Description : In the formula `S=sqrt((p^(2)+q)/(p-q))` make q the subject.
Last Answer : In the formula `S=sqrt((p^(2)+q)/(p-q))` make q the subject.
Description : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.
Last Answer : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.
Description : Find `(x+2p)/(x-2p) +(x+2q)/(x-2q),"when x" = (4pq)/(p+q)`.
Last Answer : Find `(x+2p)/(x-2p) +(x+2q)/(x-2q),"when x" = (4pq)/(p+q)`.
Description : If vectors P = 2i + 3j - k and Q = 2i - 5j + 2k. Find i. P + Q ii. 3P - 2Q
Last Answer : If vectors \(\overset\rightarrow{P}\) = 2i + 3j - k and \(\overset\rightarrow{Q}\) = 2i - ... \overset\rightarrow{P}\) - 2\(\overset\rightarrow{Q}\)
Description : Simplify `((q^(3-7q)xxq^(6-2q))/(q^(2q)xxq^(9-2q)))^(1/9)`.
Last Answer : Simplify `((q^(3-7q)xxq^(6-2q))/(q^(2q)xxq^(9-2q)))^(1/9)`.
Description : In the formula `k=sqrt((n^(2)-1)/(n^(2)+1))`, make n the subject and find n if k=0.5.
Last Answer : In the formula `k=sqrt((n^(2)-1)/(n^(2)+1))`, make n the subject and find n if k=0.5.
Description : (i) `(a^(p+q))^(p-q) (a^(q+r))^(q-r)(a^(r+p))^(r-p)` (ii) `[(a/b)^(sqrt(p)+sqrt(q))]^(sqrt(p)-sqrt(q))[(a/b)^(sqrt(q)+sqrt(r))]^(sqrt(q)-sqrt(r))` `[(
Last Answer : (i) `(a^(p+q))^(p-q) (a^(q+r))^(q-r)(a^(r+p))^(r-p)` (ii) `[(a/b)^(sqrt(p)+sqrt(q))]^(sqrt ... sqrt(r))` `[(a/b)^(sqrt(r)+sqrt(p))]^(sqrt(r)-sqrt(p))`
Description : If p and q are perfect squares then `sqrt(p)/(q)` is always a rational number .Is the statement true?
Last Answer : If p and q are perfect squares then `sqrt(p)/(q)` is always a rational number .Is the statement ... B. no C. cannot be determined D. none of these
Description : How do I justify with steps 8(2q)?
Last Answer : 8(2q) = (8*2)q = 16*q = 16q.
Description : \( Q: \int_{\frac{5 \pi}{4}}^{\frac{3 \pi}{2}} \frac{\frac{x}{x}-\frac{x \cdot x}{2}+\frac{(x 2)^{2}}{24}-\frac{x^{4} x 2}{720}+\cdots \infty}{\sqrt{\frac{1-\cos 2 x}{8}}} \)
Last Answer : (a) \( \infinite \) (b) \( \ln 2 \) (C) 0 (d) \( -2 \ln \sqrt{2} \) (e) \( e^{2} \)
Description : Frame the formula: sum of the products of p,x and q,y is equal to r.
Last Answer : Frame the formula: sum of the products of p,x and q,y is equal to r. A. py+qx=r B. px-qy=r C. px+qy=r D. px+qy+r=0
Description : The diagonal of a rectangle is 10 units. The formula to find the diagonal is `d=sqrt(l^(2)+b^(2))`. Where l and b are length and breadth respectively.
Last Answer : The diagonal of a rectangle is 10 units. The formula to find the diagonal is `d=sqrt(l^(2)+b ... breadth respectively. (10+b)(10-b) is equal to______.
Description : In the formula `T=2pisqrt((l)/(g)),T` is ____proportional to `sqrt(l)`.
Last Answer : In the formula `T=2pisqrt((l)/(g)),T` is ____proportional to `sqrt(l)`.
Description : Compounds P and R upon ozonolysis produce Q and S, respectively. The molecular formula of Q and S is `C_(8)H_(8)O`. Q undergoes cannizzaro reactions b
Last Answer : Compounds P and R upon ozonolysis produce Q and S, respectively. The molecular formula of Q and S is `C_(8) ... R , respectively is (are) A. B. C. D.
