Description : Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by a shear stress? a. [(σ x - σ y )/2 ]sin θ - τ cos 2θ b. [(σ x - ... τ cos 2θ c. [(σ x - σ y )/2 ]sin θ - τ 2 cos θ d. None of the above
Last Answer : c. [(σ x – σ y )/2 ]sin θ – τ 2 cos θ
Description : The condition of diffraction from a crystal is given by (A) nλ = 2d Sin θ (B) λ = d Sin 2θ (C) λ = 2d Sin 2θ (D) nλ = d Sin θ
Last Answer : (A) nλ = 2d Sin θ
Description : The magnitude of maximum principal stress is a. Firstly (σ x +σ y )/2+ (1/2)( σ x +σ y ) +4τ 2 ) 5 b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5 c. Thirdly (σ x +σ y )/2+ (1/2)( σ x +σ y ) 2 +4τ 2 ) 5 d. None
Last Answer : b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5
Description : The relationship between the alternating stress and mean stress is given by the following equation: σ a =σ e [1-(σ m /σ u )x], where σ e is the fatigue limit for completely reversed loading. The value of x for Gerber line is equal to _________ a) 1 b) 2 c) 0.5 d) -1
Last Answer : b) 2
Description : The relationship between the alternating stress and mean stress is given by the following equation: σ a = σ e [1-(σ m /σ u ) x ]. The value of x for Goodman line is equal to _________ a) 1 b) 2 c) 0.5 d) -1
Last Answer : a) 1
Description : In trapezoidal threads, f (coefficient of friction) can be taken as a) f sec θ b) f cos θ c) f sin θ d) f cosec θ
Last Answer : a) f sec θ
Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None
Last Answer : c. Thirdly (σ 1 –σ 2 )/2
Description : Which is the maximum principal stress? a. Firstly σ 2 b. Secondly σ 3 c. Thirdly σ 1 d. None
Last Answer : c. Thirdly σ 1
Description : In a general two dimensional stress system, planes of maximum shear stress are inclined at ___ with principal planes. a. 90 degree b. 180 degree c. 45 degree d. 60 degree
Last Answer : c. 45 degree
Description : The fringe width and the angle of wedge are related to A. β=λ/2θ B. θ =λ/2 β C. β=λ/θ D. λ= β/2θ
Last Answer : A. β=λ/2θ
Description : The angle between normal stress and tangential stress is known as angle of ______ a. declination b. orientation c. obliquity d. rotation
Last Answer : c. obliquity
Description : A force 2P is acting on the double transverse fillet weld. Leg of weld is h and length l. Determine the shear stress in a plane inclined at θ with horizontal. a) PSinθ(Sinθ+Cosθ)/hl b) P(Sinθ+Cosθ)/hl c) Pcosθ(Sinθ+Cosθ)/hl d) None of the listed
Last Answer : a) PSinθ(Sinθ+Cosθ)/hl
Description : Which of the following conditions is true for repeated stress? 1. σ m = 0 2. σ m = σ max / 2 3. σ m = σ a 4. σ min = 0 5. σ min = - σ max 6. σ a = σ max / 2 where σ m = mean ... amplitude a. condition 2 and 3 b. condition 1, 3 and 5 c. condition 2, 4, and 6 d. condition 3,4, 5 and 6
Last Answer : c. condition 2, 4, and 6
Description : The stress represented by sin (t) + 4 belongs to which category? a) Alternating Stresses b) None of the mentioned c) Repeated Stresses d) Reversed Stresses
Last Answer : a) Alternating Stresses
Description : The stress represented by sin (t) + 2 belongs to which category? a) Fluctuating Stresses b) None of the mentioned c) Repeated Stresses d) Reversed Stresses
Last Answer : a) Fluctuating Stresses
Description : The stress represented by sin (t) + 1 belongs to which category? a) Fluctuating Stresses b) Alternating stresses c) Repeated Stresses d) Reversed Stresses
Last Answer : c) Repeated Stresses
Description : The bending moment ‘M’ and a torque ‘T’ is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then ‘M’ is equal to (A) T/2 (B) T (C) 2 T (D) 4 T
Last Answer : (A) T/2
Description : All the maximum shear stresses are at an angle of (a)45 0 (b) 90 0 (c) 135 0 (d) None
Last Answer : (b) 90 0
Description : The equations for principal stresses are valid only when (a)σ x and σ y are both tensile (b) σ x is compressive and σ y is tensile (c) σ x is tensile and σ y is compressive (d) None
Last Answer : (a)σ x and σ y are both tensile
Description : The magnitude of principal stresses due to complex stresses is (a) (1/2)[ (σ x + σ y ) ± ((σ x –σ y ) 2 + 4 τ 2 )) 0.5 ] (b) (1/2)[ (σx + σy) ± (1/2)((σx –σy) 2 + 4 τ 2 )) 0.5 ] (c) (1/2)[ (σx + σy) ± ((1/2)(σx –σy) 2 + 4 τ 2 )) 0.5 ]
Last Answer : (a) (1/2)[ (σ x + σ y ) ± ((σ x –σ y ) 2 + 4 τ 2 )) 0.5 ]
Description : Parallel fillet weld and transverse fillet weld both have the plane in which maximum shear stress occurs at 45’ to the leg dimension. a) True b) False
Last Answer : b) False
Description : The torque expression of a current carrying conductor is a) T = BIA cos θ b) T = BA cos θ c) T = BIA sin θ d) T = BA sin θ
Last Answer : c) T = BIA sin θ
Description : For finding out the bending moment for the arm (spoke) of flywheel the arm is assumed as 1. a cantilever beam fixed at the rim and subjected to tangential force at the hub 2. a simply ... tangential force at the rim 4. a fixed beam fixed at hub and rim and carrying uniformly distributed load
