the product (x2 – 1) (x4 + x2 + 1) is equal to -Maths 9th

the product (x2 – 1) (x4 + x2 + 1) is equal to -Maths 9th
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Answer :

(x^2-1)(x^4+x^2+1)=x^6+x^4+x^2-x^4-x^2-1. =x^6+1.
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Find the polynomial of least degree which should be subtracted from the polynomial x4 + 2x3 – 4x2 + 6x – 3 so that it is exactly divisible by x2 – x + 1. -Maths 10th

Description : Find the polynomial of least degree which should be subtracted from the polynomial x4 + 2x3 – 4x2 + 6x – 3 so that it is exactly divisible by x2 – x + 1. -Maths 10th

Last Answer : Here, p(x) = x4 + 2x3 - 4x2 + 6x - 3, g(x) = x2 - x +1 On dividing p(x) by g(x) Therefore (x-1) must be subtracted from the polynomial p(x) to make it divisible by g(x).

The turns ratio of device 'B' shown in the illustration is two to one (total). If 220 volts were applied to terminals 'H1' & 'H2', what would be indicated across 'X1' & 'X4' with 'X2' & 'X3' connected and isolated? EL-0082 A. 55 volts B. 110 volts C. 220 volts D. 440 volts

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Last Answer : Answer: B

The turns ratio of device 'B' shown in the illustration is two to one (total). If 440 volts were applied to terminals 'H1' & 'H2', what would be indicated across 'X1' & 'X4' with 'X2' & 'X3' connected and isolated? EL-0082 A. 110 volts B. 220 volts C. 880 volts D. 1760 volts

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x4+3x3+3x2+x+1 -Maths 9th

Description : x4+3x3+3x2+x+1 -Maths 9th

Last Answer : Solution: Let p(x)= x4+3x3+3x2+x+1 The zero of x+1 is -1. p(−1)=(−1)4+3(−1)3+3(−1)2+(−1)+1 =1−3+3−1+1 =1 ≠ 0 ∴By factor theorem, x+1 is not a factor of x4+3x3+3x2+x+1

When f(x) = x4 - 2x3 + 3x2 - ax is divided by x + 1 and x - 1 , we get remainders as 19 and 5 respectively . -Maths 9th

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Last Answer : When f(x) is divided by (x+1) and (x-1) , the remainders are 19 and 5 respectively . ∴ f(-1) = 19 and f(1) = 5 ⇒ (-1)4 - 2 (-1)3 + 3(-1)2 - a (-1) + b = 19 ⇒ 1 +2 + 3 + a + b = 19 ∴ a + b = 13 ------- ... + 3x2 - 5x + 8 ⇒ f(3) = 34 - 2 33 + 3 32 - 5 3 + 8 = 81 - 54 + 27 - 15 + 8 = 47

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The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

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When f(x) = x4 - 2x3 + 3x2 - ax is divided by x + 1 and x - 1 , we get remainders as 19 and 5 respectively . -Maths 9th

Description : When f(x) = x4 - 2x3 + 3x2 - ax is divided by x + 1 and x - 1 , we get remainders as 19 and 5 respectively . -Maths 9th

Last Answer : When f(x) is divided by (x+1) and (x-1) , the remainders are 19 and 5 respectively . ∴ f(-1) = 19 and f(1) = 5 ⇒ (-1)4 - 2 (-1)3 + 3(-1)2 - a (-1) + b = 19 ⇒ 1 +2 + 3 + a + b = 19 ∴ a + b = 13 ------- ... + 3x2 - 5x + 8 ⇒ f(3) = 34 - 2 33 + 3 32 - 5 3 + 8 = 81 - 54 + 27 - 15 + 8 = 47

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The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

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