Description : Frame the formula: The square of the difference of p and q is equal to the sum of `p^(2),q^(2) and (-2pq)`
Last Answer : Frame the formula: The square of the difference of p and q is equal to the sum of `p^(2),q^(2) and (-2pq)` A. ... 2pq` D. `(p+q)^(2)=p^(2)+q^(2)-2pq`
Description : If P is population of a city in thousands and Q is fire demand in litres per minute, for proper estimate of water, the Empirical formula Q = 1135 [(P/5) + 10] is suggested by (A) National Board of fire under-writers (B) Freeman (C) Kuichling (D) None of these
Last Answer : (B) Freeman
Description : Most satisfactory formula for an estimate of fire demand Q for a city of population P in thousands for Indian conditions, is (A) Q = 1115 (p/5 + 20) (B) Q = 1640 P (1 - 0.01 P) (C) Q = 3180 P (D) None of these
Last Answer : (C) Q = 3180 P
Description : The formula Q = P - K [1.8T + 32] in which Q is runoff, P is annual rain fall in cm, T is mean annual temperature in centigrade and K is a constant, is known (A) Justin's formula (B) Khosla's formula (C) English formula (D) Vermule's formula
Last Answer : (B) Khosla's formula
Description : Pettis formula Q = C (P.B)5/4 cumecs, is based upon (A) Rainfall and drainage area (B) Run off and drainage area (C) Drainage area and its shape (D) Drainage area
Last Answer : Answer: Option A
Description : Let a vertical tower AB have its end A on the level ground. Let C be the mid-point of AB and P be a point on the ground such that AP = 2AB. If `sqrt(B
Last Answer : Let a vertical tower AB have its end A on the level ground. Let C be the mid-point of AB and P be a point on the ... 4)` C. `(2)/(9)` D. `(4)/(9)`
Description : A shaft of length L is subject to a constant twisting moment T along its length L, then angle q through which one end of the bar will twist relative to other will be (a) T/g (b) T/GJ (c) GJ/TL (d) TL/GJ
Last Answer : (d) TL/GJ
Description : A pushdown automation M = (Q, Σ, Γ, δ, q0, z, F) is set to be deterministic subject to which of the following condition(s), for every q ∈ Q, a ∈ Σ ∪ {λ} and b ∈ Γ (s1) δ(q, a, b) contains at most one ... ) must be empty for every c ∈ Σ (A) only s1 (B) only s2 (C) both s1 and s2 (D) neither s1 nor s2
Last Answer : (C) both s1 and s2
Description : If `(a)/(b)=(b)/(c)`, then make c as the subject of the formula.
Last Answer : If `(a)/(b)=(b)/(c)`, then make c as the subject of the formula.
Description : In `v^(2)-u^(2)=2as`, make a as the subject of the formula.
Last Answer : In `v^(2)-u^(2)=2as`, make a as the subject of the formula.
Description : A wire of length a units is cut into two equal pieces and make a circle of radius r with one piece. Frame the formula by making r the subject.
Last Answer : A wire of length a units is cut into two equal pieces and make a circle of radius r with one piece. Frame the formula by making r the subject.
Description : Make b the subject for the formula `f=(a+b)/(a)`.
Last Answer : Make b the subject for the formula `f=(a+b)/(a)`.
Description : For getting total revenue, the formula is (a) TR/Q (b) MR+Q © AR/Q (d) AR X Q
Last Answer : (d) AR X Q
Description : Fahrenheit temperature F is 32 more tha ninefifths of the centrigrade temperature C. Frame the formula making F as the subject.
Last Answer : Fahrenheit temperature F is 32 more tha ninefifths of the centrigrade temperature C. Frame the formula making F as the ... C-32` D. `F=32xx(9)/(5)C`
Description : A is the area of the square with side S units. Write the formula of area making S as the subject.
Last Answer : A is the area of the square with side S units. Write the formula of area making S as the subject.
Description : A is the area of the rectangle with length l units and breadth b units. Rewrite the formula for area making l as the subject.
Last Answer : A is the area of the rectangle with length l units and breadth b units. Rewrite the formula for area making l as the subject.
Description : A is the area of a circle with radius r units. Write the formula of area, making r as the subject.
Last Answer : A is the area of a circle with radius r units. Write the formula of area, making r as the subject.
Description : In the formula `k=((a-b)/(a+b))^(2)`, find the value of b if `k=36` and a=3, making b the subject.
Last Answer : In the formula `k=((a-b)/(a+b))^(2)`, find the value of b if `k=36` and a=3, making b the subject.
