There are 10 cards numbered from 1 to 10 in a box. If a card is drawn randomly, then find the probability of getting an even numbered card.

There are 10 cards numbered from 1 to 10 in a box. If a card is drawn randomly, then find the probability of getting an even numbered card.
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There are 10 cards numbered from 1 to 10 in a box. If a card is drawn randomly, then find the probability of getting an ... B. `1/5` C. `2/5` D. `1/2`
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There are 100 cards numbered from 1 to 100 in a box. If a card is drawn from the box and the probability of an event is 1/2, then the number of favour

Description : There are 100 cards numbered from 1 to 100 in a box. If a card is drawn from the box and the probability of an event is 1/2, then the number of favour

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Nine playing cards are numbered 2 to 10. A card is selected at random. What is the probability that the card will be an odd number? a. 1/9 b. 2/9 c. 4/9 d. 3/7

Description : Nine playing cards are numbered 2 to 10. A card is selected at random. What is the probability that the card will be an odd number? a. 1/9 b. 2/9 c. 4/9 d. 3/7

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A box contains 4 green, 5 red and 6 white balls. Three balls are drawn randomly. What is the probability that the balls drawn are of different colours? a) 24/91 b) 67/91 c) 21/91 d) 70/91 e) 3/13

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Last Answer : Answer is: a)

Tickets numbered 1 to 37 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 10? A) 11/37 B) 37/11 C) 12/37 D) 37/12

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Last Answer : Answer: A) Here, S = {1, 2, 3, 4, ...., 36,37}. Let E = event of getting a multiple of 4 or 10= {4,8,12,16,20,24,28,32,36,10, 30}. P(E) = n(E)/n(S) = 11/37

A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability of getting a red card or a diamond or a jack ? -Maths 9th

Description : A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability of getting a red card or a diamond or a jack ? -Maths 9th

Last Answer : (d) \(rac{7}{13}\)Here n(S) = 52 Let A, B, C be the events of getting a red card, a diamond and a jack respectively. ∵ There are 26 red cards, 13 diamonds and 4 jacks, n(A) = 26, n(B) = 13, n(C) = 4 ⇒ n(A ∩ B) = ... rac{1}{52}\)= \(rac{44}{52}\) + \(rac{16}{52}\) = \(rac{28}{52}\) = \(rac{7}{13}\) .

All red face cards are removed from a pack of playing cards. The remaining cards are well shuffled and then a card is drawn at random from them. Find the probability that the drawn card is face card. a. 2/23 b. 7/44 c. 3/23 d. 4/25

Description : All red face cards are removed from a pack of playing cards. The remaining cards are well shuffled and then a card is drawn at random from them. Find the probability that the drawn card is face card. a. 2/23 b. 7/44 c. 3/23 d. 4/25

Last Answer : c. 3/23

What is the probability a well shuffled pack of 52 cards a card is drawn at random find the probability that it is either a heart or a queen?

Description : What is the probability a well shuffled pack of 52 cards a card is drawn at random find the probability that it is either a heart or a queen?

Last Answer : 41365

If a red suit is drawn from an ordinary deck of cards what is the probability that the card is a diamond?

Description : If a red suit is drawn from an ordinary deck of cards what is the probability that the card is a diamond?

Last Answer : It is 0.5

A box contains 50 tickets. Each ticket is numbered from 1 to 50. One ticket is selected at random, find the probability that the number on the ticket

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A bag contain 4 white & 5 red and 6blue color balls,3 balls are drawn randomly.What is the probability of all the balls are red? 1)1/22 2)3/22 3)2/90 4)2/91

Description : A bag contain 4 white & 5 red and 6blue color balls,3 balls are drawn randomly.What is the probability of all the balls are red? 1)1/22 2)3/22 3)2/90 4)2/91

Last Answer : 4)2/91 Exp: 15C3/5C2=(15×14×13)/(3×2×1)=10/455=2/91

A box contains 5 cone and 4 chocobar ice-creams. Preethi eats 3 of them, by randomly choosing. What is the probability of choosing 1 chocobar and 2 cone ice-creams? a) 63/10 b) 20/63 c) 10/63 d) 63/20

Description :  A box contains 5 cone and 4 chocobar ice-creams. Preethi eats 3 of them, by randomly choosing. What is the probability of choosing 1 chocobar and 2 cone ice-creams? a) 63/10 b) 20/63 c) 10/63 d) 63/20

Last Answer :  Answer: C) Probability of choosing 1 cone= 5/9 After taking out 1 cone, the total number is 8 . Probability of choosing 2nd cone = 4/8 Probability of choosing 1chocobaricecream out of a total of 7 = 4/7 So the final probability of choosing 2 cone and 1chocobar ice cream = 5/9*1/2*4/7 =10/63

If you were spin a spinner numbered 1-10 what would is the probability of getting an odd number?

