`(1)/(sin3alpha)[sin^(3)alpha+sin^(3)((2pi)/(3)+alpha)+sin^(3)((4pi)/(3)+alpha)]` is equal to

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Answer :

`(1)/(sin3alpha)[sin^(3)alpha+sin^(3)((2pi)/(3)+alpha)+sin^(3)((4pi)/(3)+alpha)]` is equal to A. `(4)/(3)` B. `(3)/(4)` C. `(-3)/(4)` D. `(-4)/(3)`

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