Which orbital is not involved in the formation of `PCl_(5)` molecule :-

Which orbital is not involved in the formation of `PCl_(5)` molecule :-
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Which orbital is not involved in the formation of `PCl_(5)` molecule :- A. s B. `d_(z^(2))` C. `d_(x^(2)-y^(2))` D. `P_(z)`
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At 473 K,`K_(c)` for the reaction `OCl_(5(g))rArrPCl_(3(g))Cl_(2(g))` is `8.3xx10^(-3)`. What will be the value of `K_(c)` for the formation of `PCl_(

Description : At 473 K,`K_(c)` for the reaction `OCl_(5(g))rArrPCl_(3(g))Cl_(2(g))` is `8.3xx10^(-3)`. What will be the value of `K_(c)` for the formation of `PCl_(

Last Answer : At 473 K,`K_(c)` for the reaction `OCl_(5(g))rArrPCl_(3(g))Cl_(2(g))` is `8.3xx10^(-3)`. What will be ... 3)` B. 120.48 C. `8.3xx10^(-3)` D. 240 .8

Which one of the following statements is WRONG? (A) A singlet or triplet state may result when one of the electrons from the HOMO is excited to higher energy levels (B) In an excited singlet state, the spin of the electron in the higher energy orbital is paired with the electron in the ground state orbital (C) Triplet excited state is more stable than the singlet excited state (D) When the electron from the singlet excited state returns to ground state, the molecule always shows fluorescence phenomenon

Description : Which one of the following statements is WRONG? (A) A singlet or triplet state may result when one of the electrons from the HOMO is excited to higher energy levels (B) In an ... the electron from the singlet excited state returns to ground state, the molecule always shows fluorescence phenomenon

Last Answer : (C) Triplet excited state is more stable than the singlet excited state

For the gas phase reaction `PCl_(5)rarrPCl_(3)(g)+Cl_(2)(g)` which of the following conditions are correct?

Description : For the gas phase reaction `PCl_(5)rarrPCl_(3)(g)+Cl_(2)(g)` which of the following conditions are correct?

Last Answer : For the gas phase reaction `PCl_(5)rarrPCl_(3)(g)+Cl_(2)(g)` which of the following conditions are correct? A ... D. `Delta H gt 0` and `Delta S lt 0`

In the given reaction which one of the following statement is correct - `C_(6)H_(5)-underset(CH_(3))underset(|)(C)=O+NH_(2)-OH to "Oxime" overset(PCl_

Description : In the given reaction which one of the following statement is correct - `C_(6)H_(5)-underset(CH_(3))underset(|)(C)=O+NH_(2)-OH to "Oxime" overset(PCl_

Last Answer : In the given reaction which one of the following statement is correct - `C_(6)H_(5)- ... elimination reaction. D. oxime and amides are isomers.

Among the following, the number of compounds that can react with `PCl_(5)` to give `POCl_(3)` is `O_(2)`,`CO_(2)`,`SO_(2)`,`H_(2)O`,`H_(2)SO_(4)`,`P_(

Description : Among the following, the number of compounds that can react with `PCl_(5)` to give `POCl_(3)` is `O_(2)`,`CO_(2)`,`SO_(2)`,`H_(2)O`,`H_(2)SO_(4)`,`P_(

Last Answer : Among the following, the number of compounds that can react with `PCl_(5)` to give `POCl_(3)` is `O_(2)`,`CO_(2) ... 2)O`,`H_(2)SO_(4)`,`P_(4)O_(10)`.

Select the correct statement(s) regarding reaction of `SO_(2) " with " PCl_(5)`

Description : Select the correct statement(s) regarding reaction of `SO_(2) " with " PCl_(5)`

Last Answer : Select the correct statement(s) regarding reaction of `SO_(2) " with " PCl_(5)` A. It ... D. both the products have same hybridisation of central atom

In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, `PCl_(5)` as well as `PCl_(5)` are possible. It is due to

Description : In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, `PCl_(5)` as well as `PCl_(5)` are possible. It is due to

Last Answer : In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, ... P in solid while N in gaseous state at room temperature

The final product obtained on hydrolysis of `PCl_(5)` is

Description : The final product obtained on hydrolysis of `PCl_(5)` is

Last Answer : The final product obtained on hydrolysis of `PCl_(5)` is A. `H_(3)PO_(4)` B. `H_(3)PO_(3)` C. `POCl_(3)` D. `PH_(3)`

In the given reaction which one of the following statement is correct - `C_(6)H_(5)-underset(CH_(3))underset(|)(C)=O+NH_(2)-OH to "Oxime" overset(PCl_

Description : In the given reaction which one of the following statement is correct - `C_(6)H_(5)-underset(CH_(3))underset(|)(C)=O+NH_(2)-OH to "Oxime" overset(PCl_

Last Answer : In the given reaction which one of the following statement is correct - `C_(6)H_(5)- ... elimination reaction. D. oxime and amides are isomers.

