Find the term independent of x in `(2x^(5)+(1)/(3x^(2)))^(21)`

Find the term independent of x in `(2x^(5)+(1)/(3x^(2)))^(21)`
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Find the term independent of x in `(2x^(5)+(1)/(3x^(2)))^(21)`
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Check whether the following are quadratic equations: (i) (x+ 1)2=2(x-3) (ii) x – 2x = (- 2) (3-x) (iii) (x – 2) (x + 1) = (x – 1) (x + 3) (iv) (x – 3) (2x + 1) = x (x + 5) (v) (2x – 1) (x – 3) = (x + 5) (x – 1) (vi) x2 + 3x + 1 = (x – 2)2 (vii) (x + 2)3 = 2x(x2 – 1) (viii) x3 -4x2 -x + 1 = (x-2)3 -Maths 10th

Description : Check whether the following are quadratic equations: (i) (x+ 1)2=2(x-3) (ii) x - 2x = (- 2) (3-x) (iii) (x - 2) (x + 1) = (x - 1) (x + 3) (iv) (x - 3) (2x + 1) = x (x + 5) (v) (2x - 1) (x - 3) = (x ... vi) x2 + 3x + 1 = (x - 2)2 (vii) (x + 2)3 = 2x(x2 - 1) (viii) x3 -4x2 -x + 1 = (x-2)3 -Maths 10th

Last Answer : this is the correct answer!

What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

Description : What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

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Solve for x: Sol. 3x/7 + 2/7 + 4(x + 1)/5 = 2/3(2x + 1) -Maths 9th

Description : Solve for x: Sol. 3x/7 + 2/7 + 4(x + 1)/5 = 2/3(2x + 1) -Maths 9th

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f(x) = x^4 – 2x^3 + 3x^2 – ax + b is a polynomial such that when it is divided by (x – 1) and (x + 1), the remainders are respectively 5 and 19. -Maths 9th

Description : f(x) = x^4 – 2x^3 + 3x^2 – ax + b is a polynomial such that when it is divided by (x – 1) and (x + 1), the remainders are respectively 5 and 19. -Maths 9th

Last Answer : answer:

`int(2x+5)/(sqrt(x^(2)+3x+1))dx`

Description : `int(2x+5)/(sqrt(x^(2)+3x+1))dx`

Last Answer : `int(2x+5)/(sqrt(x^(2)+3x+1))dx`

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Description : Evaluate: `int(2x-5)sqrt(2+3x-x^2)dx`

Last Answer : Evaluate: `int(2x-5)sqrt(2+3x-x^2)dx`

Evaluate: `lim_(x rarr oo) (x^(5)+3x^(4)-4x^(3)-3x^(2)+2x+1)/(2x^(5)+4x^(2)-9x+16)`.

Description : Evaluate: `lim_(x rarr oo) (x^(5)+3x^(4)-4x^(3)-3x^(2)+2x+1)/(2x^(5)+4x^(2)-9x+16)`.

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Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Description : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Last Answer : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) ... -5) lt 0` `(viii) |x-1|+|x-2|+|x-3| le 6`

Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Description : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

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A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Let f and g be the functions from the set of integers to the set integers defined by f(x) = 2x + 3 and g(x) = 3x + 2 Then the composition of f and g and g and f is given as (A) 6x + 7, 6x + 11 (B) 6x + 11, 6x + 7 (C) 5x + 5, 5x + 5 (D) None of the above

Description : Let f and g be the functions from the set of integers to the set integers defined by f(x) = 2x + 3 and g(x) = 3x + 2 Then the composition of f and g and g and f is given as (A) 6x + 7, 6x + 11 (B) 6x + 11, 6x + 7 (C) 5x + 5, 5x + 5 (D) None of the above

Last Answer : (A) 6x + 7, 6x + 11 Explanation: fog(x)=f(g(x))=f(3x+2)=2(3x+2)+3=6x+7 gof(x)=g(f(x))=g(2x+3)=3(2x+3)+2=6x+11

Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

Description : Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

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Description : Divide 3x^3 – 2x^2 – 19x + 22 by (x – 2) -Maths 9th

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If the expressions (px^3 + 3x^2 – 3) and (2x^3 – 5x + p) when divided by (x – 4) leave the same remainder, then what is the value of p ? -Maths 9th

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Last Answer : Given that the following polynomials leave the same remainder when divided by (x - 4) : We are to find the value of a. Remainder theorem: When (x - b) divides a polynomial p(x), then the remainder is p(b). So, from (i) and (ii), we get Thus, the required value of a is 1.

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Description : Without actual division show that 2x^4 – 6x^3 + 3x^2 + 3x – 2 is exactly divisible by x^2 – 3x + 2 -Maths 9th

Last Answer : answer:

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Description : Without actual division, show that (x – 1)^2n – x^2n + 2x – 1 is divisible by 2x^3 – 3x^2 + x. -Maths 9th

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Description : `int(3x+1)/(2x^(2)+x-1)dx`

Last Answer : `int(3x+1)/(2x^(2)+x-1)dx`

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`lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))=`_______.

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Last Answer : `lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))=`_______.

If `lim_(x rarr 0) [(2x^(2)+3x+b)/(x^(2)+4x+3)]=2`, then the value of b is ______.

