Description : What is the standard enthalpy change at 298 K for the following reaction? `CO_(2) (g)+ C("diamond") rarr 2CO(g)` Given : `DeltaH_(f)^(@)(CO,g) = - 110
Last Answer : What is the standard enthalpy change at 298 K for the following reaction? `CO_(2) (g)+ C("diamond") rarr 2CO(g ... `+172.5 kJ//mol` D. `170.5 kJ//mol`
Description : Which of the following value of `DeltaH_(f)^(@)` represent that the product is least stable ?
Last Answer : Which of the following value of `DeltaH_(f)^(@)` represent that the product is least stable ? A. `-94` K cal B. ... C. `+21.4` K cal D. `+64.8` K cal
Description : In conversion of lime-stone to lime, `CaCO_(3(s)) to CaO_((s)) + CO_(2(g))` the values of `DeltaH^@` and `DeltaS^@` are `+179.1 kJmol^(-1)` and `160.2
Last Answer : In conversion of lime-stone to lime, `CaCO_(3(s)) to CaO_((s)) + CO_(2(g))` the values of `DeltaH^@` and ... : A. 1008 K B. 1200 K C. 845 K D. 1118 K
Description : The value of n in the molecular formula `Be_(n)Al_(2)Si_(6)O_(18)` is:
Last Answer : The value of n in the molecular formula `Be_(n)Al_(2)Si_(6)O_(18)` is:
Description : The bond energies of `F_(2),Cl_(2),Br_(2)` and `I_(2)` are 155.4, 243.6, 193.2 and `151.2 Kjmol^(-1)` respectively. The strongest bond is :
Last Answer : The bond energies of `F_(2),Cl_(2),Br_(2)` and `I_(2)` are 155.4, 243.6, 193.2 and `151.2 Kjmol^(-1)` ... . F -F B. Cl - Cl C. Br - Br D. I - I
Description : If 3 moles of a compound use 12 j of energy in a reaction what is the h f in kjmol?
Last Answer : Need answer
Description : Number of gaseous oxides among the following at room temperature is: (a) `N_(2)O` (b) `NO` (c) `N_(2)O_(3)` (d) `NO_(2)` (e) `N_(2)O_(5)` (f) `P_(4)O_
Last Answer : Number of gaseous oxides among the following at room temperature is: (a) `N_(2)O` (b) `NO` (c) `N_(2)O_(3)` ( ... (4)O_(10)` (h) `SO_(2)` (i) `SO_(3)`
Description : Number of acidic oxides among the following is: (a) `N_(2)O` (b) `NO` (c) `N_(2)O_(3)` (d) `N_(2)O_(4)` (e) `N_(2)O_(5)` (f) `P_(4)O_(6)` (g) `P_(4)O_
Last Answer : Number of acidic oxides among the following is: (a) `N_(2)O` (b) `NO` (c) `N_(2)O_(3)` (d) `N_(2)O_(4)` (e ... (h) `SO_(3)` (i) `B_(2)O_(3)` (j) `CO`
Description : `DeltaH_"vaporisation"` (KJ/mol) are given for the hydrides of halogens in the following graph. The hydride HF will correspond to
Last Answer : `DeltaH_"vaporisation"` (KJ/mol) are given for the hydrides of halogens in the following graph. The hydride HF will ... . (B)Q C. (C)R D. (D)S
Description : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be
Last Answer : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will ... B. 1.6 g C. 3.2 g D. 0.8 g
Description : Calculate the value of closing stock from the following according to Weighted Average method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units ... 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700
Last Answer : (c) Rs. 786
Description : Calculate the value of closing stock from the following according to LIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 ... , 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700
Last Answer : (b) Rs. 805
Description : Calculate the value of closing stock from the following according to FIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 ... , 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700
Last Answer : (a) Rs. 765
Description : Calculate the entropy of `Br_(2)(g)` in the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1)` given, entropy of `H_(2)` and HBr is 13
Last Answer : Calculate the entropy of `Br_(2)(g)` in the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1 ... ` C. `24.63 JK^(-1)` D. `20 KJK^(-1)`
Description : Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` and boiling point of ethanol is `78.5^(@)`.
Last Answer : Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` ... KJ mol^(-1)` D. Some more data is required
Description : Consider the following sequence of reaction: `HO-overset(O)overset(||)(C)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-C-=N overset(200^(@)
Last Answer : Consider the following sequence of reaction: `HO-overset(O)overset(||)(C)-underset(CH_(3))underset(|)overset(CH_ ... )underset(|)(C)-CH_(2)-NH_(2)` D.
