Frame the formula: The square of the difference of p and q is equal to the sum of `p^(2),q^(2) and (-2pq)`

Frame the formula: The square of the difference of p and q is equal to the sum of `p^(2),q^(2) and (-2pq)`
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Frame the formula: The square of the difference of p and q is equal to the sum of `p^(2),q^(2) and (-2pq)` A. ... 2pq` D. `(p+q)^(2)=p^(2)+q^(2)-2pq`
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Description : Frame the formula: sum of the products of p,x and q,y is equal to r.

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`(p_q)^(2)+2pq+q^(2)=1` represents an equation used in

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A joint of a frame is subjected to three tensile forces P, Q and R equally inclined to each other. If P is 10 tonnes, the other forces will be (A) Q = 10 tonnes and R = zero (B) R + 10 tonnes and Q = zero (C) Q + R = 10 tonnes (D) Q and R each is equal to 10 tonnes

Description : A joint of a frame is subjected to three tensile forces P, Q and R equally inclined to each other. If P is 10 tonnes, the other forces will be (A) Q = 10 tonnes and R = zero (B) R + 10 tonnes and Q = zero (C) Q + R = 10 tonnes (D) Q and R each is equal to 10 tonnes

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Write the following sentence in symbolic form. Sum of cubes of p and q is equal to thrice the product of r and s.

Description : Write the following sentence in symbolic form. Sum of cubes of p and q is equal to thrice the product of r and s.

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P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another Rs 18 lakh few years. At the end of 10 years profit Of R is equal to sum of profit of P and Q. Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11

Description : P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another ... Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11 

Last Answer : Answer: C) Ratio of their profit P, Q, R is 54*4+36*6:72*6+90*4:108*x+126*(10-x) =12:22:35 - 0.5x Profit of R=profit of P +profit of Q 35-0.5x=12+22 X=2 year The number of years for R invests Rs 126 lakh =10-2=8years

Among 3 persons, P, Q, R the profit of R is equal to two-fifth of the sum of one-third profit of P and onethird of Q. If at the end of the year total profit is Rs 12750, then find the average profit of P and Q? A) 4750 B) 5625 C) 7425 D) 6520

Description : Among 3 persons, P, Q, R the profit of R is equal to two-fifth of the sum of one-third profit of P and onethird of Q. If at the end of the year total profit is Rs 12750, then find the average profit of P and Q? A) 4750 B) 5625 C) 7425 D) 6520

Last Answer : Answer: B)  R=2/5(1/3 P+1/3 Q)  15R=2(P+Q)  R/(P+Q)= 2/15  Take R=2x, P+Q=15x  Total profit =15x+2x =12750  =>X=Rs.750  Average profit of P&Q =750/2 *15=5625

Frame the formula for the area (A) of a quadrilateral given by half the product of its diagonal (d) and sum of offsets drawn to the diagonal from its

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What does 2pq represents in the equation?

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What does 2pq represents in the equation?

Description : What does 2pq represents in the equation?

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Boston society of Civil Engineer's formula Q = 0.0056 × (D/t) in cumecs/square km is based upon (A) Rainfall and drainage area(B) Total run off and drainage area (C) Drainage area and its shape (D) Drainage area

Description : Boston society of Civil Engineer's formula Q = 0.0056 × (D/t) in cumecs/square km is based upon (A) Rainfall and drainage area (B) Total run off and drainage area (C) Drainage area and its shape (D) Drainage area

Last Answer : Answer: Option B

The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in the original number, but they are in reverse order. The ten's place of the original number is equal to twice the difference between its digits. What is the number?

Description : The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in ... 's place of the original number is equal to twice the difference between its digits. What is the number?

