Find any four solutions of the equation 4x+3y=12. -Maths 9th

Find any four solutions of the equation 4x+3y=12. -Maths 9th
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Given equation is 4x + 3y =12  On putting x = 0 in Eq. (i), we get  4(0) +3y =12  ⇒ 3y =12 ⇒ y = 12 / 3 = 4  So, (0, 4) is a solution of given equation.  On putting y = 0 in Eq. (i), we get  4x+ 3 (0) =12 ⇒ 4x =12 x = 12 / 4 =3  So, (3, 0) is a solution of given equation.  On putting x =1 in Eq. (i), we get   4(1) + 3y=12  ⇒ 3y = 12 - 4 = 8 ⇒  y = 8 / 3  So, (1,8 / 3) is another solution of the given equation.   Further, putting x = 2 in Eq. (i), we get  4(2) + 3y = 12 ⇒ 3y = 12 -  8 = 4 ⇒  y =  4 / 3  So, (2, 4 / 3) is also a solution of the given equation.  Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).
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Find any four solutions of the equation 4x+3y=12. -Maths 9th

Description : Find any four solutions of the equation 4x+3y=12. -Maths 9th

Last Answer : Given equation is 4x + 3y =12 On putting x = 0 in Eq. (i), we get 4(0) +3y =12 ⇒ 3y =12 ⇒ y = 12 / 3 = 4 So, (0, 4) is a solution of given equation. On putting y = 0 in Eq. (i), we ... given equation. Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).

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Description : Find the following products: (i) (3x + 2y + 2z) (9x2 + 4y2 + 4z2 – 6xy – 4yz – 6zx) (ii) (4x -3y + 2z) (16x2 + 9y2+ 4z2 + 12xy + 6yz – 8zx) (iii) (2a – 3b – 2c) (4a2 + 9b2 + 4c2 + 6ab – 6bc + 4ca) (iv) (3x -4y + 5z) (9x2 + 16y2 + 25z2 + 12xy- 15zx + 20yz) -Maths 9th

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