Description : Which of the following is true fo the reacion `H_(2)O(l)hArr H_(2)O(g)` at `100^(@)C` and 1 atmosphere
Last Answer : Which of the following is true fo the reacion `H_(2)O(l)hArr H_(2)O(g)` at `100^(@)C` and 1 atmosphere ... Delta H = Delta E` D. `Delta H = T Delta S`
Description : Assertion (A): o-phenol sulphonic acid on heating at `100^(@)C` changes to p-phenol sulphonic acid. Reason : Sulphonation of phenol is a reversible pr
Last Answer : Assertion (A): o-phenol sulphonic acid on heating at `100^(@)C` changes to p-phenol sulphonic acid. ... in correct D. A is incorrect but R is correct
Description : What is the value for G at 5000 k if H-220 KJmol and S-0.05 KJ (molK)?
Last Answer : 30 kj
Description : Which reaction shows that the enthalpy of formation of H2S is Hf -20.6 kJmol?
Last Answer : H2(g) + S(s) —> H2S + 20.6 kJ
Description : It is estimated that out of the total global warming the relative contribution of `CO_(2)`, `CH_(4)` CFCs and `N_(2)O` are found respectively as:
Last Answer : It is estimated that out of the total global warming the relative contribution of `CO_(2)`, `CH_(4)` CFCs ... 60% C. 60%,20%,14%,6% D. 6%,14%,20%,60%
Description : `CO_(2), CH_(4), N_(2)O` and CFCs are called greenhouse gases because they can absorb:
Last Answer : `CO_(2), CH_(4), N_(2)O` and CFCs are called greenhouse gases because they can absorb: ... radiations C. visible light radiations D. X-ray radiations
Description : The enthalpy changes of formation of the gaseous oxides of nitrogen `(N_(2)O` and `NO)` are positive because of `:`
Last Answer : The enthalpy changes of formation of the gaseous oxides of nitrogen `(N_(2)O` and `NO)` are positive ... The tendency of oxygen to form `O^(2-)`
Description : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 kJ / mol respectively. For the reaction `N_(2)
Last Answer : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 ... is A. `-212` B. `+212` C. `+778` D. `-778`
Description : At the equilibrium of the reaction , `N_(2)O_(4)(g)rArr2NO_(2)(g)`, the observed molar mass of `N_(2)O_(4)` is 77.70 g . The percentage dissociation o
Last Answer : At the equilibrium of the reaction , `N_(2)O_(4)(g)rArr2NO_(2)(g)`, the observed molar mass of `N_(2)O_(4)` is ... A. 28 .4 B. 46 .7 C. 22.4 D. 18 .4
Description : Nitrogen forms the largest number of oxides as it is capable of forming stable multiple bonds with oxygen. They range from `N_(2)O` (O.S of nitrogen +
Last Answer : Nitrogen forms the largest number of oxides as it is capable of forming stable multiple bonds with ... red D. Nitrogen dioxide is not acidic oxide
Description : Nitrogen forms the largest number of oxides as it is capable of forming stable multiple bonds with oxygen. They range of `N_(2)O` (O.S of nitrogen +1)
Last Answer : Nitrogen forms the largest number of oxides as it is capable of forming stable multiple bonds with oxygen. They range ... C. `NO_(2)` D. both A and C
Description : Substances burn more readily in `N_(2)O` than in air because `N_(2)O`:
Last Answer : Substances burn more readily in `N_(2)O` than in air because `N_(2)O`: A. is reactive ... temperature D. dissociates more readily than `O_(2)`
Description : The wrong statement about `N_(2)O` is :
Last Answer : The wrong statement about `N_(2)O` is : A. It is nitrous oxide B. It is a neutral oxide C. It is not a linear molecule D. It is known as laughing gas
Description : In the conversion `NH_(2)OH rarr N_(2)O`, the equivalent weight of `NH_(2)OH` will be:
Last Answer : In the conversion `NH_(2)OH rarr N_(2)O`, the equivalent weight of `NH_(2)OH` will be: A. M/4 B. M/2 C. M/5 D. M/1
Description : Arrange `CFC, CH_(4), N_(2)O, and CO_(2)` in decreasing order according to their contribution in greenhouse effect:
Last Answer : Arrange `CFC, CH_(4), N_(2)O, and CO_(2)` in decreasing order according to their contribution in greenhouse ... (2)` D. `CO_(2)gtCH_(4)gtCFCgtN_(2)O`
Description : n_ +1 = -1. what does n equal6?