Among the following, the number of compounds that can react with `PCl_(5)` to give `POCl_(3)` is `O_(2)`,`CO_(2)`,`SO_(2)`,`H_(2)O`,`H_(2)SO_(4)`,`P_(

Description : Among the following, the number of compounds that can react with `PCl_(5)` to give `POCl_(3)` is `O_(2)`,`CO_(2)`,`SO_(2)`,`H_(2)O`,`H_(2)SO_(4)`,`P_(

Last Answer : Among the following, the number of compounds that can react with `PCl_(5)` to give `POCl_(3)` is `O_(2)`,`CO_(2) ... 2)O`,`H_(2)SO_(4)`,`P_(4)O_(10)`.

Select the correct statement(s) regarding reaction of `SO_(2) " with " PCl_(5)`

Description : Select the correct statement(s) regarding reaction of `SO_(2) " with " PCl_(5)`

Last Answer : Select the correct statement(s) regarding reaction of `SO_(2) " with " PCl_(5)` A. It ... D. both the products have same hybridisation of central atom

In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, `PCl_(5)` as well as `PCl_(5)` are possible. It is due to

Description : In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, `PCl_(5)` as well as `PCl_(5)` are possible. It is due to

Last Answer : In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, ... P in solid while N in gaseous state at room temperature

The final product obtained on hydrolysis of `PCl_(5)` is

Description : The final product obtained on hydrolysis of `PCl_(5)` is

Last Answer : The final product obtained on hydrolysis of `PCl_(5)` is A. `H_(3)PO_(4)` B. `H_(3)PO_(3)` C. `POCl_(3)` D. `PH_(3)`

In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, `PCl_(5)` are possible. It is due to

Description : In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, `PCl_(5)` are possible. It is due to

Last Answer : In case of nitrogen, `NCl_(3)` is possible but not `NCl_(5)` while in case of phosphorous, ... In solid while N in gaseous state at room temperature.

When a mixture containing `PCl_(3)` and `PCl_(5)` is heated with ethyl alcohol, a total of 4 moles of ehtyl chloride is formed. Mole ratio of `PCl_(3)

Description : When a mixture containing `PCl_(3)` and `PCl_(5)` is heated with ethyl alcohol, a total of 4 moles of ehtyl chloride is formed. Mole ratio of `PCl_(3)

Last Answer : When a mixture containing `PCl_(3)` and `PCl_(5)` is heated with ethyl alcohol, a total of 4 moles of ehtyl chloride is ... : 1` C. `1 : 3` D. `2 : 1`

Compound A reacts with Na metal to give B. A also reacts with `PCl_(5)` to give C. B and C reacts with each other to give dimethyl ether. Then A, B an

Description : Compound A reacts with Na metal to give B. A also reacts with `PCl_(5)` to give C. B and C reacts with each other to give dimethyl ether. Then A, B an

Last Answer : Compound A reacts with Na metal to give B. A also reacts with `PCl_(5)` to give C. B and C reacts with each ... )Cl` D. `CH_(3)Cl, CH_(4), CH_(3)OH`

Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving :

Description : Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving :

Last Answer : Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving : A. Sulphuryl ... . Sulphurous acid C. Chlorosulphonic acid D. Thionyl choride

Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving :

Description : Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving :

Last Answer : Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving : A. Thionyl ... Sulphurous chloride C. Chlorosulphonic acid D. sulphonating agent

`CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) overset(H_(2)//Pd//BaSO_(4))to(Z) overset(OH^(-))t

Description : `CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) overset(H_(2)//Pd//BaSO_(4))to(Z) overset(OH^(-))t

Last Answer : `CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) ... W+S ` Write the structure of X,Y,Z , W and S

Phosphorus trichloride, `PCl_(3)` undergoes, hydrolysis at room temperature to produce an oxoacid. It has the formula :

Description : Phosphorus trichloride, `PCl_(3)` undergoes, hydrolysis at room temperature to produce an oxoacid. It has the formula :

