A metro train runs from station A to B to C. It takes 4 minutes in travelling from station A to station B. The train halts at station B for 20 s.

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A metro train runs from station A to B to C. It takes 4 minutes in travelling from station A ... Calculate the distance between stations A, B, and C.

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Last Answer : ANSWER: A Explanation:  Length of the train = 200 m  Man walking speed = 10 km/hr  Let the speed of the train be x' km/hr  Speed of the train relative to man = (x +10) km/hr  Convert km/hr into m/s   ... = 60(x +10)  3600 = 60x +600  60x = 3000 X = 50  So speed of the train is 110km/hr.

Description : A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train. -Maths 10th

Last Answer : Let the speed of train be x km/hr Distance to be travelled = 360km We know that, Time take by the train intially = If the speed was increased by 5km/hr Time taken by train = Difference in the time taken is 48 minutes, x2+5x -2250 = 0 (x+50)(x-45) Speed = 45 km/hr as speed cannot be negative

Description : A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length ... is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters

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Description : A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr

Last Answer : ANSWER : C Explanation: Relative speed = distance / time = (140 / 4.5) m/s = 31.11 m/s Convert m/s into km/hr  31.11 m/s = (31.11 * 18 / 50 km/hr  = (560 / 5) km/hr  = ... train (by sitting) = (112 - 25) km/hr = 87 km/hr  Therefore the speed of goods train is 87 km/hr.

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Last Answer : ANSWER:C Explanation:  Speed of goods train = 165km/hr  length of mail train (P) = 750m  length of goods train (Q) = 700m  Alternately, we can directly use the formula:  Time = ( p+q) / (v1+v2) sec  ( ...  45.833+v2 = 48.333  V2 = 2.5 m/s  Therefore the speed of the mail train is 2.5 m/s

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Last Answer : Let the speed of the train be x km/hr and that of the car be y km/hr. Then, 120/x+480/y= 8 1/x+4/y=1/15 ....(i) And, 200/x+400/y=25/3 1/x+2/y=1/24 ....(ii) Solving (i) and (ii), we get: x = 60 and y = 80. Ratio of speeds = 60 : 80 = 3 : 4. Answer: c)

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Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Last Answer : If the distance be x km, then x/40-x/50=6/60 x/4-x/5=1 x=20 km. Required time = (20/40) hour – 11 minutes = (1/2×60-11) minutes = 19 minutes Answer: c)

Description : A 250 m goods train takes 50 s to cross a person who is going in the same direction with the speed of 8 km/h. After crossing that person, the train can reach next station in 2 hr. How long that person takes to reach that station after being crossed by them? A) 2 ½ hr B) 5hr C) 3 1/2hr D) 1hr

Last Answer : ANSWER:A Explanation:  Speed of the person = 8 kmph  = (8*5/18)m/s  = 20/9 m/s  Then relative speed of train = (x-20/9)m/s  As train takes 50 sec to cross the person  Therefore 50 =250/(x-20/ ... 20,000 m  = 20 km Thus time taken by the person to cover the distance of 20km= 20/8 hr=2 ½ hr

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Last Answer : ANSWER : D  Explanation: Speed of person = 10km/hr  As the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed.  Relative speed = speed of train + speed of ... s  Distance = speed * time = 25 / 6 * 10 = 250/6 m/s = 41.6 m

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Last Answer : Answer: D Let the number of passengers travelling by first class and second class be x and 3x respectively. Lets the fares collected from each of the first class and second class passengers be 30y and y ... 3xy=33xy=1320 xy=40. Total amount collected from the second class =3xy=3 40= Rs 120.

Description : A passenger train travelling at 96 kmph completely crosses another train having half its length and travelling in opposite direction at 84 kmph, in 24 seconds. It also passes a railway platform in 90 seconds. The length of the platform is A) 1250 m B) 2258m C) 1600 m D) 3725m

Last Answer :  ANSWER:C  Explanation:  Let the length of the first train be x metres  Then, is x /2metres  Relative speed = (96+84)kmph  = 180 kmph  Convert km/hr into m/s,  = 180*5/18  = 50 m/s  Therefore (x ...  (800+y) = 90*480/18  y = 2400- 800  = 1600  Hence, the length of the platform is 1600 m

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