Description : When n cells are joined in parallel combination as shown, the strength of the current `i` is given by
Last Answer : When n cells are joined in parallel combination as shown, the strength of the current `i` is given by A. `(nE) ... ` C. `(E)/(r+Rn)` D. None of these
Description : Four cells, each of emf E and internal resistance r, are connected in series across an external resistance reverse. Then, the current in the external
Last Answer : Four cells, each of emf E and internal resistance r, are connected in series across an external resistance reverse. Then, ... (3r+R)` D. `(2E)/(3r+R)`
Description : A `5 Omega` resistor is connected in series with a parallel combination of n resistors of `6 Omega` each. The equivalent resistance is `7 Omega`. Find
Last Answer : A `5 Omega` resistor is connected in series with a parallel combination of n resistors of `6 Omega ... The equivalent resistance is `7 Omega`. Find n.
Description : Out of five resistance of `ROmega` each 3 are connected in parallel and are joined to the rest 2 in series. Find the resultant resistance.
Last Answer : Out of five resistance of `ROmega` each 3 are connected in parallel and are joined to the rest 2 in series. Find ... `(7//8)ROmega` D. `(8//7)ROmega`
Description : There are n cells, each of emf E and internal resistance r, connected in series with an external resistance R. One of the cells is wrongly connected,
Last Answer : There are n cells, each of emf E and internal resistance r, connected in series with an external resistance R. One of the ... D. `((n-2)E)/((n-2)r+R)`
Description : PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th
Last Answer : hope its clear
Description : Which one of the following is the advantage of connecting two dry cells in parallel instead of in series? Is it because the parallel arrangement: w) gives twice the EMF of one dry cell x) has no ... circuit half as fast as would a single cell z) has half the internal resistance of a single cell
Last Answer : ANSWER: Z -- HAS HALF THE INTERNAL RESISTANCE OF A SINGLE CELL
Description : Two unpedauces given by Z1 = 10 + j5 and Z2 = 8 + j9 are joined in parallel and connected across a voltage of V = 200 + j0. Calculate the circuit current and branch currents. Draw the vector diagram.
Last Answer : Solution: Given, Z1=10+j5, Z2=8+j9, V=200+j0
Description : To limit the current flow through a DC voltmeter to as low a value as possible, the moving coil circuit is provided with a/an _____________. A. high series resistance B. high parallel resistance C. series inductor D. external shunt
Last Answer : Answer: A
Description : Three identical cells each of emf 2 V and unknown internal resistance are connected in parallel. This combination is connected to a `5 Omega` resistor
Last Answer : Three identical cells each of emf 2 V and unknown internal resistance are connected in parallel. ... what is the internal resistance of each cell ?
Description : How would you arrange 64 similar cells each having an emf of 2.0 V and internal resistance `2 Omega` so as to send maximum current through an external
Last Answer : How would you arrange 64 similar cells each having an emf of 2.0 V and internal resistance ` ... current through an external resistance of `8 Omega`.
Description : 24 cells of emf `1.5 V` each having internal resistance of 1 ohm are connected to an external resistance of `1.5` ohms. To get maximum current,
Last Answer : 24 cells of emf `1.5 V` each having internal resistance of 1 ohm are connected to an external ... in series and 4 such rows are connected in parallel
Description : A resistance of `4 Omega` and a wire of length 5 meters and resistance `5 Omega` are joined in series and connected to a cell of e.m.f. `10 V` and int
Last Answer : A resistance of `4 Omega` and a wire of length 5 meters and resistance `5 Omega` are joined in series and connected ... `3.0V` C. `0.67V` D. `1.33V`
Description : Two friends M & N started a business Investing in the ratio of 6 :7 . O joined then after 6 months investing an amount equal to that of N. at the end of the year 30% profit was equal to 105000. What was the amount invested by O? A) 148484 B) 154326 C) 146738 D) 145783
Last Answer : Answer: A) Let the total profit be x Then 30% of x = 105000 X = 105000 * 100/30 X=350000 Let the capitals of M,N,O be Rs. 6x ,7x and 7x respectively. Then, (6x*12) + (7x *12) +(7x *6) = 350000*12 72x +84x +42x = 4200000 198x = 4200000 X=21212 O’s investment = Rs.148484
Description : Three equal resistors connected in series with a source of e m f together dissipate 10 W of power each. What will be the power dissipated if the same resistors are connected in parallel across the same source of e m f? a. 40 W b. 90W c. 100W d. 120W
