The number of real solutions of the equation 2|x|^2 – 5|x| + 2 = 0 is : -Maths 9th

The number of real solutions of the equation 2|x|^2 – 5|x| + 2 = 0 is : -Maths 9th
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What are the number of solutions for real x, which satisfy the equation -Maths 9th

Description : What are the number of solutions for real x, which satisfy the equation -Maths 9th

Last Answer : log2 x>0 2log2 log2 x+log21 log2 (22 x)=1 ⇒2log2 log2 x−log2 log2 (22 x)=1[∵loga1 b=−loga b] $$\Rightarrow \log _{ 2 }{ \left[ \dfrac { { \left( \log _{ 2 }{ x } \right) }^{ 2 } }{ \log_{ 2 } ... log2 (22 )2=log2 8=log2 23=3] ⇒t=3,−1=log2 x ⇒x=2−1or 23 That is x=21 or 8 Hence, the answer is 8.

How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Description : How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Last Answer : 2x + 1 = x - 3 2x-x = -3-1 ∴ x = - 4 ..(i) and it can be written as 1.x + 0. y = - 4 ..(ii) (i) Number line represent the all real values of x on the X ... the equation x + 4 = 0 represent a straight line parallel to Y-axis and infinitely many points lie on a line in the cartesian plane.

How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Description : How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Last Answer : 2x + 1 = x - 3 2x-x = -3-1 ∴ x = - 4 ..(i) and it can be written as 1.x + 0. y = - 4 ..(ii) (i) Number line represent the all real values of x on the X ... the equation x + 4 = 0 represent a straight line parallel to Y-axis and infinitely many points lie on a line in the cartesian plane.

Write any four solutions of the linear equation y = 4 x – 11. -Maths 9th

Description : Write any four solutions of the linear equation y = 4 x – 11. -Maths 9th

Last Answer : answer:

If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Description : If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Last Answer : (b) Let us consider a linear equation ax + by + c = 0 (i) Since, (-2,2), (0, 0) and (2, -2) are the solutions of linear equation therefore it satisfies the Eq. (i), we get At point(-2,2), -2a + 2b + c ... b(x + y)= 0 ⇒ x + y = 0, b ≠ 0 Hence, x + y= 0 is the required form of the linear equation.

The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Description : If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Last Answer : (b) Let us consider a linear equation ax + by + c = 0 (i) Since, (-2,2), (0, 0) and (2, -2) are the solutions of linear equation therefore it satisfies the Eq. (i), we get At point(-2,2), -2a + 2b + c ... b(x + y)= 0 ⇒ x + y = 0, b ≠ 0 Hence, x + y= 0 is the required form of the linear equation.

The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

The number of solutions satisfying the given equation -Maths 9th

Description : The number of solutions satisfying the given equation -Maths 9th

Last Answer : (d) 3Taking log of both the sides to base 3, we have,\(\big[(log_3\,x)^2-rac{9}{2}log_3\,x+5\big]\) log3x = log333/2 = \(rac{3}{2}\) (∵ log33 = 1)⇒ 2(log3x)3 - 9(log3x)2 + 10 log3x - 3 = 0 ⇒ ... log3x = 3, 2 log3x = 1 ⇒ x = 31, x = 33, x2 = 31⇒ \(x\) = (3, 27, √3)∴ There are three solutions.

Write two solutions of the equation 4x -5 y = 15. -Maths 9th

Description : Write two solutions of the equation 4x -5 y = 15. -Maths 9th

Last Answer : Solution :-

Find any four solutions of the equation 4x+3y=12. -Maths 9th

Description : Find any four solutions of the equation 4x+3y=12. -Maths 9th

Last Answer : Given equation is 4x + 3y =12 On putting x = 0 in Eq. (i), we get 4(0) +3y =12 ⇒ 3y =12 ⇒ y = 12 / 3 = 4 So, (0, 4) is a solution of given equation. On putting y = 0 in Eq. (i), we ... given equation. Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).

Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Description : Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Last Answer : As per question, the sum of the coordinates is 10 units. Let x and y be two coordinates, then we get x + y = 10. For x = 5, y = 5, therefore, (5, 5) lies on the graph of x + y = 10. For x = ... and (3, 7) on the graph paper and joining them by a line, we get graph of the linear equation x + y = 10.

Find any four solutions of the equation 4x+3y=12. -Maths 9th

Description : Find any four solutions of the equation 4x+3y=12. -Maths 9th

Last Answer : Given equation is 4x + 3y =12 On putting x = 0 in Eq. (i), we get 4(0) +3y =12 ⇒ 3y =12 ⇒ y = 12 / 3 = 4 So, (0, 4) is a solution of given equation. On putting y = 0 in Eq. (i), we ... given equation. Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).

Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Description : Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Last Answer : As per question, the sum of the coordinates is 10 units. Let x and y be two coordinates, then we get x + y = 10. For x = 5, y = 5, therefore, (5, 5) lies on the graph of x + y = 10. For x = ... and (3, 7) on the graph paper and joining them by a line, we get graph of the linear equation x + y = 10.

How many solutions does the equation 2x +5y=8 has? -Maths 9th

Description : How many solutions does the equation 2x +5y=8 has? -Maths 9th

Last Answer : Solution :- Infinitely many solutions.

Write any two solutions of the linear equation 3x + 2y =9. -Maths 9th

Description : Write any two solutions of the linear equation 3x + 2y =9. -Maths 9th

Last Answer : Solution :-

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Last Answer : (i) (x + 4)(x + 10): Using the identity (x + a)(x + b) = x2 + (a + b)x + ab, we have: (x + 4)(x + 10) = x2 + (4 + 10)x + (4 x 10) = x2 + 14x + 40 (ii) (x + 8)(x - 10): Here, a = 8 and b = ( ... have 64m3 - 343n3 = (4m)3 - (7n)3 = (4m - 7n)[(4m)2 + (4m)(7n) + (7n)2] = (4m - 7n)(16m2 + 28mn + 49n2)

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Last Answer : 1. How will you describe the position of a table lamp on your study table to another person ? To describe the position of a table lamp placed on the table, let us consider the table lamp as P and the table as a plane ... the point A(4, 3). (ii) A unique cross street as shown by the point B(3, 4).

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Last Answer : 1: Draw the graph of each of the following linear equations in two variables: (i) x + y = 4 (ii) x - y = 2 (iii) y = 3x (iv) 3 = 2x + y Solution: (i)x + y= 4 ⇒ y = 4 - x If ... graph paper and joining them, we get a straight line PQ. Thus, PQ is the required graph of the linear equation y = 5x + 3.

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Last Answer : 1. Give the geometric representations of y = 3 as an equation (i) in one variable (ii) in two variables (i) y = 3 [An equation in one variable] ∵ y = 3 is an equation in one variable, i.e. y only. ∴ It has ... equation in two variables] We can write 2x + 9 = 0 as 2x + 0y + 9 = 0 or 2x = -9 + 0y

The solutions of a linear equation in two variables always take integral values .True / false -Maths 9th

Description : The solutions of a linear equation in two variables always take integral values .True / false -Maths 9th

Last Answer : answer:

A linear equation in two variables has infinite solutions. True/false. -Maths 9th

Description : A linear equation in two variables has infinite solutions. True/false. -Maths 9th

Last Answer : answer:

If the roots of the equation x^2 – 2ax + a^2 + a – 3 = 0 are real and less than 3, then which one of the following is correct ? -Maths 9th

Description : If the roots of the equation x^2 – 2ax + a^2 + a – 3 = 0 are real and less than 3, then which one of the following is correct ? -Maths 9th

Last Answer : answer:

Let u = (log2x)^2 – 6(log2x) + 12, where x is a real number. Then the equation x^u = 256 has : -Maths 9th

Description : Let u = (log2x)^2 – 6(log2x) + 12, where x is a real number. Then the equation x^u = 256 has : -Maths 9th

Last Answer : ⇒ u=(log2 x)2−log2 x+12 ⇒ We can take log2 x=y ⇒ Then equation becomes y2−6y+12=u ⇒ Given that xu=256 Applying log we get, ⇒ ulog2 x=8 ∴ u=log2 x8 =y8 So our equation becomes, ⇒ y2−6y+12=y8 ⇒ ... We get y=2 ⇒ So, log2 x=2 ⇒ x=22 ∴ x=4 ∴ The given equation has exactly one solution for x

Is ax + by + c = 0, where a, b and c are real numbers, a linear equation in two variables? Give reason. -Maths 9th

Description : Is ax + by + c = 0, where a, b and c are real numbers, a linear equation in two variables? Give reason. -Maths 9th

Last Answer : Solution :-

If p, q, r are positive and are in A.P., the roots of quadratic equation px^2 + qx + r = 0 are real for : -Maths 9th

Description : If p, q, r are positive and are in A.P., the roots of quadratic equation px^2 + qx + r = 0 are real for : -Maths 9th

Last Answer : Given p,q,r are in A.P. then q=2p+r​.....(1). Now px2+qx+r=0 will have real root then q2−4pr≥0. or, 4(p+r)2​−4pr≥0 or, p2+r2−14pr≥0 or, r2−14rp+49p2≥48p2 or, (r−7p)2≥(43​p)2 or, (pr​−7)2≥(43​)2 [ Since p=0 for the given equation to be quadratic] or, ∣∣∣∣∣​pr​−7∣∣∣∣∣​≥43​.

