The side of a square is increasing at a rate of 3 cm/sec. Find the rate of increasing of its perimeter when the side of square is 5cm.

The side of a square is increasing at a rate of 3 cm/sec. Find the rate of increasing of its perimeter when the side of square is 5cm.
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The side of a square is increasing at a rate of 3 cm/sec. Find the rate of increasing of its perimeter when the side of square is 5cm.
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(i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate of increasing of its perimeter. (ii) If the area of a circle increases

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Find the area of a triangle having perimeter 32cm. One side of its side is equal to 11cm and difference of the other two is 5cm. -Maths 9th

Description : Find the area of a triangle having perimeter 32cm. One side of its side is equal to 11cm and difference of the other two is 5cm. -Maths 9th

Last Answer : Solutions :- We have, Perimeter of triangle = 32 cm One of its side = 11 cm Let the second side be x And third side be x + 5 Perimeter of triangle = sum of three sides A/q => 11 + x + x + 5 ... 13 cm Now, By using heron's formula, Find the area of a triangle :- Answer : Area of triangle = 43.81 cm²

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A square and an equilateral triangle each have a perimeter of 72 cm. How much longer is one side of the triangle than one side of the square?

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A rhombus shaped sheet with perimeter 40 and digonals are 12 cm is painted on bith sides at the rate of rs 5 per metre square. Find the cost of painting -Maths 9th

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Last Answer : Let ABCD be a rhombus, then AB=BC=CD=DA=x Perimeter of rhombus =40cm ⇒4x=40cm⇒x=10cm ∴AB=BC=CD=DA=10cm In △ABC,S=2a+b+c​=210+10+12​=16cm ar△ABC=16(16−10)(16−10)(16−12)​=16×6×6×4​=48cm2ar.ABCD=2×48=96cm2 Cost of painting the sheet =Rs(5×96×2)=Rs960 [Both sides]

A rhombus shaped sheet with perimeter 40 and digonals are 12 cm is painted on bith sides at the rate of rs 5 per metre square. Find the cost of painting -Maths 9th

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Last Answer : Let ABCD be a rhombus, then AB=BC=CD=DA=x Perimeter of rhombus =40cm ⇒4x=40cm⇒x=10cm ∴AB=BC=CD=DA=10cm In △ABC,S=2a+b+c​=210+10+12​=16cm ar△ABC=16(16−10)(16−10)(16−12)​=16×6×6×4​=48cm2ar.ABCD=2×48=96cm2 Cost of painting the sheet =Rs(5×96×2)=Rs960 [Both sides]

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Last Answer : Here, PQ = SR = 12cm Let PS = x and PS = QR ∴ x + 12 + x +12 = Perimeter 2x + 24 = 40 2x = 16 x = 8 Hence, length of each side of the parallelogram is 12cm , 8cm , 12cm and 8cm.

PQRS is a parallelogram, in which PQ = 12 cm and its perimeter is 40 cm. Find the length of each side of the parallelogram . -Maths 9th

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The sides of a triangle are in the ratio of 1/2:1/3:1/4. If its perimeter is 52 cm, the length of the smallest side is : (A) 9 cm (B) 10 cm (C) 11 cm (D) 12 cm

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A square has a perimeter of 32x+16. What is the length of one side of the square?

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what- the perimeter of a square patch of mulch, in feet, has the same number of units as the area in square feet.What is the length of a side of the mulch patch?

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If the length of one side of a square 12.0cm what is the perimeter of the square?

Description : If the length of one side of a square 12.0cm what is the perimeter of the square?

Last Answer : Perimeter of square: 12+12+12+12 = 48 cm

How do you find the area and perimeter of a square whose side is given?

Description : How do you find the area and perimeter of a square whose side is given?

Last Answer : A square would have four sides of the same length. A square measuring 6 inches by 6 inches would have a perimeter of (6 + 6) x 2 = 24 inches in total. Which is the same as 6 + 6+ 6+ 6 = 24 linear inches.The area is length times width. So 6 x 6 = 32 square inches.

If the length of one side of a square 12.0cm what is the perimeter of the square?

Description : If the length of one side of a square 12.0cm what is the perimeter of the square?

Last Answer : Perimeter of square: 12+12+12+12 = 48 cm

How do you find the area and perimeter of a square whose side is given?

Description : How do you find the area and perimeter of a square whose side is given?

