Use the graph to solve the system of linear equations x - y=4 4x + y=1?

Use the graph to solve the system of linear equations x - y=4 4x + y=1?
by

1 Answer

Answer :

x=4+y4x+y=1 = 4(4+y)+y=116+4y+y=116+5y=15y=-15y=-3x=4+y = x=4+(-3)x=1
by

Related questions

What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Description : What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Last Answer : (a) 3,2

What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Description : What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Last Answer : (a) 3,2

A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

In the linear equation y = 4x + 13, if x is the number of hours a labourer is on work and y are his wages in rupees then draw the graph. Also find the wages when work is done for 6 hours. -Maths 9th

Description : In the linear equation y = 4x + 13, if x is the number of hours a labourer is on work and y are his wages in rupees then draw the graph. Also find the wages when work is done for 6 hours. -Maths 9th

Last Answer : when the work is done for 6 hours x=6 y=4(6)+13 y=24+13 y=37 the labourer gets Rs.37 if he works for 6hrs

Solve the following equations (where `[*]` dentoes greatest integer function and `{*}` represent fractional part function) `(i) 2[x]+3[x]=4x-1` `(ii)

Description : Solve the following equations (where `[*]` dentoes greatest integer function and `{*}` represent fractional part function) `(i) 2[x]+3[x]=4x-1` `(ii)

Last Answer : Solve the following equations (where `[*]` dentoes greatest integer function and `{*}` represent fractional part function) ... }` `(iii) [x]+2{-x}=3x`

Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`

Description : Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`

Last Answer : Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`

Is this statement true or falseA system of linear equations is a set of two or more equations with the same variables, and the graph of each equation is a line?

Description : Is this statement true or falseA system of linear equations is a set of two or more equations with the same variables, and the graph of each equation is a line?

Last Answer : 1

53. While plotting constraints on a graph paper, terminal points on both the axes are connected by straight line because a. The resources are limited in supply b. The objective function as a linear function c. The constraints are linear equations or inequalities d. All of the above

Description : 53. While plotting constraints on a graph paper, terminal points on both the axes are connected by straight line because a. The resources are limited in supply b. The objective function as a linear function c. The constraints are linear equations or inequalities d. All of the above

Last Answer : c. The constraints are linear equations or inequalities

What are some fast ways to solve a system of 3 linear equations with this special form?

Description : What are some fast ways to solve a system of 3 linear equations with this special form?

Last Answer : Perhaps an algebraic matrix ?

If you're asked to solve a system of equations in which there is no linear equation to start with you can sometimes begin by isolating and substituting a variable that is squared in both equations?

Description : If you're asked to solve a system of equations in which there is no linear equation to start with you can sometimes begin by isolating and substituting a variable that is squared in both equations?

Last Answer : 1

Draw the graph of the following equations (1) Y =3x+2 (b) Y=x -Maths 9th

Description : Draw the graph of the following equations (1) Y =3x+2 (b) Y=x -Maths 9th

Last Answer : This answer was deleted by our moderators...

For making graph of equations `|y|=|f(|x|)|` through `y=f(x)` which order of step is right among the following order of Step `I : y=f(|x|)` (replace `

Description : For making graph of equations `|y|=|f(|x|)|` through `y=f(x)` which order of step is right among the following order of Step `I : y=f(|x|)` (replace `

Last Answer : For making graph of equations `|y|=|f(|x|)|` through `y=f(x)` which order of step is right among the following ... , `II`, `I` D. `III`, `I`, `II`

What graph would best represent the equation y -4x - 6?

Description : What graph would best represent the equation y -4x - 6?

Last Answer : If you mean y = -4x-6 then it is a straight line equation thatcan be graphed on the Cartesian plane

What points on a graph would represent y 4x?

Description : What points on a graph would represent y 4x?

Last Answer : Need answer

Which graph shows the line y=4x-2?

Description : Which graph shows the line y=4x-2?

