)=1 (a) statement (I) alone is sufficient (b) statement (II) alone is sufficient (c) Both statements (I) and (II) together are not sufficient (d) Both statements (I) and (II) together are necessary

Last Answer : (a) statement (I) alone is sufficient

If the number 481 * 637 is completely divisible by 9, what is the smallest number in place of * ? 1) 3 2) 7 3) 5 4) 9 5) 2

Description : If the number 481 * 637 is completely divisible by 9, what is the smallest number in place of * ? 1) 3 2) 7 3) 5 4) 9 5) 2

Last Answer : 2) 7

The accuracy of the floating-point numbers representable in two 16-bit words of a computer is approximately A) 16 digits B) 6 digits C) 9 digits D) All of above

Description : The accuracy of the floating-point numbers representable in two 16-bit words of a computer is approximately A) 16 digits B) 6 digits C) 9 digits D) All of above

Last Answer : Answer : A

A base-16 number system that uses sixteen distinct symbols 0-9 and A-F to represent numbers from 0 to 15. A. Binary B. Decimal C. Hexadecimal D. Hepadeximal

Description : A base-16 number system that uses sixteen distinct symbols 0-9 and A-F to represent numbers from 0 to 15. A. Binary B. Decimal C. Hexadecimal D. Hepadeximal

Last Answer : A. Binary

The accuracy of the floating-point numbers representable in two 16-bit words of a computer is approximately a. 16 digits b. 6 digits c. 9 digits d. All of above

Description : The accuracy of the floating-point numbers representable in two 16-bit words of a computer is approximately a. 16 digits b. 6 digits c. 9 digits d. All of above

Last Answer : d. All of above

In the following question from among the given alternative select the one in which the set of numbers is most like the set of number given in the questions. GiveSet:(4, 25, 81) 16. (a) (4, 36, 79) (b) (9, 48, 81) (c) (16, 64, 100) (d) (9,49, 143) 17. In the following question, number of letters are skipped in between by a particular rule. Which of the following series observes the rule? (a) BAFHTU (b) ACEGJL (c) ACFJOU (d) ADFHJL

Description : In the following question from among the given alternative select the one in which the set of numbers is most like the set of number given in the questions. GiveSet:(4, 25, 81) 16. (a) (4, 36, 79) ... . Which of the following series observes the rule? (a) BAFHTU (b) ACEGJL (c) ACFJOU (d) ADFHJL

Last Answer : 16. (c) 17. (c)

What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which nothing can be done; which devours every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Description : What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which ... every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Last Answer : Time.

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : As the given polynomial divisible by x-2 means the polynomial satisfies for the value x=2 So putting x=2 in x²+(4-k)x+2 yields 0 ⇒2²+(4-k)2+2=0 ⇒4+8-2k+2=0 ⇒ 2k=14 ⇒ k= ... ;-3x+2 if factorized yields (x-1)(x-2). Thus is divisible by x-2 as well as divisible by x-1.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : The value of 'k' is 4

An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Description : An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Last Answer : As there are 200 integers, total number of exhaustive, mutually exclusive and equally likely cases, i.e, n(S) = 200 Let A : Event of integer chosen from 1 to 200 being divisible by 6⇒ n(A) = 33 \(\bigg(rac{200}{6}=33rac{1}{3}\ ... (rac{25}{200}\) - \(rac{8}{200}\) = \(rac{50}{200}\) = \(rac{1}{4}\).

Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Description : Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Last Answer : The two digit numbers can be formed by putting any of 5 digits at the one 's place and also one of the 5 digits at ten's place. So, Total number of 2-digit numbers that can be formed using these 5-digits = 5 5 = ... 52}, i.e, 5 in number. ∴ Required probability = \(rac{5}{25}\) = \(rac{1}{5}.\)