The number of meaningful solutions of log4(x – 1) = log2 (x – 3) is -Maths 9th

Description : The number of meaningful solutions of log4(x – 1) = log2 (x – 3) is -Maths 9th

Last Answer : (b) 1log4(x - 1) = log2(x - 3) ⇒ log22 (x − 1) = log2(x - 3)⇒ \(rac{1}{2}\) log2 (x-1) = log2 (x- 3) ⇒ log2 (x-1) = 2 log2 (x- 3)\(\big[\)Using logam (bn) = \(rac{n}{m} ... x = 2 or 5 Neglecting x = 2 as log2(x - 3) is defined when x > 2.⇒ There is only one meaningful solution of the given equation.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.5 . -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.5 . -Maths 9th

Last Answer : 1. State whether the following statements are true or false. Justify your answers. (i) Every irrational number is a real number. (ii) Every point on the number line is of the form √m , where m is a natural ... 5 ⇒ OC = √5 With O as centre and OC as radius, draw an arc intersecting OX at D. Since

Draw a graph of the equation x + Y = 5 & 3x - 2y =0 on the same graph paper. Find the coordinates of the point whose two lines intersect. -Maths 9th

Description : Draw a graph of the equation x + Y = 5 & 3x - 2y =0 on the same graph paper. Find the coordinates of the point whose two lines intersect. -Maths 9th

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Draw a graph of the equation x+ y=5 & 3x -2y=0 in the same graph paper find the coordinates of the point whose two two lines intersect. -Maths 9th

Description : Draw a graph of the equation x+ y=5 & 3x -2y=0 in the same graph paper find the coordinates of the point whose two two lines intersect. -Maths 9th

Last Answer : From x + y = 5, If x = 0 0 + y = 5 y = 5 Therefore (0,5) If x = 1 1 + y = 5 y =5 - 1 y = 4 Therefore (1,4) Draw a graph for this And From 3x - 2y = 0 If x = 0 3 (0) - 2y = 0 0 - ... 2y = 0 -2y = -6 y = -6/-2 y = 3 Therefore (2,3) Draw a graph for these points And the point of intersection is (2,3)

If an integer P is chosen at random in the interval 0 ≤ p ≤ 5, the probability that the roots of the equation x^2 + px -Maths 9th

Description : If an integer P is chosen at random in the interval 0 ≤ p ≤ 5, the probability that the roots of the equation x^2 + px -Maths 9th

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The equation whose roots are the negatives of the roots of the equation x^7 + 3x^5 + x^3 – x^2 + 7x + 2 = 0 is : -Maths 9th

Description : The equation whose roots are the negatives of the roots of the equation x^7 + 3x^5 + x^3 – x^2 + 7x + 2 = 0 is : -Maths 9th

Last Answer : answer:

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.3 -Maths 9th

Last Answer : 1. Write the following in decimal form and say what kind of decimal expansion each has : (i) 36/100 Solution: = 0.36 (Terminating) (ii)1/11 Solution: Solution: = 4.125 (Terminating) ... Since the number,1.101001000100001 , is non-terminating non-repeating (non-recurring), it is an irrational number.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.2 -Maths 9th

Last Answer : Solids Bodies occupying space are called solids. A solid has three dimensions viz., length, breadth and thickness or depth or height. The space occupied by a solid body is called its volume .Volume ... a right-angled triangle VOA is revolved about OV, it generates a cone shown in figure alongside.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.4 -Maths 9th

Last Answer : 1. Is zero a rational number ? Can you write it in the form p/q , where p and q are integers and q ≠ 0? Yes, zero is a rational number. We can write it in the form (p/q). That is zero. 2. ... such as -1, -2 are non-whole numbers] (iii) False statement [∵ Rational number (1/2) is not a whole number]

The equation of X-axis is of the form x = 0 -Maths 9th

Description : The equation of X-axis is of the form x = 0 -Maths 9th

Last Answer : (b) The equation of X-axis is of the form y = 0.

The equation of X-axis is of the form x = 0 -Maths 9th

Description : The equation of X-axis is of the form x = 0 -Maths 9th

Last Answer : (b) The equation of X-axis is of the form y = 0.

