When simplified with Boolean Algebra (x + y)(x + z) simplifies to
 (A) x (B) x + x(y + z)
 (C) x(1 + yz) (D) x + yz

1 Answer

Answer :

Ans: D
 When simplified with Boolean Algebra (x + y)(x + z) simplifies to x + yz
 [(x + y) (x + z)] = xx + xz + xy + yz = x + xz + xy + yz (Qxx = x)
 = x(1+z) + xy + yz = x + xy + yz {Q(1+z) = 1}
 = x(1 + y) + yz = x + yz {Q(1+y) = 1}]

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