is avg better than kaspersky

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is avg better than kaspersky

asked Jan 24, 2022 by anonymous

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answered Jan 24, 2022 by anonymous

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The employee information of an Organization is stored in the relation: Employee (name, sex, salary, deptname) Consider the following SQL query Select deptname from Employee Where sex = ‘M’ group by deptname having avg (salary) > {select avg (salary) from Employee} Output of the given query corresponds to (A) Average salary of employee more than average salary of the organization. (B) Average salary less than average salary of the organization. (C) Average salary of employee equal to average salary of the organization. (D) Average salary of male employees in a department is more than average salary of the organization.

Description : The employee information of an Organization is stored in the relation: Employee (name, sex, salary, deptname) Consider the following SQL query Select deptname from Employee Where sex = M' ... D) Average salary of male employees in a department is more than average salary of the organization.

Last Answer : (D) Average salary of male employees in a department is more than average salary of the organization.

The STUDENT information in a university is stored in the relation STUDENT (Name, Sex, Marks, DEPT_Name) Consider the following SQL Query SELECT DEPT_Name from STUDENT where SEX='M' group by DEPT_Name having avg (Marks)>(SELECT avg (Marks) from STUDENT). It returns the Name of the Department for which: (A) The Average marks of Male students is more than the average marks of students in the same Department (B) The average marks of male students is more than the average marks of the students in the University (C) The average marks of male students is more than the average marks of male students in the University (D) The average marks of students is more than the average marks of male students in the University

Description : The STUDENT information in a university is stored in the relation STUDENT (Name, Sex, Marks, DEPT_Name) Consider the following SQL Query SELECT DEPT_Name from STUDENT where SEX='M' group by ... The average marks of students is more than the average marks of male students in the University

Last Answer : (B) The average marks of male students is more than the average marks of the students in the University

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Description : Consider the following relation: Works (emp_name, company_name, salary) Here, emp_name is primary key. Consider the following SQL query Select emp_name From Works T where salary>(select avg ( ... 4) Find all employees who earn more than the average salary of all employees of their company.

Last Answer : Find all employees who earn more than the average salary of all employees of their company.

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Consider the following ORACLE relations: R(A,B,C) = {<1,2,3>, <1,2,0>, <1,3,1>, <6,2,3>, <1,4,2>,< 3,1,4>} S(B,C,D) = {<2,3,7>, <1,4,5>, <1,2,3>, <2,3,4>, <3,1,4>} Consider the following two SQL queries SQ1 and SQ2: SQ1: SELECT R.B, AVG(S.B) FROM R, S WHERE R.A = S.C AND S.D < 7 GROUP BY R.B; SQ2: SELECT DISTINCT S.B, MIN (S.C) FROM S GROUP BY S.B HAVING COUNT (DISTINCT S.D) > 1; If M is the number of tuples returned by SQ1 and N is the number of tuples returned by SQ2 then (A) M=4, N=2 (B) M=5, N=3 (C) M=2, N=2 (D) M=3, N=3

Description : Consider the following ORACLE relations: R(A,B,C) = {, , , , ,< 3,1,4>} S(B,C,D) = {, , , , } Consider the following two SQL queries SQ1 and SQ2: SQ1: SELECT R.B, AVG(S.B) FROM R, S WHERE R.A = S.C AND S.D ... tuples returned by SQ2 then (A) M=4, N=2 (B) M=5, N=3 (C) M=2, N=2 (D) M=3, N=3

Last Answer : (A) M=4, N=2

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