What is the formula of speed or how to find the Speed of an object ? -Physics

1 Answer

Answer :

The formula for speed is : speed = distance/time. By this Formula you can find the speed of an body

Related questions

Description : What is the formula for finding speed? -Physics

Last Answer : Speed = Total disctance upon Time

Description : A brilliant Engineer offers to make you one object, it must obey the Laws of Physics, it can be any one object you choose, so what object would you choose?

Last Answer : The perfect automobile. Impeccable suspension, engine, drivetrain etc.

Description : A convex lens has a focal length of 10 cm. At what distance from the lens should the object be placed so that it forms a real and inverted image 20 cm away from the lens? What would be the size of ... ? With the help of a ray diagram show the formation of the image by the lens in this case. -Physics

Last Answer : This is the Answe:

Description : An object 2 cm high is placed at a distance of 64 cm from a white screen. On placing a convex lens at a distance of 32 cm from the object it is found that a distinct image of the object ... diagram to show the formation of the image in this position of the object with respect to the lens. -Physics

Last Answer : Since, object-screen distance is double of object-lens separation, the object is at a distance of 2f from the lens and the image should be of the same size of the object.

Description : Draw the ray diagram in each case to show the position and nature of the image formed when the object is placed: (i) at the centre of curvature of a concave mirror (ii) between the pole P and focus F of ... front of a convex mirror (iv) at 2F of a convex lens (v) in front of a concave lens -Physics

Last Answer : Answer. Nature of image: Real, inverted and same size image is formed at the centre of curvature. Nature of image: Virtual, enlarged and erect image is formed behind the mirror. Nature of image: Virtual ... : Virtual, erect and diminished image is formed between O and F on the same side of object.

Description : An object 50 cm tall is placed on the principal axis of a convex lens. Its 20 cm tall image is formed on the screen placed at a distance of 10 cm from the lens. Calculate the focal length of the lens. -Physics

Last Answer : The focal length' of convex length is 7.14 cm. Solution: The given quantities are Height of the object h = 50 cm Height of the image formed h' = -20 cm Image distance v = 10 cm The image ... object distance will be So the focal length will be Thus the focal length of the convex lens is 7.14 cm

Description : A concave lens has focal length of 20 cm. At what distance from the lens a 5 cm tall object be placed so that it forms an image at 15 cm from the lens? Also calculate the size of the image formed. -Physics

Last Answer : Answer. I hope it helped you.

Description : Two objects A and B are moving with same momentum. Mass of object 'B' is greater then mass of object 'A'. Which of the two object will have higher kinetic energy? -Physics

Last Answer : Let m1​ and m2​ be the masses of the body Let m1​>m2​Given that m1​v1​=m2​v2​v2​v1​​=m1​m2​​∴ Ratio between their kinetic energies , =K2​K1​​=21​m2​v22​21​m1​v12​​⟹K2​K1​​=m2​m1​​×m12​

Description : An object is displaced by 10 meters in the direction of applied force. If the applied force is 75 N, What is the work done by the force? -Physics

Last Answer : (d) 750 joule

Description : can average speed of a moving object be zero -Physics 9th

Last Answer : Answer : No Explaination Speed is the distance travelled in the given time. Distance can never be zero. Therefore, average speed will always be a positive value and will not be zero. Speed is a scalar quantity and has only magnitude.

Description : Physics calculation- speed of a star?

Last Answer : Relative to what?

Description : Complex-ish physics/maths question on the speed a car would need to take to go around a loop.

Last Answer : answer:The acceleration of circular motion is ( v ^2 / r ) where v = speed and r = radius of track. Because the track is vertical, the acceleration at the top must exceed the ... than gravity is pulling downward. From the viewpoint of the driver, centrifugal force at the apex exceeds gravity.

Description : The refractive indices of four media A, B, C and D are given in the following table: light-reflection-and-refraction-chapter-wise-important-questions-class-10-science-9 If light, travels from one medium to another, in which case the change in speed will be (i) minimum, (ii) maximum? -Physics

Last Answer : (i) Minimum change is seen as light moves between 1.50 and 1.52, i.e. B and C. (ii) Maximum change when light moves between 1.33 and 2.40, i.e. A and D.

