What is the answer of 2x-3y?

What is the answer of 2x-3y?
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Answer :

7--
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A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Description : A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Last Answer : Clearly, line a is parallel to X-axis at a distance of 1 unit in positive direction of Y-axis, therefore its equation is y = 1. Also, if we draw the graph of line 2x + 3y = 6, then its graph should intersect X - axis at (3,0 ... Base Height = 1/2 BC AC = 1/2 1 3 / 2 = 3 / 4 sq unit.

If (2, 0) is a solution of the linear equation 2x + 3y = k, then the value of k is -Maths 9th

Description : If (2, 0) is a solution of the linear equation 2x + 3y = k, then the value of k is -Maths 9th

Last Answer : (a) Since, (2, 0) is a solution of the given linear equation 2x + 3y = k, then put x =2 and y= 0 in the equation. ⇒ 2 (2) + 3 (0) = k ⇒ k = 4 Hence, the value of k is 4.

The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Description : The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Last Answer : (d) Since, the graph of linear equation 2x + 3y = 6 cuts the Y-axis. So, we put x = 0 in the given equation 2x+ 3y = 6, we get 2 x 0+ 3y = 6 ⇒ 3y = 6 y = 2. Hence, at the point (0, 2), the given linear equation cuts the Y-axis.

The graph of the linear equation 2x+ 3y = 6 is a line which meets the X-axis at the point. -Maths 9th

Description : The graph of the linear equation 2x+ 3y = 6 is a line which meets the X-axis at the point. -Maths 9th

Last Answer : (c) Since, the graph of linear equation 2x + 3y = 6 meets the X-axis. So, we put y = 0 in 2x + 3y = 6 ⇒ 2x + 3(0) = 6 = 2x + 0 = 6 ⇒ x = 6/2 ⇒ x = 3 Hence, the coordinate on X-axis is (3, 0).

A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Description : A student wrote the equations of the lines a and b drawn in the following graph as y =1 and 2x + 3y =6. Is he right? -Maths 9th

Last Answer : Clearly, line a is parallel to X-axis at a distance of 1 unit in positive direction of Y-axis, therefore its equation is y = 1. Also, if we draw the graph of line 2x + 3y = 6, then its graph should intersect X - axis at (3,0 ... Base Height = 1/2 BC AC = 1/2 1 3 / 2 = 3 / 4 sq unit.

If (2, 0) is a solution of the linear equation 2x + 3y = k, then the value of k is -Maths 9th

Description : If (2, 0) is a solution of the linear equation 2x + 3y = k, then the value of k is -Maths 9th

Last Answer : (a) Since, (2, 0) is a solution of the given linear equation 2x + 3y = k, then put x =2 and y= 0 in the equation. ⇒ 2 (2) + 3 (0) = k ⇒ k = 4 Hence, the value of k is 4.

The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Description : The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th

Last Answer : (d) Since, the graph of linear equation 2x + 3y = 6 cuts the Y-axis. So, we put x = 0 in the given equation 2x+ 3y = 6, we get 2 x 0+ 3y = 6 ⇒ 3y = 6 y = 2. Hence, at the point (0, 2), the given linear equation cuts the Y-axis.

The graph of the linear equation 2x+ 3y = 6 is a line which meets the X-axis at the point. -Maths 9th

Description : The graph of the linear equation 2x+ 3y = 6 is a line which meets the X-axis at the point. -Maths 9th

Last Answer : (c) Since, the graph of linear equation 2x + 3y = 6 meets the X-axis. So, we put y = 0 in 2x + 3y = 6 ⇒ 2x + 3(0) = 6 = 2x + 0 = 6 ⇒ x = 6/2 ⇒ x = 3 Hence, the coordinate on X-axis is (3, 0).

Express the given equation as linear equation in two variables in standard form: 3y = 2x. -Maths 9th

Description : Express the given equation as linear equation in two variables in standard form: 3y = 2x. -Maths 9th

Last Answer : Solution :- 2x - √3y + 0 = 0

Find the co-ordinate where the equation 2x + 3y = 6 intersects x-axis. -Maths 9th

Description : Find the co-ordinate where the equation 2x + 3y = 6 intersects x-axis. -Maths 9th

Last Answer : Solution :-

If the point (2k – 3, k + 2) lies on the graph of the equation 2x + 3y +15 = 0, find the value of k. -Maths 9th

Description : If the point (2k – 3, k + 2) lies on the graph of the equation 2x + 3y +15 = 0, find the value of k. -Maths 9th

Last Answer : Solution :-

At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Description : At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Last Answer : hope its clear