Last Answer : Phosphorus trichloride, `PCl_(3)` undergoes, hydrolysis at room temperature to produce an oxoacid. It has the formula : ... 3)PO_(4)` D. `H_(3)PO_(2)`

Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Description : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Last Answer : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` ( ... )` (xii) `COCl_(2)` (viii) `C Cl_(4)`

`PCl_(3)` reacts with water to form :

Description : `PCl_(3)` reacts with water to form :

Last Answer : `PCl_(3)` reacts with water to form : A. `PH_(3)` B. `H_(3)PO_(3) and HCl` C. `POCl_(3)` D. `H_(3)PO_(4)`

`CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) overset(H_(2)//Pd//BaSO_(4))to(Z) overset(OH^(-))t

Description : `CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) overset(H_(2)//Pd//BaSO_(4))to(Z) overset(OH^(-))t

Last Answer : `CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) ... W+S ` Write the structure of X,Y,Z , W and S

Phosphorus trichloride, `PCl_(3)` undergoes, hydrolysis at room temperature to produce an oxoacid. It has the formula :

Description : Phosphorus trichloride, `PCl_(3)` undergoes, hydrolysis at room temperature to produce an oxoacid. It has the formula :

Last Answer : Phosphorus trichloride, `PCl_(3)` undergoes, hydrolysis at room temperature to produce an oxoacid. It has the formula : ... 3)PO_(4)` D. `H_(3)PO_(2)`

Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Description : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Last Answer : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` ( ... )` (xii) `COCl_(2)` (viii) `C Cl_(4)`

`PCl_(3)` reacts with water to form :

Description : `PCl_(3)` reacts with water to form :

Last Answer : `PCl_(3)` reacts with water to form : A. `PH_(3)` B. `H_(3)PO_(3) and HCl` C. `POCl_(3)` D. `H_(3)PO_(4)`

`CH_(3)OH + PCl_(3) rarr A` `A overset(KCN)rarr B overset("hydrolysis")rarrC`. Then 'C' is

Description : `CH_(3)OH + PCl_(3) rarr A` `A overset(KCN)rarr B overset("hydrolysis")rarrC`. Then 'C' is

Last Answer : `CH_(3)OH + PCl_(3) rarr A` `A overset(KCN)rarr B overset("hydrolysis")rarrC`. Then 'C' is A. `CH_(3)CH_( ... C. `CH_(3)COOH` D. `CH_(2)OH - CH_(2)OH`

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of `CO_(2)` is

Description : In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of `CO_(2)` is

Last Answer : In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of ... A. 5 B. 1 C. 2 D. 10

In what way does the shape of a molecule affect how the molecule is involved in living systems?

Description : In what way does the shape of a molecule affect how the molecule is involved in living systems?

Last Answer : it determines how the molecule functions

What way does the shape of a molecule affect how the molecule is involved?

Description : What way does the shape of a molecule affect how the molecule is involved?

Last Answer : Feel Free to Answer

In what ways does the shape of a molecule affect how the molecule is involved with living systems?

Description : In what ways does the shape of a molecule affect how the molecule is involved with living systems?

Last Answer : it determines how the molecule functions

Which of the following statement(s) is/are true concerning ischemia reperfusion injury? a. During ischemia, ATP degradation results in increased plasma and intracellular levels of hypoxanthine and xanthene b. Oxygen free radicals such as the superoxide radical are involved in the expression of the proinflammatory phenotype of endothelial cells, macrophages and neutrophils c. The intracellular adhesion molecule-1 (ICAN-1) contributes to injury and disruption of the endothelial lining, with extensive capillary leak and resultant interstitial edema d. Animal models have demonstrated that passive immunization with antibodies to neutrophil adhesive complex lessen the ischemic/reperfusion microvascular injury

Description : Which of the following statement(s) is/are true concerning ischemia reperfusion injury? a. During ischemia, ATP degradation results in increased plasma and intracellular levels of ... immunization with antibodies to neutrophil adhesive complex lessen the ischemic/reperfusion microvascular injury

Last Answer : Answer: a, b, c, d During the ischemia and hypoperfusion phase, degradation of ATP stores essential to maintain cell integrity and significant loss of diffusible ... either the neutrophil adhesive complex or the endothelial selectins dramatically lessens ischemia/reperfusion microvascular injury

Translation results in the formation of (A) mRNA (B) tRNA (C) rRNA (D) A protein molecule

Description : Translation results in the formation of (A) mRNA (B) tRNA (C) rRNA (D) A protein molecule