Description : “The refractive index of diamond is 2.42”. What is the meaning of this statement in relation to speed of light? -Physics

Last Answer : I hope it helped you

Description : What would happen if you drove your car close to the speed of light and turned on the headlights? -Physics

Last Answer : Light in vacuum always travels at the same speed c, exactly 299,792,458 meters per second, no matter how it is created or in what frame it is observed. If you drove a car close to the speed ... space is much more feasible, but even then the sparse space dust starts to cause problems at such speeds.

Description : If speed of a car becomes 4 times, its kinetic energy becomes -Physics

Last Answer : (c) 16 times

Description : Explain and explain the third formula of falling object. ?

Last Answer : The third law of falling objects is that the distance ( h) that a falling object travels from a fixed position without hindrance at a given time is proportional to the square of that time ( t) , i.e. , h ∝ t2 . If an object is ... etc then h1 (t2) 1 = h2 (t2) 2 = h2 (t2) 3 = .......... = constant.

Description : What is the 1st formula of falling object ?

Last Answer : All objects falling from the same position and the same height without any obstruction cross the same path at the same time.

Last Answer : The mathematical form of the 3rd formula of the falling object is: h proportional t ^ 2 .

Description : Derive the formula for potential energy. -Physics 9th

Last Answer : Potential energy is the energy possessed by the body by virtue of its position or configuration. Consider a body of mass m at a height 'h' from the ground. The amount of work done to raise this body to this height h against the force of gravity: W=F×h where F is the force of gravity . W=mgh

Description : It is difficult to remember the formula of physics or the reaction of chemistry. What can I do ?

Last Answer : It is difficult to remember the formula of physics or the reaction of chemistry. What can I do ? প্রমাণ You need to know the evidence of these sources well. We all know ( a + b) 2 = a2 ... and put it in front of the table. The subconscious mind remembers things more. You can read these articles!

Description : 15. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharply focused image can be obtained? Find the size and nature of the image. -Physics-10

Last Answer : Object distance (u) = – 27 cm Object height (h) = 7 cm Focal length (f) = – 18 cm According to the mirror formula, The negative value of image height indicates that the image formed is inverted.

Description : 14. An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image. -Physics-10

Last Answer : Object distance (u) = - 20 cm Object height (h) = 5 cm Radius of curvature (R) = 30 cm Radius of curvature = 2 Focal length R = 2f f = 15 cm According to the mirror formula, ... image height indicates that the image formed is erect. Hence, the image formed is erect, virtual, and smaller in size.

Description : 12. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image. -Physics-10

Last Answer : Focal length of convex mirror (f) = +15 cm Object distance (u) = - 10 cm According to the mirror formula, The image is located at a distance of 6 cm from the mirror on the other ... and a value of less than 1 of magnification indicates that the image formed is virtual and erect and diminished.

Description : 11. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram. -Physics-10

Last Answer : Focal length of concave lens (OF1), f = – 15 cm Image distance, v= – 10 cm According to the lens formula, The negative value of u indicates that the object is placed 30 cm in front of the lens. This is shown in the following ray diagram.

Description : 10. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed. -Physics-10

Last Answer : Height of the Object, h0 = 5 cm Distance of the object from converging lens, u = -25 cm Focal length of a converging lens, f = 10 cm Using lens formula, Thus, the image is inverted and formed at a distance of 16.7 cm behind the lens and measures 3.3 cm. The ray diagram is shown below.

Description : 9. One-half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations. -Physics-10

Last Answer : Yes, it will produce a complete image of the object, as shown in the figure. This can be verified experimentally by observing the image of a distant object like a tree on a screen when the ... the lens is covered with a black paper. However, the intensity or brightness of the image will reduce.

Description : We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? -Physics-10

Last Answer : Range of the distance of the object = 0 to 15 cm from the pole of the mirror. Nature of the image = virtual, erect, and larger than the object.

Description : 3. Where should an object be placed in front of a convex lens to get a real image of the size of the object? -Physics-10

Last Answer : (b) The object should be placed at twice the focal length

Description : 2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object? -Physics-10

Last Answer : (d) The position of the object should be between the pole of the mirror and its principal focus.