If x = 0 and y = k is a solution of the equation 5x - 3 y = 0, find the value of k. -Maths 9th

Description : If x = 0 and y = k is a solution of the equation 5x - 3 y = 0, find the value of k. -Maths 9th

Last Answer : Solution :-

Express the equation –x + 3y = -2/3 in the form of ax + by + c =0 and identify the values of a,b and c. -Maths 9th

Description : Express the equation –x + 3y = -2/3 in the form of ax + by + c =0 and identify the values of a,b and c. -Maths 9th

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If one of the roots of the equation x^2 + ax + 3 = 0 is 3 and one of the roots of the equation x2 + ax + b = 0 is three -Maths 9th

Description : If one of the roots of the equation x^2 + ax + 3 = 0 is 3 and one of the roots of the equation x2 + ax + b = 0 is three -Maths 9th

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If the difference in the roots of the equation x^2 – px + q = 0 is unity, then which one of the following is correct ? -Maths 9th

Description : If the difference in the roots of the equation x^2 – px + q = 0 is unity, then which one of the following is correct ? -Maths 9th

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If the roots of the equation x^2 + x + 1 = 0 are in the ratio of m : n, then which one of the following relation holds ? -Maths 9th

Description : If the roots of the equation x^2 + x + 1 = 0 are in the ratio of m : n, then which one of the following relation holds ? -Maths 9th

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What are the roots of the equation 4^x – 3.2^(x + 2) + 32 = 0 ? -Maths 9th

Description : What are the roots of the equation 4^x – 3.2^(x + 2) + 32 = 0 ? -Maths 9th

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What are the roots of the quadratic equation a^2 b^2 x^2 – (a^2 + b^2)x + 1 = 0 ? -Maths 9th

Description : What are the roots of the quadratic equation a^2 b^2 x^2 – (a^2 + b^2)x + 1 = 0 ? -Maths 9th

Last Answer : answer:

If the roots of the equation a(b – c) x^2 + b(c – a)x + c(a – b) = 0 are equal, then a, b, c are in : -Maths 9th

Description : If the roots of the equation a(b – c) x^2 + b(c – a)x + c(a – b) = 0 are equal, then a, b, c are in : -Maths 9th

Last Answer : As we know that for the quadratic equation ax2+bx+c=0, roots will be equal if D=B2−4AC=0 Therefore, for the equation, a(b−c)x2+b(c−a)x+c(a−b)=0 A=a(b−c),B=b(c−a),C=c(a−b) D=0 B2−4AC=0 (b(c−a))2−4(a(b−c))(c(a−b))=0 ⇒ab+bc=2ac Hence a,b and c are in HP.

Two students A and B solve an equation of the form x^2 + px + q = 0. A starts with a wrong value of p and obtains the roots as 2 and 6. -Maths 9th

Description : Two students A and B solve an equation of the form x^2 + px + q = 0. A starts with a wrong value of p and obtains the roots as 2 and 6. -Maths 9th

Last Answer : Let αα and ββ be the roots of the quadratic equation x2+px+q=0x2+px+q=0 Given that, A starts with a wrong value of p and obtains the roots as 2 and 6. But this time q is correct. i.e., a product of roots ... 1 Now, from Eqs. (ii) and (iii), we get α=−3 and β=−4α=−3 and β=−4 which are correct roots.

The equation e^(sin x) – e(–sin x) – 4 = 0 has -Maths 9th

Description : The equation e^(sin x) – e(–sin x) – 4 = 0 has -Maths 9th

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If the roots of the equation x^3 – ax^2 + bx – c = 0 are three consecutive integers, then what is the smallest possible value of b ? -Maths 9th

Description : If the roots of the equation x^3 – ax^2 + bx – c = 0 are three consecutive integers, then what is the smallest possible value of b ? -Maths 9th

Last Answer : Let the roots of the equation x3 – ax2 + bx – c = 0 be (α – 1), α, (α + 1) ∴ S2 = (α – 1)α + α(α + 1) + (α + 1) ( ... ; 1 = b ⇒ 3α2 – 1 = b ∴ Minimum value of b = – 1, when α = 0.

If one root of the equation ax^2 + x – 3 = 0 is –1, then what is the other root ? -Maths 9th

Description : If one root of the equation ax^2 + x – 3 = 0 is –1, then what is the other root ? -Maths 9th

Last Answer : answer:

If the equation (a^2 + b^2) x^2 – 2 (ac + bd)x + (c^2 + d^2) = 0 has equal roots, then which one of the following is correct ? -Maths 9th

Description : If the equation (a^2 + b^2) x^2 – 2 (ac + bd)x + (c^2 + d^2) = 0 has equal roots, then which one of the following is correct ? -Maths 9th

Last Answer : The given quadratic equation is (a2 + b2)x2 − 2(ac + bd)x + (c2 + d2) = 0. If the roots of given quadratic equation are equal, then its discriminant is zero.