Last Answer : 3. a cantilever hub fixed at the rim and subjected to tangential force at the rim
Description : For finding out the bending moment for the arm (spoke) of flywheel, the arm is assumed as, (A) A cantilever beam fixed at the rim and subjected to tangential force at the hub (B) A simply ... tangential force at the rim (D) A fixed beam fixed at hub and rim and carrying uniformly distributed load
Last Answer : (C) A cantilever beam fixed at the hub and subjected to tangential force at the rim
Description : The axial deflection of spring for the small angle of θ is given by? a) 328PDɜN/Gd4 b) 8PDɜN/Gd4 c) 16PDɜN/Gd4 d) 8PD2N/Gdɜ
Last Answer : b) 8PDɜN/Gd4
Description : Which of the following equations is correct for Soderberg Criteria? a. (σ m / S ut ) + (σ a / S e ) = (1 / N f ) b. (σ m / S ut ) - (σ a / S e ) = (1 / N f ) c. (σ m / S yt ) + (σ a / S e ) = (1 / N f ) d. (σ m / S ut ) - (σ a / S e ) = (1 / N f )
Last Answer : c. (σ m / S yt ) + (σ a / S e ) = (1 / N f )
Description : In a body under hydrostatic pressure, the case exists (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None
Last Answer : (b) Secondly σ 1 = σ 2 =σ 3
Description : Under complex loading, principal stresses exist as (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None
Last Answer : (d) None
Description : Symbols for principal stresses are a. Firstly σ, τ & γ b. Secondly σ 1 , σ 2 & σ 3
Last Answer : b. Secondly σ 1 , σ 2 & σ 3
Description : The order of magnitude of the principal stresses is a. Firstly σ 1 >σ 2 >σ 3 b. Secondly σ 2 >σ 3 >σ 1 c. Thirdly σ 1 >σ 3 >σ 2 d. None
Last Answer : a. Firstly σ 1 >σ 2 >σ 3
Description : Principal planes are mutually inclined at a. 45 degree b. 60 degree c. 90 degree d. 180 degree
Last Answer : c. 90 degree
Description : All the principal strains are at an angle of (a) 45 0 (b) 90 0 (c) 135 0 (d) None
Description : All the principal stresses are at an angle of (a)90 0 (b) 45 0 (c) 135 0 (d) None
Last Answer : (a)90 0
Description : Among maximum shear stress theory and distortion energy theory, which gives the higher value shear yield strength? a) Maximum shear stress theory b) Distortion energy theory c) Both give equal values d) Vary from material to material
Last Answer : b) Distortion energy theory
Description : Maximum shear stress is equal to (a) (σ1 –σ2)/2 (b) (σ1 + σ2)/2 (c) (σ1 + 2σ2)/2 (d) None
Last Answer : (a) (σ1 –σ2)/2
Description : Under maximum shear stress theory, maximum shear stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None
Last Answer : (c) Allowable stress in shear
Description : Maximum principal stress is equal to (a) (σx + σy)/2 + [ (σx –σy) 2 + τ 2 ] 0.5 (b) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + τ 2 ] 0.5 (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5 (d) None
Last Answer : (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5
Description : Under maximum principal stress theory, maximum principal stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None
Last Answer : (a) Allowable stress in tension
Description : Tangential stress in a cylinder is given by [symbols have their usual meanings]. a) PD/2t b) 2PD/t c) PD/4t d) 4PD/t
Last Answer : a) PD/2t
Description : A muff coupling is connecting two shafts. The torque involved is 650N-m. The shaft diameter is 45mm with length and height of the key being 14mm and 80mm respectively. Find the compressive stress induced in the key. a) 70.1 N/mm2 b) 51.6N/mm2 c) 45.5N/mm2 d) None of the listed
Last Answer : b) 51.6N/mm2
Description : Minor principal stress has minimum ________ a. value of shear stress acting on the plane b. intensity of direct stress c. both a. and b. d. none of the above
Last Answer : b. intensity of direct stress
Description : Principal stress is the magnitude of ________ stress acting on the principal plane. a. Normal stress b. Shear stress c. Both a. and b. d. None of the above
Last Answer : a. Normal stress
Description : Find the area of a right angled triangle with sides of 90 degree unit and the functions described by L = cos y and M = sin x. a) 0 b) 45 c) 90 d) 180
Last Answer : d) 180
Description : Relation between throat and leg for a parallel fillet weld is a) t =h Cos (45’) b) h =t Cos (45’) c) h= t d) None of the listed
Last Answer : a) t =h Cos (45’)
Description : According to the ASME code, maximum allowable shear stress is taken as X% of yield strength or Y% of ultimate strength. a) X=30 Y=18 b) X=30 Y=30 c) X=18 Y=18 d) X=18 Y=30
Last Answer : a) X=30 Y=18
Description : The angle between a principal plane and a plane of maximum shear is a. 30 0 b. 60 0 c. 90 0 d. None
Last Answer : d. None
Last Answer : We hold theta = A. sin2A + cos2 (PM / OP) 2+ (OM / OP) 2 PM2 / OP2 + OM2OP2 (PM2 + OM2) / OP2 OP2 / OP2 => 1 So sin2A + cos2A = 1