How do i calculate the metres of perimeter for a rectangle with sides 17.5 m by 6.25 m wide?

How do i calculate the metres of perimeter for a rectangle with sides 17.5 m by 6.25 m wide?
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Description : How do i calculate the metres of perimeter for a rectangle with sides 17.5 m long by 3.3 m wide?

Last Answer : Perimeter of rectangle: 17.5+3.3+17.5+3.3 = 41.6 metres

How do i Calculate the metres of perimeter of a square with sides 2.750 m long?

Description : How do i Calculate the metres of perimeter of a square with sides 2.750 m long?

Last Answer : multiply by 2.75m by 4

What os the perimeter when it is eleven meters long and four metres wide?

Description : What os the perimeter when it is eleven meters long and four metres wide?

Last Answer : (11 + 4) × 2 = 30 metresAdd one length of 11 and one width of 4, then times by 2 as there are two lengths and two widths making up the total perimeter. This is assuming that the perimeter is a regular rectangular shape.

Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540 cm. Find its area. -Maths 9th

Description : Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540 cm. Find its area. -Maths 9th

Last Answer : Let the sides of the triangle be a = 12x cm, b = 17x cm, c = 25x cm Perimeter of the triangle = 540 cm Now, 12x + 17x + 25x = 540 ⇒ 54x = 54 ⇒ x = 10 ∴ a = (12 x10)cm = 120cm, b = (17 x 10) cm = 170 cm and c = (25 x 10)cm = 250 cm Now, semi-perimeter, s = 5402cm = 270 cm

If you have a rectangle whose Perimeter equals 60 and the Area equals 200 what are the lengths of the four sides?

Description : If you have a rectangle whose Perimeter equals 60 and the Area equals 200 what are the lengths of the four sides?

Last Answer : The rectangle must have sides with lengths of 20, 20, 10, and 10.20+20+10+10 = 60 (perimeter)20*10 = 200 (area)

Calculate the perimeter of a rectangle whose area is 25x2 – 35x + 12. -Maths 9th

Description : Calculate the perimeter of a rectangle whose area is 25x2 – 35x + 12. -Maths 9th

Last Answer : Given, Area of rectangle = 25x2 - 35x + 12 We know, area of rectangle = length breadth So, by factoring 25x2 - 35x + 12, the length and breadth can be obtained. 25x2 - 35x + 12 = 25x2 - 15x - 20x + 12 => 25x2 - 35x + ... )] = 2(5x - 3 + 5x - 4) = 2(10x - 7) = 20x - 14 So, the perimeter = 20x - 14

Write a shell script to accept length and breadth of rectangle from user. Calculate and display area, perimeter, of entered values using choice entered by user.

Description : Write a shell script to accept length and breadth of rectangle from user. Calculate and display area, perimeter, of entered values using choice entered by user.

Last Answer : #!/bin/bash # GNU bash, version 4.3.46 echo "Enter Length of Rectangle: " read length echo "Enter Breadth of Rectangle: " read breadth echo "Which operation you want to perform? 1: area 2: perimeter" read ... ) res=` echo 2 \* $length \* $breadth | bc` ;; esac echo "Result is $res" exit 0

What is the width of the rectangle if A rectangle is 25 centimeters long and The perimeter is 84 centimeters.?

Description : What is the width of the rectangle if A rectangle is 25 centimeters long and The perimeter is 84 centimeters.?

Last Answer : 17 centimetres25 + 25 + 17 + 17 = 84as25 + 25 = 5084 - 50 = 3434/2 = 17

The perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8. Find the area of the triangular field. -Maths 9th

Description : The perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8. Find the area of the triangular field. -Maths 9th

Last Answer : Let sides of △ are=6x,7x and 8x Perimeter=6x+7x+8x=21x 21x=410 x=20 Sides are 120,140 and 160 m Area =S(S−A)(S−B)(S−C)​ [Heron's Formula] S=2120+140+160​=210 m A=210(210−120)(210−140)(210−160)​=210015​ sq. m

The perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8. Find the area of the triangular field. -Maths 9th

Description : The perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8. Find the area of the triangular field. -Maths 9th

Last Answer : Let sides of △ are=6x,7x and 8x Perimeter=6x+7x+8x=21x 21x=410 x=20 Sides are 120,140 and 160 m Area =S(S−A)(S−B)(S−C)​ [Heron's Formula] S=2120+140+160​=210 m A=210(210−120)(210−140)(210−160)​=210015​ sq. m

