Description : The equation m(d 2 x/ dt 2 ) + c (dx/dt) + Kx = F 0 sin ωt is a second order differential equation. The solution of this linear equation is given as A. complementary function B. particular function C. sum of complementary and particular function D. difference of complementary and particular function
Last Answer : C. sum of complementary and particular function
Description : If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is -Maths 9th
Last Answer : (c) Let p(x) = 2x2 + kx Since, (x + 1) is a factor of p(x), then p(-1)=0 2(-1)2 + k(-1) = 0 ⇒ 2-k = 0 ⇒ k= 2 Hence, the value of k is 2.
Description : If x+1 is a factor of the polynomial 3x(square) - kx,then find the value of k. -Maths 9th
Last Answer : Solution :-
Description : For what value of k,(x+1) is a factor of p(x) - kx(square) - x - 4 ? -Maths 9th
Description : Find the values of k for which the equations x^2 – kx – 21 = 0 and x^2 – 3kx + 35 = 0 will have a common root? -Maths 9th
Last Answer : Let the common root be α ⟹α2−kα−21=0......(1) α2−3kα+35=0........(2) (1)−(2)⟹2kα=56⟹α=k28Substituting α=k28 in (1) (k28)2−28−21=0 ⟹k=±4
Description : For what value of k will the roots of the equation kx^2 – 5x + 6 = 0 be in the ratio 2 : 3 ? -Maths 9th
Last Answer : (b) 1 Let the roots of the equation kx2 - 5x + 6 = 0 be α and β. Then, α + β = \(\frac{5}{k}\) ...(i) αβ = \(\frac{6}{k}\) ...(ii) Given \(\ ... frac{9}{k}\) ⇒ 9k2 - 9k = 0 k(k - 1) = 0 ⇒ k = 0 or 1 But k = 0 does not satisfy the condition, so k = 1.
Description : One root of x^2 + kx – 8 = 0 is the square of the other, then the value of k is : -Maths 9th
Last Answer : answer:
Description : For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th
Last Answer : Given f(x) = 3x³ - kx² + 4x + 16. Since (x - k/2) is a factor of polynomial. This means x = k/2 is the zero of the given polynomial. ⇒ f(k/2) = 3(k/2)³ - k(k/2)² + 4(k/2) + 16 ⇒ 0 ... - 4k + 32) + 4(k² - 4k + 32) ⇒ 0 = (k + 4)(k² - 4k + 32) ⇒ k = -4.
Description : If the HCF of (x^2 + x – 12) and (2x^2 – kx – 9) is (x – k), then what is the value of k ? -Maths 9th
Description : If the sum of zeroes of the quadratic polynomial 3x2 – kx + 6 is 3, then find the value of k. -Maths 9th
Last Answer : Here a = 3, b = -k, c = 6 Sum of the zeroes, (α + β) = − = 3 …..(given) ⇒ −(−)3 = 3 ⇒ k = 9
Description : How to restore message in Display window of Panasonic cordless phone KX-TG6051
Last Answer : Need Answer
Description : The sinusoidal wave `y(x,t) = ym sin(kx-omegat)` is incident on the fixed end of a string at `x = L`. The reflected wave is given by :-
Last Answer : The sinusoidal wave `y(x,t) = ym sin(kx-omegat)` is incident on the fixed end of a string at `x = L` ... (kx+omegat-kL)` D. `y_(m)sin(kx+omegat-2kL)`
Description : What's the range of the Panasonic KX-TCA86 Telephone Headset?
Last Answer : 100 feet, the quality degrades after that.
Description : Definition: In a direct proportion y = kx, the number k is called the constant of ______.?