Description : 2. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? -Physics-10

Last Answer : The position of the image should be at 2F since the image is the real and same size. It is given that the image of the needle is formed at a distance of 50 cm from the convex lens. Therefore, the needle is ... (u) = - 50 cm Image distance, (v) = 50 cm Focal length = f According to the lens formula,

Description : 2. A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located? -Physics-10

Last Answer : Magnification produced by a spherical mirror: Object distance (u) = – 10 cm v = 3 × (- 10) = – 30 cm Therefore, the negative sign indicates that an inverted image is formed in front of the given concave mirror at a distance of 30 cm.

Description : 3. Name the mirror that can give an erect and enlarged image of an object. -Physics-10

Last Answer : The mirror that can give an erect and enlarged image of an object is Concave Mirror.

Description : Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

Last Answer : Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!

Description : Find the energy possessed by an object of mass 10 kg when it is at a height of 2 m above the ground. Given, g = 10 m/s2 -Physics 9th

Last Answer : Given, Mass of object m=10kg. Height h=6m. Acceleration due to gravity g=9.8m/s2 Potential Energy of object P.E=m×g×h ⇒mgh=10×9.8×6=98×6 =588J Energy possessed by the object is 588Joule.

Description : An object of mass m and velocity v has kinetic energy= 200J. Find the new kinetic energy if the mass of the object becomes double and velocity still remains the same? -Physics 9th

Last Answer : let the k.e. in first case be x x = 1/2*m*v^2=200j in second case let the kinetic energy be x' v'=v m'=2m x'= 1/2*2m*v^2 x'= 2(1/2*m*v^2) x'=2(x) x'=2*200j x'=400j

Description : An object with 100 N weights is raised to a height of 15m. Find the potential energy possessed by the object at that height. Also find the new potential energy: -Physics 9th

Last Answer : Potential Energy is given by PE=mgHPE=mgH Given mg=100N and H=15 m PE=100 15=1500JPE=100 15=1500J If If the same object is raised half of its original height i.e H= 7.5 m PE=100 7.5=750JPE=100 ... same object is raised to three times of its original height i.e H=45 m PE=100 45=4500JPE=100 45=4500J

Description : Who was the first to discuss speed formula ?

Last Answer : Newton was the first to discuss the law of motion.

Last Answer : average speed = distance traveled / time.

Description : What does the speed of an object moving at unequal speed depend on ?

Last Answer : What does the velocity of an object moving at unequal speed depend on ?

Description : Explain whether there is acceleration of a rotating object at a balanced speed in a circular motion ?

Last Answer : : In a circular path, there is no acceleration of the rotating object at a balanced speed The rate of change of unequal velocity is called acceleration. So if the velocity is balanced , there will be no acceleration Be it in a circular way or in a straight way.

Description : An object is in static equilibrium when it is _____. (1) at rest (2) moving in a circular path (3) moving with uniform velocity (4) accelerating at high speed

Last Answer : (1) at rest Explanation: When forces acting on an object which is at rest are balanced, the object is said to be in a state of static equilibrium. The resultant of these forces equals zero.

Description : An object with a constant speed – (1) is not accelerated (2) might be accelerated (3) is always accelerated (4) also has a constant velocity

Last Answer : (1) is not accelerated Explanation: Acceleration is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. An object with constant speed will have no acceleration as the speed is uniform.

Description : An object is in static equilibrium when it is _______. (1) at rest (2) moving in a circular path (3) moving with uniform velocity (4) accelerating at high speed

Last Answer : (1) at rest

Description : A force may change ______ of an object. (1) speed (2) direction (3) shape (4) All options are correct

Last Answer : (4) All options are correct

Description : An object moving in a circle of radius ‘r’ with a constant speed ‘v’ has a constant acceleration towards the center equal to A. v²⁄r B. v⁄r C. v²×r D. v×r

Last Answer : v²⁄r

Description : Speed is unchanged because work done on an object is A. zero B. positive C. negative D. infinite

Last Answer : zero

Description : Speed of an object travelling around a circle depends upon A. angular velocity B. radius C. circumference D. both A and B

Last Answer : both A and B

Description : Object moving along a circular path is A. in equilibrium B. not in equilibrium C. not moving with constant speed D. in random motion

Last Answer : not in equilibrium

Description : Centripetal force is dependent on three factors, the odd one out of these factors is A. Mass of the rotating object B. Speed of the rotating object C. Volume of the rotating object D. Path radius

Last Answer : Volume of the rotating object