Description : The Mumbai express 500m long passes a man running at 20km/hr in the same direction in which the express is going in 40sec. The speed of the express is. A) 50km/hr B) 45km/hr C) 25km/hr D) 65km/hr
Last Answer : ANSWER : D Explanation: Length of the train = 500m Speed of the expess relative to man = (500 / 40)m/s = 25/2 m/s Convert m/s into km/hr 25 / 2 m/s = 25 / 2 * 18 / 5 = 45 km/hr Let the ... x -20)km/hr Therefore x - 20 = 45 x = 45 + 20 = 65km/hr Speed of the express = 65 km/hr.
Description : A person runs opposite to that of chandigarh train at a speed of 10km/hr. If the relative speed between train and the boy running in opposite direction is 25km/hr. What is the length of the train, if it takes 10 seconds to cross a boy, when is at rest? A) 36.6 m B) 40.6 m C) 43.6m D) 41.6m
Last Answer : ANSWER : D Explanation: Speed of person = 10km/hr As the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed. Relative speed = speed of train + speed of ... s Distance = speed * time = 25 / 6 * 10 = 250/6 m/s = 41.6 m
Description : A boat goes 3.5km upstream in 24 mins and the speed of the stream is 1.5km per hour, then the speed of the boat in still water is. A) 4.3 km/hr B) 7.4 km/hr C) 5.2km/hr D) 10.25km/hr
Last Answer : ANSWER: D Explanation: Speed of upstream = 3.5 / 24 km/min = 3.5 / 24 * 60 km/hr = 8.75 km/hr Speed of the stream = ½ (a - b)km/hr = 1.5 km/hr 1.5 = ½ ( a- 8.75)km/hr a = 11.75 km/hr ... (a + b) km/hr = ½ (11.75 + 8.75) = ½(20.5) The speed of the boat in still water = 10.25 km/hr
Description : Which expression is equivalent to m-0.25m?
Last Answer : It is: m(1-0.25) or as 0.75m
Description : What volume (in mL) of 0.25M NaSO4 solution is needed to precipitate all the barium as BaSO4(s) from 12.5mL of 0.15M Ba(NO3)2 solution?
Last Answer : The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
Description : If the static deflection is 1.665×10 -3 m, calculate the critical speed of the shaft in rps. Centre of disc at 0.25m away from centre of axis of shaft. A. 8.64 B. 9.64 C. 10.64 D. 12.2
Last Answer : D. 12.2
Description : The slant height and base diameter of conical tomb are 25m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of Rs. 210 per 100 m2 -Maths 9th
Last Answer : Slant height of conical tomb, l = 25m Base radius, r = diameter/2 = 14/2 m = 7m CSA of conical tomb = πrl = (22/7)×7×25 = 550 CSA of conical tomb= 550m2 Cost of white-washing 550 m2 area, which is Rs (210×550)/100 = Rs. 1155 Therefore, cost will be Rs. 1155 while white-washing tomb.
Description : A telephone wire 125m long and 1mm in radius is stretched to a length 125.25m when a force of 800N is applied.
Last Answer : A telephone wire 125m long and 1mm in radius is stretched to a length 125.25m when a force of ... the value of Young's modulus for material of wire?
Description : How many lapse in a 1km in a 25m pool?
Last Answer : Feel Free to Answer
Description : What does 25m equals in cm?
Last Answer : 2500
Description : How many 25m lengths in 1.5k?
Last Answer : There are 1500/25 = 60 lengths of 25cm
Description : A tower of height 24m casts a shadow 50m and at the same time, a girl of height 1.8m casts a shadow. Find the length of the shadow of girl. (a) 3.7 5m (b)3 .5m (c) 3.25m (d) 3m
Last Answer : (a) 3.7 5m
Description : A flag staff 17.5 m high casts a shadow of length 40.25m. What will be the height of a building, which casts a shadow of length 28.75m under similar conditions? a) 14m b) 11.4m c) 13.5m d) 12.5 m
Last Answer : d) 12.5 m
Description : Cleaning of sugarcane is obtained at peripheral speed A. 12-15m/sec B. 18-20m/sec C. 20-25m/sec D. 25-30m/sec
Last Answer : B. 18-20m/sec
Description : A race course is 250 m long. P and Q run a race and P wins by 4m. Q and R run over the same course and Q win by 3m. R and S run over it and S wins by 12m. If P and S run over it, then who would win and by how much? a) P by 4.82m b) S by 5.30m c) P by 7.25m d) Q by 6.54m
Last Answer : B If P covers 250m, Q covers 246 m If Q covers 250m, R covers 247 m If S covers 250m, R covers 238m Now if Q covers 246 m, then R will cover =247/250*246=243.048 If R covers 243.048 m, then S will cover= ... 048=255.30 If P and S run over 250 m, then S win by =(255.30-250) S win by = 5.30 m