If 2x^2 – 7xy + 3y^2 = 0, then the value of x : y is -Maths 9th

Description : If 2x^2 – 7xy + 3y^2 = 0, then the value of x : y is -Maths 9th

Last Answer : answer:

(2x – 3y)^3 + (3y – 4z)^3 + (4z – 2x)^3 can be factorised into which one of the following ? -Maths 9th

Description : (2x – 3y)^3 + (3y – 4z)^3 + (4z – 2x)^3 can be factorised into which one of the following ? -Maths 9th

Last Answer : answer:

Determine the ratio in which 2x +3y – 30 = 0 divides the join of A(3, 4) and B(7, 8) and at what point? -Maths 9th

Description : Determine the ratio in which 2x +3y – 30 = 0 divides the join of A(3, 4) and B(7, 8) and at what point? -Maths 9th

Last Answer : Let A(1, 2) and B(11, 9) be the given points. Let the points of trisection be P and Q. Then,AP = PQ = QB = k (say)⇒ AQ = AP + PQ = 2k and PB = PQ + QB = 2k ∴ AP : PB = k : 2k = 1 : 2 and AQ ... two points of trisection are \(\big(rac{13}{3},rac{13}{3}\big)\) and \(\big(rac{23}{3},rac{20}{3}\big)\).

If 2x + 3y = 13 and xy = 6, find the value of 8x3 + 21y3. -Maths 9th

Description : If 2x + 3y = 13 and xy = 6, find the value of 8x3 + 21y3. -Maths 9th

Last Answer : 2x +3y = 13-----(1) xy =6-----(2) 8x³ +27y³ = (2x)³ +(3y)³ = (2x+3y)³ - 3*2x*3y(2x+3y) [using (a+b)³ = a³+b³+3ab(a+b)] = (13)³- 18 * 6 *13 [ using (1) and (2)] = 2197 - 1404 =793

if 2x + 3y = 8 and xy = 2, find the value of 4X2 + 9y2. -Maths 9th

Description : if 2x + 3y = 8 and xy = 2, find the value of 4X2 + 9y2. -Maths 9th

Last Answer : Given 2x+3y=8 and xy=2, formula, (a+b)2=a2+b2+2ab ∴(2x+3y)2=4x2+9y2+2(2x)(3y) (2x+3y)2=4x2+9y2+12xy 82=4x2+9y2+12(2) ∴4x2+9y2=64−24=40

For the feasibility region shown below find the maximum value of the function P=2X + 3y?

Description : For the feasibility region shown below find the maximum value of the function P=2X + 3y?

Last Answer : 5

Let `(x_0, y_0)` be the solution of the following equations In `(2x)^(In2)=(3y)^(ln3)`and `3^(lnx)=2^(lny)` Then `x_0` is

Description : Let `(x_0, y_0)` be the solution of the following equations In `(2x)^(In2)=(3y)^(ln3)`and `3^(lnx)=2^(lny)` Then `x_0` is

Last Answer : Let `(x_0, y_0)` be the solution of the following equations In `(2x)^(In2)=(3y)^(ln3)`and `3^(lnx)=2^(lny)` Then ` ... . `(1)/(3)` C. `(1)/(2)` D. `6`

How many terms are in 2x-5 plus 3y?

Description : How many terms are in 2x-5 plus 3y?

Last Answer : There are three terms in the given expression

What is 2x plus 3y equals 17 and 3x minus 2y equals 0.5?

Description : What is 2x plus 3y equals 17 and 3x minus 2y equals 0.5?

Last Answer : It is a simultaneous equation and when solved its solutions arex = 71/26 and y = 50/13

What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Description : What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Last Answer : If you mean 3x+2y = -5 and -2x+3y = -5 then they are straightline equations

What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Description : What type of lines match these equations 3x plus 2y -5 -2x plus 3y -5?

Last Answer : If you mean 3x+2y = -5 and -2x+3y = -5 then they are straightline equations

How many terms are in 2x plus 3y - 4z?

Description : How many terms are in 2x plus 3y - 4z?

