Description : Let `f : [-1, -1/2] rarr [-1, 1]` is defined by `f(x)=4x^(3)-3x`, then `f^(-1) (x)` is
Last Answer : Let `f : [-1, -1/2] rarr [-1, 1]` is defined by `f(x)=4x^(3)-3x`, then `f^(-1) (x)` is A. `cos (1/3 ... /3+1/3 cos^(-1) x)` D. `sin (1/3 sin^(-1) x)`