How do you solve Log3 log2x - log(3x plus 7)?

How do you solve Log3 log2x - log(3x plus 7)?
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If log32, log3 (2^x – 5) and log^3 (2^x – 7/2) are in A.P., then what is the value of x ? -Maths 9th

Description : If log32, log3 (2^x – 5) and log^3 (2^x – 7/2) are in A.P., then what is the value of x ? -Maths 9th

Last Answer : answer:

Solve log2x + 3 (6x^2 + 23x + 21) = 4 – log3x + 7 (4x^2 + 12x + 9). -Maths 9th

Description : Solve log2x + 3 (6x^2 + 23x + 21) = 4 – log3x + 7 (4x^2 + 12x + 9). -Maths 9th

Last Answer : answer:

If 1/3 log3 M + 3 log3 N = 1 + log 0.008 5, then -Maths 9th

Description : If 1/3 log3 M + 3 log3 N = 1 + log 0.008 5, then -Maths 9th

Last Answer : (b) \(N^9=rac{9}{M}\)\(rac{1}{3}\) log3 M + 3 log3 N = 1 + log0.008 5⇒ log3 M1/3 + log3N3 = 1 + log0.0085 ⇒ log3 M1/3 N3 = 1 + log0.0085 ⇒ M1/3 N3 = 3(1 + log0.0085) ⇒ M1/3 N3 = 31 . 3log0.0085⇒ \(N^9=rac{27 ... ^9=rac{27}{M}\big(3^{log_{rac{1}{5}}5}\big)\) = \(rac{1}{M}\) (27)(3-1) = \(rac{9}{M}.\)

How do you solve the system of equation x plus 2y-2 3x plus 4y6?

Description : How do you solve the system of equation x plus 2y-2 3x plus 4y6?

Last Answer : If you mean x+2y = -2 and 3x+4y = 6 then the solutions to theequations are x = 10 and y = -6

How do you solve the system of equation by substitution x plus 2y-2 3x plus 4y6?

Description : How do you solve the system of equation by substitution x plus 2y-2 3x plus 4y6?

Last Answer : If you mean x+2y = -2 and 3x+4y = 6 then by solving thesimultaneous equations by substitution x = 10 and y = -6

How To Solve A Function F(x) Has These Properties The Domain Of F Is The Set Of Natural Numbers F (1)1 F (x plus 1)f(x) plus 3x(x plus 1) plus 1 A. Determine F (2) F(3) F (4) F (5) F(6) THANKS!!!!!!?

Description : How To Solve A Function F(x) Has These Properties The Domain Of F Is The Set Of Natural Numbers F (1)1 F (x plus 1)f(x) plus 3x(x plus 1) plus 1 A. Determine F (2) F(3) F (4) F (5) F(6) THANKS!!!!!!?

Last Answer : The function (sequence generator) f(x) with x∈ℕ has been defined as a recursive function (sequence), with the initial value defined for some x, ie starting form some some natural number (in this case 1), the value of the function (sequence) is ... (4 + 1) = f(4) + ...f(6) = f(5 + 1) = f(5) + ...

Let u = (log2x)^2 – 6(log2x) + 12, where x is a real number. Then the equation x^u = 256 has : -Maths 9th

Description : Let u = (log2x)^2 – 6(log2x) + 12, where x is a real number. Then the equation x^u = 256 has : -Maths 9th

Last Answer : ⇒ u=(log2 x)2−log2 x+12 ⇒ We can take log2 x=y ⇒ Then equation becomes y2−6y+12=u ⇒ Given that xu=256 Applying log we get, ⇒ ulog2 x=8 ∴ u=log2 x8 =y8 So our equation becomes, ⇒ y2−6y+12=y8 ⇒ ... We get y=2 ⇒ So, log2 x=2 ⇒ x=22 ∴ x=4 ∴ The given equation has exactly one solution for x

solve the following inequality: 38 < 4x + 3 + 7 – 3x. -General Knowledge

Description : solve the following inequality: 38 < 4x + 3 + 7 – 3x. -General Knowledge

