A number is increased by 10% and the increased num\ber is decreased by 10%. Show that the net decrease is 1 -Maths

A number is increased by 10% and the increased num\ber is decreased by 10%. Show that the net decrease is 1 -Maths
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Last Answer : each side of cube=l incresed by 10%=L+L/10 =11L/10 surface area of the new cube= 6l^2 =6x 11L/10 x 11L/10 =726/100L^2 % increase= 726/100L^2 - 6L^2 / 6L^2 x 100 =126L^2/100 / 6L^2 x 100 =126L^2/600L^2 x 100 =126L^2/ 6L^2 =126/6 =21 %