Last Answer : Answer: 46

Write the given sets in roster form: (a). P = {y: y is an integer and -4 < y < 6}. (b). Q = {y: y is a natural number which is <8} (c). R = {y: y is a 2 digit natural number in which the sum of its digits is 9} -Other

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There are two sets of five numbers each – set P and set Q. P is a set of consecutive even numbers and Q is a set of consecutive numbers. The sum of the numbers of P is 230. The second least number in Q is 33 less than twice the least number in P. Find the sum of the numbers in Q. 1 : 260 2 : 250 3 : 240 4 : 270 5 : None of these

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Last Answer : 1 : 260

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If P is population of a city in thousands and Q is fire demand in litres per minute, for proper estimate of water, the Empirical formula Q = 1135 [(P/5) + 10] is suggested by (A) National Board of fire under-writers (B) Freeman (C) Kuichling (D) None of these

Description : If P is population of a city in thousands and Q is fire demand in litres per minute, for proper  estimate of water, the Empirical formula Q = 1135 [(P/5) + 10] is suggested by  (A) National Board of fire under-writers  (B) Freeman  (C) Kuichling  (D) None of these 

Last Answer : (B) Freeman 

Most satisfactory formula for an estimate of fire demand Q for a city of population P in thousands for Indian conditions, is (A) Q = 1115 (p/5 + 20) (B) Q = 1640 P (1 - 0.01 P) (C) Q = 3180 P (D) None of these

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Last Answer : (C) Q = 3180 P

The formula Q = P - K [1.8T + 32] in which Q is runoff, P is annual rain fall in cm, T is mean annual temperature in centigrade and K is a constant, is known (A) Justin's formula (B) Khosla's formula (C) English formula (D) Vermule's formula

Description : The formula Q = P - K [1.8T + 32] in which Q is runoff, P is annual rain fall in cm, T is mean annual  temperature in centigrade and K is a constant, is known  (A) Justin's formula  (B) Khosla's formula  (C) English formula  (D) Vermule's formula

Last Answer : (B) Khosla's formula 

Pettis formula Q = C (P.B)5/4 cumecs, is based upon (A) Rainfall and drainage area (B) Run off and drainage area (C) Drainage area and its shape (D) Drainage area

Description : Pettis formula Q = C (P.B)5/4 cumecs, is based upon (A) Rainfall and drainage area (B) Run off and drainage area (C) Drainage area and its shape (D) Drainage area

Last Answer : Answer: Option A

In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Description : In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Last Answer : In △PAD, ∠A = 90° and DA = PA = PB ⇒ ∠ADP = ∠APD = 90° / 2 = 45° Similarly, in △QBC, ∠B = 90° and BQ = BC = AB ⇒∠BCQ = ∠BQC = 90° / 2 = 45° In △PAD and △QBC , we have PA = QB [given] ∠A = ... [each = 90° + 45° = 135°] ⇒ △PDC = △QCD [by SAS congruence rule] ⇒ PC = QD or DQ = CP

Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Description : Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Last Answer : see the below answer

P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Description : In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Last Answer : In △PAD, ∠A = 90° and DA = PA = PB ⇒ ∠ADP = ∠APD = 90° / 2 = 45° Similarly, in △QBC, ∠B = 90° and BQ = BC = AB ⇒∠BCQ = ∠BQC = 90° / 2 = 45° In △PAD and △QBC , we have PA = QB [given] ∠A = ... [each = 90° + 45° = 135°] ⇒ △PDC = △QCD [by SAS congruence rule] ⇒ PC = QD or DQ = CP

Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Description : Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Last Answer : see the below answer

P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

ABCD is a square. P, Q, R, S are the mid-points of AB, BC, CD and DA respectively. By joining AR, BS, CP, DQ, we get a quadrilateral which is a -Maths 9th

Description : ABCD is a square. P, Q, R, S are the mid-points of AB, BC, CD and DA respectively. By joining AR, BS, CP, DQ, we get a quadrilateral which is a -Maths 9th

Last Answer : According to the given statement, the figure will be a shown alongside; using mid-point theorem: In △ABC,PQ∥AC and PQ=21 AC .......(1) In △ADC,SR∥AC and SR=21 AC .... ... are perpendicular to each other) ∴PQ⊥QR(angle between two lines = angle between their parallels) Hence PQRS is a rectangle.