Last Answer : There are 3 terms in the given expression

One equation of a pair of dependent linear equation is -2x + 3y = 9 , the second equation can be e) 4x + 6y = 18 f) 4x - 6y = - 18 g) -4x – 6y = 18 h) None of these

Description : One equation of a pair of dependent linear equation is -2x + 3y = 9 , the second equation can be e) 4x + 6y = 18 f) 4x - 6y = - 18 g) -4x – 6y = 18 h) None of these

Last Answer : f) 4x - 6y = - 18

One equation of a pair of dependent linear equation is -2x + 3y = 9 , the second equation can be a) 4x + 6y = 18 b) 4x - 6y = - 18 c) -4x – 6y = 18 d) None of these

Description : One equation of a pair of dependent linear equation is -2x + 3y = 9 , the second equation can be a) 4x + 6y = 18 b) 4x - 6y = - 18 c) -4x – 6y = 18 d) None of these

Last Answer : b) 4x - 6y = - 18

All solutions of the linear equation 2x + 3y = 7 are also the solutions of equation (a) 5x + 6y = 13 (b) 4x + 6y = 11 (c) 6x + 9y = 7 (d) 6x + 9y = 21

Description : All solutions of the linear equation 2x + 3y = 7 are also the solutions of equation (a) 5x + 6y = 13 (b) 4x + 6y = 11 (c) 6x + 9y = 7 (d) 6x + 9y = 21

Last Answer : (d) 6x + 9y = 21

A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Find the charge density when the electric flux density is given by 2x i + 3y j + 4z k. a) 10 b) 9 c) 24 d) 0

Description : Find the charge density when the electric flux density is given by 2x i + 3y j + 4z k. a) 10 b) 9 c) 24 d) 0

Last Answer : b) 9

If 2x-y=4 then calculate 6x-3y=? (a)15 (b)12 (c)18 (d)10

Description : If 2x-y=4 then calculate 6x-3y=? (a)15 (b)12 (c)18 (d)10

Last Answer : (b)12

What is the answer 6x-8y-5x plus 3y?

Description : What is the answer 6x-8y-5x plus 3y?

Last Answer : The given expression can be simplified to: x-5y

My 3y/o is scared of dying. How best to calm him down?

Description : My 3y/o is scared of dying. How best to calm him down?

Last Answer : Let him listen to your heart beat. Make sure he can hear it and ask him to mimic the sound. Then do the same to him and explain how strong the heart is. Then give him a big safe hug and let ... full life. And let him check every so often just to make sure! I remember that day like yesterday! Enjoy!

Find any four solutions of the equation 4x+3y=12. -Maths 9th

Description : Find any four solutions of the equation 4x+3y=12. -Maths 9th

Last Answer : Given equation is 4x + 3y =12 On putting x = 0 in Eq. (i), we get 4(0) +3y =12 ⇒ 3y =12 ⇒ y = 12 / 3 = 4 So, (0, 4) is a solution of given equation. On putting y = 0 in Eq. (i), we ... given equation. Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).

If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Description : If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Last Answer : Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point. Now, put x = 3 and y = 4 in given equation, we get 3(4) = a (3)+7 ⇒ 12 = 3a+7 ⇒ 3a = 12 – 7 ⇒ 3a = 5 Hence, the value of a is 5/3.

Find any four solutions of the equation 4x+3y=12. -Maths 9th

Description : Find any four solutions of the equation 4x+3y=12. -Maths 9th

Last Answer : Given equation is 4x + 3y =12 On putting x = 0 in Eq. (i), we get 4(0) +3y =12 ⇒ 3y =12 ⇒ y = 12 / 3 = 4 So, (0, 4) is a solution of given equation. On putting y = 0 in Eq. (i), we ... given equation. Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).

If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Description : If the point (3, 4) lies on the graph of 3y = ax + 7, then find the value of a. -Maths 9th

Last Answer : Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point. Now, put x = 3 and y = 4 in given equation, we get 3(4) = a (3)+7 ⇒ 12 = 3a+7 ⇒ 3a = 12 – 7 ⇒ 3a = 5 Hence, the value of a is 5/3.

Find the value of k,if y+3 is a factor of 3y(to the power square) + ky + 6. -Maths 9th

Description : Find the value of k,if y+3 is a factor of 3y(to the power square) + ky + 6. -Maths 9th

Last Answer : Solution :-

Express the equation –x + 3y = -2/3 in the form of ax + by + c =0 and identify the values of a,b and c. -Maths 9th

Description : Express the equation –x + 3y = -2/3 in the form of ax + by + c =0 and identify the values of a,b and c. -Maths 9th

Last Answer : answer:

x^4 + xy^3 + x^3y + xz^3 + y^4 + yz^3 is divisible by : -Maths 9th

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Last Answer : answer:

If the points (2, 1) and (1, – 2) are equidistant from the point (x, y), show that x + 3y = 0. -Maths 9th

Description : If the points (2, 1) and (1, – 2) are equidistant from the point (x, y), show that x + 3y = 0. -Maths 9th