Last Answer : 38 38 x > 38 - 10 x > 28

Solve for x: Sol. 3x/7 + 2/7 + 4(x + 1)/5 = 2/3(2x + 1) -Maths 9th

Description : Solve for x: Sol. 3x/7 + 2/7 + 4(x + 1)/5 = 2/3(2x + 1) -Maths 9th

Last Answer : Solution :-

Solve these following equations: (i) 3x + 3 = 15 (ii) 2y + 7 =19 -Maths 9th

Description : Solve these following equations: (i) 3x + 3 = 15 (ii) 2y + 7 =19 -Maths 9th

Last Answer : answer:

Solve the following inequalities `(i) log_(5)(3x-1) lt 1` `(ii) (log_(.5)x)^(2)+log_(.5)x-2 le 0` `(iii) log_(3)(x+1)+log_(3)(x+7) ge 3` `(iv)log_(1//

Description : Solve the following inequalities `(i) log_(5)(3x-1) lt 1` `(ii) (log_(.5)x)^(2)+log_(.5)x-2 le 0` `(iii) log_(3)(x+1)+log_(3)(x+7) ge 3` `(iv)log_(1//

Last Answer : Solve the following inequalities `(i) log_(5)(3x-1) lt 1` `(ii) (log_(.5)x)^(2)+log_(.5)x-2 le 0` `(iii) ... `(iv)log_(1//2)log_(3)(x^(2)+5)+1 le 0`

Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Description : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Last Answer : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) ... -5) lt 0` `(viii) |x-1|+|x-2|+|x-3| le 6`

Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Description : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Last Answer : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Solve for `x : 3x + 5 gt 7`

Description : Solve for `x : 3x + 5 gt 7`

Last Answer : Solve for `x : 3x + 5 gt 7` A. `x gt 3//2` B. `x gt 2//3` C. `x lt 3//2` D. `x lt 2//3`

Evaluate x if log3 (3 + x) + log3 (8 – x) – log3 (9x – 8) = 2 – log39 -Maths 9th

Description : Evaluate x if log3 (3 + x) + log3 (8 – x) – log3 (9x – 8) = 2 – log39 -Maths 9th

Last Answer : (c) 4log3 (3 + x) + log3 (8 - x) - log3 (9x - 8) = 2 - log39 ⇒ log3 (3 + x) + log3 (8 - x) - log3 (9x - 8) + log39 = 2⇒ log3 \(\bigg[rac{(3+x)(8-x)(9)}{(9x-8)}\bigg]=2\)⇒ \(rac{9(24+8x-3x-x^2)}{(9x- ... = 9x - 8 ⇒ x2 + 4x - 32 = 0 ⇒ (x + 8) (x - 4) = 0 ⇒ x = - 8, 4. Taking the positive value x = 4.

If 1, log9 (3^(1–x) + 2) and log3 (4.3^x –1) are in A.P., then x is equal to -Maths 9th

Description : If 1, log9 (3^(1–x) + 2) and log3 (4.3^x –1) are in A.P., then x is equal to -Maths 9th

Last Answer : (d) log3\(\big(rac{3}{4}\big)\) 1, log9 (31 - x + 2), log3 (4.3x -1) are in A.P. ⇒ log33 , log3 (31- x + 2)1/2, log3 (4.3x - 1) are in A.P. ⇒ 3, (31 - x + 2)1/2, (4.3x - 1) are in G.P.\ ... (rac{1}{3}\), \(rac{3}{4}\)∴ Rejecting the negative value, we have 3x = \(rac{3}{4}\)⇒ x = log3\(rac{3}{4}.\)

Evaluate log3 81.

Description : Evaluate log3 81.

Last Answer : Solution:

`lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))=`_______.

Description : `lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))=`_______.

Last Answer : `lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))=`_______.

3x+4yplease solve it?

Description : 3x+4yplease solve it?

