(–2, –1) and (4, –5) are the co-ordinates of vertices B and D respectively of rhombus ABCD. Find the equation of the diagonal AC. -Maths 9th

1 Answer

Answer :

3\(x\) – 2y + 5 = 0 ⇒ –2y = –3\(x\) – 5 ⇒ y = \(rac{3}{2}\)\(x\) + \(rac{5}{2}\)On comparing with y = m\(x\) + c, we see that slope of given line = \(rac{3}{2}\)As the required line is perpendicular to the given line, Slope of required line = \(rac{-3}{2}\)∴ Equation of required line: (y – 5) = \(rac{-3}{2}\) (\(x\) - 4)⇒ 3(y – 5) = – 2\(x\) + 8 ⇒ 3y – 15 = –2\(x\) + 8 ⇒ 3y + 2\(x\) – 23 = 0

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