Last Answer : If n + 1 = -1 then n = -2
Description : Compound A is chiral and has the molecular formula `C_(8)H_(11)N`. When A reacts nitrous acid then occurs a brisk evolution of `N_(2)` gas. A dissolve
Last Answer : Compound A is chiral and has the molecular formula `C_(8)H_(11)N`. When A reacts ... . 1-phenylethanamine C. 1-cyclohexylethanamine D. N-ethylaniline
Description : 1The elements of the second period of the Periodic Table are given below: Li Be B C N O F (a) Give reason to explain why atomic radii decrease from Li to F. (b) Identify the most (i) metallic and (ii)non-metallic element. -Science
Last Answer : a) It is because nuclear charge increases due to increase in atomic number, therefore, force of attraction between nucleus and valence electrons increases, i.e. effective nuclear charge increases, hence ... element is ‘F’ because it can gain electrons easily due to smallest atomic size.
Description : A ray of light incident at `49^(@)` on the face of an equilaternal prism passes symmetrically. Calculate the refractive index of the material of the p
Last Answer : A ray of light incident at `49^(@)` on the face of an equilaternal prism passes symmetrically. ... the refractive index of the material of the prism.
Description : The refractive index of the material of a prism of `60^(@)` angle for yellow light is `sqrt(2)`. Calculate angle of minimum deviation, angle of incide
Last Answer : The refractive index of the material of a prism of `60^(@)` angle for yellow light is ... deviation, angle of incidence and angle of refraction.
Description : The refracting angle of a glass prism is `60^(@)`. The value of minium deviation for light passing through the prism is `40^(@)`. Calculate the value
Last Answer : The refracting angle of a glass prism is `60^(@)`. The value of minium deviation for light passing through the ... prism. Given `sin 50^(@) = 0.766`.
Description : White light is passed through a prism of `5^(@)`. If refractive indices for red and blue rays are `1.641 and 1.659` respectively, calculate the angula
Last Answer : White light is passed through a prism of `5^(@)`. If refractive indices for red and ... respectively, calculate the angular dispersion of the prism.
Description : Two hybrid orbitals have a bond angle of `120^(@)`. The percentage of p character in the hybrid orbital is nearly :-
Last Answer : Two hybrid orbitals have a bond angle of `120^(@)`. The percentage of p character in the hybrid orbital is nearly ... 25%` B. `33%` C. `50%` D. `66%`
Description : Standard quantity of material per unit 5KG. Standard Price Rs 5 per KG. actual number of units 400 units. Actual quantity 2,200KG and price of material Rs 4.80 per kg. Calculate material price. a) 100(F) b) 500(A) c) 440(F) d) 600(F)
Last Answer : The standard quantity of material per unit is 5KG, so the standard quantity for 400 units would be: Standard quantity = 5KG/unit x 400 units = 2000KG The standard price per KG is Rs 5, so the ... material cost was lower than the standard material cost. Option (c) is the correct answer: 440(F).
Description : What is the value returned by the function f given below when n = 100 ? int f(int n) { if (n==0) then return n; else return n + f(n-2); } (A) 2550 (B) 2556 (C) 5220 (D) 5520
Last Answer : (A) 2550
Description : In a company M and O invested amount in the ratio 3 : 2 whereas the ratio between amounts invested by M and N was 4 : 3. If Rs.1,80,000 was their profit, how much did N receive?(calculate approximate value) A) 75432 B) 74483 C) 76854 D) 76443
Last Answer : Answer: B) M : O = 3:2 O: M= 2:3 = 8:12 M:N = 4 :3 =12:9 O:M:N = 8:12:9 Therefore N’s share = Rs (1,80,000 * 12/29) =Rs(2160000/29) = Rs.74483(approx.)
Description : `EDTA^(4-)` i9s ethylenediamine tetraacetate ion The total number of `N-CO-O` bond angles in `[Co(EDTA)]^(-1)` complex ion is .
Last Answer : `EDTA^(4-)` i9s ethylenediamine tetraacetate ion The total number of `N-CO-O` bond angles in `[Co(EDTA)]^(-1)` complex ion is .