What volume (in mL) of 0.25M NaSO4 solution is needed to precipitate all the barium as BaSO4(s) from 12.5mL of 0.15M Ba(NO3)2 solution?

1 Answer

Answer :

The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.

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