Description : If you were spin a spinner numbered 1-10 what would is the probability of getting an odd number?

Last Answer : It is 0.5

There are three cards in a box. Both sides of one card are black, both sides of one card are red, and the third card has one black side and one red side. We pick a card at random and observe only one side. What is the probability that the opposite side is the same colour as the one side we observed? (A) 3/4 (B) 2/3 (C) 1/2 (D) 1/3

Description : There are three cards in a box. Both sides of one card are black, both sides of one card are red, and the third card has one black side and one red side. We pick a card at random and observe only one side. What is the ... the same colour as the one side we observed? (A) 3/4 (B) 2/3 (C) 1/2 (D) 1/3 

Last Answer : (B) 2/3

When you roll a 6 sided die with faces numbered 1 through 6 and toss a coin what is the probability of rolling a 5 and getting tails?

Description : When you roll a 6 sided die with faces numbered 1 through 6 and toss a coin what is the probability of rolling a 5 and getting tails?

Last Answer : As the two events are independent multiply the respectiveprobabilities together:pr(5) = 1/6pr(tails) = 1/2*→ pr(5 and tails) = 1/6 1/2 = 1/12*Actually it is ... coin itbecomes a real possibility as (accidentally) demonstrated in the1997 Royal Institution Christmas Lecture "The Magical Maze"

There are 20 marbles in a box which are marked with distinct numbers from 1 to 20. If a marble is drawn, then find the probability that the marble bei

Description : There are 20 marbles in a box which are marked with distinct numbers from 1 to 20. If a marble is drawn, then find the probability that the marble bei

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A box contains 3red, 8 blue and 5 green marker pens. If 2 marker pens are drawn at random from the pack, not replaced and then another pen is drawn. What is the probability of drawing 2 blue marker pens and 1 red marker pen? a) 3/20 b) 1/20 c) 7/20 d) 9/20

Description : A box contains 3red, 8 blue and 5 green marker pens. If 2 marker pens are drawn at random from the pack, not replaced and then another pen is drawn. What is the probability of drawing 2 blue marker pens and 1 red marker pen? a) 3/20 b) 1/20 c) 7/20 d) 9/20

Last Answer : Answer: B) Probability of drawing 1 blue marker pen =8/16 Probability of drawing another blue marker pen = 7/15 Probability of drawing 1 red marker pen = 3/14 Probability of drawing 2 blue marker pens and 1 red marker pen = 8/16*7/15*3/14=1/20

Find the probability that the three cards drawn from a pack of 52 cards are all black ? -Maths 9th

Description : Find the probability that the three cards drawn from a pack of 52 cards are all black ? -Maths 9th

Last Answer : Number of ways in which three cards can be drawn from a pack of 52 cards n(S) = 52C3. Let A : Event of drawing all the three cards as black Then, n(A) = 26C3 (∵There are 26 black cards)∴ P(A ... (rac{^{26}C_3}{^{52}C_3}\) = \(rac{26 imes25 imes24}{52 imes51 imes50}\) = \(rac{2}{17}.\)

Four cards are drawn from a full pack of cards. Find the probability that : -Maths 9th

Description : Four cards are drawn from a full pack of cards. Find the probability that : -Maths 9th

Last Answer : 4 cards can be drawn from a pack of cards in 52C4 ways ∴ Exhaustive number of cases = n(S) = 52C4 (a) There are 4 suits, each containing 13 cards. Let A : Event of drawing one card from each suit ⇒ Favourable number of ... = \(rac{15229}{54145}\) (∵ P(Event) + P(complement of event) = 1)

Two cards are drawn from a pack of 52 cards. What is the probability that either both are red or both are kings ? -Maths 9th

Description : Two cards are drawn from a pack of 52 cards. What is the probability that either both are red or both are kings ? -Maths 9th