Last Answer : 6

How many linear equations in x and y can be satisfied by x = 1 and y = 2 ? -Maths 9th

Description : How many linear equations in x and y can be satisfied by x = 1 and y = 2 ? -Maths 9th

Last Answer : (c) Let the linear equation be ax + by + c = 0. On putting x = 1 and y = 2, in above equation we get =s a + 2b + c = 0, where a, b and c, are real number Here, different values of a, b and ... a + 2b + c = 0. Hence, infinitely many linear equations in x and yean be satisfied by x = 1 and y = 2.

Draw the graphs of linear equations y = x and y = – x on the same Cartesian plane. -Maths 9th

Description : Draw the graphs of linear equations y = x and y = – x on the same Cartesian plane. -Maths 9th

Last Answer : The given equation is y = x. To draw the graph of this equations, we need atleast two points lying on the given line. For x = 1, y = 1, therefore (1,1) satisfies the linear equation y = x. For x = 4, y = 4, ... of y = - x. We observe that, the line y = x and y = - x intersect at the point 0(0, 0).

How many linear equations in x and y can be satisfied by x = 1 and y = 2 ? -Maths 9th

Description : How many linear equations in x and y can be satisfied by x = 1 and y = 2 ? -Maths 9th

Last Answer : (c) Let the linear equation be ax + by + c = 0. On putting x = 1 and y = 2, in above equation we get =s a + 2b + c = 0, where a, b and c, are real number Here, different values of a, b and ... a + 2b + c = 0. Hence, infinitely many linear equations in x and yean be satisfied by x = 1 and y = 2.

Draw the graphs of linear equations y = x and y = – x on the same Cartesian plane. -Maths 9th

Description : Draw the graphs of linear equations y = x and y = – x on the same Cartesian plane. -Maths 9th

Last Answer : The given equation is y = x. To draw the graph of this equations, we need atleast two points lying on the given line. For x = 1, y = 1, therefore (1,1) satisfies the linear equation y = x. For x = 4, y = 4, ... of y = - x. We observe that, the line y = x and y = - x intersect at the point 0(0, 0).

How many linear equations satisfy x = 2 and y = -3? -Maths 9th

Description : How many linear equations satisfy x = 2 and y = -3? -Maths 9th

Last Answer : Solution :- Infinitely many equations.

If (x, y) is a solution of the following pair of linear equations in two variables, then the value of expression (√ is: x + 2y = 4 and 3x - y = 5 (a) 2 (b) 3 (c) 4 (d) √

Description : If (x, y) is a solution of the following pair of linear equations in two variables, then the value of expression (√ is: x + 2y = 4 and 3x - y = 5 (a) 2 (b) 3 (c) 4 (d) √2

Last Answer : (a) 2

"Ravi is 10 years older than Rehan. Five years ago, one-seventh of Ravi's age was equal to one-fifth of Rehan's age." If Rehan's age be 'x' years and Ravi's age be 'y' years, which of the following pair of linear equations is describing it algebraically? (a) x - y = 10 and 7x - 5y + 10 = 0 (b) y -x = 10 and 5y -7x + 10 = 0 (c) x + y = 10 and 7x + 5y - 10 = 0 (d) x - y = -10 and 7y - 5x + 10 = 0

Description : "Ravi is 10 years older than Rehan. Five years ago, one-seventh of Ravi's age was equal to one-fifth of Rehan's age." If Rehan's age be 'x' years and Ravi's age be 'y' years, which of the following pair of linear equations is ... y = 10 and 7x + 5y - 10 = 0 (d) x - y = -10 and 7y - 5x + 10 = 0

Last Answer : (b) y -x = 10 and 5y -7x + 10 = 0

Solve the following equations for x and y. log100 |x+y| = 1/2, -Maths 9th

Description : Solve the following equations for x and y. log100 |x+y| = 1/2, -Maths 9th

Last Answer : (b) \(\bigg(rac{10}{3},rac{20}{3}\bigg)\). (+ 10, 20) log100 |x+y| = \(rac{1}{2}\) ⇒ |x + y| = 100\(^{rac{1}{2}}\)⇒ |x + y| = 10 as (-10 is inadmissible) ...(i) log10y - log10| x | = log1004⇒ log10 ... x < 0, then x = 10.∴ If x = \(rac{10}{3}\), then y = \(rac{20}{3}\) and if x = 10, y = 20.

