The third law of falling objects is that the distance ( h) that a falling object travels from a fixed position without hindrance at a given time is proportional to the square of that time ( t) , i.e. , h ∝ t2 . If an object is allowed to fall from a stationary position without hindrance, but if it crosses the distance h in one second, it will cross the distance h × 22 or 4h in two seconds , it will cross the distance h × 22 or 9h in three seconds . So t1, t2, t3 ..... in seconds if the distance traveled by the object is h1, h2, h3 ....... etc then h1 (t2) 1 = h2 (t2) 2 = h2 (t2) 3 = .......... = constant.