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Description : How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? -Maths 9th

Last Answer : Given, radius (r) = 7 m and height (h) = 24m ∴ Slant height (l) = √h2 + r2 = √242 + 72 = √625 = 25 m ∴ Length of canvas required

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Description : How many metres of 5 m wide cloth will be required to make a conical tent, the radius of whose base is 3.5 m and height is 12 m ? -Maths 9th

Last Answer : l = √h2 + r2 = √(3.5)2 + (12)2 = √12.25 + 144 = √156.25 = 12.5 m Curved surface area = πrl = 22 / 7 × 3.5 × 12.5 = 137.5 m2 Area of cloth = 137.5 m2 Length of cloth required = C.S.A. / Width l = 137.5 / 5 = 27.5 m

How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? -Maths 9th

Description : How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? -Maths 9th

Last Answer : Given, radius (r) = 7 m and height (h) = 24m ∴ Slant height (l) = √h2 + r2 = √242 + 72 = √625 = 25 m ∴ Length of canvas required

How many metres of 5 m wide cloth will be required to make a conical tent, the radius of whose base is 3.5 m and height is 12 m ? -Maths 9th

Description : How many metres of 5 m wide cloth will be required to make a conical tent, the radius of whose base is 3.5 m and height is 12 m ? -Maths 9th

Last Answer : l = √h2 + r2 = √(3.5)2 + (12)2 = √12.25 + 144 = √156.25 = 12.5 m Curved surface area = πrl = 22 / 7 × 3.5 × 12.5 = 137.5 m2 Area of cloth = 137.5 m2 Length of cloth required = C.S.A. / Width l = 137.5 / 5 = 27.5 m

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Description : If 15.6 and CE 4.5 what is the perimeter of the rectangle?

Last Answer : If the given dimensions are the length and width of a rectanglethen its perimeter is 15.6+4.5+15.6+4.5 = 40.2

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Description : What is the perimeter of 15.5 m and 10.3 wide?

Last Answer : 15.5 + 10.3 = 25.8.... 25.8 x 2 = 51.6

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Description : Why A rectangle is 25 in. long and 13 in. wide. What is the area of the rectangle?

Last Answer : 325 square inches

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Description : What is the perimeter of a rectangle that is 6 inches by 12 inches?

Last Answer : The perimeter would be 36 inches.

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Description : The sides of a triangle are in the ratio of 3 : 4 : 5 and its perimeter is 510 m. What is the measure of its greatest side? -Maths 9th

Last Answer : Let the sides of triangle be 3x,4x,5x Perimeter =3x + 4x + 5x=144 cm 12x=144 ∴x=12 Then sides of triangle are 3x=3 12=36 cm, 4x=4 12=48 cm, 5x=5 12=60 cm. Now, Semi perimeter, s=2 Sum of sides of ... , Area of triangle =s (s−a)(s−b)(s−c) = 72(72−36)(72−48)(72−60) = 72 36 24 12 = 864 cm2

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Description : The perimeter of a triangular field is 240 m. If two of its sides are 78 m and 50 m, -Maths 9th

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An R.C.C. beam of 25 cm width and 50 cm effective depth has a clear span of 6 metres and carries a U.D.L. of 3000 kg/m inclusive of its self weight. If the lever arm constant for the section is 0.865, the maximum intensity of shear stress, is (A) 8.3 kg/cm2 (B) 7.6 kg/cm2 (C) 21.5 kg/cm2 (D) 11.4 kg/cm2

Description : An R.C.C. beam of 25 cm width and 50 cm effective depth has a clear span of 6 metres and carries a U.D.L. of 3000 kg/m inclusive of its self weight. If the lever arm constant for the section is 0.865, the maximum intensity ... , is (A) 8.3 kg/cm2 (B) 7.6 kg/cm2 (C) 21.5 kg/cm2 (D) 11.4 kg/cm2

Last Answer : Answer: Option A

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Description : What is the perimeter in feet of a rectangle with length 5 feet and width 3 feet?

Last Answer : 15 feet

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Description : If BD16.5 and CE4.5 what is the perimeter of the rectangle?

