Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be

Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be
by

1 Answer

Answer :

Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will ... B. 1.6 g C. 3.2 g D. 0.8 g
by
selected by

Related questions

In the following reaction, `SO_(4)` acts as a reducing agent: `SO_(2)+Cl_(2)+2H_(2)O to H_(2)SO_(4)+3HCl` Find the equivalent weight of `SO_(2)`.

Description : In the following reaction, `SO_(4)` acts as a reducing agent: `SO_(2)+Cl_(2)+2H_(2)O to H_(2)SO_(4)+3HCl` Find the equivalent weight of `SO_(2)`.

Last Answer : In the following reaction, `SO_(4)` acts as a reducing agent: `SO_(2)+Cl_(2)+2H_(2)O to H_(2)SO_(4)+3HCl` Find the equivalent weight of `SO_(2)`.

In which of the following reaction `H_(2)O_(2)` acts as reducing agent :-

Description : In which of the following reaction `H_(2)O_(2)` acts as reducing agent :-

Last Answer : In which of the following reaction `H_(2)O_(2)` acts as reducing agent :- A. `2FeCl_(2)+2HCl+H_(2)O_(2)rarr ... 3)+H_(2)O_(2)rarr H_(2)SO_(4)+H_(2)O`

Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated ... 56 mL B. 112 mL C. 168 mL D. 224 mL

Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... . 0.8 g C. 4.2 g D. 0.98 g

Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... 37.2 mL C. 5.6 mL D. 22.4 mL

HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Description : HOW TO PREPARE 200 mL O.75 N NaOH SOLUTION?

Last Answer : Dissolve 6 g dry sodium hydroxide in 200 mL water.

To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes

Description : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes

Last Answer : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of ... strength of `H_(2)O_(2)` is 1.344 L

The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150

The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

Description : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

Last Answer : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :

The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present in `30 mL` of `0.01M` solution of `[Cr(H_(2)O)_(

Description : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present in `30 mL` of `0.01M` solution of `[Cr(H_(2)O)_(

Last Answer : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present ... Cl]Cl_(2)`, as silver chloride is close to:

Compound A is chiral and has the molecular formula `C_(8)H_(11)N`. When A reacts nitrous acid then occurs a brisk evolution of `N_(2)` gas. A dissolve

Description : Compound A is chiral and has the molecular formula `C_(8)H_(11)N`. When A reacts nitrous acid then occurs a brisk evolution of `N_(2)` gas. A dissolve

Last Answer : Compound A is chiral and has the molecular formula `C_(8)H_(11)N`. When A reacts ... . 1-phenylethanamine C. 1-cyclohexylethanamine D. N-ethylaniline

Assertion :- Bromide ion is serving as a reducing agent in the reaction `2MnO_(4)^(-)(aq.)+Br^(-)(aq.)+H_(2)Orarr2MnO_(2)(aq.)+BrO_(3)^(-)(aq.)+2OH^(-

Description : Assertion :- Bromide ion is serving as a reducing agent in the reaction `2MnO_(4)^(-)(aq.)+Br^(-)(aq.)+H_(2)Orarr2MnO_(2)(aq.)+BrO_(3)^(-)(aq.)+2OH^(-

Last Answer : Assertion :- Bromide ion is serving as a reducing agent in the reaction `2MnO_(4)^(-)(aq.)+Br^( ... is False. D. If both Assertion & Reason are False.

STATEMENT-1 : `H_(2)SO_(4)` can not act as reducing agent. STATEMENT-2 : Sulphur can not increase its oxidation number beyond `+6`.

Description : STATEMENT-1 : `H_(2)SO_(4)` can not act as reducing agent. STATEMENT-2 : Sulphur can not increase its oxidation number beyond `+6`.

Last Answer : STATEMENT-1 : `H_(2)SO_(4)` can not act as reducing agent. STATEMENT-2 : Sulphur can not increase ... False. D. If both Assertion & Reason are False.

Assertion: Reaction of `SO_(2)` and `H_(2)S` in the presence of `Fe_(2)O_(3)` catalyst gives elemental sulphur. Reason: `SO_(2)` is a reducing agent.