Last Answer : Answer : D

From two amino acids peptide bond formation involves removal of one molecule of (A) Water (B) Ammonia (C) Carbondioxide (D) Carboxylic acid

Description : From two amino acids peptide bond formation involves removal of one molecule of (A) Water (B) Ammonia (C) Carbondioxide (D) Carboxylic acid

Last Answer : Answer : A

Which of the following statement(s) is/are true concerning translation of the mRNA message to protein synthesis? a. An adaptor molecule, tRNA, recognizes specific nucleic acid bases and unites them with specific amino acids b. Covalent attachment of tRNA to amino acids is energy dependent c. The formation of a peptide bond between the growing peptide chain and the free amino acid occurs in the free cytoplasm d. Complete protein synthesis takes hours

Description : Which of the following statement(s) is/are true concerning translation of the mRNA message to protein synthesis? a. An adaptor molecule, tRNA, recognizes specific nucleic acid bases and unites them ... and the free amino acid occurs in the free cytoplasm d. Complete protein synthesis takes hours

Last Answer : Answer: a, b The synthesis of protein involves conversion from a four-letter nucleotide language to one of 20 chemically distinct amino acids. This process is referred to as ... translation and be moving down the mRNA molecules simultaneously, thus increasing the rate of protein synthesis

Hydrogen and chlorine react vigorously in the presence of light (explosively) due to the formation of (a) Hydrogen-free radicals (b) Chlorine-free radicals (c) Hydrogen chloride molecule (d) Both hydrogen- and chlorine-free radicals

Description : Hydrogen and chlorine react vigorously in the presence of light (explosively) due to the formation of (a) Hydrogen-free radicals (b) Chlorine-free radicals (c) Hydrogen chloride molecule (d) Both hydrogen- and chlorine-free radicals

Last Answer : Ans:(b)

(4) less soluble in blood than nitrogen at high pressure Explanation: Deep-sea divers have their oxygen supply mixed with helium in order to avoid the toxic nature of oxygen under extreme pressures. The Helium atom is much smaller than the Nitrogen molecule, has a smaller electron cloud and is less polarizable. It, therefore is less soluble in blood than nitrogen and prevents the formation of nitrogen bubbles in blood which blocks blood flow as the diver comes to the surface of the sea from underwater.

Description : (4) less soluble in blood than nitrogen at high pressure Explanation: Deep-sea divers have their oxygen supply mixed with helium in order to avoid the toxic nature of oxygen under extreme pressures. The ... blood which blocks blood flow as the diver comes to the surface of the sea from underwater.

Last Answer : The chemical bahaviour of an atom depends upon - (1) the number of protons in its nucleus (2) the number of neutrons in the nucleus (3) the number of electrons orbiting around the nucleus (4) the number of nucleons in the nucleus

How many hydrogen-bonded water molecule(s) are present in CuSO4.5H2O ? Draw its structure to show formation of hydrogen bond.

Description : How many hydrogen-bonded water molecule(s) are present in CuSO4.5H2O ? Draw its structure to show formation of hydrogen bond.

Last Answer : Ans- one molecule of water is bonded by hydrogen bond and is deeply embedded in the lattice, While four molecules are bonded with coordinate bond. [ Cu(H2O)4] SO4.H2O

Explain the formation of H2 molecule on the basis of valence bond theory.

Description : Explain the formation of H2 molecule on the basis of valence bond theory.

Last Answer : Ans. When two H atoms come closer the following forces operate between them: a. Attractive : i.nucleus of atom and its electron ii.nucleus of one atom and electron of other. b.repulsive ... and the system acquires minimum energy .At this stage two hydrogen atoms are said to be bonded together.

During translation initiation in prokaryotes, a GTP molecule is needed in (a) formation of formyl-met-tRNA (b) binding of 30S subunit of ribosome with mRNA (c) association of 30S mRNA with formyl-met- tRNA (d) association of 50S subunit of ribosome with initiation complex.

Description : During translation initiation in prokaryotes, a GTP molecule is needed in (a) formation of formyl-met-tRNA (b) binding of 30S subunit of ribosome with mRNA (c) association of 30S mRNA with formyl-met- tRNA (d) association of 50S subunit of ribosome with initiation complex.

Last Answer : (c) association of 30S mRNA with formyl-met- tRNA

.During translation initiation in prokaryotes, a GTP molecule is needed in (a) formation of formyl-met-tRNA (b) binding of 30S subunit of ribosome with mRNA (c) association of 30S mRNA with formyl-met- tRNA (d) association of 50S subunit of ribosome with initiation complex.