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Description : If a rectangle and a parallelogram are equal in area and have the same base and are situated on the same side, and the ratio of the perimeter -Maths 9th

Last Answer : answer:

what- based on the given information, which conjecture is invalidGiven: A rectangle has a perimeter of 24 inches.?

Description : what- based on the given information, which conjecture is invalidGiven: A rectangle has a perimeter of 24 inches.?

Last Answer : The rectangle has a length of 12.

what- the perimeter of a rectangle is 100 centimeters. The length is twice the width.Which equation could you use to find the width of the rectangle in centimeters?

Description : what- the perimeter of a rectangle is 100 centimeters. The length is twice the width.Which equation could you use to find the width of the rectangle in centimeters?

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What is the formula for determining the perimeter of a rectangle ?

Description : What is the formula for determining the perimeter of a rectangle ?

Last Answer : Formula 2 for determining the perimeter of a rectangle (length + width)

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Description : What if the width of a rectangle is 23 centimeters. If the perimeter of the rectangle is 104 centimeters what is the length?

Last Answer : Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter

If a rectangle measure 15 inches by 1 34 feet what is the perimeter in yards?

Description : If a rectangle measure 15 inches by 1 34 feet what is the perimeter in yards?

Last Answer : 1.72666 yards.

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Description : What is The perimeter of the rectangle is what inches?

Last Answer : It is 1+4+1+4 = 10 inches.

What is the width of a rectangle who has 222 millimeters as the perimeter and a length of 60 millimeters?

Description : What is the width of a rectangle who has 222 millimeters as the perimeter and a length of 60 millimeters?

Last Answer : ForP = perimeterL = lengthW = width2L + 2W = PFor the given information this means2x60 + 2W = 222120 + 2W = 2222W = 222W = 51So the Width would be 51 millimeters

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Description : What is the perimeter of a rectangle 5X4?

Last Answer : What is the answer ?

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Description : What is the area of a rectangle if the perimeter is 24 units?

Last Answer : Need answer

What is the perimeter of 30 unit rectangle?

Description : What is the perimeter of 30 unit rectangle?

Last Answer : 22 units

What is the area of a 24 unit perimeter of a rectangle?

Description : What is the area of a 24 unit perimeter of a rectangle?

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What is the work The length of a rectangle is 4 cm more than 3 times the width. The perimeter is 88 cm. What are the dimensions of the rectangle Write a system of equations based on the info?

Description : What is the work The length of a rectangle is 4 cm more than 3 times the width. The perimeter is 88 cm. What are the dimensions of the rectangle Write a system of equations based on the info?

Last Answer : Let its length be 3x+4 and its width be x Perimeter: 2*(3x+4+x) = 88 Solving the equation x = 10 Therefore: length = 34 cm and width = 10 cm Check: 2*(34+10) = 88 cm

Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla this brress is doins centinuously infinite46. The perimeter of 7 th triangle is \( ( \) in \( cm ) \)a) \( \frac{3}{4} \)b) \( \frac{5}{8} \)c) \( \frac{9}{8} \)d) \( \frac{7}{8} \)47. The sum of perimeter of all triangle is (in \( cm \) )a) 144b) 625c) 400d) 16948. The area of all the triangle is (in sq cm)a) 576b) \( 144 \sqrt{3} \)c) \( 169 \sqrt{3} \)d) \( 192 \sqrt{3} \)49. The sum of perimeter of first 6 triangle is (in \( cm \) )a) 120b) \( \frac{567}{4} \)c) \( \frac{569}{4} \)d) 14450. The side of the 5th triangle is (in \( cm \) )a) 6b) \( 1.5 \)c) \( 0.75 \)d) 3

Description : Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla this brress is doins centinuously infinite46. The perimeter of 7 th triangle is \( ( \) in \( cm ) \)a) \( \ ... of the 5th triangle is (in \( cm \) )a) 6b) \( 1.5 \)c) \( 0.75 \)d) 3

Last Answer : Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla ... ( 1.5 \) c) \( 0.75 \) d) 3

The sides of a triangle are in the ratio 3 : 5 : 7 and its perimeter is 30 cm. The length of the greatest side of the triangle in cm is (1) 6 (2) 10 (3) 14 (4) 16