Description : The formula with subject C is `C=(5F-160)/(9)`. Then what is the formula with subject F?
Last Answer : The formula with subject C is `C=(5F-160)/(9)`. Then what is the formula with subject F?
Description : Why does Integral[(e^sqrt(x)) / sqrt(x)] NOT equal e^sqrt(x) + C? Details of how I got there inside...
Last Answer : The derivative of sqrt(x) isn’t 1/sqrt(x), it is .5/sqrt(x), because sqrt(x) can be rewritten as x^.5, and the chain rule applies and makes the derivative .5*x^-.5
Description : `int_(0)^(pi//4) sqrt(cot x dx) =?`
Last Answer : `int_(0)^(pi//4) sqrt(cot x dx) =?` A. `(Pi sqrt(2))/(4)+(1)/(sqrt(2)) log (sqrt(2)-1)` B. `(- ... (pisqrt(2))/(4) -(1)/(sqrt(2))log (sqrt(2)-1)` D.
Description : `int_(0)^(1//2) (x sin^(-1)x)/(sqrt(1-x^(2)))dx=?`
Last Answer : `int_(0)^(1//2) (x sin^(-1)x)/(sqrt(1-x^(2)))dx=?` A. `(pi sqrt(3))/(12)+(1)/(2)` B. `(pisqrt(3))/(12)-(1)/(2)` C. `(pisqrt(3))/(12) -(1)/(2)` D.
Description : `int (1)/(sqrt(sin^(3) x cos x))dx =?`
Last Answer : `int (1)/(sqrt(sin^(3) x cos x))dx =?` A. `-2sqrt(tan x) +c` B. `(2)/(sqrt(tan x)) +c` C. `(-2)/(sqrt(tan x)) +c` D.
Description : `int_(0)^(1) (x)/(sqrt(1+x^(2)))dx=?`
Last Answer : `int_(0)^(1) (x)/(sqrt(1+x^(2)))dx=?` A. `sqrt(2)-1` B. `sqrt(2)` C. `-sqrt(2)` D.
Description : `int_(0)^(1) sqrt((1-x)/(1+x)) dx=?`
Last Answer : `int_(0)^(1) sqrt((1-x)/(1+x)) dx=?` A. `(pi)/(2)+1` B. `(pi)/(2) -1` C. None of these D.
Description : `int(sin x)/( sqrt(1+cos x))dx=?`
Last Answer : `int(sin x)/( sqrt(1+cos x))dx=?` A. `sqrt(1+cos x) +c` B. `-2sqrt(1+ cos x)+c` C. `2sqrt(1+ cos x) +c` D.
Description : `int_(0)^(1) x sqrt((1-x^(2))/(1+x^(2)))dx`
Last Answer : `int_(0)^(1) x sqrt((1-x^(2))/(1+x^(2)))dx`
Description : `int_(0)^(2) sqrt((2+x)/(2-x)) dx`
Last Answer : `int_(0)^(2) sqrt((2+x)/(2-x)) dx`
Description : `int_(0)^(1//sqrt(2)) (sin^(-1))/((1-x^(2))^(3//2))dx`
Last Answer : `int_(0)^(1//sqrt(2)) (sin^(-1))/((1-x^(2))^(3//2))dx`
Description : `int_(1)^(2) (x)/(sqrt(1+2x^(2)))dx`
Last Answer : `int_(1)^(2) (x)/(sqrt(1+2x^(2)))dx`
Description : `int_(0)^(1) (x sin^(-1)x)/(sqrt(1+2x)^(2))dx`
Last Answer : `int_(0)^(1) (x sin^(-1)x)/(sqrt(1+2x)^(2))dx`
Description : `int_(0)^(a) (x)/(sqrt(a^(2)-x^(2)))dx`
Last Answer : `int_(0)^(a) (x)/(sqrt(a^(2)-x^(2)))dx`
Description : `int_(a)^(2a) (sqrt((a)/(x))+sqrt((x)/(a)))^(2)dx`
Last Answer : `int_(a)^(2a) (sqrt((a)/(x))+sqrt((x)/(a)))^(2)dx`
Description : `int_0^a(dx)/(sqrt(a x-x^2))`
Last Answer : `int_0^a(dx)/(sqrt(a x-x^2))`
Description : `int_(0)^(1) (1)/(sqrt(1-x^(2)))dx`
Last Answer : `int_(0)^(1) (1)/(sqrt(1-x^(2)))dx`