Last Answer : Let S : Drawing 2 cards out of 52 card A : Drawing 2 red cards B : Drawing 2 kings A ∪ B : Drawing 2 red cards or 2 kings ∴ n(S) = 52C2 n(A) = 26C2 (∵ There are 26 red cards) n(B) = 4C2 ... \(rac{4 imes3}{52 imes51}\) - \(rac{2}{52 imes51}\) = \(rac{660}{2652}\) = \(rac{55}{221}.\)

Two cards are drawn at random from a well-shuffled pack of 52 cards. What is the probability that either both are black or both are kings ? -Maths 9th

Description : Two cards are drawn at random from a well-shuffled pack of 52 cards. What is the probability that either both are black or both are kings ? -Maths 9th

Last Answer : (b) \(rac{55}{221}\)S : Drawing 2 cards out of 52 cards ⇒ n(S) = 52C2 = \(rac{|\underline{52}}{|\underline{52}|\underline2}\) = \(rac{52 imes51}{2}\) = 1326A : Event of drawing 2 black cards out of 26 black cards⇒ n ... ) + \(rac{6}{1326}\) - \(rac{1}{1326}\) = \(rac{330}{1326}\) = \(rac{55}{221}\).

Two cards are drawn at random from a pack of 52 cards. What is the probability that both of them are either black or queen cards? a) 55/442 b) 54/221 c) 55/221 d) 51/221

Description : Two cards are drawn at random from a pack of 52 cards. What is the probability that both of them are either black or queen cards? a) 55/442 b) 54/221 c) 55/221 d) 51/221

Last Answer : c) 55/221

Three cards are drawn at random from an ordinary pack of cards. Find out the probability that they will consist of a king, aqueen and an ace?

Description : Three cards are drawn at random from an ordinary pack of cards. Find out the probability that they will consist of a king, aqueen and an ace?

Last Answer : Answer: 64/2210.

Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are Red or both are king? A) 52/221 B) 55/190 C) 55/221 D) 19/221

Description :  Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are Red or both are king? A) 52/221 B) 55/190 C) 55/221 D) 19/221

Last Answer : Answer: C) We have n(s) = 52C2 = 1326. Let A = event of getting both red cards B = event of getting both king A∩B = event of getting king of red cards n(A) = 26C2 = 325, n(B)= 4C2= 6 and n(A∩B) = 2C2 = 1 P(A ... S) = 1/1326 P(A∪B) = P(A) + P(B) - P(A∩B) = (325+6-1) / 1326 = 330/1326 = 55/221

A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Description : A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Last Answer : 4) 1/12

A bag contains 30 tickets numbered from 1 to 30. Five tickets are drawn at random and arranged in ascending order -Maths 9th

Description : A bag contains 30 tickets numbered from 1 to 30. Five tickets are drawn at random and arranged in ascending order -Maths 9th

Last Answer : Total number of ways in which 5 tickets can be drawn = n(S) = 30C5. The tickets are arranged in the form T1, T2, T3 (= 20), T4, T5 Where T1, T2 ∈{1, 2, 3, , 19} and T4, T5 ∈{21, 22, , 30 ... {10 imes9}{2}\) x \(rac{5 imes4 imes3 imes2 imes1}{30 imes29 imes28 imes27 imes26}\) = \(rac{285}{5278}.\)

One technique of Black Box testing is Equivalence Partitioning. In a programstatement that accepts only one choice from among 10 possible choices,numbered 1 through 10, the middle partition would be from _____ to _____ a) 4 to 6 b) 0 to 10 c) 1 to 10 d) None of the above

Description : One technique of Black Box testing is Equivalence Partitioning. In a programstatement that accepts only one choice from among 10 possible choices,numbered 1 through 10, the middle partition would be from _____ to _____ a) 4 to 6 b) 0 to 10 c) 1 to 10 d) None of the above

Last Answer : c) 1 to 10

If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Description : If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Last Answer : (c) \(rac{4}{1155}\)Let n(S) = Number of ways of selecting 3 numbers from 100 numbers = 100C3 Let E : Event of selecting three numbers divisible by both 2 and 3 from numbers 1 to 100 = Event of selecting three ... C_3}{^{100}C_3}\) = \(rac{16 imes15 imes14}{100 imes99 imes98}\) = \(rac{4}{1155}\).