Description : Assertion: Reaction of `SO_(2)` and `H_(2)S` in the presence of `Fe_(2)O_(3)` catalyst gives elemental sulphur. Reason: `SO_(2)` is a reducing agent.

Last Answer : Assertion: Reaction of `SO_(2)` and `H_(2)S` in the presence of `Fe_(2)O_(3)` catalyst gives ... is False. D. If both Assertion & Reason are False.

How many of the following species can act as both bleaching agent and reducing agent `O_(3),H_(2)O_(2),SO_(2),HCl,SO_(3)`

Description : How many of the following species can act as both bleaching agent and reducing agent `O_(3),H_(2)O_(2),SO_(2),HCl,SO_(3)`

Last Answer : How many of the following species can act as both bleaching agent and reducing agent `O_(3),H_(2)O_(2),SO_(2),HCl,SO_(3)`

Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases

Description : Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases

Last Answer : Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In ... C. `SO_(3)^(2-)` D. `KI`

Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases

Description : Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases

Last Answer : Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In ... C. `SO_(3)^(2-)` D. `KI`

Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases

Description : Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases

Last Answer : Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In ... ` C. `SO_(3)^(2-)` D. Kl

Assertion: `SO_(3)` acts as an oxidising agent as well as a reducing agent Reason: `SO_(2)` acts as an oxidising as well as a reducing agent

Description : Assertion: `SO_(3)` acts as an oxidising agent as well as a reducing agent Reason: `SO_(2)` acts as an oxidising as well as a reducing agent

Last Answer : Assertion: `SO_(3)` acts as an oxidising agent as well as a reducing agent Reason: `SO_(2)` acts as an oxidising as well as a reducing agent

In which of the following ozone acts as reducing agent?

Description : In which of the following ozone acts as reducing agent?

Last Answer : In which of the following ozone acts as reducing agent? A. `BaO_(2)+O_(3)rarrBaO+2O_(2)` B. `2HCl+O_(3) ... . `2KI+O_(3)+H_(2)Orarr2KOH+I_(2)+O_(2)`

Which of the following acts only as reducing agent

Description : Which of the following acts only as reducing agent

Last Answer : Which of the following acts only as reducing agent A. `KMnO_(4)` B. `CaOCl_(2)` C. `H_(2)S` D. `HNO_(2)`

Which of the following is the primary reason for adding calcium carbonate to the reduction process of iron oxide ores ? The calcium carbonate: w) acts as an oxidizing agent x) removes silicate waste products y) acts as a reducing agent z) removes sulfur waste products

Description : Which of the following is the primary reason for adding calcium carbonate to the reduction process of iron oxide ores ? The calcium carbonate: w) acts as an oxidizing agent x) removes silicate waste products y) acts as a reducing agent z) removes sulfur waste products

Last Answer : ANSWER: X -- REMOVES SILICATE WASTE PRODUCTS

Hot conc. `H_(2)SO_(4)` acts as moderately strong oxidising agent. It oxidises both metals and non-metals. Which of the following elements is oxidised

Description : Hot conc. `H_(2)SO_(4)` acts as moderately strong oxidising agent. It oxidises both metals and non-metals. Which of the following elements is oxidised

Last Answer : Hot conc. `H_(2)SO_(4)` acts as moderately strong oxidising agent. It oxidises both metals and non-metals. Which ... products ? A. Cu B. S C. C D. Zn

Anion exchanger is regenerated usually with (A) NaOH (B) H2SO4 (C) Hydrazine (D) Alum solution

Description : Anion exchanger is regenerated usually with (A) NaOH (B) H2SO4 (C) Hydrazine (D) Alum solution

Last Answer : (A) NaOH

Cation exchanger is regenerated usually with (A) NaOH (B) H2SO4 (C) Hydrazine (D) Alum solution

Description : Cation exchanger is regenerated usually with (A) NaOH (B) H2SO4 (C) Hydrazine (D) Alum solution

