Evaluate x if log3 (3 + x) + log3 (8 – x) – log3 (9x – 8) = 2 – log39 -Maths 9th

Evaluate x if log3 (3 + x) + log3 (8 – x) – log3 (9x – 8) = 2 – log39 -Maths 9th
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(c) 4log3 (3 + x) + log3 (8 – x) – log3 (9x – 8) = 2 – log39 ⇒ log3 (3 + x) + log3 (8 – x) – log3 (9x – 8) + log39 = 2⇒ log3 \(\bigg[rac{(3+x)(8-x)(9)}{(9x-8)}\bigg]=2\)⇒ \(rac{9(24+8x-3x-x^2)}{(9x-8)}=3^2=9\)⇒ –x2 + 5x + 24 = 9x – 8 ⇒ x2 + 4x – 32 = 0 ⇒ (x + 8) (x – 4) = 0 ⇒ x = – 8, 4. Taking the positive value x = 4.
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