A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Description : A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Last Answer : Clearly, line a is parallel to X-axis at a distance of 1 unit in positive direction of Y-axis, therefore its equation is y = 1. Also, if we draw the graph of line 2x + 3y = 6, then its graph should intersect X - axis at (3,0 ... Base Height = 1/2 BC AC = 1/2 1 3 / 2 = 3 / 4 sq unit.

A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Description : A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Last Answer : Clearly, line a is parallel to X-axis at a distance of 1 unit in positive direction of Y-axis, therefore its equation is y = 1. Also, if we draw the graph of line 2x + 3y = 6, then its graph should intersect X - axis at (3,0 ... Base Height = 1/2 BC AC = 1/2 1 3 / 2 = 3 / 4 sq unit.

Find the coordinate where the linear equation 4x - 23 y = 7 meets at y-axis. -Maths 9th

Description : Find the coordinate where the linear equation 4x - 23 y = 7 meets at y-axis. -Maths 9th

Last Answer : 4x-2=-7*3y 4x+21y=2 The equation meets y axis when x=0 4.0+21y=2 y=21/2 Hence , the equation meets y-axis at (0,21/2)

What is y=4x-3 in Linear Equation?

Description : What is y=4x-3 in Linear Equation?

Last Answer : y = 4x-3 is already a linear equation. The slope is 4 and the y-intercept is -3

The graph of the linear equation y = x passes through the point. -Maths 9th

Description : The graph of the linear equation y = x passes through the point. -Maths 9th

Last Answer : (c) The linear equation y = x has same value of x and y-coordinates are same. Therefore, the point (1,1) must lie on the line y = x.

The graph of the linear equation y = x passes through the point. -Maths 9th

Description : The graph of the linear equation y = x passes through the point. -Maths 9th

Last Answer : (c) The linear equation y = x has same value of x and y-coordinates are same. Therefore, the point (1,1) must lie on the line y = x.

Determine the point on the graph of the linear equation x + y = 6, whose ordinate is 2 times its abscissa. -Maths 9th

Description : Determine the point on the graph of the linear equation x + y = 6, whose ordinate is 2 times its abscissa. -Maths 9th

Last Answer : Solution :-

Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th

Description : Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th

Last Answer : hope it helps

graph the linear equation y=-2 x +1?

Description : graph the linear equation y=-2 x +1?

Last Answer : -1

A bar graph is drawn to the scale 1 cm = 4x units .The length of the bar represeting a quantity 1000 units is 1.25 cm . Find x

Description : A bar graph is drawn to the scale 1 cm = 4x units .The length of the bar represeting a quantity 1000 units is 1.25 cm . Find x

Last Answer : A bar graph is drawn to the scale 1 cm = 4x units .The length of the bar represeting a quantity 1000 units is 1.25 cm . Find x

which graph shows the solution to the system of linear inequalities y>2x+1 y?

Description : which graph shows the solution to the system of linear inequalities y>2x+1 y?

Last Answer : 3

Solve for x: 5(4x + 3) = 3(x -2) -Maths 9th

Description : Solve for x: 5(4x + 3) = 3(x -2) -Maths 9th

Last Answer : Solution :-

how do i solve 4x-9=k for x?

Description : how do i solve 4x-9=k for x?

Last Answer : 4x-9=k4x=k+9Divide by 4 to isolate the xx=(1/4)k+(9/4)x=1/4 k+ 9/4

Solve the following inequlities `(i) sqrt(x-1) lt x-3` `(ii) sqrt(x-3) gt sqrt(7-x)` `(iii) sqrt (x^(2)+4x+9) gt x +2` `(iv) 4-x lt sqrt(2x-x^(2))` `(

Description : Solve the following inequlities `(i) sqrt(x-1) lt x-3` `(ii) sqrt(x-3) gt sqrt(7-x)` `(iii) sqrt (x^(2)+4x+9) gt x +2` `(iv) 4-x lt sqrt(2x-x^(2))` `(

Last Answer : Solve the following inequlities `(i) sqrt(x-1) lt x-3` `(ii) sqrt(x-3) gt sqrt(7-x)` `(iii) sqrt (x^(2)+4x+ ... (ix) (|x+2|-|x|)/(sqrt(8-x^(3))) ge 0`

Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Description : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Last Answer : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Description : The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.