Last Answer : A square would have four sides of the same length. A square measuring 6 inches by 6 inches would have a perimeter of (6 + 6) x 2 = 24 inches in total. Which is the same as 6 + 6+ 6+ 6 = 24 linear inches.The area is length times width. So 6 x 6 = 32 square inches.

The distance of the object from the plain mirror is 1.5 cm . What will be the total distance between the object and its image. a) 1.5cm b)3cm c)2.5cm d)1cm

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What is answer Curved surface area of a cylinder is 176cm square area of base is 38.5cm square fund volume?

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The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer than the smaller side and the third side is 6 cm less than twice the smaller side. -Maths 9th

Description : The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer than the smaller side and the third side is 6 cm less than twice the smaller side. -Maths 9th

Last Answer : Let the smallest side of the triangle be x cm long So, second side =(x+4)cm and third side =(2x−6)cm Given, perimeter =50cm Therefore, x+(x+4)+(2x−6)=50 ⇒4x=52 ⇒x=13cm So, first side of the triangle is ... =25cm Therefore, area of Δ=s(s−a)(s−b)(s−c) =25(25−13)(25−17)(25−20) =25 12 8 5 = 2030 cm2

The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer than the smaller side and the third side is 6 cm less than twice the smaller side. -Maths 9th

Description : The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer than the smaller side and the third side is 6 cm less than twice the smaller side. -Maths 9th

Last Answer : According to question find the area of triangle.

Each of the equal sides of an isosceles triangle is 5 cm greater than the base. The perimeter is 46 Centimeters. What is the length of each side of the triangle?

Description : Each of the equal sides of an isosceles triangle is 5 cm greater than the base. The perimeter is 46 Centimeters. What is the length of each side of the triangle?

Last Answer : a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm ... = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm

Each of the equal sides of an isosceles triangle is 5 cm greater than the base. The perimeter is 46 Centimeters. What is the length of each side of the triangle?

Description : Each of the equal sides of an isosceles triangle is 5 cm greater than the base. The perimeter is 46 Centimeters. What is the length of each side of the triangle?

Last Answer : a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm ... = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm

Which of the following statements about septic shock are true? A. A circulating myocardial depressant factor may account for the cardiac dysfunction sometimes seen with shock due to sepsis or SIRS. B. A cardiac index (CI) of 6 liters per minute per square meter of body surface, a pulmonary capillary wedge pressure of 15 mm. Hg, and a systemic vascular resistance index (SVRI) of 800 dynes-sec/(cm 5-m 2) is a hemodynamic profile consistent with septic shock. C. An increase in SvO 2 in septic patients may be explained by the finding of anatomic arteriovenous shunts. D. Results of human trials employing antimediator therapy, such as antiendotoxin antibodies, IL-1 receptor antagonist, and tumor necrosis factor (TNF) antibodies, have confirmed animal studies that demonstrate a significant im

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A matchbox measures 4 cm×2.5cm×1.5cm. What will be the volume of a packet containing 12 such boxes? -Maths 9th

Description : A matchbox measures 4 cm×2.5cm×1.5cm. What will be the volume of a packet containing 12 such boxes? -Maths 9th

Last Answer : Dimensions of a matchbox (a cuboid) are l×b×h = 4 cm×2.5 cm×1.5 cm respectively Formula to find the volume of matchbox = l×b×h = (4×2.5×1.5) = 15 Volume of matchbox = 15 cm3 Now, volume of 12 such matchboxes = (15×12) cm3 = 180 cm3 Therefore, the volume of 12 matchboxes is 180cm3.

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface of the bowl. -Maths 9th

Description : A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface of the bowl. -Maths 9th

Last Answer : Inner radius of hemispherical bowl = 5cm Thickness of the bowl = 0.25 cm Outer radius of hemispherical bowl = (5+0.25) cm = 5.25 cm Formula for outer CSA of hemispherical bowl = 2πr2, where r is radius of ... 22/7) (5.25)2 = 173.25 Therefore, the outer curved surface area of the bowl is 173.25 cm2.