What is the probability that a card drawn from a standard deck is a heart or an 8?

Description : What is the probability that a card drawn from a standard deck is a heart or an 8?

Last Answer : the probabiity that you draw a heart is 13/52 or 1/4, since a quarter of the cards are hearts. Since you want to know the probability of BOTH events happening, you multiply the two. One half times one fourth is 1/8, or A.

What is the probability that a randomly selected bit string of length 10 is a palindrome? (A) 1/64 (B) 1/32 (C) 1/8 (D) ¼

Description : What is the probability that a randomly selected bit string of length 10 is a palindrome? (A) 1/64 (B) 1/32 (C) 1/8 (D) ¼

Last Answer : (B) 1/32

In a Coupon, there are 30prizes and 75blanks. A Coupon is drawn at random. What is the probability of getting a prize? A) 2/7 B) 5/7 C) 1/5 D) 1/2

Description : In a Coupon, there are 30prizes and 75blanks. A Coupon is drawn at random. What is the probability of getting a prize? A) 2/7 B) 5/7 C) 1/5 D) 1/2

Last Answer : Answer: A) Total number of outcomes possible, n(S) = 30+75 = 105 Total number of prizes, n(E) = 30 P(E)=n(E)/n(S)=30/105=2/7

How many numbered cards in a deck of cards?

Description : How many numbered cards in a deck of cards?

Last Answer : 36 cards, numbered 2-10, x 4 suits.

How many numbered cards in a deck of cards?

Description : How many numbered cards in a deck of cards?

Last Answer : 36 cards, numbered 2-10, x 4 suits.

One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. -Maths 9th

Description : One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. -Maths 9th

Last Answer : (c) \(rac{1}{26}\)There is a total of 52 cards n(S) = 52 Let A : Event of drawing a red king Since there are only two red kings in the pack, n(A) = 2 ∴ P(A) = \(rac{2}{52}\) = \(rac{1}{26}\).

A card is drawn at random from a well shuffled pack of 52 cards -Maths 9th

Description : A card is drawn at random from a well shuffled pack of 52 cards -Maths 9th

Last Answer : (c) P(X) = P(Y) > P(Z) P(X) = \(rac{26}{52}\) + \(rac{4}{52}\) - \(rac{2}{52}\) = \(rac{28}{52}\) (∵ There are 26 black cards, 4 kings and 2 black kings)P(Y) = \(rac{13}{52}\) + \(rac{ ... }{52}\)(∵ There are 4 aces, 13 diamonds, 4 queens, 1 ace of diamond, 1 queen of diamond) ∴ P(X) = P(Y) > P(Z).

If you have two decks of cards and draw a card from each at random. What is the probability of drawing a number smaller than 5 from the first deck and a jack from the second one?

Description : If you have two decks of cards and draw a card from each at random. What is the probability of drawing a number smaller than 5 from the first deck and a jack from the second one?

Last Answer : ask from anyone else

Consider the example of finding the probability of selecting a red card or a 9 from a deck of 52 cards. A) 15/26 B) 26/15 C) 7/13 D) 13/7

Description : Consider the example of finding the probability of selecting a red card or a 9 from a deck of 52 cards. A) 15/26 B) 26/15 C) 7/13 D) 13/7

Last Answer : Answer: C) We need to find out P(R or 6) Probability of selecting a Red card = 26/52 Probability of selecting a 9 = 4/52 Probability of selecting both a red card and a 9 = 2/52  P(R or 9) = P(R) + P(9) – P(R and 9) = 26/52 + 4/52 – 2/52 = 28/52 = 7/13.

If a dics is thrown, then the probability of getting an even number is _______.

Description : If a dics is thrown, then the probability of getting an even number is _______.

Last Answer : If a dics is thrown, then the probability of getting an even number is _______.

750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Description : 750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Last Answer : (i) P(no boy child) =100 / 750 = 2 / 15 (ii) P (no girl child) = 120 /750 =4 / 25

750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Description : 750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Last Answer : (i) P(no boy child) =100 / 750 = 2 / 15 (ii) P (no girl child) = 120 /750 =4 / 25

6 boys and 6 girls are sitting in a row randomly. The probability that boys and girls sit alternately is -Maths 9th

Description : 6 boys and 6 girls are sitting in a row randomly. The probability that boys and girls sit alternately is -Maths 9th

Last Answer : (b) \(rac{1}{462}\)Let S be the sample space. Then, n(S) = Number of ways in which 6 boys and 6 girls can sit in a row = 12! Let E : Event of 6 girls and 6 boys sitting alternately. Then, the ... )= \(rac{2 imes6 imes5 imes4 imes3 imes2 imes1}{12 imes11 imes10 imes9 imes8 imes7}\) = \(rac{1}{462}\).