Last Answer : (B) H2SO4

A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified

Description : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified

Last Answer : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for ... +2H_(2)O " " `(Atomic weight : As = 75)

Structure of `N_(2)O` is `N = N = O`. Calculate bond enthalphy of `N = N` bond in `N_(2)O`. Given : `{:(DeltaH_(f,N_(2)O)^(@)=100 "kJmol"^(-1)" "BE_(N

Description : Structure of `N_(2)O` is `N = N = O`. Calculate bond enthalphy of `N = N` bond in `N_(2)O`. Given : `{:(DeltaH_(f,N_(2)O)^(@)=100 "kJmol"^(-1)" "BE_(N

Last Answer : Structure of `N_(2)O` is `N = N = O`. Calculate bond enthalphy of `N = N` bond in `N_(2)O`. Given : `{:( ... )` C. `400 kJ mol^(-1)` D. `420 mol^(-1)`

How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 4.5 L of a 1 percent solution?

Description : How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 4.5 L of a 1 percent solution?

Last Answer : 90 ml of dextrose and 4.41 litres of water.

How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 4.5 M CH3OH?

Description : How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 4.5 M CH3OH?

Last Answer : The answer is 9.6 grams.

20 gram of caustic soda are dissolved in water to prepare 500 ml of solution. Find the normality and molarity of solution.

Description : 20 gram of caustic soda are dissolved in water to prepare 500 ml of solution. Find the normality and molarity of solution.

Last Answer : Basis: 500 ml solution. Weight of solute = 20 gm Molecular weight of NaOH = 40 Gram moles of solute = 20/40 = 0.5 Molarity = Gram moles/ Volume of solution in lit  0.5/0.5 = 1 M Normality = gram equivalent of solute/ volume of solution in lit  = 0.5/0.5 = 1N 

Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` acidified with dilute of `H_(2)SO_(4)`. The same volu

Description : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` acidified with dilute of `H_(2)SO_(4)`. The same volu

Last Answer : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` ... calculate the molarity of `H_(2)O_(2)`.

If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_(2)O_(4)` solution react with o.1 mL of previous `K

Description : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_(2)O_(4)` solution react with o.1 mL of previous `K

Last Answer : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_( ... 15/6 mL B. 13/16 C. `11/14` D. None of these

A dilute solution of `H_(2)SO_(4)` is made by adding 5 mL of `3N H_(2)SO_(4)` to 245 mL of water. Find the normality and molarity of the diluted solut

Description : A dilute solution of `H_(2)SO_(4)` is made by adding 5 mL of `3N H_(2)SO_(4)` to 245 mL of water. Find the normality and molarity of the diluted solut

Last Answer : A dilute solution of `H_(2)SO_(4)` is made by adding 5 mL of `3N H_(2)SO_(4)` ... of water. Find the normality and molarity of the diluted solution.

Borazole `(B_(3)N_(3)H_(6))` is related to benzene as

Description : Borazole `(B_(3)N_(3)H_(6))` is related to benzene as

Last Answer : Borazole `(B_(3)N_(3)H_(6))` is related to benzene as A. isostructural B. isoelectronic C. both (1) and (2) D. none

20.0 kg of `N_(2(g))` and 3.0 kg of `H_(2(g))` are mixed to produce `NH_(3(g))`. The amount of `NH_(3(g))` formed is :-

Description : 20.0 kg of `N_(2(g))` and 3.0 kg of `H_(2(g))` are mixed to produce `NH_(3(g))`. The amount of `NH_(3(g))` formed is :-

Last Answer : 20.0 kg of `N_(2(g))` and 3.0 kg of `H_(2(g))` are mixed to produce `NH_(3(g))`. The amount of `NH_(3 ... is :- A. 17 kg B. 34 kg C. 20 kg D. 3 kg

In nature, ammonia is synthesisd by nitrifying bacteria using enzymes while in industry it is manufactured from `N_(2)` and `H_(2)` using iron oxide c

Description : In nature, ammonia is synthesisd by nitrifying bacteria using enzymes while in industry it is manufactured from `N_(2)` and `H_(2)` using iron oxide c

Last Answer : In nature, ammonia is synthesisd by nitrifying bacteria using enzymes while in industry it is manufactured from ... use nitrates in place of `N_(2)`.

