How do you write 72.50 in word form?

How do you write 72.50 in word form?
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Answer :

seventy-two and five tenths
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Is blood pressure of 78 over 36 with a pulse of 50 after eating too low for a 72 year old male?

Description : Is blood pressure of 78 over 36 with a pulse of 50 after eating too low for a 72 year old male?

Last Answer : yes your blood pressure should be 120/80 and your pulse should be 60 or above. I would go to the doctor. I am an RN

X Ltd. forfeited 20 shares of Rs. 10 each on which Rs. 6 per share were paid. If out of these shares, 8 shares were reissued to Ram as fully paid up on payment of Rs. 5•50 per share, the amount that will remain standing to the credit of Share Forfeited A/c will be– (A) Rs. 48 (B) Rs. 72 (C) Rs. 84 (D) Rs. 120

Description : X Ltd. forfeited 20 shares of Rs. 10 each on which Rs. 6 per share were paid. If out of these shares, 8 shares were reissued to Ram as fully paid up on payment of Rs. 5 50 per share, the amount that will remain standing ... Share Forfeited A/c will be- (A) Rs. 48 (B) Rs. 72 (C) Rs. 84 (D) Rs. 120

Last Answer : Answer: Rs. 120

The input terminal impedance at the center of a folded dipole antenna is A. 72 Ω B. 300 Ω C. 50 Ω D. 73 Ω

Description : The input terminal impedance at the center of a folded dipole antenna is A. 72 Ω B. 300 Ω C. 50 Ω D. 73 Ω

Last Answer : B. 300 Ω

What is the input terminal impedance at the center if a folded dipole antenna? A. 300 ohms B. 72 ohms C. 50 ohms D. 450 ohms

Description : What is the input terminal impedance at the center if a folded dipole antenna? A. 300 ohms B. 72 ohms C. 50 ohms D. 450 ohms

Last Answer : A. 300 ohms

The distance b/w Earth and Moon is------? A. 3,50,000km B. 3,60,100km C. 3,72,000km D. 3,84,400km (Answer)

Description : The distance b/w Earth and Moon is------? A. 3,50,000km B. 3,60,100km C. 3,72,000km D. 3,84,400km (Answer)

Last Answer : D. 3,84,400km (Answer)

The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Description : The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Last Answer : (D) 72,000

The population of a city in 2000 is 50,000. The average increase in population over last 8 decades is 7500 and average incremental increase during 8 decades is 750. The population of the city based on incremental method, in the year 2020 will be (A) 55,000 (B) 60,500 (C) 66,500 (D) 72,500

Description : The population of a city in 2000 is 50,000. The average increase in population over last 8 decades is  7500 and average incremental increase during 8 decades is 750. The population of the city based  on incremental method, in ... (A) 55,000  (B) 60,500  (C) 66,500  (D) 72,500 

Last Answer : (C) 66,500

The specific gravity of marble, is (A) 2.50 (B) 2.60 (C) 2.66 (D) 2.72

Description : The specific gravity of marble, is (A) 2.50 (B) 2.60 (C) 2.66 (D) 2.72

Last Answer : Answer: Option D

The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

The next term in the series 2, 5, 10, 17, 26, 37, ? is: (A) 50 (B) 57 (C) 62 (D) 72

Description : The next term in the series  2, 5, 10, 17, 26, 37, ? is: (A) 50 (B) 57 (C) 62 (D) 72

Last Answer : Answer: A

The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to complete the project using the effort formula of basic COCOMO given below: E = a(KLOC)b Assume that the values of a and b are 2.5 and 1.0 respectively. (A) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Description : The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to ... ) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Last Answer : (C) 62.5 person months 

A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Description :  A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Last Answer : Answer: B 25 paise = 25/100 Rs, 50 paise = 50/100 Rs So value ratio of these coins become = 3*(25/100) : 4*(50/100) : 6*(1) = 3/4 : 2 : 6 = 3 : 8 : 24 So 25 paise coins value= [3/(3+8+24)] * ... 100/50) = 144 So 1 paise coins value= [24/(3+8+24)] * 315 = Rs 216, so coins = 215 * (100/100) = 216

A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Description : A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Last Answer : Answer: B Sol. Let the number of one-rupee coins, 50-paise coins and 25-paise coins be 2k, 3k and 5k, respectively. ∴ 2k × 1 + 3k × 0.50 + 5k × 0.25 = 114 ⇒ 2k + 1.50k + 1.25k = 114  ⇒ 4.75k = 114 ⇒ k = 24. 50 paise value = 1.5x = 1.5*24 = 36

The average age of 160 boys in a class is 58 yrs. The average group of 30 boys in the class is 42 yrs and the average of another group of 50 boys in the class is 36 years. What is the average age of the remaining boys? A) 72.58 B) 74.25 C) 77.75 D) 75.68

Description : The average age of 160 boys in a class is 58 yrs. The average group of 30 boys in the class is 42 yrs and the average of another group of 50 boys in the class is 36 years. What is the average age of the remaining boys? A) 72.58 B) 74.25 C) 77.75 D) 75.68 

Last Answer : C) Total age of 160 boys = 160* 58= 9280 total age of 30 boys = 30 * 42= 1260 total age of next 50boys = 50 * 36= 1800 average of the remaining boys = [(9280-{1260+1800})/[160 - (30 + 50)] =>9280-3060/80 =>6220/80 =77.75yrs

A students maks were wrongly entered as 72 instead of 52. Due to that the average marks for the class got increased by half. The number of students in the class is. A) 50 B) 56 C) 46 D) 40

Description : A students maks were wrongly entered as 72 instead of 52. Due to that the average marks for the class got increased by half. The number of students in the class is. A) 50 B) 56 C) 46 D) 40

Last Answer : D)  Let there be y students in the class Total increase in marks = y *1/2 = y/2 Therefore y/2 = (72 – 52) y/2 = 20 y = 40

How do you write 72 100 asapercentage?

Description : How do you write 72 100 asapercentage?

Last Answer : If you mean 72/100 then as a percentage it is 72%

How do you write 72.5 as a fraction?

Description : How do you write 72.5 as a fraction?

Last Answer : 72.5 / 1 = 725 / 10 = 145 / 2

In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Description : In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Last Answer : Total ways = 4 ! x 2 ! = 4 × 3 × 2 x 2= 48 Answer: a)

In how many different ways can the letters of the word "POMADE" be arranged in such a way that the vowels occupy only the odd positions? a) 72 b) 144 c) 532 d) 36

Description :  In how many different ways can the letters of the word "POMADE" be arranged in such a way that the vowels occupy only the odd positions? a) 72 b) 144 c) 532 d) 36

Last Answer : Answer: D)  There are 6 different letters in the given word, out of which there are 3 vowels and 3 consonants.  Let us mark these positions as under:  [1] [2] [3] [4] [5] [6]  Now, 3 vowels can be ... of these arrangements = 3P3  = 3!  = 6 ways.  Therefore, total number of ways = 6 x 6 = 36.