Last Answer : proportion
Description : Conductance is given by (where, x = thickness, A = heat flow area, K = thermal conductivity.) (A) x/KA (B) KA/x (C) K/Ax (D) A/Kx
Last Answer : (B) KA/x
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... Φ) C x = (A - Bt) e - ωt D x = X e - ξωt (cos ω d t + Φ)
Last Answer : A x = (A + Bt) e – ωt
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... ) C. x = (A - Bt) e - ωt D. x = X e - ξωt (cos ω d t + Φ
Last Answer : A. x = (A + Bt) e – ωt
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the A differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... (C)x = (A - Bt) e - ωt ( D )x = X e - ξωt (cos ω d t + Φ
Last Answer : ( A ) x = (A + Bt) e – ωt
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equati damped free vibrations having single degree of freedom. What will be the solution to this differ equation if the system is critically ... c. x = (A - Bt) e - ωt d. x = X e - ξωt (cos ω d t + Φ)
Last Answer : a. x = (A + Bt) e – ωt
Description : For what value of k , the following system of equations have infinite solutions : kx + 4y = k-4, 16x + ky = k (a) k = 2 (b) k = 4 (c) k = 6 (d) k = 8
Last Answer : (d) k = 8
Description : Assertion (A) : The value of k for which the system of linear equations kx+2y+1=0 and 6x+4y-5=0 has a unique solution is 3. Reason (R):The system of linear equations a1x + b1y + c1= 0 and a2x + ... not the correct explanation of A. (c) A is correct; R is incorrect. (d) R is correct; A is incorrect.
Last Answer : (d) R is correct; A is incorrect.
Description : The value(s) of 'k' for which the following pair of linear equations will represent a pair of intersecting lines graphically is/are: 3x - 4y + 7 = 0 kx - 8y = 5 (a) k = 6 (b) k ≠ 6(c) any real number (d) any real number except 6
Last Answer : (d) any real number except 6
Description : If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured ... ) Kx (1 - x/l) + bw (C) Kx (1 + x/l) + bw (D) All the above
Last Answer : Answer: Option B
Description : a squar ABCD in which AC =BE when BC produced .A is joined to E prove that FG=GE when AE intersect BD at F and CD at G -Maths 9th
Last Answer : Please give the figure to get your answer, as it is necessary to have figure to answer the question related to geometry.
Description : E and F are respectively the mid-points of the non-parallel sides AD and BC of a trapezium ABCD. Prove that EF||AB and EF = 1/2 (AB +CD). -Maths 9th
Description : In Fig. 8.53,ABCD is a parallelogram and E is the mid - point of AD. A line through D, drawn parallel to EB, meets AB produced at F and BC at L.Prove that (i) AF = 2DC (ii) DF = 2DL -Maths 9th
Last Answer : Given, E is mid point of AD Also EB∥DF ⇒ B is mid point of AF [mid--point theorem] so, AF=2AB (1) Since, ABCD is a parallelogram, CD=AB ⇒AF=2CD AD∥BC⇒LB∥AD In ΔFDA ⇒LB∥AD ⇒LDLF=ABFB=1 from (1) ⇒LF=LD so, DF=2DL
Description : Bisectors of angles A, B and C of a triangle ABC intersects its circumcircle at D, E and F respectively. Prove that angles of triangle DEF are 90° - A/2, 90° - B/2 and 90° - C/2. -Maths 9th
Last Answer : We have ∠BED = ∠BAD (Angles in the same segment) ⇒ ∠BED = 1/2∠A ...(i) Also, ∠BEF = ∠BCF (Angles in the same segment) ⇒ ∠BEF = 1/2∠C ...(ii) From (i) and (ii) ∠BED + ∠BEF = 1/2∠A + 1/2∠C ∠DEF ... ∠A + ∠C) ⇒ ∠DEF = 1/2(180° - ∠B) (Since, ∠A + ∠B + ∠C = 180°) ⇒ ∠DEF = 90° - 1/2∠B
Description : ABCD is a rhombus and AB is produved to E and F such that AE=AB=BF prove that ED and FC are perpendicular to each other -Maths 9th
Last Answer : This answer was deleted by our moderators...
Description : For what values of x, the function `f(x) = x^(5)-5x^(4)+5x(3)-1` is maximum or minimum? Prove that at x = 0, the function is neither maximum nor minim
Last Answer : For what values of x, the function `f(x) = x^(5)-5x^(4)+5x(3)-1` is maximum or minimum ... that at x = 0, the function is neither maximum nor minimum.
Description : From the formula F = qE, can prove that work done is a product of force and displacement. State True/False a) True b) False
Last Answer : a) True
Description : When no one believes in you, do you feel lonely or do you feel motivated by it and want to prove yourself?
Last Answer : As long as you believe in yourself the rest will follow.
Description : suppose you want to prove the isosceles triangle theorem by proving that JKL?
Last Answer : L
Description : What did Ferdinand want to prove when he set sail?
Last Answer : Feel Free to Answer