Description : .During translation initiation in prokaryotes, a GTP molecule is needed in (a) formation of formyl-met-tRNA (b) binding of 30S subunit of ribosome with mRNA (c) association of 30S mRNA with formyl-met- tRNA (d) association of 50S subunit of ribosome with initiation complex.

Last Answer : (c) association of 30S mRNA with formyl-met- tRNA

The oxygenation activity of RuBisCO enzyme in photorespiration leads to the formation of (a) 2 molecules of 3-C compound (b) 1 molecule of 3-C compound (c) 1 molecule of 6-C compound (d) 1 molecule of 4-C compound and 1 molecule of 2-C compound

Description : The oxygenation activity of RuBisCO enzyme in photorespiration leads to the formation of (a) 2 molecules of 3-C compound (b) 1 molecule of 3-C compound (c) 1 molecule of 6-C compound (d) 1 molecule of 4-C compound and 1 molecule of 2-C compound

Last Answer : (b) 1 molecule of 3-C compound

Agonists affect the receptor molecule in the following manner: A. Alter its amino acid sequence B. Denature the receptor protein C. Alter its folding or alignment of subunits D. Induce covalent bond formation

Description : Agonists affect the receptor molecule in the following manner: A. Alter its amino acid sequence B. Denature the receptor protein C. Alter its folding or alignment of subunits D. Induce covalent bond formation

Last Answer : C. Alter its folding or alignment of subunits

Agonists affect the receptor molecule in the following manner: A. Alter its amino acid sequence B. Denature the receptor protein C. Alter its folding or alignment of subunits D. Induce covalent bond formation

Description : Agonists affect the receptor molecule in the following manner: A. Alter its amino acid sequence B. Denature the receptor protein C. Alter its folding or alignment of subunits D. Induce covalent bond formation

Last Answer : C. Alter its folding or alignment of subunits

Name the type of bonding in water molecule and explain its formation.

Description : Name the type of bonding in water molecule and explain its formation.  

Last Answer : Type of bonding : Single co-valent bonding.  Formation of Water Molecule:  Water molecule (H2O) contains two atoms of hydrogen & one atom of oxygen. Each hydrogen atom is in short ... atom. Thus, two separate single co-valent bonds are formed between hydrogen & oxygen atoms. 

Explain the formation of water molecule and name the type of bonding.

Description : Explain the formation of water molecule and name the type of bonding. 

Last Answer : Formation of Water Molecule:   H ( Z = 1 ) 1S1 (1)   O ( Z = 8 ) 1S2 , 2S2 , 2P4 (2, 6)  Water molecule (H2O) contains two atoms of hydrogen & one atom of oxygen. ... single co-valent bonds are formed between hydrogen & oxygen atoms.  Type of bonding: Single co-valent bonding. 

1. Which countries were involved in 100 year war? 2. Who is the author of a collection of poems called Golden Threshold? 3. What do ligaments join? 4. Which is the most important factor in soil formation? 5. Who were the first to issue gold coins?

Description : 1. Which countries were involved in 100 year war? 2. Who is the author of a collection of poems called Golden Threshold? 3. What do ligaments join? 4. Which is the most important ... creation of climatic homogeneity by the sea? 20. Who invented the technique of extracting scent from Rose?

Last Answer : Answer : 1. England and France 2. Sarojini Naidu 3. Bone to bone 4. Climate 5. Indo Greeks 6. 6 months 7. Remains same 8. Increasing 9. Mantle 10. Due to the invasion of Timur 11. Thomos ... nobility created by Iltutmish 16. Water gas 17. Brian Lara 18. 1999-2000 19. Marine west coast 20. Nurjahan

The factors involved in the formation of new species are

Description : The factors involved in the formation of new species are

Last Answer : The factors involved in the formation of new species are A. competition and variation B. ... . competition and mutation D. isolation and mutation

___,_____ and ____ are three processes involved in urine formation.

Description : ___,_____ and ____ are three processes involved in urine formation.

Last Answer : ___,_____ and ____ are three processes involved in urine formation.

Name the plant hormones which are involved in growth promoting activities such as cell division, cell enlargement, pattern formation, tropic growth, f

Description : Name the plant hormones which are involved in growth promoting activities such as cell division, cell enlargement, pattern formation, tropic growth, f

Last Answer : Name the plant hormones which are involved in growth promoting activities such as cell division, ... growth, flowering, fruiting and seed formation.