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Description : Solve: `(x^2 - 3x)^2 - 16 (x^2-3x) -36 =0`

Last Answer : Solve: `(x^2 - 3x)^2 - 16 (x^2-3x) -36 =0`

Solve the following rational in equalities `(i) ((x-1)(x+2))/((x-3)(x+3)) lt 0` `(ii) ((1-x)^(3)(x+2)^(4))/((x+9)^(2)(x-8))ge0` `(iii) ((x^(2)-3x+1)^(

Description : Solve the following rational in equalities `(i) ((x-1)(x+2))/((x-3)(x+3)) lt 0` `(ii) ((1-x)^(3)(x+2)^(4))/((x+9)^(2)(x-8))ge0` `(iii) ((x^(2)-3x+1)^(

Last Answer : Solve the following rational in equalities `(i) ((x-1)(x+2))/((x-3)(x+3)) lt 0` `(ii) ((1-x)^(3)(x+2)^(4 ... ` `(vi) 1 lt (3x^(2)-7x+8)/(x^(2)+1) le2`

Solve : `(5x -2)/(3) + (4x+3)/(2) = (3x+19)/(2)`

Description : Solve : `(5x -2)/(3) + (4x+3)/(2) = (3x+19)/(2)`

Last Answer : Solve : `(5x -2)/(3) + (4x+3)/(2) = (3x+19)/(2)`

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Description : Solve : `(sqrt(10+3x)+sqrt(10-3x))/(sqrt(10+3x)-sqrt(10-3x))=3.`

Last Answer : Solve : `(sqrt(10+3x)+sqrt(10-3x))/(sqrt(10+3x)-sqrt(10-3x))=3.`

What is the solution set of the equation x squared plus 3x - 46?

Description : What is the solution set of the equation x squared plus 3x - 46?

Last Answer : 49

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Description : What is 3x plus 14 5(x plus 1)?

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Description : What is 2x plus 3y equals 17 and 3x minus 2y equals 0.5?

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What are the points of intersection between the line 3x -y equals 5 and the curve 2x squared plus y squared equals 129?

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Last Answer : If: 3x-y = 5 then y^2 = (3x_5)^2 => 9x^2 -30x+25If: 2x^2 + y^2 = 129 then y^2 = 129-2x^2So: 9x^2 -30x+25 = 129-2x^2Transposing terms: 11x^2 -30x -104 = 0Factorizing the above: (11x- ... x = 52/11 or x= -2By substituting x into the original equation intersections areat: (52/11, 101/11) and (-2, -11)

What are the values of x y and k when the line y equals 3x plus 1 is a tangent to the circle x squared plus y squared equals k?

Description : What are the values of x y and k when the line y equals 3x plus 1 is a tangent to the circle x squared plus y squared equals k?

Last Answer : If y = 3x + 1 is a tangent to x² + y² = k (k > 0 since it isa square), then where they meet has a repeated root; they meetat:x² + (3x + 1)² = k→ x² + 9x² + 6x + 1 - k = 0→ 10x² + 6x + (1 - k) = 0This is the ... 3/10→ y = 3 -3/10 + 1 = 9/10 + 1 = 1/10→ point of contact is (-3/10, 1/10) with k = 1/10

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Description : If f(x) 3x plus 10x and g(x) 2x and ndash 4 find (f and ndash g)(x).?

Last Answer : Feel Free to Answer

Is 2(6-3x) plus x equivalent to 2(3x) plus x?

Description : Is 2(6-3x) plus x equivalent to 2(3x) plus x?

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What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Description : What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Last Answer : If you mean 3x+2y = -5 and -2x+3y = -5 then they are straightline equations

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Description : What is (3x plus 5) plus (-8x-10)?

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Description : What is 7x(3x plus x) when x8?

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What of the binomials below is a factor of this trinomial x2 plus 3x - 4?

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What is (3x plus 5) plus (-8x-10)?

Description : What is (3x plus 5) plus (-8x-10)?

Last Answer : It is equivalent to: 3x+6+5 = 3x+11

What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Description : What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

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Description : What is the minimum value of 3x plus 5y in the feasible region?

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Description : negative 3 x plus 15 equals 18 Can someone solve this for me Thank you?

Last Answer : x = -1Since -3(-1) + 15 = 18

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Last Answer : Without an equality sign the given expression is not an equationand so therefore a solution is not possible.

How xy plus x plus y plus 1 will solve?

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Description : How do you solve 32 plus 32 and divide2?

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Description : What Solve a divided by 5 plus 3 equals 8?

Last Answer : a/5 + 3 = 8a/5 = 5a = 25