Last Answer : b. 90W
Description : A resistor of value R/2 is connected in parallel with a resistor of value R/3. The voltage drop across the parallel combination is V. The total current supplied by the voltage source is: w) 2 V/R (read: 2 V over R) x) 3 V/R (read: 3 V over R) y) 4 V/R (read: 4 V over R) z) 5 V/R (read: 5 V over R)
Last Answer : ANSWER: Z -- 5 V/R
Last Answer : Req= (1/1200 +1/560 + 1/2.1)^-1 = 2.1 ohms RT= 2.1 + 7.8 = 9.9 ohms IT = V/R = 24/9.9 = 2.4 A Veq= R I = 2.1 2 ... 7.8 = 12.096 w = 44.928 w _________________________________________ By: Ellis-Junior Kamatjipose [email protected]
Description : A cell which has an emf `1.5` V is connectedin series with an external resistance of `10Omega`. If the potential difference across the cell is `1.25`
Last Answer : A cell which has an emf `1.5` V is connectedin series with an external resistance of `10Omega`. If the potential ... `0.25` C. `1.5` D. `0.3`
Description : A wire of resistance R is cut into ‘n’ equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be – (1) nR (2) R/n (3) n/R (4) R/n²
Last Answer : (4) R/n² Explanation: Since R is directly proportional to length of the wire, when wire is cut into equal parts, then Resistance of each part = R/n
Description : A wire of resistance R is cut into ‘n’ equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be
Last Answer : R/n2
Description : Two batteries A and B each of e.m.f. 2 V are connected in series to an external resistance R = 1 ohm . If the internal resistance of battery A is 1.9
Last Answer : Two batteries A and B each of e.m.f. 2 V are connected in series to an external resistance R = 1 ohm . If the ... V B. `3.8` V C. zero D. `4.8` V
Description : N resistors of each of resistance R when connected in series offer an equivalent resistance of 50 ohm and when reconnected in parallel the effective resistance is 2 ohm the value of R is
Last Answer : 25 ohms
Description : Which of the following statements is true if a 100 watt lamp and a 75 watt lamp are connected in parallel across a 100 volt power supply? A. The 75 watt lamp will draw as much current as the 100 ... Current flow will be the same across each lamp. D. The 75 watt lamp will have a higher resistance.
Last Answer : Answer: D
Description : Which of the following statements is true concerning simple parallel resistance circuits? A. The total current flow equals the sum of the individual currents. B. The total current flow equals the ... resistance. D. The total voltage equals the sum of the individual voltages across each resistance.
Description : Which of the following statements concerning a simple parallel resistance circuit is correct? A. The voltage drop across each resistor is the same. B. The total current flow equals the reciprocal ... resistances. D. The total voltage equals the sum of the individual voltages across each resistance.
Description : The ............ operator preserves unmatched rows of the relations being joined. A) Inner join B) Outer join C) Union D) Union join
Last Answer : B) Outer join
Description : The electrical diagram shown in the illustration shows _____________. EL-0021 A. 'R1', 'R2', and 'R3' are connected is series B. 'R1', 'R2', and 'R3' are connected in parallel C. the voltages measured across ... if 'R1', 'R2' and 'R3' have different values D. the total resistance equals R1 + R2 + R3
Last Answer : Answer: B
Description : Which of the following statements is correct for the illustrated circuit? EL-0020 A. 'R1', 'R2', and 'R3' are connected in series. B. 'R1', 'R2', and 'R3' are connected in parallel. C. The voltages measured across 'R1', 'R2', and 'R3' are equal. D. The total resistance equals 1/R1 + 1/R2 + 1/R
Description : The line by which all the least cost combination points are joined to each other
Last Answer : Ans. Expansion Path
Description : Two resistances are joined in parallel whose resultant is `6//8 ohm`. One of the resistance wire is broken and the effective resistance becomes `2 Ome
Last Answer : Two resistances are joined in parallel whose resultant is `6//8 ohm`. One of the resistance wire is broken and the ... /5` B. 2 C. `6//5` D. 3
Description : A series combination of resistance 100 ohm and capacitance 50µf is connected in series to a 230 V, 50HZ supply. Calculate (i) Capacitive reactance (ii) Current (iii) Power factor (iv) Power consumed
Last Answer : For RC series circuit
Description : Two cells, having the same emf, are connected in series through an external resistance `R`. Cells have internal resistance `r_(1)` and `r_(2) (r_(1) g
Last Answer : Two cells, having the same emf, are connected in series through an external resistance `R`. Cells have internal resistance ... D. `(r_(1)+r_(2))/(2)`