Last Answer : (a) The distance d between any two points say P(x1, y1) and Q(x2, y2) is given by:d = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)⇒ d2 = (x2 - x1)2 + (y2 - y1)2 ⇒ d = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)( ... distance of a point P(x1, y1) form the origin= \(\sqrt{(x_2-0)^2+(y_2-0)^2}\) = \(\sqrt{x^2_1+y^2_1}\)

What is the equation of the line joining the origin with the point of intersection of the lines 4x + 3y = 12 and 3x + 4y = 12 ? -Maths 9th

Description : What is the equation of the line joining the origin with the point of intersection of the lines 4x + 3y = 12 and 3x + 4y = 12 ? -Maths 9th

Last Answer : (b) (5, 6)Let the foot of the perpendicular be M(x1, y1) Slope of line AB, i.e., y = -x + 11 = -1 Slope of line PM = \(rac{y_1-3}{x_1-2}\)Now, PM ⊥ AB⇒ \(\bigg(rac{y_1-3}{x_1-2}\bigg)\) x - ... get 2x1 = 10 ⇒ x1 = 5 Putting x1 in (ii), we get y1 = 6. ∴ Required foot of the perpendicular M is (5, 6).

The image of the origin with reference to the line 4x + 3y – 25 = 0 is -Maths 9th

Description : The image of the origin with reference to the line 4x + 3y – 25 = 0 is -Maths 9th

Last Answer : (c) 25x + 25y - 4 = 0 The point of intersection of the given lines can be obtained by solving the equations of the two lines simultaneously. 100x + 50y = 1 ...(i) 75x + 25y = -3 ... = \(rac{4}{25}\)∴ Eqn of required line: x + y = \(rac{4}{25}\) ⇒ 25 + 25y - 4 = 0.

The acute angle which the perpendicular from the origin on the line 7x –3y = 4 makes with the x-axis is: -Maths 9th

Description : The acute angle which the perpendicular from the origin on the line 7x –3y = 4 makes with the x-axis is: -Maths 9th

Last Answer : (c) negativeAs the line from the origin is perpendicular to the line 7x - 3y = 4, so its slope = \(rac{-1}{ ext{slope of }\,7x-3y=4}\)Slope of 7x - 3y - 4 = \(rac{7}{3}\)∴ Slope of line from origin = \(rac{-1} ... of x-axis⇒ θ = tan-1 \(\big(rac{-3}{7}\big)\) = - tan-1 \(\big(rac{3}{7}\big)\)

Find the following products: (i) (3x + 2y + 2z) (9x2 + 4y2 + 4z2 – 6xy – 4yz – 6zx) (ii) (4x -3y + 2z) (16x2 + 9y2+ 4z2 + 12xy + 6yz – 8zx) (iii) (2a – 3b – 2c) (4a2 + 9b2 + 4c2 + 6ab – 6bc + 4ca) (iv) (3x -4y + 5z) (9x2 + 16y2 + 25z2 + 12xy- 15zx + 20yz) -Maths 9th

Description : Find the following products: (i) (3x + 2y + 2z) (9x2 + 4y2 + 4z2 – 6xy – 4yz – 6zx) (ii) (4x -3y + 2z) (16x2 + 9y2+ 4z2 + 12xy + 6yz – 8zx) (iii) (2a – 3b – 2c) (4a2 + 9b2 + 4c2 + 6ab – 6bc + 4ca) (iv) (3x -4y + 5z) (9x2 + 16y2 + 25z2 + 12xy- 15zx + 20yz) -Maths 9th

Last Answer : answer:

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Last Answer : 4x−3y+4=0 ⟹x=4−4+3y Let, y=4, then x=4−4+3(4) =2 Similarly, when y=0,x=−1 4x+3y−20=0 ⟹x=420−3y Let, y=4, then x=420−3(4) =2 Similarly, when y=0,x=5 Plotting the above points on the graph, ... point i.e(2,4) Area of the region bounded by these lines and x-axis =21 6units 4 units =12 sq. units.

What is the coefficient of “p” after simplifying the following expressions 6y + 7p – 3y + 6p -7p²A. 7B. 9C. 13D. 22?

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If a relation `R` on the set `N` of natural numbers is defined as `(x,y)hArrx^(2)-4xy+3y^(2)=0,Aax,yepsilonN`. Then the relation `R` is

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if `x:y=2:5` then `(10x+3y):(5x+2y)` is _____.

Description : if `x:y=2:5` then `(10x+3y):(5x+2y)` is _____.

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