Description : The sides of a triangle are in the ratio 3 : 5 : 7 and its perimeter is 30 cm. The length of the greatest side of the triangle in cm is (1) 6 (2) 10 (3) 14 (4) 16

Last Answer : (3) 14

If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Description : If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Last Answer : LET EACH SIDE BE X 6X+11X+15X=96 32X=96 X=3 SIDES=6 3=18 11 3=33 15 3=45 AREA OF TRIANGLE BY HERONS FORMULA=S=96/2=48 WHOLE UNDERROOT 48 48-18 48-33 48-45 UNDERROOT=12 4 30 15 3 4 3 15ROOT2 180 ... bh/2 180root2=18 h/2 360root2=18h h=20 root2 But root 2=1.4(approx) h=20 1.4(approx) h=28cm(approx).

If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Description : If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Last Answer : LET EACH SIDE BE X 6X+11X+15X=96 32X=96 X=3 SIDES=6 3=18 11 3=33 15 3=45 AREA OF TRIANGLE BY HERONS FORMULA=S=96/2=48 WHOLE UNDERROOT 48 48-18 48-33 48-45 UNDERROOT=12 4 30 15 3 4 3 15ROOT2 180 ... bh/2 180root2=18 h/2 360root2=18h h=20 root2 But root 2=1.4(approx) h=20 1.4(approx) h=28cm(approx).

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Description : The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Last Answer : Here, length of rectangle ABCD = 8 cm and breadth of rectangle ABCD = 6.cm Let E, F, G and H are the mid-points of the sides of rectangle ABCD, then EFGH is a rhombus.

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Description : The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Last Answer : Here, length of rectangle ABCD = 8 cm and breadth of rectangle ABCD = 6.cm Let E, F, G and H are the mid-points of the sides of rectangle ABCD, then EFGH is a rhombus.

An R.C.C beam of 25 cm width has a clear span of 5 metres and carries a U.D.L. of 2000 kg/m inclusive of its self weight. If the lever arm of the section is 45 cm., the beam is (A) Safe in shear (B) Is safe with stirrups (C) Is safe with stirrups and inclined members (D) Needs revision of the section

Description : An R.C.C beam of 25 cm width has a clear span of 5 metres and carries a U.D.L. of 2000 kg/m inclusive of its self weight. If the lever arm of the section is 45 cm., the beam is ( ... shear (B) Is safe with stirrups (C) Is safe with stirrups and inclined members (D) Needs revision of the section

Last Answer : Answer: Option A

A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Description : A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Last Answer : Katie earned 84,92,84,75 and 70 on her first 5 tests. What is the minimum grade Katie needs to earn on the next test to have a mean of 84?

Sides of a triangle are in the ratio of 12:17:25 and... -Maths 9th

Description : Sides of a triangle are in the ratio of 12:17:25 and... -Maths 9th

Last Answer : Let the sides of the triangle be 12x, 17x and 25x Perimeter of the triangle = 540 cm ∴ 12x + 17x + 25x = 540 ⇒ 54x = 540 ⇒ x = 10 Let a = 12x = 12 x 10 = 120 cm b = 17x = 17 x 10 = 170 cm ... ( √270 x 150 x 100 x 20) = 100 under root( √27 x 15 x 20) = 100 x 9 x 5 x 2 = 9000 cm2

A beam of uniform rectangular section 200 mm wide and 300mm deep is simply supported at its ends.It carries a uniformly distributed load of 9KN/m run over the entire span of 5m.If E=1×104 N/mm2, what is the maximum deflection? a.14.26 mm b.17.28 mm c.18.53 mm d.16.27 mm.

Description : A beam of uniform rectangular section 200 mm wide and 300mm deep is simply supported at its ends.It carries a uniformly distributed load of 9KN/m run over the entire span of 5m.If E=1×104 N/mm2, what is the maximum deflection? a.14.26 mm b.17.28 mm c.18.53 mm d.16.27 mm.

Last Answer : d.16.27 mm.

A T-section beam having flange 180mm wide and 20 mm thick and web 150 mm long and 20 mm thick carries a udl of 80 kN/m over an effective span of 8 m. Calculate the maximum bending stress.

Description : A T-section beam having flange 180mm wide and 20 mm thick and web 150 mm long and 20 mm thick carries a udl of 80 kN/m over an effective span of 8 m. Calculate the maximum bending stress.

Last Answer : Solution :