The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Description : The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Last Answer : (d) Since, the graph of linear equation 2x + 3y = 6 cuts the Y-axis. So, we put x = 0 in the given equation 2x+ 3y = 6, we get 2 x 0+ 3y = 6 ⇒ 3y = 6 y = 2. Hence, at the point (0, 2), the given linear equation cuts the Y-axis.

The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Description : The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.

The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Description : The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Last Answer : (d) Since, the graph of linear equation 2x + 3y = 6 cuts the Y-axis. So, we put x = 0 in the given equation 2x+ 3y = 6, we get 2 x 0+ 3y = 6 ⇒ 3y = 6 y = 2. Hence, at the point (0, 2), the given linear equation cuts the Y-axis.

At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Description : At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Last Answer : hope its clear

What is the equation to a linear equation with the solution x 3 and some equations using x 3 for the solution?

Description : What is the equation to a linear equation with the solution x 3 and some equations using x 3 for the solution?

Last Answer : Need answer

Which of the following pair of linear equations represent the two parallel tracks of the railway line? a) x-2y-4=0 and 2x + 4y - 12 = 0 c) 2x + 4y -12 = 0 and x +2y-4=0 b) x +2y-4=0 and 2x + 4y +12 = 0 d) 2x + 4y + 12 = 0 and x-2y-4=0

Description : Which of the following pair of linear equations represent the two parallel tracks of the railway line? a) x-2y-4=0 and 2x + 4y - 12 = 0 c) 2x + 4y -12 = 0 and x +2y-4=0 b) x +2y-4=0 and 2x + 4y +12 = 0 d) 2x + 4y + 12 = 0 and x-2y-4=0

Last Answer : c) 2x + 4y -12 = 0 and x +2y-4=0

In the following figure ABCD is a cyclic quadrilateral, the sum of degree measures of ∠A and ∠D is: (SOURCE: Fig. 3.7, Exercise 3.7, Chapter 3, PAIR of LINEAR EQUATIONS in TWO VARIABLES, NCERT, Class X) (a) 120° (b) 180° (c) 230°(d) 250°

Description : In the following figure ABCD is a cyclic quadrilateral, the sum of degree measures of ∠A and ∠D is: (SOURCE: Fig. 3.7, Exercise 3.7, Chapter 3, PAIR of LINEAR EQUATIONS in TWO VARIABLES, NCERT, Class X) (a) 120° (b) 180° (c) 230°(d) 250°

Last Answer : (c) 230°

Is there a general way to solve equations involving both a multiple of x and a power of x?

Description : Is there a general way to solve equations involving both a multiple of x and a power of x?

Last Answer : Do they know about logarithms yet?

Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1)` `(iii) (log_(10)(100x))^(2)+(log_(10)(10

Description : Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1)` `(iii) (log_(10)(100x))^(2)+(log_(10)(10

Last Answer : Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1 ... 1)` `(v)5^(2x)=3^(2x)+2.5^(x)+2.3^(x)`

Solve the following equations `(i) sgn({[x]})=0` `(ii) sgn(x^(2)-2x-8)=-1` `(iii)sgn((x^(2)-5x+4)/({x}))=-1`

Description : Solve the following equations `(i) sgn({[x]})=0` `(ii) sgn(x^(2)-2x-8)=-1` `(iii)sgn((x^(2)-5x+4)/({x}))=-1`

Last Answer : Solve the following equations `(i) sgn({[x]})=0` `(ii) sgn(x^(2)-2x-8)=-1` `(iii)sgn((x^(2)-5x+4)/({x}))=-1`

My TI-83 won't graph equations, instead telling me that I have invalid dimensions. Any ideas for fixing it?

Description : My TI-83 won't graph equations, instead telling me that I have invalid dimensions. Any ideas for fixing it?

Last Answer : answer:User error. http://www.tc3.edu/instruct/sbrown/ti83/funcgrf.htm