A cubical box has each edge 10 cm and another cuboidal box is 12.5cm long, 10 cm wide and 8 cm high -Maths 9th

Description : A cubical box has each edge 10 cm and another cuboidal box is 12.5cm long, 10 cm wide and 8 cm high -Maths 9th

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The sowing depth of dwarf wheat varieties is- (a) 6-7 cm (b) 2-3 cm (c) 4-5cm (d) 5-6 cm

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ABCD is a parallelogram with diagonal AC If a line XZ is drawn such that XZ ∥ AB, then BX/XC = ? (a) (AY/AC) (b) DZ/AZ (c) AZ/ZD (d) AC/AY Answer: (c) AZ/ZD 13. In the given figure, value of x (in cm) is (a) 5cm (b) 3.6 cm (c) 3.2 cm (d) 10 cm

Description : ABCD is a parallelogram with diagonal AC If a line XZ is drawn such that XZ ∥ AB, then BX/XC = ? (a) (AY/AC) (b) DZ/AZ (c) AZ/ZD (d) AC/AY Answer: (c) AZ/ZD 13. In the given figure, value of x (in cm) is (a) 5cm (b) 3.6 cm (c) 3.2 cm (d) 10 cm

Last Answer : (a) 5cm

A water main 1 m in diameter contains a fluid having pressure 1 N/mm2. If the maximum permissible tensile stress in the metal is 20 N/mm2, th thickness of the metal required would be a) 2 cm b) 2.5cm c) 1 cm d) 0.5 cm

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Last Answer : b) 2.5cm

A short, hollow cast iron cylinder with a wall thickness of 1 cm is to carry a compressive load of 10 tonnes. If the working stress in compression is 800 kg/cm2, the outside diameter of the cylinder should not be less than a) 0.5cm b) 5 cm c) 2.5cm d) 4.5 cm

Description : A short, hollow cast iron cylinder with a wall thickness of 1 cm is to carry a compressive load of 10 tonnes. If the working stress in compression is 800 kg/cm2, the outside diameter of the cylinder should not be less than a) 0.5cm b) 5 cm c) 2.5cm d) 4.5 cm

Last Answer : b) 5 cm

Generally weeds seeds are abundant at a depth of a). 1.0-1.5cm b). 5 cm c).10cm d).15cm

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Shallow germinating weed seeds are at depth a). Upto 5cm b).10 cm c).15cm d).7.5cm

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Deep germinating weed seeds are at depth of a). Upto 5cm b). 2.5 cm c). 15cm d). 1cm

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The average height of 60 girls was calculated to be 300 cm. It was detected later that one value of 330 cm was wrongly copied as 270 cm for the computation of the mean. Find the correct mean. A) 301cm B) 300.5cm C) 307cm D) 311cm

Description : The average height of 60 girls was calculated to be 300 cm. It was detected later that one value of 330 cm was wrongly copied as 270 cm for the computation of the mean. Find the correct mean. A) 301cm B) 300.5cm C) 307cm D) 311cm

Last Answer : A) Calculated average height of 60 girls = 300cm. Incorrect sum of the heights of 60 girls = (300 60)cm = 18000 cm. Correct sum of the heights of 60 girls = (incorrect sum) - (wrongly copied item) ... 330) cm = 18060cm. Correct mean = correct sum/number of girls = (18060/60) cm = 301 cm.

The area of a trapezium is 39cm2 . The distance between its parallel sides is 6cm. If one of the parallel sides is 5cm, then find the other parallel side. -Maths 9th

Description : The area of a trapezium is 39cm2 . The distance between its parallel sides is 6cm. If one of the parallel sides is 5cm, then find the other parallel side. -Maths 9th

Last Answer : area of trapezium = 39 cm sq height of trpezium = 6 cm one || side = 5 cm let other be x area of trapezium = 1/2 × ( sum of || sides) × h 39 = 1/2 × ( 5+x) × 6 39×2 = (5+x) × 6 78/6 = 5+x 13-5 = x 8 = x x = 8cm

A rhombus shaped sheet with perimeter 40 cm and one diagonal 12 cm, is painted on both sides at the rate of Rs. -Maths 9th

Description : A rhombus shaped sheet with perimeter 40 cm and one diagonal 12 cm, is painted on both sides at the rate of Rs. -Maths 9th

Last Answer : Cost of painting =

A rhombus shaped sheet with perimeter 40 cm and one diagonal 12 cm, is painted on both sides at the rate of Rs. -Maths 9th

Description : A rhombus shaped sheet with perimeter 40 cm and one diagonal 12 cm, is painted on both sides at the rate of Rs. -Maths 9th

Last Answer : Cost of painting =