(i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Description : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Last Answer : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2) ... lone pair of electrons on the central atom is present in pure s-orbital

`N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3), HNO_(3), H_(3)PO_(3)`. (a) Among the above compounds, co

Description : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3), HNO_(3), H_(3)PO_(3)`. (a) Among the above compounds, co

Last Answer : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3 ... `d pi - p pi` bond are y. Given the answer as `x + y`

(i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Description : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Last Answer : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2) ... lone pair of electrons on the central atom is present in pure s-orbital

`N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3), HNO_(3), H_(3)PO_(3)`. (a) Among the above compounds, co

Description : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3), HNO_(3), H_(3)PO_(3)`. (a) Among the above compounds, co

Last Answer : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3 ... `d pi - p pi` bond are y. Given the answer as `x + y`

The Hinsberg test of a `C_(5)H_(14)N_(2)` compound produces a solid that is insoluble in 10% aq. `NaOH`. This solid derivative dissolves in `10%` aq.

Description : The Hinsberg test of a `C_(5)H_(14)N_(2)` compound produces a solid that is insoluble in 10% aq. `NaOH`. This solid derivative dissolves in `10%` aq.

Last Answer : The Hinsberg test of a `C_(5)H_(14)N_(2)` compound produces a solid that is insoluble in 10% aq. `NaOH` ... would best fit these facts ? A. B. C. D.

The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is:

Description : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is:

Last Answer : The amount of wet NaOH containing 15% water required to prepare 70 liters of 0.5 N solution is: A. 1.65 kg B. 1.4 kg C. 16.5 kg D. 140 kg

What volume at NTP of gaseous ammonia will be required to be passed into `30 cm^(3)` of 1 N `H_(2)SO_(4)` solution to bring down the acid strength of

Description : What volume at NTP of gaseous ammonia will be required to be passed into `30 cm^(3)` of 1 N `H_(2)SO_(4)` solution to bring down the acid strength of

Last Answer : What volume at NTP of gaseous ammonia will be required to be passed into `30 cm^(3)` of 1 N `H_(2 ... down the acid strength of the latter of 0.2 N ?

`{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for complete neutralization"),("(B)" 4.9 g H_(3)PO_(4),"(q) 200 mi

Description : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for complete neutralization"),("(B)" 4.9 g H_(3)PO_(4),"(q) 200 mi

Last Answer : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for ... Na_(2)CO_(3),"(s)May react with an oxidising agent"):}`

You have a solution of 5 molar Sodium Phosphate and n to prepare a solution of 500 millimolar Sodium Phosphate. How much water would you add to 100 milliliter of the original 5 molar solution to produc the 500 millimolar solution?

Description : You have a solution of 5 molar Sodium Phosphate and n to prepare a solution of 500 millimolar Sodium Phosphate. How much water would you add to 100 milliliter of the original 5 molar solution to produc the 500 millimolar solution?

Last Answer : ANSWER: 900 MILLILITERS (or 0.9 LITERS)

25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu

Description : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu

Last Answer : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_ ... is the molarity of the `Fe^(2+)` solution ?

A solution of sulphur dioxide in water reacts with `H_(2)S` precipitating sulphur. Here sulphur dioxide acts as

Description : A solution of sulphur dioxide in water reacts with `H_(2)S` precipitating sulphur. Here sulphur dioxide acts as

Last Answer : A solution of sulphur dioxide in water reacts with `H_(2)S` precipitating sulphur. Here sulphur dioxide ... a reducing agent C. an acid D. a catalyst

A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to

Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`

What volume of water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution?

Description : What volume of water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution?

Last Answer : What volume of water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution? A. 40 mL B ... to `H_(3)AsO_(4)` C. 100 mL D. 20 mL

For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute

Description : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value (number of milli moles of solute

Last Answer : For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating ... A. `200` B. `100` C. `50` D. `25`