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Determine the nature of the roots of the following equatins : (a) `x^(3) + 2x +4 = 0` (b) `3x^(2) - 10x + 3 = 0` (c ) `x^(2) - 24x + 144 = 0`

Description : Determine the nature of the roots of the following equatins : (a) `x^(3) + 2x +4 = 0` (b) `3x^(2) - 10x + 3 = 0` (c ) `x^(2) - 24x + 144 = 0`

Last Answer : Determine the nature of the roots of the following equatins : (a) `x^(3) + 2x +4 = 0` (b) `3x^(2) - 10x + 3 = 0` (c ) `x^(2) - 24x + 144 = 0`

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Description : The roots of the equation `2x^(2) + 3x + c = 0` (where `x lt 0`) could be `"______"`.

Last Answer : The roots of the equation `2x^(2) + 3x + c = 0` (where `x lt 0`) could be `"______"`.

If `f(x)=|(1,x,x+1),(2x,x(x-1),(x+1)x),(3x(x-1),x(x-1)(x-2),(x+1)x(x-1))|,` then f(100) is equal to - (i)`0` (ii)`1` (iii)`100` (iv)`-100`

Description : If `f(x)=|(1,x,x+1),(2x,x(x-1),(x+1)x),(3x(x-1),x(x-1)(x-2),(x+1)x(x-1))|,` then f(100) is equal to - (i)`0` (ii)`1` (iii)`100` (iv)`-100`

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If f(x) 3x plus 10x and g(x) 2x and ndash 4 find (f and ndash g)(x).?

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Last Answer : Feel Free to Answer

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Description : The value of quadratic polynomial f (x) = 2x 2 – 3x- 2 at x = -2 is ...... (a) 12 (b) 15 (c) -12 (d) 16

Last Answer : (a) 12

If a + b = 1 ,and the ordered pair (a, b) satisfies the equation 2x + y = , then it also satisfies (a) 2x + y (b) 3x + 4y = 3 (c) x + 2y = (d) 2x + 4y =

Description : If a + b = 1 ,and the ordered pair (a, b) satisfies the equation 2x + y = , then it also satisfies (a) 2x + y (b) 3x + 4y = 3 (c) x + 2y = (d) 2x + 4y =

Last Answer : (c) x + 2y =

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Description : `int(4x-3)/(3x^2+2x-5)dx`

Last Answer : `int(4x-3)/(3x^2+2x-5)dx`

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Description : For what values of m does the equation, `mx^(2) + (3x-1)m + 2x + 5 = 0` have equal roots of opposite sign ?

Last Answer : For what values of m does the equation, `mx^(2) + (3x-1)m + 2x + 5 = 0` have equal roots of opposite sign ?

A quadratic equation whose roots are 2 moe than the roots of the quadratic equation `2x^(2) +3x + 5 = 0`, can be obtained by substituting `"_____"` fo

Description : A quadratic equation whose roots are 2 moe than the roots of the quadratic equation `2x^(2) +3x + 5 = 0`, can be obtained by substituting `"_____"` fo

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Description : What are the points of intersection between the line 3x -y equals 5 and the curve 2x squared plus y squared equals 129?

Last Answer : If: 3x-y = 5 then y^2 = (3x_5)^2 => 9x^2 -30x+25If: 2x^2 + y^2 = 129 then y^2 = 129-2x^2So: 9x^2 -30x+25 = 129-2x^2Transposing terms: 11x^2 -30x -104 = 0Factorizing the above: (11x- ... x = 52/11 or x= -2By substituting x into the original equation intersections areat: (52/11, 101/11) and (-2, -11)

What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Description : What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Last Answer : If you mean 3x+2y = -5 and -2x+3y = -5 then they are straightline equations

What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Description : What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Last Answer : If you mean 3x+2y = -5 and -2x+3y = -5 then they are straightline equations

what is the result of adding the system of equations? 2x + y = 4 3x - y = 6 -General Knowledge

Description : what is the result of adding the system of equations? 2x + y = 4 3x - y = 6 -General Knowledge

Last Answer : The result of adding the system of equations 2x + y = 4, 3x - y = 6 is 5x = 10.

The solution set for the inequality 2x – 10 < 3x – 15 over the set of real numbers is -Maths 9th

Description : The solution set for the inequality 2x – 10 < 3x – 15 over the set of real numbers is -Maths 9th

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`int(1)/(sqrt(2x^(2)+3x-2))dx`

Description : `int(1)/(sqrt(2x^(2)+3x-2))dx`

Last Answer : `int(1)/(sqrt(2x^(2)+3x-2))dx`

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Description : Evaluate `int e^(2x) sin 3x dx`.

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Description : Evaluate `int e^(2x) sin 3x dx`.

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Description : `int e^(3x) " cos 2x dx "`

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Description : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.

Last Answer : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.

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Description : How do you factorise 2x squared minus 13x plus 21?

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Mendel studied inheritance of seven pairs of traits in pea which can have 21 possible combinations. If you are told that in one of these combinations, independent assortment is not observed in later studies, your reaction will be (a) independent assortment principle may be wrong (b) Mendel might not have studied all the combinations (c) it is impossible (d) later studies may be wrong.

Description : Mendel studied inheritance of seven pairs of traits in pea which can have 21 possible combinations. If you are told that in one of these combinations, independent assortment is not observed in later ... have studied all the combinations (c) it is impossible (d) later studies may be wrong.

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For what value of p is the coefficient of x^2 in the product (2x – 1) (x – k) (px + 1) equal to 0 and the constant term equal to 2 ? -Maths 9th

Description : For what value of p is the coefficient of x^2 in the product (2x – 1) (x – k) (px + 1) equal to 0 and the constant term equal to 2 ? -Maths 9th

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Factorise: 2x(square) - 7x -15 by spliting the middle term. -Maths 9th

Description : Factorise: 2x(square) - 7x -15 by spliting the middle term. -Maths 9th

Last Answer : Solution :-