446 g of PbO , 46 g of `NO_(2)` and 16 g of `O_(2)` are allowed to react according to the equation :- `PbO+2NO_(2)+(1)/(2)O_(2)toPb(NO_(3))_(2)` The a

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Answer :

446 g of PbO , 46 g of `NO_(2)` and 16 g of `O_(2)` are allowed to react according to the equation :- ... 331 g B. 662 g C. 165.5 g D. none of these

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