Description : Two wire of the same meta have same length, but their cross-sections are in the rati `3:1` . They are joined in series. The resistance of thicker wire
Last Answer : Two wire of the same meta have same length, but their cross-sections are in the rati `3:1` . They are ... )Omega` C. `(5)/(2)Omega` D. `100Omega`
Description : Five cells, each with an e.m.f. of 2V and internal resistance of 0.5Ω are connected in series. The resulting battery will have
Last Answer : Five cells, each with an e.m.f. of 2V and internal resistance of 0.5Ω are connected in series. The resulting battery will have An e.m.f. of 10V and an internal resistance of 2.5 Ω
Description : A capacitor and a coil are connected in series. The capacitor is charged and allowed to discharge through the coil. The current that will then flow through the capacitor-coil combination will do ... but diminish steadily to zero z) oscillate at high frequency at first but then at slower frequency
Last Answer : ANSWER: Y -- OSCILLATE BUT DIMINISH STEADILY TO ZERO
Description :
Last Answer : By using current rule
Description : 10 cells, each of internal resistance `0.5 Omega` and 1.2 V emf are connected (a) all in series and (b) all in paralle. Calculate the current sent in
Last Answer : 10 cells, each of internal resistance `0.5 Omega` and 1.2 V emf are connected (a) all in ... each case through a wire of resistance `0.8 Omega`.
Description : A 24 volt battery supplies three devices wired in parallel that each have a resistance of 9 ohms. What is the voltage drop across each device?
Last Answer : A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
Description : Two infinitely long parallel conductors in vacuum any separated 1 metre between centers >then a current of 1 ampere flows the. uk each conductor, produce on each other a force of (a) 2 x 1(T2 N/m) (b) 2 x KT3 N/m (c) 2 x 10"5 N/m (d) 2x 1(T7 N/m)
Last Answer : (d) 2x 1(T7 N/m)
Description : The solution to a transportation problem with ‘m’ rows and ‘n’ columns is feasible if the number of positive allocations are: a. m + n b. m x n c. m +n – 1 d. m +n + 1
Last Answer : c. m +n – 1
Description : Consider the following conditions : (a) The solution must be feasible, i.e. it must satisfy all the supply and demand constraints. (b) The number of positive allocations must be equal to m+n-1, where m is the number of rows and n is ... B) (a) and (c) only (C) (b) and (c) only (D) (a), (b) and (c)
Last Answer : (D) (a), (b) and (c)
Description : Which of the following is a combination of columns and rows ?
Last Answer : Database consists of columns and rows.
Description : In a DC series circuit, all the conductors have the same ____________. A. power expended in them B. voltage drop across them C. resistance to current flow D. current passing through them
Description : If current of 20 mA is passing through op-amp and voltage drop across series resistor is 10 V then value of resistance is A. 500Ω B. 400Ω C. 300Ω D. 200Ω
Last Answer : 500Ω
Description : Three identical, each of emf 2 V and internal resistance `0.2 Omega` are connected in series to an external resistor of `7.4 Omega`. Calculate the cur
Last Answer : Three identical, each of emf 2 V and internal resistance `0.2 Omega` are connected in series to ... 7.4 Omega`. Calculate the current in the circuit.
Description : For two shafts joined in parallel, the --------------- in each shaft is same. a. shear stress. b. Angle of twist c. torque d. torsional stress.
Last Answer : b. Angle of twist
Description : `6Omega` and `12Omega` resistors are connected in parallel. This combination is connected in series with 10 V battery and `6 Omega` resistor. What is
Last Answer : `6Omega` and `12Omega` resistors are connected in parallel. This combination is connected in series with 10 V battery and ... 4 V B. 16 V C. 2 D. 8 V
Description : ___ has a series RC combination in one arm and a parallel RC combination in the adjoining arm and used as a notch filter in harmonic distortion analyzer.
Last Answer : wein bridge
Description : M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days
Last Answer : C Work done by M in 8 days = 1/40*8 =1/5 Remaining work = 1-1/5 = 4/5 (M+N)’s 1 day work = 1/40 + 1/24 =(3+5)/120 =8/120 =1/15 Now 1/15 work is done by M & N in 1 day. So 4/5 work will be done by X and Y is, =15 / 1 * 4/5 =12 days Hence total time taken = 12+8 = 20 days
Description : To draw the maximum current from a combination of cells, how should be the cells be grounded ?
Last Answer : To draw the maximum current from a combination of cells, how should be the cells be ... of internal and external resistance D. Mixed grouping