Let P(–3, 2), Q(–5, –5), R(2, –3) and S(4, 4) be four points in a plane. Then show that PQRS is a rhombus. Is it a square ? -Maths 9th

Description : Let P(–3, 2), Q(–5, –5), R(2, –3) and S(4, 4) be four points in a plane. Then show that PQRS is a rhombus. Is it a square ? -Maths 9th

Last Answer : Let P(1, -1), Q \(\big(rac{-1}{2},rac{1}{2}\big)\) and R(1,2) be the vertices of the ΔPQR.Then, PQ = \(\sqrt{\big(rac{-1}{2}-1\big)^2+\big(rac{1}{2}+1\big)^2}\) = \(\sqrt{rac{9}{4}+rac{9}{4}} ... {3\sqrt2}{2}\)PR = \(\sqrt{(1-1)^2+(2+1)^2}\) = \(\sqrt9\) = 3∵ PQ = QR, the triangle PQR is isosceles.

If intensity of rainfall in cm per hour is I, percentage coefficient of run-off is P, area of catchment in square kilometres is A, the total run-off Q, is given by (A) Q = 1.758 × 102 × API(B) Q = 2.758 × 102 × API(C) Q = 2.758 × 103 × API(D) Q = 2.758 × 103 × A/PI

Description : If intensity of rainfall in cm per hour is I, percentage coefficient of run-off is P, area of catchment in  square kilometres is A, the total run-off Q, is given by  (A) Q = 1.758 102   API (B) Q = 2.758 ... API (C) Q = 2.758 103   API (D) Q = 2.758 103   A/PI

Last Answer : (C) Q = 2.758 × 103  × API

The figure shows the front view of a convex lens, which originally had only one edge. Five holes of different shapes, namely triangle, square, pentagon, hexagon and circle, were drilled through it at points P, Q, R, S and T in such a way that the holes were parallel to each other, perpendicular to the edge and all the holes were still within the lens edge. What is the total number of edges in the lens after the holes were drilled?

Description : The figure shows the front view of a convex lens, which originally had only one edge. Five holes of different shapes, namely triangle, square, pentagon, hexagon and circle, were drilled through it at points P ... . What is the total number of edges in the lens after the holes were drilled? 

Last Answer : 57

Among 3 Persons P,Q,R the profit Of Q is equal to one- third of the difference between the profit of R and triple of P. If at the end of the year, total profit is Rs 27000. Then find the profit of R? A) 13000 B) 17850 C) 14500 D) 20250

Description : Among 3 Persons P,Q,R the profit Of Q is equal to one- third of the difference between the profit of R and triple of P. If at the end of the year, total profit is Rs 27000. Then find the profit of R? A) 13000 B) 17850 C) 14500 D) 20250

Last Answer : Answer: D)  Q=1/3(R-3P)  3Q=R-3P R=3[P+Q]  R/(P+Q) =3/1  R/(P+Q+R)=3/4  R/27000 =3/4  R=Rs.20250

A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

Description : A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

Last Answer : 2 - 5 - 8 - 11 - 14 - 17 - 20 - 23 - 26

The volume of a cube is numerically equal to sum of its edges. What is the total surface area in square units ? -Maths 9th

Description : The volume of a cube is numerically equal to sum of its edges. What is the total surface area in square units ? -Maths 9th

Last Answer : answer:

if the slant height (l) of a cone is equal to the square root of the sum of the squares of radius (r) and height (h) then,

Description : if the slant height (l) of a cone is equal to the square root of the sum of the squares of radius (r) and height (h) then,

Last Answer : if the slant height (l) of a cone is equal to the square root of the sum of the squares of radius (r) and height (h) ... (2))` D. `r^(2)-h^(2)=l^(2)`.