What Ten of the 50 digital video recorders (DVRs) in an inventory are known to be defective. What is the probability you randomly select an item that is not defective?

Description : What Ten of the 50 digital video recorders (DVRs) in an inventory are known to be defective. What is the probability you randomly select an item that is not defective?

Last Answer : It is 0.8

In a school, 22% of the students are sixth graders. What is the probability that a randomly chosen student will not be a sixth grader?

Description : In a school, 22% of the students are sixth graders. What is the probability that a randomly chosen student will not be a sixth grader?

Last Answer : 50 percent

In a large population, 54 % of the people have been vaccinated. If 5 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

Description : In a large population, 54 % of the people have been vaccinated. If 5 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

Last Answer : We will use Q and P to help solve this problem with Q representing the possibility that none of the randomly selected people are vaccinated and P representing the possibility that at least 1 randomly selected ... -0.0206=0.9794. The probability that at least 1 person has been vaccinated is 0.9794.

In a recent research study initiated by Tel-E-Fone Telecommunications, survey calls were made to a randomly selected group in which every member has an equal chance of selection. This type of sample selection is called A. Probability sample B. Convenience sample C. Judgment sample D. Quota sample E. Area sample

Description : In a recent research study initiated by Tel-E-Fone Telecommunications, survey calls were made to a randomly selected group in which every member has an equal chance of selection. This type of sample selection ... sample B. Convenience sample C. Judgment sample D. Quota sample E. Area sample

Last Answer : A. Probability sample

Two decks of playing cards are well shuffled and 26 cards are randomly distributed to a player. -Maths 9th

Description : Two decks of playing cards are well shuffled and 26 cards are randomly distributed to a player. -Maths 9th

Last Answer : (b) \(rac{23}{26}\)Total number of ways in which 3 letters can be selected from 26 letters = 26C3. If A is not to be included in the choice, there are 25 letters left, so number of ways in which 3 letters can be ... 25}C_3}{^{26}C_3}\) = \(rac{25 imes24 imes23}{26 imes25 imes24}\) = \(rac{23}{26}\).

In a class 140 students numbered 1 to 140, all even numbered students opted Mathematics course, those whose number is divisible by 3 opted Physics cou

Description : In a class 140 students numbered 1 to 140, all even numbered students opted Mathematics course, those whose number is divisible by 3 opted Physics cou

Last Answer : In a class 140 students numbered 1 to 140, all even numbered students opted Mathematics course, those whose number is ... B. `42` C. `102` D. `1`

Find the probability of getting a red face card. A. 3/26 B. 1/13 C. 1/52 D. 1/4

Description : Find the probability of getting a red face card. A. 3/26 B. 1/13 C. 1/52 D. 1/4

Last Answer : A. 3/26

Find the probability of getting a face card. A. 1/26 B. 1/13 C. 2/13 D. 3/13

Description : Find the probability of getting a face card. A. 1/26 B. 1/13 C. 2/13 D. 3/13

Last Answer : B. 1/13

In a throw of a die, find the probability of getting an even number. -Maths 9th

Description : In a throw of a die, find the probability of getting an even number. -Maths 9th

Last Answer : Total even number on a die = 3 P (getting an even numbers) = 3/6 = 1/2

Two dice are rolled once. Find the probability of getting an even number on the first die, or a total of 7. -Maths 9th

Description : Two dice are rolled once. Find the probability of getting an even number on the first die, or a total of 7. -Maths 9th

Last Answer : (c) \(rac{7}{12}\)Total number of ways in which 2 dice are rolled = 6 6 = 36 ⇒ n(S) = 36 Let A : Event of rolling an even number of 1st dice B : Event of rolling a total of 7 ⇒ A = {(2, 1), (2, 2) , (2, 6), (4 ... (rac{18}{36}\) + \(rac{6}{36}\) - \(rac{3}{36}\) = \(rac{21}{36}\) = \(rac{7}{12}\).