(i) Write command to compute sum of every column of the data frame. -Technology

Description : (i) Write command to compute sum of every column of the data frame. -Technology

Last Answer : (i) df1.sum()(ii) df1[‘Rainfall’].mean()(iii) df1.loc[:11, ‘maxtemp’:’Rainfall’].mean( )

When two concurrent and coplaner forces P and Q act at an angle of 180?, their resultant will be a a.moment equal to PQ b.couple c.(P-Q) d.107 dynes e.zero

Description : When two concurrent and coplaner forces P and Q act at an angle of 180?, their resultant will be a a.moment equal to PQ b.couple c.(P-Q) d.107 dynes e.zero

Last Answer : c. (P-Q)

l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Description : l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Last Answer : Though E, draw a line parallel to p intersecting L at G and n at H respectively. Since l | | m ⇒ AG | | BE and AB | | GE [by construction] ∴ Opposite sides of quadrilateral AGEB are ... ∠DGE = ∠FHE [alternate interior angles] By ASA congruence axiom, we have △DEG ≅ △FEH Hence, DE = EF

l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Description : l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Last Answer : Though E, draw a line parallel to p intersecting L at G and n at H respectively. Since l | | m ⇒ AG | | BE and AB | | GE [by construction] ∴ Opposite sides of quadrilateral AGEB are ... ∠DGE = ∠FHE [alternate interior angles] By ASA congruence axiom, we have △DEG ≅ △FEH Hence, DE = EF

Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Description : Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Last Answer : Let x = 0.7Bar ⇒ x = 0.777.......... .........(1) Multiplying (1) by 10 ⇒ 10x = 7.7...... = 7.777 ...........(2) Subtracting (1) from (2) ⇒ 10x - x = 9x ⇒ 7.777 - 0.777 = 7 ... and then solving it, we get. ⇒ (594 + 770 + 470)/990 ⇒ 1834/990 ⇒ 917/495 Hence, 0.6 + 0.7Bar + 0.47Bar = 917/495

Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Description : Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Last Answer : Let x=0.666....... (1) Multiply equation (1 by 10 10x = 6.666....... (2) Subtract equation (1) from (2) x=6/9 Similarly 0.7bar =7/9 and 0.47bar = 47/99. 6/9+7/9+47/99=190/99

l,m and n are three parallel lines intersected by transversal p and q such that l,m and n cut-off equal intersepts AB and BC on p (Fig.8.55). Show that l,m and n cut - off equal intercepts DE and EF on q also. -Maths 9th

Description : l,m and n are three parallel lines intersected by transversal p and q such that l,m and n cut-off equal intersepts AB and BC on p (Fig.8.55). Show that l,m and n cut - off equal intercepts DE and EF on q also. -Maths 9th

Last Answer : Given:l∥m∥n l,m and n cut off equal intercepts AB and BC on p So,AB=BC To prove:l,m and n cut off equal intercepts DE and EF on q i.e.,DE=EF Proof:In △ACF, B is the mid-point of ... a triangle, parallel to another side, bisects the third side. Since E is the mid-point of DF DE=EF Hence proved.

PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th

Description : PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th

Last Answer : hope its clear

If pqr = 1, the value of (1)/([1+p+q^-1]) + (1)/([1+q+r^-1])+ (1)/([1+r+p^-1]) will be equal to : -Maths 9th

Description : If pqr = 1, the value of (1)/([1+p+q^-1]) + (1)/([1+q+r^-1])+ (1)/([1+r+p^-1]) will be equal to : -Maths 9th

Last Answer : answer:

Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th

Description : Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th

Last Answer : this is the ans hope its clear

Points P,Q,R(in this order) divide the line joining the points A(-2,2) and B(2,8) into four equal parts. The coordinates of the point Q are: (a) (-1,7/2) (b) (1,13/2) (c) (0,5) (d) (5,1/2)

Description : Points P,Q,R(in this order) divide the line joining the points A(-2,2) and B(2,8) into four equal parts. The coordinates of the point Q are: (a) (-1,7/2) (b) (1,13/2) (c) (0,5) (d) (5,1/2)

Last Answer : (c) (0,5)